I am pretty new to Tensorflow, and I am currently learning it through given website https://www.tensorflow.org/get_started/get_started
It is said in the manual that:
We've created a model, but we don't know how good it is yet. To evaluate the model on training data, we need a y placeholder to provide the desired values, and we need to write a loss function.
A loss function measures how far apart the current model is from the provided data. We'll use a standard loss model for linear regression, which sums the squares of the deltas between the current model and the provided data. linear_model - y creates a vector where each element is the corresponding example's error delta. We call tf.square to square that error. Then, we sum all the squared errors to create a single scalar that abstracts the error of all examples using tf.reduce_sum:"
q1."we don't know how good it is yet.", I didn't understand this
quote as the simple model created is a simple slope equation and on
what it should train for?, as the model is a simple slope. Is it
require an perfect slope or what? why am I training that model and
for what?
q2.what is a loss function? Is loss function is used to determine the
accuracy of the model? Why is it required?
q3. I didn't understand " 'sums the squares of the deltas' between
the current model and the provided data."
q4.I didn't understood this part of code,"squared_deltas =
tf.square(linear_model - y)
this is the code:
y = tf.placeholder(tf.float32)
squared_deltas = tf.square(linear_model - y)
loss = tf.reduce_sum(squared_deltas)
print(sess.run(loss, {x:[1,2,3,4], y:[0,-1,-2,-3]}))
this may be simple questions, but I am a beginner to Tensorflow and having a hard time understanding it.
1) So you're kind of right about "Why should we train for a simple problem" but this is just an introduction piece. With any machine learning task you need to evaluate your model to see how good it is. In this case you are just trying to train to find the coefficients for the line of best fit.
2) A loss function in any machine learning context represents your error with your model. This usually means a function of your "distance" of your calculated value to the ground truth value. Think of it as an internal evaluation score. You want to minimise your loss so the gradients and parameter changes are based on your loss.
3/4) Your question here is more to do with least square regression. It's a statistical method to create lines of best fit between points. The deltas represent the differences between your calculated values and the truth values. The aim is to minimise the area of the squares and hence minise the error and have a better line of best fit.
What you are doing in this Tensorflow example is creating a machine learning model that will learn the coefficients for the line of best fit automatically using a least squares based system.
Pretty much all of your question have to-do with the loss function.
The loss function is a function that determines how far apart your output are from the expected (correct) output.
It has two usages:
Help the algorithm determine if the tweaking of the weight is helping going in the good or bad direction
Determinate the accuracy (~the number of time your system guesses the correct answer)
The loss function is the sum of the deltas witch is: the addition of the diff (delta) between the expected output and the actual output.
I think It's squared to magnifies the error the algorithm makes.
Related
I have LinearSVC algorithm that predicts some data for stock. It has a 90% acc rating, but I think this might be due to the fact that some y's are far more likely than others. I want to see if there is a way to see if for each y I've defined, how accurately that y was predicted.
I haven't seen anything like this in the docs, but it just makes sense to have it.
If what your really want is a measure of confidence rather than actual probabilities, you can use the method LinearSVC.decision_function(). See the documentation or the probability calibration CalibratedClassifierCV using this documentation.
You can use a confusion matrix representation implemented in SciKit to generate an accuracy matrix between the predicted and real values of your classification problem for each individual attribute. The diagonal represents the raw accuracy, which can easily be converted to a percentage accuracy.
I'm trying to fit a simple Bayesian regression model to some right-skewed data. Thought I'd try setting family to a log-normal distribution. I'm using pymc3 wrapper BAMBI. Is there a way to build a custom family with a log-normal distribution?
It depends on what you want the mean function of the model to look like.
If you want a model like
then Yes, this is easily achieved by simply log transforming Y and then estimating the usual linear model with Normal response. Notice that in this model Y is an exponential function of the predictor X, so when plotting Y against X (both untransformed), the regression line can curve up or down. It also has a multiplicative error term so that the variance is greater for larger predicted Y values. We can say that such a model has a log link function and a lognormal response.
But if you want a model like
then No, this kind of model is not currently supported by bambi*. This is a model with a lognormal response but an identity link function. The regression of Y on X is a straight line, but the errors have the same lognormal distribution at every point along X, so that the variance does not increase for larger predicted Y values. Note that this is an unusual model that I personally have never actually seen used.
* It's possible in theory to roll your own custom Families (although it would require some slight hacking), but the way this is designed in bambi ultimately depends on the families implemented in statsmodels.genmod, which does not currently include lognormal.
Unless I'm misunderstanding something, I think all you need to do is specify link='log' in the fit() call. If your assumption is correct, the exponentiated linear prediction will be normally distributed, and the default error distribution is gaussian, so I don't think you need to build a custom family for this—the default gaussian family with a log link should work fine. But feel free to clarify if this doesn't address your question.
I recently came across LightFM while learning to train a recommender system. And so far what I know is that it utilizes loss functions which are logistic, BPR, WARP and k-OS WARP. I did not go through the math behind all these functions. Now what I am confused about is that how will I know that which loss function to use where?
From lightfm model documentation page:
logistic: useful when both positive (1) and negative (-1) interactions are present.
BPR: Bayesian Personalised Ranking 1 pairwise loss. Maximises the prediction difference between a positive example and a randomly chosen negative example. Useful when only positive interactions are present and optimising ROC AUC is desired.
WARP: Weighted Approximate-Rank Pairwise [2] loss. Maximises the rank of positive examples by repeatedly sampling negative examples until rank violating one is found. Useful when only positive interactions are present and optimising the top of the recommendation list (precision#k) is desired.
k-OS WARP: k-th order statistic loss [3]. A modification of WARP that uses the k-the positive example for any given user as a basis for pairwise updates.
Everything boils down to how your dataset is structured and what kind of user interacions you're looking at. Obviously one approach would be to include the loss function in your parameter grid when going through hyperparameter tuning (at least that's what I did) and check model accuracy. I find investingating why a given loss function performed better/worse on a dataset as a good learning exercise.
I have a particular classification problem that I was able to improve using Python's abs() function. I am still somewhat new when it comes to machine learning, and I wanted to know if what I am doing is actually "allowed," so to speak, for improving a regression problem. The following line describes my method:
lr = linear_model.LinearRegression()
predicted = abs(cross_val_predict(lr, features, labels_postop_IS, cv=10))
I attempted this solution because linear regression can sometimes produce negative predictions values, even though my particular case, these predictions should never be negative, as they are a physical quantity.
Using the abs() function, my predictions produce a better fit for the data.
Is this allowed?
Why would it not be "allowed". I mean if you want to make certain statistical statements (like a 95% CI e.g.) you need to be careful. However, most ML practitioners do not care too much about underlying statistical assumptions and just want a blackbox model that can be evaluated based on accuracy or some other performance metric. So basically everything is allowed in ML, you just have to be careful not to overfit. Maybe a more sensible solution to your problem would be to use a function that truncates at 0 like f(x) = x if x > 0 else 0. This way larger negative values don't suddenly become large positive ones.
On a side note, you should probably try some other models as well with more parameters like a SVR with a non-linear kernel. The thing is obviously that a LR fits a line, and if this line is not parallel to your x-axis (thinking in the single variable case) it will inevitably lead to negative values at some point on the line. That's one reason for why it is often advised not to use LRs for predictions outside the "fitted" data.
A straight line y=a+bx will predict negative y for some x unless a>0 and b=0. Using logarithmic scale seems natural solution to fix this.
In the case of linear regression, there is no restriction on your outputs.
If your data is non-negative (as in your case the values are physical quantities and cannot be negative), you could model using a generalized linear model (GLM) with a log link function. This is known as Poisson regression and is helpful for modeling discrete non-negative counts such as the problem you described. The Poisson distribution is parameterized by a single value λ, which describes both the expected value and the variance of the distribution.
I cannot say your approach is wrong but a better way is to go towards the above method.
This results in an approach that you are attempting to fit a linear model to the log of your observations.
A project i am working on has a reinforcement learning stage using the REINFORCE algorithm. The used model has a final softmax activation layer and because of that a negative learning rate is used as a replacement for negative rewards. I have some doubts about this process and can't find much literature on using a negative learning rate.
Does reinforement learning work with switching learning rate between positive and negative? and if not what would be a better approach, get rid of softmax or has keras a nice option for this?
Loss function:
def log_loss(y_true, y_pred):
'''
Keras 'loss' function for the REINFORCE algorithm,
where y_true is the action that was taken, and updates
with the negative gradient will make that action more likely.
We use the negative gradient because keras expects training data
to minimize a loss function.
'''
return -y_true * K.log(K.clip(y_pred, K.epsilon(), 1.0 - K.epsilon()))
Switching learning rate:
K.set_value(optimizer.lr, lr * (+1 if won else -1))
learner_net.train_on_batch(np.concatenate(st_tensor, axis=0),
np.concatenate(mv_tensor, axis=0))
Update, test results
I ran a test with only positive reinforcement samples, omitting all negative examples and thus the negative learning rate. Winning rate is rising, it is improving and i can safely assume using a negative learning rate is not correct.
anybody any thoughts on how we should implement it?
Update, model explanation
We are trying to recreate AlphaGo as described by DeepMind, the slow policy net:
For the first stage of the training pipeline, we build on prior work
on predicting expert moves in the game of Go using supervised
learning13,21–24. The SL policy network pσ(a| s) alternates between convolutional
layers with weights σ, and rectifier nonlinearities. A final softmax
layer outputs a probability distribution over all legal moves a.
Not sure if it the best way but at least i found a way that works.
for all negative training samples i reuse the network prediction, set the action i want to unlearn to zero and adjust all values to sum up to one again
i tried several ways to adjust them afterwards but haven't run enough tests to be sure what works best:
apply softmax ( action that has to be unlearned gets a nonzero value.. )
redistribute old action value over all other actions
set all illigal action values to zero and distribute the total removed value
distribute value proportional to value of other values
probably there are several other ways to do so, it might depend on use case what works best and there might be a better way to do so but this one works at least.