I would like to check if anyone can help with the below.
I would like to have a validation formula for email addresses. After combing through the internet and other threads, I found something that works.
However, I'd like the data validation to check for comma and flag that as error too. The current formula only flag spaces.
Any advice/suggestion to tweak this formula?
=AND(FIND(“#”,A2),FIND(“.”,A2),ISERROR(FIND(” “,A2)))
To "tweak" your formula to also check for a comma, you can use an array constant:
EDIT: to correct formula to allow for its use in Data Validation (remove array constant)
=AND(ISNUMBER(FIND("#",A2)),ISNUMBER(FIND(".",A2)),ISERROR(OR(FIND(" ",A2),FIND(",",A2))))
I provide this only as a method of showing one way of testing to exclude multiple characters from a string. This is NOT, in my opinion, a good way to validate an email address.
Note that your formula, if it does NOT find an "#" or a ".", will return a #VALUE! error. If you would rather it return FALSE, suggest you wrap those FIND's in an ISNUMBER function.
However, and this is my opinion only, I think the best way to ensure that an email address is both valid and correct is to use a system which includes an activation email. That can avoid both typos and malformed data.
Of course, your formula will allow certain types of invalid emails. For example, it does not test that the # is in the middle of the string, nor the dot. Nor that the dot precedes the #. etc, etc, etc
Related
I am in charge of adding new employees to our speech recognition and gamification systems.
When I get a batch of tickets, I compile a bunch of data into a spreadsheet that I then reference when adding those users to the systems (Which unfortunately do not have a JSON/CSV upload option or anything similar)
To save some time with compiling, I've started exporting a bunch of data from our database and our HR management system into that sheet, and then using the new employee's email to XLOOKUP all the other data fields.
For one of our systems, it has a strict character limit, and the format for the username is "cde\firstname.lastname". This is no problem to CONCATENATE normally, but it has a strict character limit, so if the user has a hyphenated last name, I will basically dump everything after the hyphen.
At first I tried a simple formula using a combination of LEFT and FIND -1 to find the hyphen, and then take everything to the left of it. This obviously doesn't end up working because I get a #VALUE! for anyone without a hyphen in their last name.
I tried using IFERROR to say "OK try to return the last name without a hyphen, otherwise just return the last name", but for some reason when I put the reference in the Return_If_Error portion, it doesn't recognize it as a reference.
So I am looking for a formula that will work with a LOOKUP'd value and only give me what's before a hyphen, but otherwise will still just give me the last name.
The baseline formula I have, that just looks up and concatenates the first and last into the "cde\firstname.lastname" is:
=CONCATENATE("cde\",LOWER(XLOOKUP(G578,Sheet4!M:M,Sheet4!B:B)),".",LOWER(XLOOKUP(G578,Sheet4!M:M,Sheet4!C:C)))
To expand on the comments, you've got the right idea, just use an IF statement for testing if the string contains "-", then use the normal string functions like FIND, LEFT, etc. to pick out the things you want.
For example:
="cde/"&
LEFT(H1,FIND(".",H1)-1)&
IF(ISNUMBER(FIND("-",H1)),MID(H1,FIND(".",H1),FIND("-",H1)-FIND(".",H1)),
MID(H1,FIND(".",H1),FIND("#",H1)-FIND(".",H1)))
I have a field in my excel spreadsheet that depends on several different fields to determine the calculation that should be made. I think I have my formula correct but I am not getting the appropriate responses so I know there must be something I am missing. Let me start by summarizing what I am attempting to do.
If D5=2, then I need to verify if $AI$12-AB14>(3/24) and return a T if it is or leave the field blank if not. Alternatively, if D5=1, then I have to also verify that Y14=Y and Z14=Y, and finally $AC$12-AA14>(3/24) and return a T if so, or leave the field blank if not.
(The reference to 3/24 is required as I am performing time calculations from data entry fields pulling from a userform)
What I am receiving for a response is 'True'. That is not an option so I suspect it is returning the result of a specific logical statement? Below is my formula:
=IF(AND(D5="2",$AI$12-AB14>(3/24),),"T","")
=IF(AND(D5="1",Y14="Y",Z14="Y",$AC$12-AA14>(3/24),),"T","")
I can't insert an image in comments, so I'll reply. This simplified example shows how it works:
And pay attention to D5 - are there really values 1 and 2 as text. If not, the quotation marks must be removed from the formula
I have a dictionary containing lots of words - I want the user to be able to input a list of substrings, and then a filtered list will be updated, containing only words that contain those substrings and nothing else. Any words that contain extra characters the user didn't specify, should not appear. Cell F3 will use a FILTER function to create the list. As in the mock-up below:
What I need is a formula that would generate the TRUE or FALSE flags from the yellow section (B3:B9), but I'm not sure how to go about this.
I'm sure this could be solved by VBA or Regex using Google Sheets, but I want to know if there's a way to do this by formula, as I don't want this to require a button press or script execution, and my spreadsheet can't be hosted on Google sheets due to its size. Any ideas?
You can also use a combination of ISNUMBER and SUMPRODUCT:
=ISNUMBER(SUMPRODUCT(MATCH(MID(A3,ROW(INDEX(A:A,1,1):INDEX(A:A,LEN(A3),1)),1),$D$3:$D$5,0)))
Adjusted formula:
=ISNUMBER(SUMPRODUCT(MATCH(MID(A3,ROW(A$1:INDEX(A:A,LEN(A3))),1),$D$3:$D$5,0)))
The result:
The test being ran below is subtracting each instance of your dictionary from the length of original string. If the result is 0, this returns TRUE. If not, this returns FALSE. This is not case sensitive - a & A will be treated equally here.
=NOT(LEN(A1)-(LEN(A1)-LEN(SUBSTITUTE(UPPER(A1),D1,"")))-(LEN(A1)-LEN(SUBSTITUTE(UPPER(A1),D2,"")))-(LEN(A1)-LEN(SUBSTITUTE(UPPER(A1),D3,""))))
The equation works fine although I don't know if it is an optimal solution for you, but posting as answer in case it is for somebody else. The issue with this approach is the equation gets longer and longer for each character you add to your dictionary. Depending on the size of dictionary and strings to test against, this can get sloppy and calc heavy really quick.
Have you considered a UDF in VBA?
I'm trying to bring back one of two possible words (Local or National) from a text string, and if neither of these words are in the text string, then bring back the string in the whole cell
The issue I have is that I can bring back either word when they appear, but I get an error when they do not
I'm currently using
=IFERROR(IF(SEARCH("*local*",B2,1),"Local"),IF(SEARCH("*national*",B2,1),"National"))
However this obviously this doesn't bring back if the words not exist
I'm sure it's easy and I'm missing something, but I just cannot figure it out. any help would be great
Cheers all
You can use:
Formula in B1:
=IF(ISNUMBER(SEARCH("*local*",A1)),"Local",IF(ISNUMBER(SEARCH("*national*",A1)),"national",A1))
Drag down
Note:
Notice that your wildcards make it that even a string with 'international' in it will return 'national'. If this is not what you want, you should remove the wildcards.
You can also use INDEX/AGGREGATE:
=IFERROR(INDEX({"local","national"},AGGREGATE(15,7,ROW($1:$2)/(ISNUMBER(SEARCH({"local";"national"},A1))),1)),A1)
This will allow one to replace the both hard coded arrays with a range of cells that contain the outputs. If Local and National were in D1:D2 then you can use:
=IFERROR(INDEX($D:$D,AGGREGATE(15,7,ROW($D$1:$D$2)/(ISNUMBER(SEARCH($D$1:$D$2,A1))),1)),A1)
That way if the list gets bigger the formula does not.
I'd suggest regular expressions.
=IF(REGEXMATCH(A2,"(Local|National)"),REGEXEXTRACT(A2,"(Local|National)"),A2)
Seems like it would be a simple thing really (and it may be), but I'm trying to take the string data of a column and then through a calculated column, replace all the spaces with %20's so that the HTML link in the workflow produced email will actually not break off at the first space.
For example, we have this in our source column:
file:///Z:/data/This is our report.rpt
And would like to end up with this in the calculated column:
file:///Z:/data/This%20is%20our%20report.rpt
Already used the REPLACE, and made up a ghastly super nested REPLACE/SEARCH version, but the problem there is that you have to nest for EACH potential space, and if you don't know how many up front, it doesn't work, or will miss some.
Have any of you come across this scenario and how did you handle it?
Thanks in advance!
As far as I know there is no generic solution using the calculated-column syntax. The standard solution for this situation is using an ItemAdded (/ItemUpdated) event and initializing the field value from code.
I was able to solve this issue for my circumstances by using a series of calculated columns.
In the first calculated column (C1) I entered a formula to remove the first space, something like this:
=IF(ISNUMBER(FIND(" ",[Title])),REPLACE([Title],FIND(" ",[Title]),1,"%20"),[Title])
In the second Calculated column (C2) I used:
=IF(ISNUMBER(FIND(" ",[C1])),REPLACE([C1],FIND(" ",[C1]),1,"%20"),[C1]).
In my case, I wanted to encode upto four spaces, so I used 3 calculated columns (C1, C2, C3) in the same fashion and got the desired result.
This is not as efficient as using a single calculated column, but if SUBSTITUTE will not work in your SharePoint environment, and you cannot use an event handler or workflow, it may offer a workable alternative.
I actually used a slightly different formula, but it was on a work machine to which I don't have access at the moment, so I just grabbed this formula from a similar S.O. question. Any formula that will replace the first occurrence of a space with "%20" will work, the trick is to a) make sure the formula returns the original string unchanged if it does not have more spaces in it, and b) test, test, test. Create a view of your list that has the field you are trying to encode, plus the calculated fields, and see if you are getting the results you want.
so that the HTML link in the workflow produced email will actually not break off at the first space.
The browser only does this if you have not enclosed your link in quotes
If you wrap the link in quotes, it does not cut off at the first space
In a SharePoint Formula it would be:
="""file:///Z:/data/This is our report.rpt"""
becuase two quotes are the SP escape notation to output a quote
You can use this formula (Start trim for 1, in my case was 4):
=IF(ISBLANK([EUR Amount]),"",(TRIM(MID([EUR Amount],4,2))&TRIM(MID([EUR Amount],6,2))&TRIM(MID([EUR Amount],8,2))&TRIM(MID([EUR Amount],10,2))&TRIM(MID([EUR Amount],12,2))&TRIM(MID([EUR Amount],14,2)))*1)