is there anything i can do to further improve performance of this formula ?
=IF($A3<>"",IF(Jan!$E6<>"",LET(d_patt,IF(Jan!$E6<>"",VLOOKUP(Jan!$E6,SETTINGS!$A$12:$B$27,2,FALSE)&IF(Jan!$B6<>"",Jan!$B6,0)&IF(Jan!$C6<>"",Jan!$C6,0)&IF(Jan!$D6<>"",Jan!$D6,0),""),"ROT"&IF(LEN(Teams!$BHR4)>0,MID(Teams!$BHR4,MOD(NETWORKDAYS.INTL(Teams!$C4,I$2,"0000000")-1,LEN(Teams!$BHR4)/3)*3+1,3),"000")&IF(LEFT(d_patt,3)="OVT",d_patt,"OVT000")&IF(LEFT(d_patt,3)="SSI",d_patt,"SSI000")&IF(LEFT(d_patt,3)="SSO",d_patt,"SSO000")&IF(LEFT(d_patt,3)="SDS",d_patt,"SDS000")&IF(LEFT(d_patt,3)="HOL",d_patt,"HOL000")&IF(LEFT(d_patt,3)="LID",d_patt,"LID000")&IF(LEFT(d_patt,3)="UNP",d_patt,"UNP000")&IF(LEFT(d_patt,3)="FLD",d_patt,"FLD000")&IF(LEFT(d_patt,3)="MAT",d_patt,"MAT000")&IF(LEFT(d_patt,3)="LIS",d_patt,"LIS000")&IF(LEFT(d_patt,3)="CBR",d_patt,"CBR000")&IF(LEFT(d_patt,3)="ABS",d_patt,"ABS000")),"ROT"&IF(LEN(Teams!$BHR4)>0,MID(Teams!$BHR4,MOD(NETWORKDAYS.INTL(Teams!$C4,I$2,"0000000")-1,LEN(Teams!$BHR4)/3)*3+1,3),"000")&"OVT000SSI000SSO000SDS000HOL000LID000UNP000FLD000MAT000LIS000CBR000ABS000"),"")
i have this on a sheet for each day of the year x 400 people so 146k+ times. this is therefor taken up 80% of the sheet load time.
The sheet basically gets shift patters from Teams, check if there is any holidays, overtime etc from the relevant month tab and relevant cell for the day, and then will generate a code like below.
ROT080OVT000SSI000SSO000SDS234HOL000LID000UNP000FLD000MAT000LIS000CBR000ABS000
i have so far managed to make this faster by using the LET function, but not show if its possible to make any further improvements.
if you need an example file i can send this or upload somewhere, not sure if that is possible via stackoverflow or a preferred site to upload to.
Thanks
The following is a shortened version of your formula to reduce the complexity of computations.
Instead of building the 'OVT000SSI000...' string one piece after another while always checking if the first 3 characters of 'd_patt' match the current piece, we can set the whole string with '000's as default and only replace the section that matches 'd_patt' (see highlighted elements in screenshot below)
Which results in the full formula:
=IF(LEN($A3)>0,"ROT"&IF(LEN(Teams!$BHR4)>0,MID(Teams!$BHR4,MOD(NETWORKDAYS.INTL(Teams!$C4,I$2,"0000000")-1,LEN(Teams!$BHR4)/3)*3+1,3),"000")&LET(default,"OVT000SSI000SSO000SDS000HOL000LID000UNP000FLD000MAT000LIS000CBR000ABS000",d_patt,VLOOKUP(Jan!$E6,SETTINGS!$A$12:$B$27,2,FALSE)&IF(LEN(Jan!$B6)>0,Jan!$B6,0)&IF(LEN(Jan!$C6)>0,Jan!$C6,0)&IF(LEN(Jan!$D6)>0,Jan!$D6,0),IF(LEN(d_patt)>0,REPLACE(default,SEARCH(LEFT(d_patt,3),default),6,d_patt),default)),“”)
If $B6, $C6 and $D6 can only be either empty or a numerical number, in other words, if they are never a letter or special character, the 'd_patt' function can be further shortened as follows:
Which results in the full formula:
=IF(LEN($A3)>0,"ROT"&IF(LEN(Teams!$BHR4)>0,MID(Teams!$BHR4,MOD(NETWORKDAYS.INTL(Teams!$C4,I$2,"0000000")-1,LEN(Teams!$BHR4)/3)*3+1,3),"000")&LET(default,"OVT000SSI000SSO000SDS000HOL000LID000UNP000FLD000MAT000LIS000CBR000ABS000",d_patt,VLOOKUP(Jan!$E6,SETTINGS!$A$12:$B$27,2,FALSE)&(Jan!$B6+0)&(Jan!$C6+0)&(Jan!$D6+0),IF(LEN(d_patt)>0,REPLACE(default,SEARCH(LEFT(d_patt,3),default),6,d_patt),default)),“”)
Over the weekend, my work laptop did a restart and Microsoft gave me the perfect gift in Excel, it introduced the implicit intersection operator which has completely messed up my world, literally every formula has gone crazy.
I've checked every link I can and cannot work out how to correct even the most basic formula. I would like to ask about this one so I can at least make some progress forwards.
=FIND('Value Definitions'!C3,'User Interface'!K:K) was my formula that was worked forever.
The explanation of this formula is to flag all value definitions that have been used within text of all rows in the user interface column K.
When Excel asks me to correct the formula, it rewrites it as =FIND('Value Definitions'!C3,#'User Interface'!K:K).
This results in #VALUE rather than a number of where the first occurrence was found. If I remove the # then I get #SPILL!.
Just to reiterate the purpose of the formula, I identify which phrases exist in an interface that come from the value definitions worksheet, irrespective of the number value I get (character count of first occurence), I just want to identify that it exists at least once. Then I can use this flag to lookup all related value definitions to be included on the user interface.
Thanks for your help in advance.
I have a field in my excel spreadsheet that depends on several different fields to determine the calculation that should be made. I think I have my formula correct but I am not getting the appropriate responses so I know there must be something I am missing. Let me start by summarizing what I am attempting to do.
If D5=2, then I need to verify if $AI$12-AB14>(3/24) and return a T if it is or leave the field blank if not. Alternatively, if D5=1, then I have to also verify that Y14=Y and Z14=Y, and finally $AC$12-AA14>(3/24) and return a T if so, or leave the field blank if not.
(The reference to 3/24 is required as I am performing time calculations from data entry fields pulling from a userform)
What I am receiving for a response is 'True'. That is not an option so I suspect it is returning the result of a specific logical statement? Below is my formula:
=IF(AND(D5="2",$AI$12-AB14>(3/24),),"T","")
=IF(AND(D5="1",Y14="Y",Z14="Y",$AC$12-AA14>(3/24),),"T","")
I can't insert an image in comments, so I'll reply. This simplified example shows how it works:
And pay attention to D5 - are there really values 1 and 2 as text. If not, the quotation marks must be removed from the formula
I have a dataset in long format with a unique ID representing people at different points in time. I already have a list of ID's with the first code, but would like to add a column for the second and third code, if available.
An example of the data, with what the output should look like at the bottom
I already have the first two columns in this example. I was thinking I would specify that I want to look at the values that are not the first code, and output a different code in the range if available, otherwise it returns blank. I also want to be able to use the command with few modifications in a third cell for a third code, again as long as it exists.
Ideally this can all be done without the use of vba, however if that would be easier, then by all means go ahead. Any solution not necessarily following my logic map are appreciated as well. Thanks in advance for the help!
Basically I am trying to improve a spreadsheet that current uses fixed IF functions within IF functions to determine where to find data, then originally used the VLOOKUP function to return the appropriate cable cleat size. Where "Cleat Diameter">"Cable Diameter".
I've been using this for a while, however excel quickly runs out of resources with all the remaining calculations being performed. As a result, I've opted to put all data a single table, and try to use the match function to retrieve the necessary row. Then Simply use the =INDIRECT function to retrieve data from the appropriate column of the associated row.
Unfortunately I believe the issue relates to the fact that I first need to perform at MATCH Type 0 (exact match), followed by a type -1 for the size to identify the next size up that can accommodate a specific cable size.
I've managed a simple lookup on another dataset using (for exact matches):
=MATCH($B3,'Current Raw Data'!A:A,0)+ROW('Current Raw Data'!A:A)-1
However when I attempt the same thing with two types of matches I get errors. The closest I get it using the following array formula, but it does not work unless the data set is arranged so that the contents of Cell C3 is the first occurring item in the dataset in column A:A:
{=MATCH(C3,($B3='Lookup - Cleats'!A:A)*('Lookup - Cleats'!B:B),-1)}
Main sheet:
Dataset Example:
With this array formula (click Ctrl + Shift + Enter together inside formula bar), you should be able to get your results:
=IFERROR(INDEX('Lookup - Cleats'!C$3:C$26,MATCH($B3&$C3,'Lookup - Cleats'!$A$3:$A$26&'Lookup - Cleats'!$B$3:$B$26,0)),"")
I tried my best to use your data setup but maybe miss one or two things that you will need to adjust accordingly. Let me know if this is not working.