Deleting part of a strings-cell array - string

Question

This is my sample data (cell array)
>A_
'CUST_1627_PI425479659' 'Pri-miR-100u2' 'u2'
'CUST_2430_PI425479649' 'Pri-miR-L7a-3d' 'd'
'CUST_226_PI425479649' 'Pri-miR-3130-4u1' 'u1'
'CUST_1618_PI425479649' 'Pri-miR-147bu' 'u'
'CUST_1449_PI425479659' 'Pri-miR-107u' 'u'
'CUST_1546_PI425479659' 'Pri-miR-4299d1' 'd1'
The last one character or two last characters in the second column are written in the third column. I would like to remove them from strings in second column.
In a result it should look like this
>A_
'CUST_1627_PI425479659' 'Pri-miR-100' 'u2'
'CUST_2430_PI425479649' 'Pri-miR-L7a-3' 'd'
'CUST_226_PI425479649' 'Pri-miR-3130-4' 'u2'
'CUST_1618_PI425479649' 'Pri-miR-147b' 'u'
'CUST_1449_PI425479659' 'Pri-miR-107' 'u'
'CUST_1546_PI425479659' 'Pri-miR-4299' 'd1'
I tried in this way but it doesn't work.
s= {'u','u1','u2','d','d1'};
for i=1:length(A_(:,2))
A_(i,2)= erase(A_(i,2),s)
end

Answer 1

Use regexprep to replace the occurrences of the third column in the second column with ''.
A_(:,2) = regexprep( A_(:,2), A_(:,3), '');
or to fix your code which uses erase (introduced in R2016b):
for k=1:length(A_(:,2))
A_(k,2) = erase(A_(k,2), A_(k,3)); %You need A_(k,3) here
end
but... since erase is directly applicable on cell arrays, so you don't need a loop here i.e.
A_(:,2) = erase(A_(:,2), A_(:,3));