I am getting the value of a field as ["value"]
I want to print only the value removing the [ "from the result value.
That looks like a JSON array of Strings? No idea, as you don't provide any context, but you could do:
import groovy.json.JsonSlurper
def valueField = '["value"]'
def result = new JsonSlurper().parseText(valueField).head()
println result
Prints value
The following script should be what you need
def str = '["value"]'
println(str.replaceAll(/\[|\]/,''))
Related
How can I use jsonSlurper.parseText to parse "807-000" that has dash in it with groovy ?
You are generating the below string for parsing:
[807-000]
What I think you wanted is an json array containing a string:
["807-000"]
You could generate that json yourself:
def arr2 = "[" + arr.collect({ '"' + it + '"' }).join(",") + "]"
But why reinvent the wheel, when you can do it like this:
def arr2 = groovy.json.JsonOutput.toJson(arr)
It's not entirely clear what exactly do you want to do. parseText() is waiting for json to be input. I suggest several options for parsing.
def text = jsonSlurper.parseText("""{ "key": "807-000" } """)
Or did you mean that before the dash is the key, and after it is the value? If so then you can try this:
def map = "807-000".split("-").toSpreadMap()
map.each {row ->
def parsedText = jsonSlurper.parseText("""{ "${row.key}": "${row.value}" } """)
println(parsedText)
}
output is = [807:000]
How can I use jsonSlurper.parseText to parse "807-000" that has dash
in it with groovy ?
I am not sure what the challenge actually is. Something I can think of is possibly you are having trouble using Groovy property access to retrieve the value of a key when the key has a hyphen in it. You can do that by quoting the property name:
String jsonString = '''
{"807-000":"Eight O Seven"}
'''
def slurper = new JsonSlurper()
def json = slurper.parseText(jsonString)
// quote the property name which
// contains a hyphen...
String description = json.'807-000'
assert description == 'Eight O Seven'
I got a string from a server response:
responseString:"{"session":"vvSbMInXHRJuZQ==","age":7200,"prid":"901Vjmx9qenYKw","userid":"user_1"}"
then I do:
responseString[1..-2].tokenize(',')
got:
[""session":"vvSbMInXHRJuZQ=="", ""age":7200", ""prid":"901Vjmx9qenYKw"", ""userid":"user_1""]
get(3) got:
""userid":"user_1""
what I need is the user_1, is there anyway I can actually get it? I have been stuck here, other json methods get similar result, how to remove the outside ""?
Thanks.
If you pull out the proper JSON from responseStr, then you can use JsonSlurper, as shown below:
def s = 'responseString:"{"session":"vvSbMInXHRJuZQ==","age":7200,"prid":"901Vjmx9qenYKw","userid":"user_1"}"'
def matcher = (s =~ /responseString:"(.*)"/)
assert matcher.matches()
def responseStr = matcher[0][1]
import groovy.json.JsonSlurper
def jsonSlurper = new JsonSlurper()
def json = jsonSlurper.parseText(responseStr)
assert "user_1" == json.userid
This code can help you get you to the userid.
def str= 'responseString:"{:"session":"vvSbMInXHRJuZQ==","age":7200,"prid":"901Vjmx9qenYKw","userid":"user_1","hdkshfsd":"sdfsdfsdf"}'
def match = (str=~ /"userid":"(.*?)"/)
log.info match[0][1]
this pattern can help you getting any of the values you want from the string. Try replacing userid with age, you will get that
def match = (str=~ /"age":"(.*?)"/)
#Michael code is also correct. Its just that you have clarified that you want the user Name to be specific
Hello Groovy Experts,
I am using the below command to get all the ODI Dataservers.
def PSchema=DServer.getPhysicalSchemas();
When I print the PSchema variable I getting the following values.
[oracle.odi.domain.topology.OdiPhysicalSchema ABC.X1, oracle.odi.domain.topology.OdiPhysicalSchema ABC.X2]
What I am trying to achieve here I will be passing X1 or X2 during runtime...
And then I want to validate this value with the PSchema result and the print the following value:
oracle.odi.domain.topology.OdiPhysicalSchema ABC.X2
I tried using the following options:
def PSchema44 = PSchema11.findIndexValues { it =~ /(X1)/ }
def pl=PSchema11.collect{if(it.contains ('X1)){return it}}
I tried for loop to check whether values are getting printed properly ..result is fine:
for (item in PSchema11 )
{
println item
}
Assuming 'X1' and 'X2' are the names for the physical schemas, you should be able to do something like this:
def phys = "X1"
def pSchemas = dServer.getPhysicalSchemas()
def schema = pSchemas.find{it.schemaName == phys}
also I guess you are new to Groovy, I suggest you read up on syntax and naming conventions. For example, variable names should always start with a lower case letter
I currently have a fixed format for an asset management code, which uses the Groovy string format using the dollar sign:
def code = "ITN${departmentNumber}${randomString}"
Which will generate a code that looks like:
ITN120AHKXNMUHKL
However, I have a new requirement that the code format must be customizable. I'd like to expose this functionality by allowing the user to set a custom format string such as:
OCP${departmentNumber}XI${randomString}
PAN-${randomString}
Which will output:
OCP125XIBQHNKLAPICH
PAN-XJKLBPPJKLXHNJ
Which Groovy will then interpret and replace with the appropriate variable value. Is this possible, or do I have to manually parse the placeholders and manually do the string.replace?
I believe that GString lazy evaluation fits the bill:
deptNum = "C001"
randomStr = "wot"
def code = "ITN${deptNum}${->randomStr}"
assert code == "ITNC001wot"
randomStr = "qwop"
assert code == "ITNC001qwop"
I think the original poster wants to use a variable as the format string. The answer to this is that string interpolation only works if the format is a string literal. It seems it has to be translated to more low level String.format code at compile time. I ended up using sprintf
baseUrl is a String containing http://example.com/foo/%s/%s loaded from property file
def operation = "tickle"
def target = "dog"
def url = sprintf(baseUrl, operation, target)
url
===> http://example.com/foo/tickle/dog
I believe in this case you do not need to use lazy evaluation of GString, the normal String.format() of java would do the trick:
def format = 'ITN%sX%s'
def code = { def departmentNumber, def randomString -> String.format(format, departmentNumber, randomString) }
assert code('120AHK', 'NMUHKL') == 'ITN120AHKXNMUHKL'
format = 'OCP%sXI%s'
assert code('120AHK', 'NMUHKL') == 'OCP120AHKXINMUHKL'
Hope this helps.
for Triple double quoted string
def password = "30+"
def authRequestBody = """
<dto:authTokenRequestDto xmlns:dto="dto.client.auth.soft.com">
<login>support#soft.com</login>
<password>${password}</password>
</dto:authTokenRequestDto>
"""
This question already has answers here:
How to get Python to gracefully format None and non-existing fields [duplicate]
(3 answers)
Closed 8 years ago.
Is there a way to use python string.format such that no exception is thrown when an index is missing, instead an empty string is inserted.
result = "i am an {error} example string {error2}".format(hello=2,error2="success")
here,result should be :
"i am an example string success"
Right now, python throws a keyerror and stops formatting. Is it possible to change this behavior ?
Thanks
Edit:
There exists Template.safe_substitute (even that leaves the pattern intact instead of inserting an empty string) , but couldn't something similar for string.format
The desired behavior would be similar to string substitution in php.
class Formatter(string.Formatter):
def get_value(self,key,args,kwargs):
try:
if hasattr(key,"__mod__"):
return args[key]
else:
return kwargs[key]
except:
return ""
This seems to provide the desired behavior.
The official solution (Python 3 Docs) for strings in format mappings is to subclass the dict class and to define the magic-method __missing__(). This method is called whenever a key is missing, and what it returns is used for the string formatting instead:
class format_dict(dict):
def __missing__(self, key):
return "..."
d = format_dict({"foo": "name"})
print("My %(foo)s is %(bar)s" % d) # "My name is ..."
print("My {foo} is {bar}".format(**d)) # "My name is ..."
Edit: the second print() works in Python 3.5.3, but it does not in e.g. 3.7.2: KeyError: 'bar' is raised and I couldn't find a way to catch it.
After some experiments, I found a difference in Python's behavior. In v3.5.3, the calls are __getitem__(self, "foo") which succeeds and __getitem__(self, "bar") which can not find the key "bar", therefore it calls __missing__(self, "bar") to handle the missing key without throwing a KeyError. In v3.7.2, __getattribute__(self, "keys") is called internally. The built-in keys() method is used to return an iterator over the keys, which yields "foo", __getitem__("foo") succeeds, then the iterator is exhausted. For {bar} from the format string there is no key "bar". __getitem__() and hence __missing_() are not called to handle the situation. Instead, the KeyError is thrown. I don't know how one could catch it, if at all.
In Python 3.2+ you should use format_map() instead (also see Python Bug Tracker - Issue 6081):
from collections import defaultdict
d = defaultdict(lambda: "...")
d.update({"foo": "name"})
print("My {foo} is {bar}".format_map(d)) # "My name is ..."
If you want to keep the placeholders, you can do:
class Default(dict):
def __missing__(self, key):
return key.join("{}")
d = Default({"foo": "name"})
print("My {foo} is {bar}".format_map(d)) # "My name is {bar}"
As you can see, format_map() does call __missing__().
The following appears to be the most compatible solution as it also works in older Python versions including 2.x (I tested v2.7.15):
class Default(dict):
def __missing__(self, key):
return key.join("{}")
d = Default({"foo": "name"})
import string
print(string.Formatter().vformat("My {foo} is {bar}", (), d)) # "My name is {bar}"
To keep placeholders as-is including the format spec (e.g. {bar:<15}) the Formatter needs to be subclassed:
import string
class Unformatted:
def __init__(self, key):
self.key = key
def __format__(self, format_spec):
return "{{{}{}}}".format(self.key, ":" + format_spec if format_spec else "")
class Formatter(string.Formatter):
def get_value(self, key, args, kwargs):
if isinstance(key, int):
try:
return args[key]
except IndexError:
return Unformatted(key)
else:
try:
return kwargs[key]
except KeyError:
return Unformatted(key)
f = Formatter()
s1 = f.vformat("My {0} {1} {foo:<10} is {bar:<15}!", ["real"], {"foo": "name"})
s2 = f.vformat(s1, [None, "actual"], {"bar":"Geraldine"})
print(s1) # "My real {1} name is {bar:<15}!"
print(s2) # "My real actual name is Geraldine !"
Note that the placeholder indices are not changed ({1} remains in the string without a {0}), and in order to substitute {1} you need to pass an array with any odd first element and what you want to substitute the remaining placeholder with as second element (e.g. [None, "actual"]).
You can also call the format() method with positional and named arguments:
s1 = f.format("My {0} {1} {foo:<10} is {bar:<15}!", "real", foo="name")
s2 = f.format(s1, None, "actual", bar="Geraldine")
str.format() doesn't expect a mapping object. Try this:
from collections import defaultdict
d = defaultdict(str)
d['error2'] = "success"
s = "i am an {0[error]} example string {0[error2]}"
print s.format(d)
You make a defaultdict with a str() factory that returns "". Then you make one key for the defaultdict. In the format string, you access keys of the first object passed. This has the advantage of allowing you to pass other keys and values, as long as your defaultdict is the first argument to format().
Also, see http://bugs.python.org/issue6081
Unfortunately, no, there is no such way to do by default. However you can provide it defaultdict or object with overridden __getattr__, and use like this:
class SafeFormat(object):
def __init__(self, **kw):
self.__dict = kw
def __getattr__(self, name):
if not name.startswith('__'):
return self.__dict.get(name, '')
print "i am an {0.error} example string {0.error2}".format(SafeFormat(hello=2,error2="success"))
i am an example string success
I made a version that does work similarly to Daniel's method but without the {0.x} attribute access.
import string
class SafeFormat(object):
def __init__(self, **kw):
self.__dict = kw
def __getitem__(self, name):
return self.__dict.get(name, '{%s}' % name)
string.Formatter().vformat('{what} {man}', [], SafeFormat(man=2))
prints out
'{what} 2'