Want to only use the first email if multiple are added. Made a function which looks for ',', if it finds it, displays a message and returns the first email.
For a strange reason, it seems to loop through the dataframe twice when using 'applymap', because it prints the message twice.
When I use the 'apply' function on the series, it -as expected-prints out once. Any idea why is this discrepancy?
From the documentation, version 0.25.0, I quote :
Notes
In the current implementation applymap calls func twice on the first column/row to decide whether it can take a fast or slow code path. This can lead to unexpected behavior if func has side-effects, as they will take effect twice for the first column/row.
Related
I have a set of data that is generated:
=((E31/320)^2)/(2+(E31/380))
=((E32/320)^2)/(2+(E32/380))
=((E33/320)^2)/(2+(E33/380))
...
I want to create a sum of these, but I don't want to just SUM them together; I want to write a function that put these together. I came up with this row:
=SUMPRODUCT(((ROW(E1:INDEX(E31:E63;C34)))/320)^2/(2 + (E31:E63/380)))
The problem with this line is it seems to overdo the whole thing. I need to somehow use one variable for the both E31:E63 intervals, because it will otherwise loop through the second E31:E63 n-times, instead of using the same value.
As I see it, there are two solutions.
Write the data in columns, but using the first solution
Write the function, but try to find something that makes the two E31:E63 work as one variable.
I want to implement the second option.
I believe
=SUMPRODUCT(((E31:E63/320)^2)/(2+(E31:E63/380)))
Will do what you want.
I have step where I am have String Array, something like this:
Then Drop-dow patient_breed contains ['Breed1', 'Breed2',.... Breed20']
I need to split this text on two lines. I know that in Gherkin there is expression """. I try something like this:
Then Drop-dow patient_breed contains ['Breed1',
"""
'Breed2',.... Breed20']
"""
It didn't help. Is there any solution?
What do you gain by putting this string in your scenario. IMO all you are doing is making the scenario harder to read!
What do you lose by putting this string in your scenario?
Well first of all you now have to have at least two things the determine the exact contents of the string, the thing in the application that creates it and the hardcoded string in your scenario. So you are repeating yourself.
In addition you've increased the cost of change. Lets say we want our strings to change from 'Breedx' to 'Breed: x'. Now you have to change every scenario that looks at the drop down. This will take much much longer than changing the code.
So what can you do instead?
Change your scenario step so that it becomes Then I should see the patient breeds and delegate the HOW of the presentation of the breeds and even the sort of control that the breeds are presented in to something that is outside of Cucumber e.g. a helper method called by a step definition, or perhaps even something in your codebase.
Try with a datatable approach. You will have to add a DataTable argument in the stepdefinition.
Then Drop-dow patient_breed contains
'Breed1'
'Breed2'
...
...
...
'Breed20']
For a multiline approach try the below. In this you will have to add a String argument to the stepdefinition.
Then Drop-dow patient_breed contains
"""
['Breed1','Breed2',.... Breed20']
"""
I would read the entire string and then split it using Java after it has been passed into the step. In order to keep my step as a one or two liner, I would use a helper method that I implemented myself.
I have to extract the onset times for a fMRI experiment. I have a nested output called "ResOut", which contains different matrices. One of these is called "cond", and I need the 4th element of it [1,2,3,4]. But I need to know its onset time just when the items in "pict" matrix (inside ResOut file) have a name that ends with "*v.JPG".
Here's the part of the code that I wrote (but it's not working):
for i=1:length(ResOut);
if ResOut(i).cond(4)==1 && ResOut(i).pict== endsWith(*"v.JPG")
What's wrong? Can you halp me to fix it out?
Thank you in advance,
Adriano
It's generally helpful to start with unfamiliar functions by reading their documentation to understand what inputs they are expecting. Per the documentation for endsWith, it expects two inputs: the input text and the pattern to match. In your example, you are only passing it one (incorrectly formatted) string input, so it's going to error out.
To fix this, call the function properly. For example:
filepath = ["./Some Path/mazeltov.jpg"; "~/Some Path/myfile.jpg"];
test = endsWith(filepath, 'v.jpg')
Returns:
test =
2×1 logical array
1
0
Or, more specifically to your code snippet:
endsWith(ResOut(i).pict, 'v.JPG')
Note that there is an optional third input, 'IgnoreCase', which you can pass as a boolean true/false to control whether or not the matching ignores case.
This is my code:
for films in filmlist:
with codecs.open('peliculas.txt', encoding='utf8', mode='r') as lfile:
filmsDone = lfile.read()
filmsDoneList = filmsDone.split(',')
if films not in filmsDoneList:
with codecs.open('peliculas.txt', encoding='utf8', mode='a+') as lfile:
lfile.write(films.strip() + ',')
It will never recognize the last item of the list.
I have printed filmsDoneList and the last item in PyCharm looks like this: u'X Men.Primera Generacion'. I have printed films and they looks like this: X Men.Primera Generacion'
So I have no idea where is the problem. Thanks in advance.
#Rafa, for you to better understand what I meant in the comments, I had to write an entire answer in order for me to attach codes and screenshots.
Let's say the peliculas.txt file has the following format:
You can import such file in python according the following 3 commands:
fileIN=open('peliculas.txt','r')
filmsDoneList=fileIN.readlines()
fileIN.close()
So you basically open the file, import each line thanks to readlines() and then close the file because its contents are available in filmsDoneList. The latter has the following contents (in PyCharm):
Obviously this list is quite long and does not fit in my screen, but you get the point.
You can now get rid of that annoying newline tag '\r\n' by means of the following loop:
for id in range(len(filmsDoneList)):
filmsDoneList[id]=filmsDoneList[id].strip()
and now filmsDoneList has the form:
much better now, innit?
Now, let's say you want to add the following films:
newFilms=['The Exorcist','Back to the Future','Aliens','Back to the Future']
To make your code more robust, I have added Back to the Future twice. Basically you can get rid of duplicates in newFilms by means of the set() function. This will convert newFilms in a set with duplicates removed, but we will convert it back to a list thanks to this command:
newFilms=list(set(newFilms))
and now newFilms has the form:
Now that everything has been sorted, it's time to check if items in newFilms already are in filmsDoneList which, recall, is the contents of peliculas.txt.
Reopen peliculas.txt as follows:
fileOUT=open('peliculas.txt','a')
the 'a' tag means "append", so basically everything you write will be added to the file without removing anything from it.
And the main loop goes:
for film in newFilms:
if film in filmsDoneList:
pass
else:
fileOUT.write(film+'\n')
the pass means "do nothing". The write commands also appends the newline tag to the movie title: this will keep the previous format of 1 title per line. At the end of this loop you might as well close fileOUT.
The resulting peliculas.txt is
and, as you can see, Back to the Future was in newFilms but wasn't appended to the end of this file because already was in it. As instead, The Exorcist and Aliens have been appended to this file, at the bottom.
If your file has titles separated by commas, this approach is still valid. However you must add
filmsDoneList=filmsDoneList[0].split(',')
after the first for loop. Also in the write function (in the last for loop) you might want to replace the newline value with a comma.
This approach is cleaner, I reckon will also fix the problem you've been having and avoids continuous open/close files in a loop. Hope this helps!
I like to keep things DRY, that's why I want to have the following in one of my steps:
if first(:css, "#blabla") != nil
find_by_id(blabla).click
end
find_by_id(....)
....
This means, that it will look for a certain element, and if it exists, it will click on it. If not, I will not lose time (my default wait time is 20 secs, which will be used if I put find instead of first there.
The main issue is that I don't want to lose time when checking for a certain element in this case, but I am also wondering if this is a good approach.
I see the issue that your code does unnecessary second query to browser (you already have first(:css, "#blabla") so no need to do find_by_id(blabla))
I propose you to find element using one query:
el = first('#blabla')
el.click unless el.nil?
Note that there is no losing time here as first doesn't block.
However, first doesn't check that there no other elements on the page. You can add :maximum to check it:
el = first('#blabla', maximum: 1)
el.click unless el.nil?
When you're using #find to decide on element presence, you should reduce the wait time for just that call:
if page.has_css?('#blabla', wait: 0)
# Do something
end
However, in your special case, the suggested solution is even better, because it saves you multiple "find" calls for the same element.