I am trying to count the distance between two cells using:
days = Range(price0.Rows(1), price.Rows(1)).Cells.count
where price0 and price are the initial price and range of prices of interest respectively.
I want to be able to count the distance between two prices so that I can run a function only when days > x (where x is an integer). Currently, using the above code, I am unable to count the distance between 2 cells when the value of price is 0.
How should I change my code so that I can count the days between two ranges? Thanks!
If you just want to get count of cells between those two prices, You Can use .Column to get the first column and last column number and then simply count the cells in between.
try like this
days = Abs(price0.Column - price.Column)
To count cells between two rows days = Abs(price0.Rows(1).row - price.Rows(1).row)
I think you might need Cells instead of Rows:
days = Range(price0.Cells(1), price.Cells(1)).Cells.Count
Related
I have 3 Columns of data. Column E = Duration. The user will enter a number of days (Duration) for 20 employees. Column F = Pay. List of wage for each employee. Column R = Pay Total. This is a calculated field based on the number of days (Duration) and the employees pay (Pay).
To keep my employees from finding out their coworkers pay I only want to see a sum for Column C if there are at least 3 records in Column A.
I found this Sum only if 3
From that answer I tried to use =IF(COUNTIF(E2:E15,">2"),SUM(R2:R15))
What this does is only returns records with a duration of greater than 2 days. I don't care about the number of days. I want the indicator to be that there are 3 cells populated in this column.
I think the only issue with the formula is the CountIF part. I need to know what I should use to count cells not days.
Screenshot of My Sheet
In the image above you can see that it's returning a sum bc both records are greater than 2. Like I said before I don't care what number is in the cell I just want to see the sum if there are more than 2 cells populated in that column.
Thanks for any help
As per my understanding of the question, I came up with this solution. Give it a try.
=IF(COUNT($E$2:$E$15)>2,SUM($R$2:$R$15), 0)
This formula would give what you want
=IF(COUNTA(E2:E15)>2,SUM(R2:R15),"")
This would show sum only if count of non empty cells is greater than 2 in Range "E2:E15" else it would show empty.
So i have a row of numbers which is consistently added to, which may be like 4,N/A,N/A,5,5,6,7,4,N/A,N/A,N/A,5,N/A and I need a formula which is able to calculate the average of the last 10 numbers in the row.
I have tried
=AVERAGE(OFFSET(C7,0,COUNT(C7:X7)-MIN(10,COUNT(C7:X7)),1,MIN(10,COUNT(C7:X7))))
Use:
=AVERAGE(INDEX(1:1,AGGREGATE(14,7,COLUMN(1:1)/(ISNUMBER(1:1)),MIN(10,COUNT(1:1)))):INDEX(1:1,AGGREGATE(14,7,COLUMN(1:1)/(ISNUMBER(1:1)),1)))
in excel, I have two columns. one containing months of the year (in numbers) each month number occurring in different number of rows, and in the second column I have a duration of time for each row (in hours and minutes).
now I want to do the following job with an excel function in just one cell (the same job could be done using a table with 12 cells, each for one month but I want to pack it all in one cell):
1- for each month number, sum all cells in the second column (time) which have that month number in the adjacent cell (this could be done with a sumif )
2- if that sum is more than 4 hours then return one for that month else return zero (this step could be done with a formula like this: IF(R10>(--"4:00");1;"") )
3. in the end the numbers assigned to each month summed together.
thanks to everyone who helps
the picture below, shows the steps:
enter image description here
Try,
=SUM(--(SUMIFS(Table1[time],Table1[month],{1,2,3,4,5,6,7,8,9,10,11,12})>TIME(4,0,0)))
I have a very simple sheet with dates in column A and product names in column B. I just need to know how many sales I make on average per day.
Sales:
01/01/2018 PRODUCT A
01/01/2018 PRODUCT A
01/02/2018 PRODUCT A
01/02/2018 PRODUCT B
Average sales per day: 2
So I don't care what product it is. Just how many sales per day on average.
You can use counta(a2:a5) to get the count of items in a range (adjust your range to suit of course).
You can use the array formula sum(1/countif(a2:a5,a2:a5)) to get the count of unique items in a range. The way to get an array formula is to enter it with CTRLSHIFTENTER rather than just ENTER (it will show up in the formula bar with {braces}).
It should then be a simple matter of dividing the former by the latter to get the average items per unique item (sales per day and, again, this should be an array formula):
=counta(a2:a5)/sum(1/countif(a2:a5,a2:a5))
The only tricky bit there is the countif formula. The expression countif(range,value) will give you a count of all items in the range that match the value.
By making the value the same as the range, it counts (for each item in the range) the number of times an item appears.
So, if your range contains a,a,a,a,b,b,c, you'll get the array (4,4,4,4,2,2,1). Doing the sum of the reciprocals of those values for each cell in the range gives:
(1/4 + 1/4 + 1/4 + 1/4) + (1/2 + 1/2) + (1/1)
which is basically a sneaky way of counting the unique items.
Assuming dates are entered as real Date (and not just text that only looks like dates), use this
=COUNT(A:A)/SUM(--(FREQUENCY(A:A,A:A)>0))
(Frequency formula sourced from here )
how can I merge two columns of data into one like the following:
Col1 Col2 Col3
========================
A 1 A
B 2 1
C 3 B
2
C
3
You can use the following formula in column D as per my example. Keep in mind to increase the $A$1:$B$6 range according to your data.
=INDEX($A$1:$B$6,INT((ROWS(D$2:D2)-1)/2)+1,MOD(ROWS(D$2:D2)-1,2)+1)
Result:
Thank you to #Koby Douek for the answer. Just an addition--if you are using Open Office Calc, you replace the commas with semi-colons.
=INDEX($A$1:$B$6;INT((ROWS(D$2:D2)-1)/2)+1;MOD(ROWS(D$2:D2)-1;2)+1)
Expanding #koby Douek's answer to more columns and explaining some of the terms
Original Code for 2 columns to 1 alternating
=INDEX($A$1:$B$6,INT((ROWS(D$2:D2)-1)/2)+1,MOD(ROWS(D$2:D2)-1,2)+1)
$A$1:$B$6 Defines the columns and rows to source the final set of data from, the $s are only present to keep the formula from changing the columns and rows selects if it is copied and pasted or dragged.
To extend to work on any values you dump into the columns instead of having to expand the range every time it should be amended to $A:$B or A:B so you can easily copy it to other sets of columns and create new merges, but it will also give the 1st value in every column as one of the alternating values so if you instead have headers you would be able to do this by instead using a large number so $A$1:$B$99999 or A$1:B$99999 if you want to past and move the columns ymmv which is better by situation.
lets assume you are fine including the values in the 1st row
This changes the formula to
=INDEX($A:$B,INT((ROWS(D$2:D2)-1)/2)+1,MOD(ROWS(D$2:D2)-1,2)+1)
Now on to D$2:D2
This is the row that is being used to calculate the difference between the current row the formula is in (D2) and the reference row (D$2) The important thing to make sure you do is to set the reference row number to the 1st row you will be putting values in, so if your 1st row is a header in the sort column you will use the 2nd row as the reference, if your values in the combined column D begin on the 3rd row then the reference row would be D$3
Since I like the more general form where the 1st row isn't a header row I'll use D$1:D1 but you could still mix source rows without headers into a combined row with a header of as many rows as you like just by incrementing that reference row number to be the 1st row where your values should begin.
This changes the formula to
=INDEX($A:$B,INT((ROWS(D$1:D1)-1)/2)+1,MOD(ROWS(D$1:D1)-1,2)+1)
Now INT((ROWS(D$1:D1)-1)/2)+1 and MOD(ROWS(D$1:D1)-1,2)+1
INT returns an integer value so any decimal places are dropped, it essentially functions like rounding down to the nearest whole number
MOD functions by returning the remainder of a division, it's result will be a whole number between 0 and n-1 where n is the number we are dividing by. (eg: 0/3=0; 1/3=1; 2/3=2; 3/3=0; 4/3=1 ... etc)
So -1)/2)+1 and -1,2)+1
the first value is again the difference between the current row and the reference row. but D$1:D1 is going to be the count of the rows, which is 1 so we have to correct for the rows count starting at 1 instead of 0 which would throw off our calculations, so both are using the -1 to reduce the count of the rows by 1
in the case of /2 and ,2 both are because we are dividing by 2 in the first statement it's a normal division by 2 /2 in the modulus statement it's an argument of the Mod function so ,2
finally we need to add 1 using +1 to correct for the index's need to have a value series which begins at 1.
INT((ROWS(D$2:D2)-1)/2)+1 is finding the row number to select the value from.
MOD(ROWS(D$1:D1)-1,2)+1 is finding the column number to select the value from
Thus we can change /2 and ,2 to /3 and ,3 to do this with 3 columns
This yields:
=INDEX($A:$B,INT((ROWS(D$1:D1)-1)/3)+1,MOD(ROWS(D$1:D1)-1,3)+1)
So maybe that's the confusing way to look at it but it's closer to how my mind works on it. Here is an alternative view:
=INDEX([RANGE],[ROW_#],[COLUMN_#]) returns the value from a range of rows and columns
Using the example:
=INDEX($A:$B,INT((ROWS(D$1:D1)-1)/3)+1,MOD(ROWS(D$1:D1)-1,3)+1)
[RANGE] = $A:$B this is the range of source columns.
[ROW_#] = INT((ROWS(D$1:D1)-1)/3)+1
INT([VALUE_A])+1 returns an integer value so any decimal places are dropped. Then adds one to it. we add one to the value because the result of the next steps will be 1 less than the value we need.
[Value_A] = (ROWS(D$1:D1)-1)/3
ROWS(D$1:D1) returns the number of rows in the Range to the current row in the results column, we use D$1 to designate the row number where the values in the results column begin. D1 is the current row in the results column giving us a range from the source row, allowing us to count the rows. we have to subtract 1 from this value using -1 to get the difference between the source and current. This is then divided by /3 because we have three columns we want to look through in this example so we only change rows when the result is divisible by 3. the INT drops any decimal places as mentioned so it only increments when cleanly divisible by 3.
[COLUMN_#] = MOD(ROWS(D$1:D1)-1,3)+1
MOD([VALUE],[Divisor])+1 returns the remainder of the value when divided by the divisor.
Using the example:
MOD(ROWS(D$1:D1)-1,3)+1
In this case we still divide by 3 but it's an argument to the MOD function, we still need to count the number of rows and subtract 1 before dividing it, this will return a 0, 1, or 2 for the column, but as above we are shifted backwards by 1 as the column numbers begin with the number 1, so as before we must add 1
And here we add column A and D
two different formulas depending on if you add the formula to an odd row or an even row.
https://1drv.ms/x/s!AncAhUkdErOkguUaToQkVkl5Qw-l_g?e=5d9gVM
Odd Start row
=INDEX($A$2:$D$9;ROUND(ROW(A1)/2;0);IF(MOD(ROW()-ROW($A$2);2)=1;4;1))
Even Start row
=INDEX($A$2:$D$9;ROUND(ROW(A1)/2;0);IF(MOD(ROW()-ROW($A$1);2)=1;4;1))
What is A1 in the picture is the cell directly above your first data cell.
If you want to place it on a different sheet you just add the sheet name:
=INDEX(MySheet!$A$2:$D$9;ROUND(ROW(MySheet!A1)/2;0);IF(MOD(ROW()-ROW(MySheet!$A$2);2)=1;4;1))
=INDEX(MySheet!$A$2:$D$9;ROUND(ROW(MySheet!A1)/2;0);IF(MOD(ROW()-ROW(MySheet!$A$1);2)=1;4;1))