division to zero handling excel - excel

So I have a table like this:
Element Rate
Apple 3
Apple 4
Banana 2
Banana 0
Ananas 0
Ananas 0
Kiwi (empty)
I want to find a average of the elements when it is above 0, when all 0 to get 0 and when cell is empty/blank to return n.a.
The core part of the formula I use is something like this :
AVERAGEIFS(Overview[Rate];Overview[Element]; D61;Overview[Rate]; ">0")
which gives me division to zero error, when all my values are 0 in the table such as if I want to find average for the Ananas, I thought this might work and the error I would get from in case of the empty cell I could just use IFERROR function to return "n.a.", but stucked, what is the reason for this and how can it be solved?

Well, as I said wrap your function in an iferror as shown:

Related

Find all values in Column A which are present in Column B

Consider the sheet below:
A
B
1
4
3
5
2
2
5
0
4
1
I want to find if there is a match for each row of column 1 with any row of column 2. So ideally this would give me:
A
B
C
1
4
Yes
3
5
No
2
2
Yes
5
0
Yes
4
1
Yes
As a first and simple step, I am using =MATCH(A2,B2:B6) to get the index of the match and then manually calling this across the rows to get something like this:
A
B
C
1
4
6
3
5
-
2
2
3
5
0
2
4
1
1
I am now having a problem:
I want to apply this for a row of 500 in A and 2000 in B. I was thinking of manually filling in the first few rows and then select and drag over the first 500 rows. This however does not work as for each subsequent cell, it just changes the formula to =MATCH(A(N +1),B2 + N:B6 + N) which gives me wrong values and at worst, just repeats the older pattern ahead.
Can anyone help me with how I can just use the MATCH function to find all the values in A that are present in B?
Let me continue where you arrived:
=MATCH(A2,B2:B6,0)
(You forgot the last zero)
This formula is correct, but it is also wrong.
???
Well, when you drag it down, you get:
=MATCH(A3,B3:B7,0)
This is not what you want: you want the search term (A2) to change into A3 but you want the search array (B2:B6) not to change. In order to get this done, you need to work with absolute references. This looks like this:
=MATCH(A2,B$2:B$6,0)
When you drag this down, this is what you get:
=MATCH(A3,B$2:B$6,0)
=> ok so far.
Problem now: you need to translate your current results (a number or #N/A) into "yes" or "no". This can be done in numerous ways, let me give you an example:
=IF(ISERROR(MATCH(A2,B$2:B$6,0)),"No","Yes")
One remark: there exists an IFERROR() function in Excel, but this does not have an "else"-clause, hence the choice for the IF(ISERROR( combination.
Within Sheets you may try this out:
=index(if(len(A2:A),if(ifna(xmatch(A2:A,B2:B)),"Yes","No"),))
If you want to separate those matching values then could use FILTER() function.
=FILTER(A1:A5,COUNTIFS(B1:B9,A1:A5))
And for YES, NO dynamically, try MAP() function.
=MAP(A1:A5,LAMBDA(x,ISNUMBER(XMATCH(x,B:B))))

Count of consecutive repeated value only when repeated 3+ times

My goal is to count and potentially conditionally format the occurrences when a certain number of days pass with 0 sales.
I am trying to return the number of times 0 is repeated consecutively 3 or more times. So for this example I would like to see the return value of 3. So far I can't wrap my brain around how to do this, any ideas?
1
5
0
0
0
0
0
2
0
0
1
0
2
0
0
0
5
0
0
0
0
Thanks!
So #Barry Houdini's method applied to this problem would give
=SUM(--(FREQUENCY(IF(A1:A21=0,ROW(A1:1A21)),IF(A1:A21>0,ROW(A1:A21)))>=3))
entered as an array formula using CtrlShiftEnter
If you wanted to make it more dynamic and exclude blanks you could use
=SUM(--(FREQUENCY(IF(A1:A100<>"",IF(A1:A100=0,ROW(A1:A100))),IF(A1:A100>0,ROW(A1:A100)))>=3))
How about you make a help column with a simple sum formula with a "window" of three rows (or whatever you need). Then you conditionally format all values which are 0 in that column. That should provide you with the information you are looking for.

Counting digit in column based on subject

I am just using formulas in excel and was wondering how you could count all the 0s until a 1 is reached, and then start the process over again, based on subject number. If this is not possible simply with formulas, how could I write a VBA code for this?
Right now I am trying to use,
=IF(OR(F4=0,F3=1),"",COUNTIFS($A$2:A2, $A$2,$F$2:F2,0)-SUM($I$2:I2))
which I input in I3 and I change the COUNTIFS($A$#:A#, $A$#...) part for each subject number.
This seems to work with the exception of the last grouping, as it won't output a number before the next subject.
Example Data:
subid yes number_yes(output)
1 0
1 0
1 0 3
1 1
1 0 1
1 1
1 0
2 0
2 0 2
2 1
2 0
2 0
3
etc.
A blank cell is numerically zero and that is one of your accepted conditions. Differentiate between blanks and zero values.
=IF(and(f4<>"", OR(F4=0,F3=1)),"",COUNTIFS($A$2:A2, $A$2,$F$2:F2,0)-SUM($I$2:I2))
Based on #Jeeped answer. If you use -SUMIF($A$2:A2,A3,$I$2:I2) instead of -SUM($I$2:I2) you don't need to adjust this part for each subject number. Just use the following formula in I3 and copy it down.
=IF(AND(F4<>"",OR(F4=0,F3=1)),"",COUNTIFS($A$2:A3,A3,$F$2:F3,0)-SUMIF($A$2:A2,A3,$I$2:I2))
Note that I also changed the second parameter in the COUNTIFS to A3.

Average ifs with or in excel

So, I have this problem, I would like to find the average of a column by using the OR function to check criteria from adjusted columns, I tried putting OR into AverageIf function, fail, also tried the "Average(IF(OR(" again not the correct return. Thought it is a simple thing could be done easily but don't know why it doesn't work. So my table is something like this:
ID: Rate Check 1 Check 2 Check 3
1 5 1 1 1
2 3 1 1
3 2 1
4 4
5 5 1 1
6 3
7 4 1
I would like to find the average of the rate column by checking if there are any value in either Check 1; Check 2 or Check 3 columns, so in the above case i will get the average of all but row with the id 4 and 6. Is this possible without using a helper column?
You can use SUMPRODUCT()
=SUMPRODUCT(((C2:C8<>"")+(D2:D8<>"")+(E2:E8<>"")>0)*(B2:B8<>"")*B2:B8)/SUMPRODUCT(--((C2:C8<>"")+(D2:D8<>"")+(E2:E8<>"")>0)*(B2:B8<>""))
If your first ID starts in A2, use this formula (edited to handle empty values in the "Rate" column):
=AVERAGE(IF(MMULT(LEN(C2:E8)*LEN(B2:B8),ROW(INDIRECT("1:"&COLUMNS($C$1:$E$1)))),B2:B8))

Optimal to lookup and display column/row names from a table of binary data

Job Coach ConsumerName Monthly General Goals
Anna Joe 0 0 0
Sam John 0 0 0
Veron Jane 0 0 0
Bill Jack 1 1 1
Anna Jill 1 1 1
Jim 0 0 0
Bill Jiang 1 1 1
Jolly 0 1 1
Sam Jiant 0 0 0
Jap 0 1 1
Joule 1 1 1
Aardvark 0 1 0
Drake Darding 0 0 0
Hello, as you can see above I have two columns of strings; one column is "job coach" the other is "consumer name". There are three columns of 1's and 0's; monthly, general, and goals.
I'm trying to find the specific pattern of 1's and 0's in each of the rows, and to report it. For instance, the data says:
Consumer Jolly still has a a monthly which needs to be completed;
Consumer Aardvark still has a monthly which needs to be completed;
Consumer Aardvark still has a monthly and a goals which needs to be completed.
Lookup doesn't really work, because it only will return the first instance of the corresponding variable and not additionally instances.
I've tried a index function like this:
{=INDEX($C$2:$E$14,SMALL(IF($C$2:$C$14=0,ROW($C$2:$C$14)),ROW(1:1)),3)}
But that only would look up for a single column at a time, which makes the report rather cumbersome. I'm open to doing a loop in excel without formulas, however its not a simple looping formula, because I'm trying to look at each cell and to output the specific column name.
Any thoughts on how to best do it?
It's not exactly clear what the condition you want to check is, but if you want to check for a specific given pattern and return the customer name you can use this adjusted formula:
=INDEX($B$2:$B$14,SMALL(IF($C$2:$C$14&$D$2:$D$14&$E$2:$E$14="010",ROW($C$2:$C$14)-1),ROW(1:1)),1)
In your formula you checked only the first binary column and returned the last. You also had a mistake of returning the row number and not the index in the list which is row-1 in your case.
So notice:
The INDEX returns values from column B.
The IF checks a pattern of C&D&E equals a pattern like 010 which can be changed or set to a reference.
Then return the ROW()-1 in case your list starts at row 2, to return the index in the data and not the actual row.

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