I am trying to filter specific chars out of a txt.file by copying the content selectively to a string and write this to a second file:
file = open(filepath, 'r')
file2 = open("C:/.../test2.txt", 'w')
newline = ""
for line in file:
for letter in line:
if letter == "#": continue
else: newline += letter
newline += "\n"
file2.write(newline)
I only manage to copy and mutate the content of file1 by using the newline character after reading each line, but with the effect of having undesired empty lines in my new txt2 file:
fewfewfw
fwefewf
How do I prevent having to remove these empty lines afterwards? Is there a better way to adjust a txt file anyway?
If you are trying to remove all the # symbols from the file, use:
with open(filepath, 'r') as f1, open("C:/.../test2.txt", 'w') f2:
content = f1.read()
f2.write(content.replace('#', ''))
Related
So I have a text file, and I need to define a function to open the file, read through it, and then return and print the number of characters within the file.
So far I've got:
def num_chars_in_file(file):
path = 'planets.txt'
file_handle = open(path)
for text in file_handle:
file = file_handle.readlines()
print(file)
print(f"\nProblem 1: {num_chars_in_file()}")
# I'm not sure where to go from where.
You could create a count variable to store the cumulative total of characters as you iterate over each line, something like this:
def num_chars_in_file():
path = 'planets.txt'
file_handle = open(path)
count = 0
for text in file_handle:
count += len(text.rstrip())
file_handle.close() # Make sure to close the file if you're not using with
return count
print(f"\nProblem 1: {num_chars_in_file()}")
with open('my_words.txt') as infile:
lines=0
words=0
characters=0
for line in infile:
wordslist=line.split()
lines=lines+1
words=words+len(wordslist)
characters += sum(len(word) for word in wordslist)
print(lines)
print(words)
print(characters)
Try this to print number of line, words and characters in the file.
Refer to this similar question more details.
Let's say I have a text file which contains both alphanumerical values and only numerical values of length 10 digits line by line, like the one shown below:
abcdefgh
0123456789
edf6543jewjew
9876543219
I want to delete all the lines which contains only those random 10 digit numbers, i.e. expected output for the above example is the following:
abcdefgh
edf6543jewjew
How can one do this in Python 3.x?
with open("yourTextFile.txt", "r") as f:
lines = f.readlines()
with open("yourTextFile.txt", "w") as f:
for line in lines:
if not line.strip('\n').isnumeric():
f.write(line)
elif len(line.strip('\n')) != 10:
f.write(line)
Open the input file, read all its lines, filter out the lines that contain only digits, then write the filtered lines back to a new file.
import re
with open(input_file_path) as file:
lines = file.readlines()
output_lines = [line for line in lines if not re.match(r'^[0-9]+$', line.strip('\n'))]
with open(output_file_path, 'w') as file:
file.write('\n'.join(output_lines))
import re
fh=open('Desktop\Python13.txt','r+')
content=fh.readlines()
fh.seek(0)
for line in content:
if re.match(r'[0-9]{10}',line):
content.remove(line)
fh.write(''.join(content))
fh.truncate()
fh.close()
I have a text file where I want to replace the character \ by ,. After reading the answer of #Jack Aidley in this SO post:
# Read in the file
with open('file.txt', 'r') as file :
filedata = file.read()
# Replace the target string
filedata = filedata.replace('n', '***IT WORKED!!!***')
# Write the file out again
with open('file.txt', 'w') as file:
file.write(filedata)
I could successfully change the content such as simple letter like n into ***IT WORKED!!!***. However, if I replace
filedata.replace('n', '***IT WORKED!!!***')
by
filedata.replace('\', '***IT WORKED!!!***')
I get the syntax error:
SyntaxError: EOL while scanning string literal
How can I replace all the \ by ,?
I have some files containing a lot of lines. At the start of each line there are some numbers which there is ";" between them. How can I delete these numbers and ";"? (I tested split to put numbers together so can I delete them but when I use split, the word next to the numbers is put with them and when I delete the numbers, they delete, too. but I don't want to delete words. Just the the numbers and ";"). Or is there a way in notepad++?
The sample file:
https://www.dropbox.com/s/yvgc659f9rrfhop/N.txt?dl=0
file = "c:/Python34/N.txt"
h = ["1","2","3","4","5","6","7","8","9","0", ";"]
with open (file) as f:
for line in f:
for i in h:
if i in line:
line.replace(i, "")
print (line)
with open ("new.txt", "w") as f2:
f2.write(line)
Regular expressions can deal with this:
import re
file = 'c:/Python34/N.txt'
with open(file) as f:
contents = re.sub(r'\d+;', '', f.read())
with open('new.txt', 'w') as f2:
f2.write(contents)
Ive a csv file that I would like to get all the rows in one column. Ive tried importing into MS Excel or Formatting it with Notedpad++ . However with each try it considers a piece of data as a new row.
How can I format file with pythons csv module so that it removes a string "BRAS" and corrects the format. Each row is found between a quote " and delimiter is a pipe |.
Update:
"aa|bb|cc|dd|
ee|ff"
"ba|bc|bd|be|
bf"
"ca|cb|cd|
ce|cf"
The above is supposed to be 3 rows, however my editors see them as 5 rows or 6 and so forth.
import csv
import fileinput
with open('ventoya.csv') as f, open('ventoya2.csv', 'w') as w:
for line in f:
if 'BRAS' not in line:
w.write(line)
N.B I get a unicode error when trying to use in python.
return codecs.charmap_decode(input,self.errors,decoding_table)[0]
UnicodeDecodeError: 'charmap' codec can't decode byte 0x8f in position 18: character maps to <undefined>
This is a quick hack for small input files (the content is read to memory).
#!python2
fnameIn = 'ventoya.csv'
fnameOut = 'ventoya2.csv'
with open(fnameIn) as fin, open(fnameOut, 'w') as fout:
data = fin.read() # content of the input file
data = data.replace('\n', '') # make it one line
data = data.replace('""', '|') # split char instead of doubled ""
data = data.replace('"', '') # remove the first and last "
print data
for x in data.split('|'): # split by bar
fout.write(x + '\n') # write to separate lines
Or if the goal is only to fix the extra (unwanted) newline to form a single-column CSV file, the file can be fixed first, and then read through the csv module:
#!python2
import csv
fnameIn = 'ventoya.csv'
fnameFixed = 'ventoyaFixed.csv'
fnameOut = 'ventoya2.csv'
# Fix the input file.
with open(fnameIn) as fin, open(fnameFixed, 'w') as fout:
data = fin.read() # content of the file
data = data.replace('\n', '') # remove the newlines
data = data.replace('""', '"\n"') # add the newlines back between the cells
fout.write(data)
# It is an overkill, but now the fixed file can be read using
# the csv module.
with open(fnameFixed, 'rb') as fin, open(fnameOut, 'wb') as fout:
reader = csv.reader(fin)
writer = csv.writer(fout)
for row in reader:
writer.writerow(row)
For solving this you need not to go to even code.
1: Just open file in Notepad++
2: In first line select from | symble till next line
3: go to replace and replace the selected format with |
Search mode can be normal or extended :)
Well, since the line breaks are consistent, you could go in and do find/replace as suggested, but you could also do a quick conversion with your python script:
import csv
import fileinput
linecount = 0
with open('ventoya.csv') as f, open('ventoya2.csv', 'w') as w:
for line in f:
line = line.rstrip()
# remove unwanted breaks by concatenating pairs of rows
if linecount%2 == 0:
line1 = line
else:
full_line = line1 + line
full_line = full_line.replace(' ','')
# remove spaces from front of 2nd half of line
# if you want comma delimiters, uncomment next line:
# full_line = full_line.replace('|',',')
if 'BRAS' not in full_line:
w.write(full_line + '\n')
linecount += 1
This works for me with the test data, and if you want to change the delimiters while writing to file, you can. The nice thing about doing with code is: 1. you can do it with code (always fun) and 2. you can remove the line breaks and filter content to the written file at the same time.