I type in the number 1,234.5678 in cell A1
I type in the formula =round(A1, 1)
And get this error:
(my , and . are switched because of European/Asian standards - could that be the reason you think?)
I tried =sum(round(A1,1)) and any other variation I could think of, all give the same error.
I tried to switch , and . to American standard, and I used ROUND instead of round. Still same error
How about:
=ROUND(A1;1)
as the comma is often swapped with a semi colon on some systems.
Use
=ROUND(A1,2)
And make sure that columns are numbers in format.
Related
This is my first StackOverflow question, so apologies if I am unclear.
Currently, my work uses an Excel tracking doc to log project info. The column info is like so:
CELL B1 (Project Number) =IF(B2=""," ",MID(B2,FIND("P2",B2),9))
CELL B2 (Project Name) Client / P2XXXXXXX / Name
Thus, the P2XXXXXXX gets pulled out of B2 and populated into B1.
However, management has recently switched systems, so now, some project numbers have the P2XXXXXXX format and others have a PRJ-XXXXX format.
So we need a formula the produces nothing if the cell is blank and EITHER the P2XXXXXXX number or PRJ-XXXXX number if the cell is not blank.
Is it possible? If any further details are needed, let me know. Thanks in advance!
Well, if the / is always there then this can work:
IF(B2="","",MID(B2,FIND("/",B2,1)+2,9))
assuming the name is always 9 characters.
String Between Two Same Characters
Maybe the next month your company will start using a different first letter or could add more numbers e.g. SPRXXXXXXXXXX. So you could solve this problem by extracting whatever is between those two slashes.
=IF(B2="","",TRIM(MID(B2,FIND("/",B2)+1,FIND("/",B2,FIND("/",B2)+1)-FIND("/",B2)-1)))
Find the first character =FIND("/",B2), but we need the next one:
=FIND("/",B2)+1
Find the second character but search from the postition after the first found:
=FIND("/",B2,FIND("/",B2)+1)
Now get the string between them:
=MID(B2,FIND("/",B2)+1,FIND("/",B2,FIND("/",B2)+1)-FIND("/",B2)-1)
(note how the last minus was 'converted' from a plus to a minus (- + + = -)).
Remove the leading and trailing spaces:
=TRIM(MID(B2,FIND("/",B2)+1,FIND("/",B2,FIND("/",B2)+1)-FIND("/",B2)-1))
Add the condition when the cell is blank:
=IF(B2="","",TRIM(MID(B2,FIND("/",B2)+1,FIND("/",B2,FIND("/",B2)+1)-FIND("/",B2)-1)))
Here's another way using LEFT and RIGHT:
=IF(B2="","",TRIM(LEFT(RIGHT(B2,LEN(B2)-FIND("/",B2)),FIND("/",B2))))
Although you can solve this problem with a combination of slicing, trimming, and complex conditionals, the most expressive and easy to maintain solution is to use regular expressions. Regular expressions have a bit of a learning curve, but there's a great playground website where you can experiment with them, and this page has a pretty good writeup on how regular expressions work in excel.
Specifically, this regular expression addresses the two naming conventions you've highlighted, but it can be updated to support more naming conventions as your company inevitably adds more:
P(RJ-)?((\d){9}|(\d){5})
To break that down from left to right:
P: both patterns start with a "P"
(RJ-)? One pattern follows with "RJ-", but the other doesn't. This is a grouped part of the pattern, and the question mark means that this part of the pattern is optional.
((\d){9}|(\d){5}): by far the nastiest part, but this basically means that there is going to be a sequence of numbers (\d), and there will either be nine of them or five of them. By wrapping the whole thing in parenthesis, they are always the second captured group, no matter the length of the sequence of numbers. This means that you can always extract the project id by looking at the value of the second capture group.
You can also make the expression more generalized by replacing ((\d){9}|(\d){5}) with simply (\d+). That just means "one or more digits." That gives you a much more simplified overall expression of this:
P(RJ-)?(\d+)
Depending on whether or not you care about validating strictly that project ids are 5 OR 9 digits long, that pattern above might be suitable, and it has the benefit of being more flexible. Still, the project ID is in the second captured group.
I have written instruction from my college professor to type this formula:
=SIN(MOD($B5;23)/23*2*PI()),
but when I do it, Excel won't accept it, because the formula contains an error.
Am I doing something wrong or is it possible that professor gave us bad instructions?
If the formula contains , character too, then that's why. Otherwise the formula works for me in a blank Excel, which means that the error may be somewhere in $B5 if it's not the , character.
functions:
sin()
mod()
pi()
and parenthesis seems ok + the rest is just numbers. (Excel 2010)
=SIN(MOD($B5;23)/23*2*PI())
It looks like your professor made a typo on the instructions. Try
=SIN(MOD($B5,23)/23*2*PI())
I'm not on a computer with Excel so I'm unable to test it. However, the documentation for the MOD function in excel uses a comma instead of a semicolon.
Thanks, professor made a typo, it's working when I put comma instead of the semicolon.
I'm trying to get this into excel: e^(-(2.2/9.58)^2)
According to my graphical calculator AND wolfram alpha this should give: 0.9486
However when I type it in excel with the following formula: =EXP(-(2.2/9.58)^2) I get 1.054
I've tried multiple different things but I still can't get the right answer out of it. What am I doing wrong with the formula in Excel??
Excel seems to mess up the brackets and does some distribution on its own. Very odd.
=EXP(-((2,2/9,58)^2)) should work
By way of some explanation, in Excel (as conventional) the negation operator has precedence over exponentiation. So:
=EXP(-(2.2/9.58)^2)
is treated just as:
=EXP((-2.2/9.58)^2)
or
=EXP(0.052737)
would be, hence resulting in 1.05415. Whereas:
=EXP(-0.052737)
is 0.948629.
Ok so i have been trying to do this and i pretty much keep on failing :p
Basically what i want to do is take the date 10/1/2013 and turn it into 201310. I tried to concatenate using left and right. tried to make it into text using left and right. Nothing seems to be working. The closest i got was to 20130 by using =CONCATENATE(TEXT(J3,"mmyyyy")) Which turned the date into 102013 than i tried =RIGHT(L3,4)*LEFT(L3,2) and got 20130 which is still incorrect. Any help would be appreciated!
You could simply turn around your first example and use the correct string:
=TEXT(J3, "yyyyMM")
Note, I used upper case M. Lower case m means minutes, while upper case M means month.
The CONCATENATE is unnecessary.
Please also note, that this is prone to localization issues, i.e. it depends on the language settings. I am from Germany and I need to use jjjj instead of yyyy.
Seems like it would be a simple thing really (and it may be), but I'm trying to take the string data of a column and then through a calculated column, replace all the spaces with %20's so that the HTML link in the workflow produced email will actually not break off at the first space.
For example, we have this in our source column:
file:///Z:/data/This is our report.rpt
And would like to end up with this in the calculated column:
file:///Z:/data/This%20is%20our%20report.rpt
Already used the REPLACE, and made up a ghastly super nested REPLACE/SEARCH version, but the problem there is that you have to nest for EACH potential space, and if you don't know how many up front, it doesn't work, or will miss some.
Have any of you come across this scenario and how did you handle it?
Thanks in advance!
As far as I know there is no generic solution using the calculated-column syntax. The standard solution for this situation is using an ItemAdded (/ItemUpdated) event and initializing the field value from code.
I was able to solve this issue for my circumstances by using a series of calculated columns.
In the first calculated column (C1) I entered a formula to remove the first space, something like this:
=IF(ISNUMBER(FIND(" ",[Title])),REPLACE([Title],FIND(" ",[Title]),1,"%20"),[Title])
In the second Calculated column (C2) I used:
=IF(ISNUMBER(FIND(" ",[C1])),REPLACE([C1],FIND(" ",[C1]),1,"%20"),[C1]).
In my case, I wanted to encode upto four spaces, so I used 3 calculated columns (C1, C2, C3) in the same fashion and got the desired result.
This is not as efficient as using a single calculated column, but if SUBSTITUTE will not work in your SharePoint environment, and you cannot use an event handler or workflow, it may offer a workable alternative.
I actually used a slightly different formula, but it was on a work machine to which I don't have access at the moment, so I just grabbed this formula from a similar S.O. question. Any formula that will replace the first occurrence of a space with "%20" will work, the trick is to a) make sure the formula returns the original string unchanged if it does not have more spaces in it, and b) test, test, test. Create a view of your list that has the field you are trying to encode, plus the calculated fields, and see if you are getting the results you want.
so that the HTML link in the workflow produced email will actually not break off at the first space.
The browser only does this if you have not enclosed your link in quotes
If you wrap the link in quotes, it does not cut off at the first space
In a SharePoint Formula it would be:
="""file:///Z:/data/This is our report.rpt"""
becuase two quotes are the SP escape notation to output a quote
You can use this formula (Start trim for 1, in my case was 4):
=IF(ISBLANK([EUR Amount]),"",(TRIM(MID([EUR Amount],4,2))&TRIM(MID([EUR Amount],6,2))&TRIM(MID([EUR Amount],8,2))&TRIM(MID([EUR Amount],10,2))&TRIM(MID([EUR Amount],12,2))&TRIM(MID([EUR Amount],14,2)))*1)