Can someone tell me how to get the zeroes to show in a regular Expression containing zeroes for decimals.
For Example 1,320.00 When I turn it to a Regular Expression the .00 disappears. I need them to show. Here is the formula I was working with.
(^\d*\.?\d*[0-9]+\d*$)|(^[0-9]+\d*\.\d*$)
Any help would be appreciated.
thanks,
Here's a pattern which will capture the full number, including commas and decimals:
^(\d{1,3},)*\d{1,3}\.\d\d$
The first group, (\d{1,3),), will match groups of one to three digits followed by a comma. It is followed by a *, so the pattern will match 0 or more of these groups (i.e. it will still match 320.00 and 12,312,122.00).
The second part, \d{1,3}\., will match the 1-3 digits preceding the decimal point.
Finally, \d\d$ match the two decimal points. It looked like you're trying to match US currency, so I hard-coded in 2 digits for readability, but if you need to match, say, one or more decimal points, try this:
^(\d{1,3},)*\d{1,3}\.\d+$
Here's a demo.
Related
I'm using the FIND function in Excel to check whether certain characters appear in a string of characters in a cell.
However, this function doesn't work cleanly for certain special characters. Specifically F̌,B̌, and some others. When F̌ appears in the string, FIND recognizes it as both F and F̌.
Notable that this is not the case for characters such as Ď and Č. FIND works nicely for these.
How can I get the formula to always differentiate between characters with and without the hat? Is there a way to work in EXACT?
Thank you!
It is because F̌ is actually two characters.
=LEN("F̌") returns 2 not 1. The second character is the hat.
If you do:
=UNICHAR(70)&UNICHAR(780)
It will return the F̌
And as such =FIND("F","F̌") will return 1 as it is the first letter of a two character string.
To find "F" in A,B,F̌,F use:
=AGGREGATE(15,7,ROW($ZZ1:INDEX($ZZ:$ZZ,LEN(A1)))/((MID(A1,ROW($ZZ1:INDEX($ZZ:$ZZ,LEN(A1))),1)="F")*(MID(A1,ROW($ZZ2:INDEX($ZZ:$ZZ,LEN(A1)+1)),1)<>UNICHAR(780))),1)
To find either then we need to use IF:
=IF(LEN(A2)=2,FIND(A2,A1),AGGREGATE(15,7,ROW($ZZ$1:INDEX($ZZ:$ZZ,LEN(A1)))/((MID(A1,ROW($ZZ$1:INDEX($ZZ:$ZZ,LEN(A1))),1)=A2)*(MID(A1,ROW($ZZ$2:INDEX($ZZ:$ZZ,LEN(A1)+1)),1)<>UNICHAR(780))),1))
Given that your substrings are comma-separated, look for the character followed by a comma (and add a comma to the end of the string to find the last character).
This allows you to separate multicharacter substrings from uni-character substrings where the latter is contained in the former.
You could use something like:
=FIND("F,",A5&",")
That will find an F in A5, but will not find an F if only F̌ is present
I need to display with no decimal, but retaining the numbers that
appear after the last decimal. For example, given `03.1037.190
I tried roundup and trunct but not sure how it works.
Try this on a string where . could be on a dynamic spot
=SUBSTITUTE(A1,".","",LEN(A1)-LEN(SUBSTITUTE(A1,".","")))
Or when your string always follows the same pattern ##.####.####.## you could try:
=REPLACE(A1,13,1,"")
The question is quite unclear as you have a value with the same thousand and decimal delimiter and also 4 numbers between the delimiters. It would help a lot if you specified the actual number without thousand delimiters.
Assuming there are no decimals (31.037.190.301): remove "." using:
=SUBSTITUTE(A1,".","")
and Excel will recognize it as a number
I have a column in excel which is formatted a general and it contains numbers, some of which are prefixed with a ~. I know that this character is representing leading zeroes, but in some cases it is one, or it can be two, three or more leading zeroes.
Is there a way to convert this to a number and preserve the correct number of leading zeroes? I need this to lookup on another list and match them, and the format must be identical.
There needs to be a way to determine how many leading zeros are required. If you want to replace the tilda with a single leading 0, then use the Replace Dialog to replace two tildas with single-quote 0:
(use as many zeros as are required.)
I have a very large number (a couple hundred digits long), and I'd like to use vim to add commas to the number in the appropriate manner, i.e. after each group of three digits, moving from right to left. How can I do this efficiently?
Taken from here
Substitue command that adds commas in the right spot.
:%s/\(\d\)\(\(\d\d\d\)\+\d\#!\)\#=/\1,/g
This uses a zero width lookahead to match any number that isn't followed by groups of three numbers followed by one number. (or 3n+1 numbers)
So the numbers that match in are marked with ^. These are then replaced with a comma after it the match.
31415926
^ ^
Which replaces to
31,415,926
A friend of mine suggests using the printf program: ciw<C-r>=system("printf \"%'d\" ".shellescape(#"))<CR>.
This is one way of doing it:
s/\d\{-1,}\ze\(\d\{3}\)\+\s/&,/g
Notes:
\{-1,} is saying match at least 1 but in a non-greedy way (Vim doesn't seem to support the usual \+\? syntax; also, for quantifiers, you just need to escape the opening curly brace)
\ze is saying match the pattern behind this but don't store the match in & (equivalent to positive look-ahead)
\(\d\{3}\)\+\> matches groups of 3 digits that ends with word-nonword boundary (word in this sense means alphanumerical + underscore).
Alternatively, you can use \s for space/tab, or \D for non-digit instead of \>, whichever fits your needs better
The way that I used is to create a macro that adds one single comma, and then invoke the macro a whole bunch of times, like qahhi,<ESC>hq#a#a#a#a…
I want to give a pattern in cognos. like this
my number : 12.20
my wanted number : 12.2 i want to delet 0 how I give pattern.
If no data format is mentioned, then the default format will take care of trailing zeros.
But if you are using some data format (number, currency) then the trailing zeros will be added till the mentioned decimal places in your format.
To suppress a digit if the value is zero, you can use pattern attribute in the Data Format property.
In your example, to suppress 2nd decimal place zero, you can mention the pattern as
.0#
With this pattern, first decimal place digit will be shown even if the value is zero. Whereas, second decimal place digit will not be shown even if the value is zero.
Please refer to IBM Cognos inforcenter for Decimal Format Symbols for the Pattern. http://publib.boulder.ibm.com/infocenter/c8bi/v8r4m0/index.jsp