I have an excel sheet that recorded data like following:
_____|__A__|__B__
__1__|__x__|_____
__2__|__x__|_____
__3__|__y__|_____
__4__|__x__|_____
__5__|__x__|_____
__6__|__y__|_____
__7__|__x__|_____
__8__|__ __|_____
__9__|__x__|_____
_10__|__y__|_____
_11__|__ __|_____
_12__|__x__|_____
I would like to count all field contained 'y' and ' ' from A1 to A12. Here's what I did for now:
=COUNTIF(A1:A12, "y") + COUNTIF(A1:A12, "")
It will become longer if I count more specified character...
Would you suggest any better way ?
You can use this shorthand to achieve your result
=SUM(COUNTIF(A1:A12,{"y",""}))
This is exactly the same as
=COUNTIF(A1:A12, "y") + COUNTIF(A1:A12, "")
The shorthand allows you to easily add more characters you want to count.
You can read more about this here:
https://excelxor.com/2014/09/28/countifs-multiple-or-criteria-for-one-or-two-criteria_ranges/
Related
I have had to look up hundreds (if not thousands) of free-text answers on google, making notes in Excel along the way and inserting SAS-code around the answers as a last step.
The output looks like this:
This output contains an unnecessary number of blank spaces, which seems to confuse SAS's search to the point where the observations can't be properly located.
It works if I manually erase superflous spaces, but that will probably take hours. Is there an automated fix for this, either in SAS or in excel?
I tried using the STRIP-function, to no avail:
else if R_res_ort_txt=strip(" arild ") and R_kom_lan=strip(" skåne ") then R_kommun=strip(" Höganäs " );
If you want to generate a string like:
if R_res_ort_txt="arild" and R_kom_lan="skåne" then R_kommun="Höganäs";
from three variables, let's call them A B C, then just use code like:
string=catx(' ','if R_res_ort_txt=',quote(trim(A))
,'and R_kom_lan=',quote(trim(B))
,'then R_kommun=',quote(trim(C)),';') ;
Or if you are just writing that string to a file just use this PUT statement syntax.
put 'if R_res_ort_txt=' A :$quote. 'and R_kom_lan=' B :$quote.
'then R_kommun=' C :$quote. ';' ;
A saner solution would be to continue using the free-text answers as data and perform your matching criteria for transformations with a left join.
proc import out=answers datafile='my-free-text-answers.xlsx';
data have;
attrib R_res_ort_txt R_kom_lan length=$100;
input R_res_ort_txt ...;
datalines4;
... whatever all those transforms will be performed on...
;;;;
proc sql;
create table want as
select
have.* ,
answers.R_kommun_answer as R_kommun
from
have
left join
answers
on
have.R_res_ort_txt = answers.res_ort_answer
& have.R_kom_lan = abswers.kom_lan_answer
;
I solved this by adding quotes in excel using the flash fill function:
https://www.youtube.com/watch?v=nE65QeDoepc
Hi I would like to extract dynamically the numbers from string in Excel.
I have the following strings and I would like to have only the numbers before ". pdf". taken out of the string into the next column.
As you can see the number of characters varies from line to line.
I have invented something like this:
=MID(M20;SEARCH("_";M20);20)
But this takes out only the numbers after "_" and .pdf after this....
How to make it the way I like?
D:\Users\xxxx\Desktop\1610\ts25b_4462.pdf
D:\Users\xxx\Desktop\1610\ts02b_39522.pdf
D:\Users\xxxxx\Desktop\1610\ts02b_except_39511.pdf
D:\Users\xxxx\Desktop\1610\ts02b_except_39555.pdf
D:\Users\xxxx\Desktop\1610\ts22b_6118.pdf
So that I have just :
4462
39522
39511
39555
6118
and so on...
Thank you!!!
With VBA, try to do it like this:
Public Function splitThings(strInput As String) As String
splitThings = Split(Split(strInput, "_")(1), ".")(0)
End Function
Concerning your formula, try to use =LEFT(MID(M20;SEARCH("_";M20);20),K), where K is the difference of the length of ts22b_6118.pdf and 4 (.pdf). 4 is the length of .pdf.
Something like this should do the work:
=LEFT(MID(I3,SEARCH("_",I3)+1,LEN(I3)),LEN(MID(I3,SEARCH("_",I3),LEN(I3)))-5)
You should do it using Excel formula. For example:
=SUBSTITUTE(LEFT(A1,FIND(".pdf",A1)-1),LEFT(A1,FIND("_",A1)),"")
Using the first line as an example, with LEFT(A1,FIND(".pdf",A1)-1) you will have D:\Users\xxxx\Desktop\1610\ts25b_4462 and with the LEFT(A1,FIND("_",A1)) D:\Users\xxxx\Desktop\1610\ts25b_, if you SUBSTITUTE the first part by "" you will have 4462.
Hope this can help.
With this formula, you should be able to get the numbers you want:
=MID(A1,FIND("|",SUBSTITUTE(A1,"_","|",LEN(A1)-LEN(SUBSTITUTE(A1,"_",""))))+1,FIND(".",A1)-FIND("|",SUBSTITUTE(A1,"_","|",LEN(A1)-LEN(SUBSTITUTE(A1,"_",""))))-1)
Basically, this is the initial fomula:
=MID(A1,FIND("_",A1)+1,FIND(".",A1)-FIND("_",A1)-1)
But since there may be two _ in the string so this is the one to find the 2nd _:
=SUBSTITUTE(A1,"_","|",LEN(A1)-LEN(SUBSTITUTE(A1,"_","")))
Now just replace this SUBSTITUTE with A1 above and you get that long formula. Hope this helps.
This will return the number you want regardless of extension (could be .pdf, could be .xlsx, etc) and regardless of the number of underscores present in the filename and/or filepath:
=TRIM(LEFT(RIGHT(SUBSTITUTE(SUBSTITUTE(M20,".",REPT(" ",LEN(M20))),"_",REPT(" ",LEN(M20))),LEN(M20)*2),LEN(M20)))
This is my sample data (cell array)
>A_
'CUST_1627_PI425479659' 'Pri-miR-100u2' 'u2'
'CUST_2430_PI425479649' 'Pri-miR-L7a-3d' 'd'
'CUST_226_PI425479649' 'Pri-miR-3130-4u1' 'u1'
'CUST_1618_PI425479649' 'Pri-miR-147bu' 'u'
'CUST_1449_PI425479659' 'Pri-miR-107u' 'u'
'CUST_1546_PI425479659' 'Pri-miR-4299d1' 'd1'
The last one character or two last characters in the second column are written in the third column. I would like to remove them from strings in second column.
In a result it should look like this
>A_
'CUST_1627_PI425479659' 'Pri-miR-100' 'u2'
'CUST_2430_PI425479649' 'Pri-miR-L7a-3' 'd'
'CUST_226_PI425479649' 'Pri-miR-3130-4' 'u2'
'CUST_1618_PI425479649' 'Pri-miR-147b' 'u'
'CUST_1449_PI425479659' 'Pri-miR-107' 'u'
'CUST_1546_PI425479659' 'Pri-miR-4299' 'd1'
I tried in this way but it doesn't work.
s= {'u','u1','u2','d','d1'};
for i=1:length(A_(:,2))
A_(i,2)= erase(A_(i,2),s)
end
Use regexprep to replace the occurrences of the third column in the second column with ''.
A_(:,2) = regexprep( A_(:,2), A_(:,3), '');
or to fix your code which uses erase (introduced in R2016b):
for k=1:length(A_(:,2))
A_(k,2) = erase(A_(k,2), A_(k,3)); %You need A_(k,3) here
end
but... since erase is directly applicable on cell arrays, so you don't need a loop here i.e.
A_(:,2) = erase(A_(:,2), A_(:,3));
I have a crystal report I need to modify to leave out duplicate rows by "name". So in Section Expert I am putting in a formula in Suppress and I cannot figure out how to compare the current name field being added to all the previous names that are in the group already. I was trying to use the Filter() function, but for the String array parameters I don't know what to enter that would be all of the other names previously added to the group. I need to compare the current name being added and see if it is already in the group so I can then compare another field called "date" and if the date of the field being added is more recent then the date of the duplicate name it will over write the row and only show the row with the most recent date.
Basically the question is how do I create an array with all the current fields already in the group(or does one exist already) so that I may use the Filter() function to see if the current name being added is already in that array of names added?
Well I figured it out, so for anyone who runs into this here is my solution.
first off I made a formula in the "formula fields" section that creates two arrays when reading the data from the database and keeps only one copy of each id and date in the record. Then for any other records that have the same id it will compare the date of that record to the record in the array with the same name and if the date is greater(later) then it will replace the date with the currently read in one. I named this formula field idArray.
Global StringVar Array idArray;
Global DateVar Array expArray;
BooleanVar addName;
NumberVar x;
StringVar idTest;
StringVar expDateTest;
whilereadingrecords;
(
addName := true;
for x := 1 to Ubound(idArray) step 1 do
(
if({hrpersnl.p_empno} = idArray[x]) then
(
addName := false;
if(Date({nemphist.enddate}) > expArray[x]) then
expArray[x] := Date({nemphist.enddate});
)
);
if(addName = true) then
(
reDim Preserve idArray[Ubound(idArray) + 1];
reDim Preserve expArray[Ubound(expArray) + 1];
idArray[Ubound(idArray)] := {hrpersnl.p_empno};
expArray[Ubound(expArray)] := Date({nemphist.enddate});
//idTest := idTest + ' ' + {hrpersnl.p_empno};
//expDateTest := expDateTest + ' ' + toText(Date({nemphist.enddate}));
);
//idTest
//Ubound(idArray)
//expDateTest
)
The commented out lines are what I used for testing to see how the arrays were building. I left them in there just as an example of how to debug crystal reports, since it doesn't come with a debugger.
The next step is to create a record suppression formula. In the Report menu I went to "section expert" and in the "Details" section of my group I clicked the little x-2 button next to the "Suppress (No Drill-Down)" option. I then inserted this code that looks at the current record's id and date and if the id is in the first array it will take its position and use that to retrieve the date from the second array and if the current record's date is less than the date we now know to be the max then it will suppress the record.
Global StringVar Array idArray;
Global DateVar Array expArray;
NumberVar x;
BooleanVar suppress := false;
for x := 1 to Ubound(idArray) do
(
if({hrpersnl.p_empno} = idArray[x]) then
if(Date({nemphist.enddate}) < expArray[x]) then
suppress := true;
);
if(suppress = true) then
true
else
false
Some lessons learned along the way...
Crystal Reports does global variables in a weird way. It took me a few hours of fudging around with them to figure out that you can basically use them anywhere in the report as long as you declare them in each section you put them in with the Global [vartype] "name" syntax. Even though you are re-declaring it each time Crystal does not remove the value of it or reset it or anything.
This operator ":=" is different than "=". The ":=" operator is used to set values for variables whereas the "=" seems to be used only for comparisons.
Crystal reports is really weird with its design. If you do want your formula field to return a specific variable or something you just type in that variable name without a ";" after it. Anything without a ";" after it is considered the end of the formula. So if you get this dumb "oh this code looks like its not part of the formula" error then it is because you didn't put a ";" after something and Crystal is assuming your function is ending at the location. But if you don't put a variable without a ";" after it your formula with just return "false" by default. So in my formula where I have //idTest
//Ubound(idArray)
//expDateTest
all I have to do is uncomment the variable I want to be returned and the formula will do so.
I am looking for a function in Microsoft Excel that can separate number with symbol. For the example :
I want to separate number in this code:
12345_ABCD
I am looking for a function that can enables me to get the number (in this case 12345) without another character (in this case _ABCD).
And the problem is the the total character of number can be vary. For the example, it can be 12345_ABCD or 234_ABC or 34567_AB.
Please kindly help my problem. Thanks for your concern
If your cells always have numbers in front and then an underscore you could use this:
=Left(A1;Find("_";A1)-1)
Here is the function to get the number alone (in your case)
Public Function segregatenumber(a As String)
segregatenumber = Left(a, InStr(a, "_") - 1)
End Function
then you may use it as function in Excel cells