Trying to load CSV file while doing simple linear regression . When I try to run , the error is coming as - "File name" is not exist as file/directory . Do I need to save the file in a particular folder or directory ?
try to use the full qualified path, or in the same directory of the main programm
Related
Might just be an edge case but I extracted a zip file to a directory using the zip file module. When extracting, zip file names the directory it extracts to.
If there is a way I get to specify the name of the folder Zip file creates to extract the files to? I am hitting an error because I am using the same folder zipped up to test zip file and it keeps using the old folder name which already exists so it throws an error. Here is my code:
orginalFolderName = jobFolder + name
with zipfile.ZipFile(directory,"r") as zip_ref:
zip_ref.extractall(jobFolder)
os.rename(orginalFolderName, newFoldername)
directory = newFoldername
with zipfile.ZipFile(filepath) as z:
z.extractall(dest_folder)
filepath - Complete path of zipfile
dest_folder - destination folder
I am getting an error writing a file, that is driving me crazy.
I have an C# netcore 5 application running on RH Linux.
I mounted an shared folder (windows) using: sudo mount -t cifs -o username=MyDomainUsername,password=MyDomainUsernamePassword,domain=MyDomain,dir_mode=0777,file_mode=0777 //ipv4_from_destination/Reports /fileshare/Reports
Then I run the app, using just ./WebApi --urls=http://+:8060
The read/write test executes the following steps:
Create a text file.
Write the text file.
Delete de text file.
Creates a directory
Creates a text file inside that directory
Writes the text file
Deletes the text file
Deletes the directory.
Now the problem:
The text file is created
The write operation fails.
Where goes part of the log:
Creating file: /fileshare/Reports/test.616db7d1-07fb-4599-a0cf-749e6a8b34ec.tmp...Ok
Writing file: /fileshare/Reports/test.616db7d1-07fb-4599-a0cf-749e6a8b34ec.tmp...[16:22:20 ERR] ID:87988856-a765-4474-9ed9-2f04aef35771 PATH:/api/about ERROR:System.UnauthorizedAccessException:Access to the path '/fileshare/Reports/test.616db7d1-07fb-4599-a0cf-749e6a8b34ec.tmp' is denied. TRACE: at System.IO.FileStream.WriteNative(ReadOnlySpan`1 source)
at System.IO.FileStream.FlushWriteBuffer()
at System.IO.FileStream.FlushInternalBuffer()
at System.IO.FileStream.Flush(Boolean flushToDisk)
at System.IO.FileStream.Flush()
at System.IO.StreamWriter.Flush(Boolean flushStream, Boolean flushEncoder)
at System.IO.StreamWriter.Flush()
at WebApi.Controllers.ApplicationController.TestFileSystem(String folder) in xxxxxxx\WebApi\Controllers\ApplicationController.cs:line 116
What I discovered so far:
I can create and delete the files and directories.
I cannot write to files.
Can someone give me an hint on this?
Solved using the cifs option nobrl
I want to get details about a selected harbour,by taking val s from a list extracted using readLines from a .txt file, where each harbour has a .txt file in the assets directory. I generate the file name but when the app is run in the emulator I get a file not found error.
In this case I am trying to get at a file called Brehatharm.txt
var portChosen = "Brehat"
//"tide2a/app/src/main/assets/"+//various paths to try
fileName = "assets/"+portChosen+"harm.txt"
val harmConsList:List<String> = File(fileName).readLines()
val portDisplayName = harmConsList[0]
val longTude = harmConsList[1]
val MTL =harmConsList[2]
etc,
The log cat reads :-
2021-01-10 15:40:34.044 7108-7108/com.example.tide2a E/AndroidRuntime: FATAL EXCEPTION: main
Process: com.example.tide2a, PID: 7108
java.lang.RuntimeException: Unable to start activity ComponentInfo{com.example.tide2a/com.example.tide2a.MainActivity}: java.io.FileNotFoundException: assets/Brehatharm.txt: open failed: ENOENT (No such file or directory)
The full windows path to the file is :-
C:\Users.......\OneDrive\Coding projects\tide2a\app\src\main\assets\Brehatharm.txt
I am sure the file is there, and spelled correctly, so I suspect I am specifying the path incorrectly. Please advise me.
Files in assets/ cannot be accessed using the File class. Use context.assets to get the AssetManager, and you can open InputStreams to the files.
I have variable address = /data/train/1.jpg, and I'm trying to read file by
im = Image.open(address)
FileNotFoundError: [Errno 2] No such file or directory: '/data/train/1.jpg'
By some reasons I can't use full name of file.
I started jupyter notebook from folder which actually contains file 1.jpg in /data/train/.
How can I fix it?
Relative addressing means from the perspective of the current working directory. So if you script is in the same directory that the data folder is in, your path to the file would be ./data/train/1.jpg. Note the ./, which means the current directory.
use relative path, this one is absolute
address = './data/train/1.jpg'
im = Image.open(address)
in this case . means current location while slash means the environments root (view and explanation) on this depends on your OS
I have a website script, it 212MB and it's in RAR format , I could not upload it via filezilla ftp , it gave me a timeout error after sometime, I could not upload it from the filemanager of cpanel as it also kept showing an error. Then I used a php script to upload it directly from the link but now I can not extract it as its RAR not ZIP. I converted the RAR into ZIP and have it on drop box and google drive but there is no direct link which I can use to upload via the php script, SO, Is there any way to extract the rar file from cpanel or using a php script or some other tweak. I have been working on it for 2 hours now and can not find a way around.
create a php file and extra the .rar with that php file. use the following code
$archive = RarArchive::open('archive.rar');
$entries = $archive->getEntries();
foreach ($entries as $entry) {
$entry->extract('/extract/to/this/path');
}
$archive->close();