There is an external table in hive pointing to s3 location that is not partitioned. The table points to a folder in s3 but the data is in multiple subfolders inside that folder.
This table can be queried even though the table is not partitioned by setting few properties in hive like below,
set hive.input.dir.recursive=true;
set hive.mapred.supports.subdirectories=true;
set hive.supports.subdirectories=true;
set mapred.input.dir.recursive=true;
However, when the same table is used in spark to load the data into a dataframe using a sql statement like df = sqlContext.sql("select * from table_name"), the action fails saying 'The subfolders in the external s3 location is not a file'.
I tried setting above hive properties in spark using sc.hadoopConfiguration.set("mapred.input.dir.recursive","true") method, but it did not help. Looks like this would help only for sc.textFile kind of loading.
This can be achieved by setting the following property in spark,
sqlContext.setConf("mapreduce.input.fileinputformat.input.dir.recursive","true")
Note here that the property is set usign sqlContext instead of sparkContext.
And I tested this in spark 1.6.2
Related
Env : linux (spark-submit xxx.py)
Target database : Hive
We used to use beeline to execute hql, but now we try to run the hql through pyspark and faced some issue when tried to set table properties while creating the table.
SQL
CREATE EXTERNAL TABLE example.a(
column_a string)
TBLPROPERTIES (
'discover.partitions'='true',
'spark.sql.sources.schema.numPartCols'='1',
'spark.sql.sources.schema.numParts'='1',
'spark.sql.sources.schema.part.0'='{"type":"struct","fields":[{"name":"column_a","type":"string","nullable":true,"metadata":{}}]}',
'spark.sql.sources.schema.partCol.0'='received_utc_date_partition');
Error message
Hive - ERROR - Cannot persist
example.a into Hive metastore as table property
keys may not start with 'spark.sql.': [spark.sql.sources.schema.partCol.0, spark.sql.sources.schema.numParts,
spark.sql.sources.schema.numPartCols, spark.sql.sources.schema.part.0];
In line 130-147 in spark source code it seems that it prevent all table properties that start with "spark.sql"
Not sure if I did it wrong or there's another way to set up the table properties for hive table.
Any kinds of suggestion is appreciated.
I am trying to create an external hive table using spark. But facing below error:
using Create but with is expecting
Use of location implies that a created table via Spark it will be treated as an external table.
From the manual: https://docs.databricks.com/spark/latest/spark-sql/language-manual/create-table.html. You can also reference this: https://spark.apache.org/docs/latest/sql-data-sources-hive-tables.html
LOCATION
The created table uses the specified directory to store its data. This
clause automatically implies EXTERNAL.
More explicitly:
// Prepare a Parquet data directory
val dataDir = "/tmp/parquet_data"
spark.range(10).write.parquet(dataDir)
// Create a Hive external Parquet table
sql(s"CREATE EXTERNAL TABLE hive_bigints(id bigint) STORED AS PARQUET LOCATION '$dataDir'")
// The Hive external table should already have data
sql("SELECT * FROM hive_bigints").show()
Also, has nothing to do with pyspark.
If using spark dataframe writer, then the option "path" used below means unmanaged and thus external as well.
df.write.mode("OVERWRITE").option("path", unmanagedPath).saveAsTable("myTableUnmanaged")
I am trying to insert data into a Hive External table from Spark Sql.
I am created the hive external table through the following command
CREATE EXTERNAL TABLE tab1 ( col1 type,col2 type ,col3 type) CLUSTERED BY (col1,col2) SORTED BY (col1) INTO 8 BUCKETS STORED AS PARQUET
In my spark job , I have written the following code
Dataset df = session.read().option("header","true").csv(csvInput);
df.repartition(numBuckets, somecol)
.write()
.format("parquet")
.bucketBy(numBuckets,col1,col2)
.sortBy(col1)
.saveAsTable(hiveTableName);
Each time I am running this code I am getting the following exception
org.apache.spark.sql.AnalysisException: Table `tab1` already exists.;
at org.apache.spark.sql.DataFrameWriter.saveAsTable(DataFrameWriter.scala:408)
at org.apache.spark.sql.DataFrameWriter.saveAsTable(DataFrameWriter.scala:393)
at somepackage.Parquet_Read_WriteNew.writeToParquetHiveMetastore(Parquet_Read_WriteNew.java:100)
You should be specifying a save mode while saving the data in hive.
df.write.mode(SaveMode.Append)
.format("parquet")
.bucketBy(numBuckets,col1,col2)
.sortBy(col1)
.insertInto(hiveTableName);
Spark provides the following save modes:
Save Mode
ErrorIfExists: Throws an exception if the target already exists. If target doesn’t exist write the data out.
Append: If target already exists, append the data to it. If the data doesn’t exist write the data out.
Overwrite: If the target already exists, delete the target. Write the data out.
Ignore: If the target already exists, silently skip writing out. Otherwise write out the data.
You are using the saveAsTable API, which create the table into Hive. Since you have already created the hive table through command, the table tab1 already exists. so when Spark API trying to create it, it throws error saying table already exists, org.apache.spark.sql.AnalysisException: Tabletab1already exists.
Either drop the table and let spark API saveAsTable create the table itself.
Or use the API insertInto to insert into an existing hive table.
df.repartition(numBuckets, somecol)
.write()
.format("parquet")
.bucketBy(numBuckets,col1,col2)
.sortBy(col1)
.insertInto(hiveTableName);
I have loaded a parquet table from HDFS into a DataFrame:
val df = spark.read.parquet("hdfs://user/zeppelin/my_table")
I now want to expose this table to Spark SQL but this must be a persitent table because I want to access it from a JDBC connection or other Spark Sessions.
Quick way could be to call df.write.saveAsTable method, but in this case it will materialize the contents of the DataFrame and create a pointer to the data in the Hive metastore, creating another copy of the data in HDFS.
I don't want to have two copies of the same data, so I would want create like an external table to point to existing data.
To create a Spark External table you must specify the "path" option of the DataFrameWriter. Something like this:
df.write.
option("path","hdfs://user/zeppelin/my_mytable").
saveAsTable("my_table")
The problem though, is that it will empty your hdfs path hdfs://user/zeppelin/my_mytable eliminating your existing files and will cause an org.apache.spark.SparkException: Job aborted.. This looks like a bug in Spark API...
Anyway, the workaround to this (tested in Spark 2.3) is to create an external table but from a Spark DDL. If your table have many columns creating the DDL could be a hassle. Fortunately, starting from Spark 2.0, you could call the DDL SHOW CREATE TABLE to let spark do the hard work. The problem is that you can actually run the SHOW CREATE TABLE in a persistent table.
If the table is pretty big, I recommend to get a sample of the table, persist it to another location, and then get the DDL. Something like this:
// Create a sample of the table
val df = spark.read.parquet("hdfs://user/zeppelin/my_table")
df.limit(1).write.
option("path", "/user/zeppelin/my_table_tmp").
saveAsTable("my_table_tmp")
// Now get the DDL, do not truncate output
spark.sql("SHOW CREATE TABLE my_table_tmp").show(1, false)
You are going to get a DDL like:
CREATE TABLE `my_table_tmp` (`ID` INT, `Descr` STRING)
USING parquet
OPTIONS (
`serialization.format` '1',
path 'hdfs:///user/zeppelin/my_table_tmp')
Which you would want to change to have the original name of the table and the path to the original data. You can now run the following to create the Spark External table pointing to your existing HDFS data:
spark.sql("""
CREATE TABLE `my_table` (`ID` INT, `Descr` STRING)
USING parquet
OPTIONS (
`serialization.format` '1',
path 'hdfs:///user/zeppelin/my_table')""")
I'd like to save data in a Spark (v 1.3.0) dataframe to a Hive table using PySpark.
The documentation states:
"spark.sql.hive.convertMetastoreParquet: When set to false, Spark SQL will use the Hive SerDe for parquet tables instead of the built in support."
Looking at the Spark tutorial, is seems that this property can be set:
from pyspark.sql import HiveContext
sqlContext = HiveContext(sc)
sqlContext.sql("SET spark.sql.hive.convertMetastoreParquet=false")
# code to create dataframe
my_dataframe.saveAsTable("my_dataframe")
However, when I try to query the saved table in Hive it returns:
hive> select * from my_dataframe;
OK
Failed with exception java.io.IOException:java.io.IOException:
hdfs://hadoop01.woolford.io:8020/user/hive/warehouse/my_dataframe/part-r-00001.parquet
not a SequenceFile
How do I save the table so that it's immediately readable in Hive?
I've been there...
The API is kinda misleading on this one.
DataFrame.saveAsTable does not create a Hive table, but an internal Spark table source.
It also stores something into Hive metastore, but not what you intend.
This remark was made by spark-user mailing list regarding Spark 1.3.
If you wish to create a Hive table from Spark, you can use this approach:
1. Use Create Table ... via SparkSQL for Hive metastore.
2. Use DataFrame.insertInto(tableName, overwriteMode) for the actual data (Spark 1.3)
I hit this issue last week and was able to find a workaround
Here's the story:
I can see the table in Hive if I created the table without partitionBy:
spark-shell>someDF.write.mode(SaveMode.Overwrite)
.format("parquet")
.saveAsTable("TBL_HIVE_IS_HAPPY")
hive> desc TBL_HIVE_IS_HAPPY;
OK
user_id string
email string
ts string
But Hive can't understand the table schema(schema is empty...) if I do this:
spark-shell>someDF.write.mode(SaveMode.Overwrite)
.format("parquet")
.saveAsTable("TBL_HIVE_IS_NOT_HAPPY")
hive> desc TBL_HIVE_IS_NOT_HAPPY;
# col_name data_type from_deserializer
[Solution]:
spark-shell>sqlContext.sql("SET spark.sql.hive.convertMetastoreParquet=false")
spark-shell>df.write
.partitionBy("ts")
.mode(SaveMode.Overwrite)
.saveAsTable("Happy_HIVE")//Suppose this table is saved at /apps/hive/warehouse/Happy_HIVE
hive> DROP TABLE IF EXISTS Happy_HIVE;
hive> CREATE EXTERNAL TABLE Happy_HIVE (user_id string,email string,ts string)
PARTITIONED BY(day STRING)
STORED AS PARQUET
LOCATION '/apps/hive/warehouse/Happy_HIVE';
hive> MSCK REPAIR TABLE Happy_HIVE;
The problem is that the datasource table created through Dataframe API(partitionBy+saveAsTable) is not compatible with Hive.(see this link). By setting spark.sql.hive.convertMetastoreParquet to false as suggested in the doc, Spark only puts data onto HDFS,but won't create table on Hive. And then you can manually go into hive shell to create an external table with proper schema&partition definition pointing to the data location.
I've tested this in Spark 1.6.1 and it worked for me. I hope this helps!
I have done in pyspark, spark version 2.3.0 :
create empty table where we need to save/overwrite data like:
create table databaseName.NewTableName like databaseName.OldTableName;
then run below command:
df1.write.mode("overwrite").partitionBy("year","month","day").format("parquet").saveAsTable("databaseName.NewTableName");
The issue is you can't read this table with hive but you can read with spark.
metadata doesn't already exist. In other words, it will add any partitions that exist on HDFS but not in metastore, to the hive metastore.