Calculating the amount of overlapping days between two ranges - excel-formula

I have a set of Elements all with a start date and a projected end date. I wish display the number of days each element overlaps with every row on the Holidays section. - I will use this as a guide to how far I need to extend the Timeline - End:
I have tried using MMULT, TRANSPOSE, INDEX and ROW in combination but throws !VALUE.
The current formula I tried using was:
=MMULT((TRANSPOSE($C$4+ROW(C19:INDEX($C:$C, $D$20-$C$4+1))-1)>=$C$20:$C$40)*(TRANSPOSE($C$4+ROW(C19:INDEX($C:$C, $D$20-$C$4+1))-1)<=D20:D40), ROW(C19:INDEX($C:$C, $D$4-$C$4+1))^0)
I expect the number of days that the all 'Holidays' over lap with each row in the Elements section.

Assuming (since I cannot read/get which 2 ranges that you intent to compare..) that range1 is from to and range2 is from to , with these values are located in A1= , B1= , A2= , B2= . Do :
=if((if(B2<B1,B2,B1)-if(A2>A1,A2,A1))>=0,(if(B2<B1,B2,B1)-if(A2>A1,A2,A1)),"no overlap")
Idea : get the earliest end date, minus the latest start date.
please share if it works/not.

Related

Find End & Start Date Double Vlookup Excel

I have thousands of cells of data formated with the headers of
UID, Date, Mass, Start / End, Float Days, Days from Start
I have a simple version of what the sheet looks like below:
Each new data entry is entered as a row.
The data for each UID ( unique ID) is taken on non-consistent days over the length of its float life. (ex: wood floats and I take its mass on different days until it sinks).
I want to Identify a "Float Days" by taking the Sink date and subtracting it by the first reference of the ID.
#simple:
When the row has "1" in the D column, Find the ID on that row, then find that ID when that row has "0".
Take the date from that row and subtract by sink date to give me float days
#complex:
=IF(D16="1", (vlookup(A16 & "0",$A$1:$F$999,2,0)-B16, "")
If possible, I would like to use the framework of the formula to also calculate each data-inputs date in days from its Start Date as shown below:
#simple: in row E
Take the date from current row (row 10 for example), find that ID's start date,
subtract from one another to give me days from time=0
#complex:
=B10-vlookup(A10 & "0",$A$1:$F$999,B,0)
I am confused as to whether I am typing the formula incorrectly or if there is another and easier way to do this.
Thank you!
SUMFIS is the better choice here. In cell E2 and copied down:
=IF(D2=1,B2-SUMIFS(B:B,A:A,A2,D:D,0),"")
If you want a same day start/end pair to be equal to 1 instead of 0, just add a +1 to the end of the SUMIFS.

Excel - count days in each month between two dates (both dates available)

I have found the solution thought it would be good to share:
so the formula should be :
=((MAX(CT$6-$N8,0)-MAX(EOMONTH(CT$6,-1)-$N8,0))-(MAX(CT$6-$O8,0)-MAX(EOMONTH(CT$6,-1)-$O8,0))+(EOMONTH(CT$6,0)=EOMONTH($N8,0)))*1
:)
I am trying to write an excel formula which can be dragged across a row of cells to give the number of days in each month between two specified dates. E.g:
I tried using a if with sum product formula from the same website but for some reason it is not recognising the days of last month. was wondering if someone could help explain what this formula does and how to correct it.
=IFERROR(IF(AND(CS$6>=$M9,CS$6<=$N9),SUMPRODUCT(--(MONTH(ROW(INDIRECT($M9&":"&IF($N9="",TODAY(),$N9))))=MONTH(CS$6))),),"")
SECOND REVISION (R2)
Updated workbook link to capture fixed column headings
Eqn / formula also includes static view
Depending upon years spanned, R2 represents a less favourable outcome re space (will require more columns). In this case, number of additional columns required to match stacked view ~100 (!!).
FIRST REVISION (R1) etc. based upon #Charlotte.Sarah.Smith feedback
Days in each month were 1 day less than they should have been - this has been corrected (in both screenshot, linked sheet, and relevant eqns)
Also showcase a couple of sample illustrations/visual representations which may/not be of interest (included within linked sheet too)
Suppose we wanted to expand upon #Will's solution by stacking the dates by year, so that column headings can vary according to different start dates (as opposed to the very first start date that happens to appear)...
For instance, if the next row included the date range 'start = 10/02/16' through 'end = 15/03/19' - you'll appreciate that the number of columns spanning Jan-Dec ('16), Jan-Dec ('17),... up to (and incl.) the range in the first row (Jan '21 - Mar '23) becomes unwieldy.
By using a data table (see here) you can produce a 'stacked' view of the number of days per month regardless of the year (!) - see screenshot below and link to this [updated/corrected] worksheet.
R2 screenshot:
REVISION
See validation/reconciliation column at end
*Visual representations - could be useful for assessing trends etc.
Fun in 3D too!
1] Red font: first row that defines the construct of the data table: enter date range in the format '10/02/2021-15/08/2023'
Cell E3 eqn (drag to right):
=IFERROR(IF($A3>EDATE(E$2,1),0,MAX(,IFERROR(IF(MIN($B3,MIN(EDATE(E$2,1),$B3))=E$2-1,0,MIN($B3,MIN(EDATE(E$2,1),$B3))),"")-MAX($A3,E$2))),0)
(Similar to what we've seen previously)
2] Table below red font: enter any start date (as a regular date, e.g. dd/mm/yyyy) < end date (likewise, regular date) in columns A, B as desired/req.
Data Table
3] Data Table (column data): enter the following in cell c4 (drag down as req.)
=TEXT(A4,"dd/mm/yyyy")&"-"&TEXT(B4,"dd/mm/yyyy")
4] Data Table (highlight cells c3:d42, insert data table, select blank/empty cell for 'row input' and c2 for 'column input')
The data table should 'come to life' (calculate sheet, shift + F9) otherwise.
FilterXML
5] Split result by delimiter '|' using FilterXML as follows (cell E4, only drag down, not to right):
=IFERROR(TRANSPOSE(FILTERXML("<AllText><Num>"&SUBSTITUTE(LEFT(MID(D4,2,LEN(D4)-1),LEN(MID(D4,2,LEN(D4)-1))-1),"|","</Num><Num>")&"</Num></AllText>","//Num")),"")
VALIDATION
Note the check column: date difference = sum of days in table (default cell colour is otherwise RED):
REVISION 2
Here is the formula for a static version of above (i.e. no stacking by year, instead, each date in column headers are distinct re calcs) - it was already available in row with red font(!!)
=IFERROR(IF($A3>EDATE(C$2,1),0,MAX(,IFERROR(IF(MIN($B3,MIN(EDATE(C$2,1),$B3))=C$2-1,0,MIN($B3,MIN(EDATE(C$2,1),$B3))),"")-MAX($A3,C$2))),0)
Viola!
One potential solution would be to compare dates using the MIN and MAX functions like this:
=IF(MIN($B2+1,D$1)-MAX($A2,C$1)<0,"",MIN($B2+1,D$1)-MAX($A2,C$1))
screenshot
This solution uses month starting dates (e.g., Feb 1, 2021), but it could be adapted to work with month end dates instead (e.g., Feb 28, 2021).
The idea is that you take the later of the finish date or month end date minus the lesser of the start date or the month start date. For the first month and last months, this returns the number of days within that range inclusive of the first and last day. For all the months between the first and last months, it returns the number of days in the month.
The +1 on the minimum of the end dates seems a little counterintuitive, but it's necessary to include the first and last day in the count. Without it, you'd get 14 days in March 2022 instead of 15.
The "if less than zero" function makes it return a blank (or zero if you'd prefer) for any month outside the dat range.
This solution does not summarize by month (e.g., 19 days for Feb 2021 plus 28 days for 2022 to get 47 total days in February), but that's consistent with the sample you provided. The comments also indicate that you want to consider the years as well.

Trying to split campaign names by days between start and end date in EXCEL

I am trying to split campaign names by day.
For Example : For each campaign, I want to see x number of rows where x = the number of days between the start and end date
Formula solution
(Some adjusting to the original date in order to reduce the number of days for demonstration only)
In E2, formula copied down :
=IFERROR(INDEX(A:A,AGGREGATE(15,6,ROW($2:$4)/(C$2:C$4-B$2:B$4>=COLUMN($1:$1)),ROW(A1))),"")

How to filter out partial match in an Excel row?

I have an Excel sheet with dates in the rows. A given month should be used only once in a row. How can I filter out, if there are two dates in the same row from the same month?
For example I have the following array, and I would like to have as a result, that there is a match in this row (2012-03).
2012-03-04 2012-02-05 2012-04-06 2012-03-07 2012-10-08 2012-11-09 2012-12-10
I have tried to combine aggregate and match functions, but I cannot find out how to do it properly.
One of my codes, of course it gave an error:
=aggregate(9,6,(MATCH("*"&LEFT(A8,7)&"*","*"&LEFT(b8,7)&"*",0), MATCH("*"&LEFT(b8,7)&"*","*"&LEFT(c8,7)&"*",0)))
Ok, now I have tried another way, and I could get a solution, but with a code which is like a km long...I have first created a new dataset, cutting down the days by using: =""&LEFT(A8,7)&""
Then I have compared all the cells in a given row of my new dataset. Could someone help me how to shorten the exact( ) parts? The aim is to compare all.
=if((or(exact(A2, B2), exact(A2,C2),exact(A2,D2),exact(A2,E2),exact(A2,F2),exact(A2,G2),exact(A2,H2),exact(A2,I2),exact(A2,J2),exact(A2,K2),exact(A2,L2),exact(A2,M2),exact(A2,N2),exact(A2,O2),exact(A2,P2),exact(A2,Q2),exact(A2,R2),exact(B2,C2),exact(B2,D2),exact(B2,E2),exact(B2,F2),exact(B2,G2),exact(B2,H2),exact(B2,I2),exact(B2,J2),exact(B2,K2),exact(B2,L2),exact(B2,M2),exact(B2,N2),exact(B2,O2),exact(B2,P2),exact(B2,Q2),exact(B2,R2),exact(C2,D2),exact(C2,E2),exact(C2,F2),exact(C2,G2),exact(C2,H2),exact(C2,I2),exact(C2,J2),exact(C2,K2),exact(C2,K2),exact(C2,L2),exact(C2,M2),exact(C2,N2),exact(C2,O2),exact(C2,P2),exact(C2,Q2),exact(C2,R2),exact(D2,E2),exact(D2,F2),exact(D2,G2),exact(D2,H2),exact(D2,I2),exact(D2,J2),exact(D2,K2),exact(D2,L2),exact(D2,M2),exact(D2,N2),exact(D2,O2),exact(D2,P2),exact(D2,Q2),exact(D2,R2),exact(E2,F2),exact(E2,G2),exact(E2,H2),exact(E2,I2),exact(E2,J2),exact(E2,K2),exact(E2,L2),exact(E2,M2),exact(E2,N2),exact(E2,O2),exact(E2,P2),exact(E2,Q2),exact(E2,R2),exact(F2,G2),exact(F2,H2),exact(F2,I2),exact(F2,J2),exact(F2,K2),exact(F2,L2),exact(F2,M2),exact(F2,N2),exact(F2,O2),exact(F2,P2),exact(F2,Q2),exact(F2,R2),exact(G2,H2),exact(G2,I2),exact(G2,J2),exact(G2,K2),exact(G2,L2),exact(G2,M2),exact(G2,N2),exact(G2,O2),exact(G2,P2),exact(G2,Q2),exact(G2,R2),exact(H2,I2),exact(H2,J2),exact(H2,K2),exact(H2,L2),exact(H2,M2),exact(H2,N2),exact(H2,O2),exact(H2,P2),exact(H2,Q2),exact(H2,R2),exact(I2,J2),exact(I2,K2),exact(I2,L2),exact(I2,M2),exact(I2,N2),exact(I2,O2),exact(I2,P2),exact(I2,Q2),exact(I2,R2),exact(J2,K2),exact(J2,L2),exact(J2,M2),exact(J2,N2),exact(J2,O2),exact(J2,P2),exact(J2,Q2),exact(J2,R2),exact(K2,L2),exact(K2,M2),exact(K2,N2),exact(K2,O2),exact(K2,P2),exact(K2,Q2),exact(K2,R2),exact(L2,M2),exact(L2,N2),exact(L2,O2),exact(L2,P2),exact(L2,Q2),exact(L2,R2),exact(M2,N2),exact(M2,O2),exact(M2,P2),exact(M2,Q2),exact(M2,R2),exact(N2,O2),exact(N2,P2),exact(N2,Q2),exact(N2,R2),exact(O2,P2),exact(O2,Q2),exact(O2,R2),exact(P2,Q2),exact(P2,R2),exact(Q2,R2))),"same month","ok")
Thank you in advance.
I am not sure if there is a better way, but this is how I'd tackle the problem based on my Excel knowledge:
Add data of dates above in cells A1-G1
On row below date add formulas for dates: A2=DATE(A1) ..... G2=DATE(G1)
At the end of the original row of dates add the numbers 1 thru 12:
using formula cell H1=1, I1=H1+1 ..... S1=R1+1
After the months on row 2:H2=COUNTIF($A2:$G2,H1) ..... S2=COUNTIF($A2:$G2,S1)Counting frequency for each of the 12 months
T2=MAX(H2:S2)
Then select on cell T2being more than 1.
Here it is as a Google sheet (you can download it and open in Excel if you want)
Maybe this will help. Assume that the range of dates is in $A$1:$G$1. Also assume that the entries are numerical dates; if they are instead text you can handle this by using the DATEVALUE function. Then we can get the years and months of the range with:
{=YEAR($A$1:$G$1)}
{=MONTH($A$1:$G$1))
This and all other formulas must be entered as array formulas (CrtlShiftEnter).
We next convert back to a date, but use 1 for the day, so that all dates get shifted to the first day of the month (this means that any dates from the same month are shifted to the same date):
{=DATE(YEARS,MONTHS,1)}
We can produce an NxN comparison of the shifted dates by:
{=TRANSPOSE(SHIFTED_DATES)=SHIFTED_DATES}
We can count the number of True's in this array by:
{=SUM(--(ARRAY))}
If there we no dates from the same month we'd expect this to sum to N because this method compare each date to itself as well as the other dates. The causes the N elements on the main diagonal of this array to be True. If any dates are in the same month off-diagonal elements will also be True. So to detect if there are dates from the same month we make the comparison:
{=SUM(--(ARRAY)) > N}
or more generally:
{=SUM(--(ARRAY)) > COUNT($A$1:$G$1)}
Rolling all of these up into one formula:
=IF(SUM(--(TRANSPOSE(DATE(YEAR($A$1:$G$1),MONTH($A$1:$G$1),1))=DATE(YEAR($A$1:$G$1),MONTH($A$1:$G$1),1)))>COUNT(DATE(YEAR($A$1:$G$1),MONTH($A$1:$G$1),1)),"same month","ok")
If your dates are in a range other than $A$1:$G$1 then make the appropriate substitutions.
Hope that helps.

EXCEL - SUM column if date matches TODAY()

I've tried using SUMIF to obtain my results but it doesn't work properly.
I have a row of dates (XX/XX/XXXX format) and I would like to check this row for the current date.
If the row contains the current date, then I would like to sum the total of that column and row 5-20.
For example - today is 10/13/2016. I would like to search for TODAY() in a certain row (Row 1 for example), and if TODAY() is found, then total this column from row 1 down to row 3.
--A-- --B--
10/13/2016 10/14/16
1 50 10
2 10 4
3 5 6
The result should be 65 only IF the date matches TODAY().
I've also checked on giving the column letter based on the date but with no luck.
Any tips are appeciated! Thank you.
I think you can achieve this with a simple IF and a SUM
i.e. in your example above if you want the result to appear on the bottom row you can just use:
=if(B2=today(), sum(B3:B5), "")
This will display the sum at the bottom of the column for columns where the date = today and a blank in the other columns
You need to use the OFFSET function. You can find the documentation here: https://support.office.com/en-us/article/OFFSET-function-C8DE19AE-DD79-4B9B-A14E-B4D906D11B66
In your particular example the following formula will work:
=SUM(OFFSET(D2, 1, MATCH(B2, $D$2:$F$2, FALSE) - 1, 20))
You can see the formula working below. Assuming you know what the SUM formula is doing, I will explain what the OFFSET formula is doing:
First Parameter: Says start at cell D2
Second Parameter: This is how many row up/down do you want to do. In your case you need start at row below the date so '1' it is.
Third Parameter: This is how many columns to the right do you want to
go. Well the number of columns you want to go is based upon where
your date is. So this uses the match formula to figure out how far
to the right to go.
Fourth Parameter: This is how many row do you want to include. I just picked 20 to include the 20 rows below the selected cell.
You obviously need to modify the parameters a little bit to fit your exact data shape.
So I'll give it a shot:
{=SUM(HLOOKUP(TODAY(),Table_With_Dates_and_Three_Rows_Cell_Reference,{2,3,4}))}
NB: Don't type {} but put the formula inside it and then hit Ctrl+Shift+Enter to create what is called an array formula (it does array calculations element by element then submits the aggregating function value---in this case that is sum).

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