python - splitting string by first occurrence of Alpha character - python-3.x

Question

I have a list of string like follow (each line is a string variable)
6.40 D5
8.45 F5
9.00 E5
10.30 D5
12.30 E5
13.00HUm5 <-- outlier, without space
13.15 F5
15.05 F5
15.45 Fm5
I simply want to split the time (the front one) from the attribute (the back one).
This can be simply achieved by str.split().
However, the problem is that there may be a case about an outlier string like 13.00HUm5, where there are no white space between time and attribute.
It will fail if I use the code above.
I want it to be ['13.00', 'HUm5']
How can I tell the code to split the string when an Alpha characters appears after a Digit characters ?
Is it possible to achieve something like that ?

Answer 1

Using Regex.
Ex:
import re
s = """6.40 D5
8.45 F5
9.00 E5
10.30 D5
12.30 E5
13.00HUm5
13.15 F5
15.05 F5
15.45 Fm5"""
for line in s.splitlines():
m = re.match(r"(\d+\.\d+)\s*(.*)$", line)
if m:
print([m.group(1), m.group(2)])
Output:
['6.40', 'D5']
['8.45', 'F5']
['9.00', 'E5']
['10.30', 'D5']
['12.30', 'E5']
['13.00', 'HUm5']
['13.15', 'F5']
['15.05', 'F5']
['15.45', 'Fm5']