How to form the webservice url for getting order, products etc.details using webservice calls from Hybris installed in the local system.
Which all files to be checked to form the url?
For Example : http://localhost:9001/../../..
What should be filled in the blanks?
I am using a trail version of Hybris.
You have to generate a webservice extension by the modulegen ant target. This extension provides you a logic how you can make your hybris application reachabel by a webcall.
https://help.hybris.com/6.2.0/hcd/8c83443586691014a4b1ebdb08146283.html - Here is the WIKI Page about webservices
https://help.hybris.com/6.2.0/hcd/8b9e3f1c86691014bd71bdc414663e44.html - Here is an example of a webservice
The list is quite long to be posted here.
Currently you can found v1 WS definition in Calls Reference - v1 (check child pages).
The new v2 WS are described in Calls Reference - v2 and extends v1 WS.
Basically for user, cart and order, you can find below the model of URL to call:
User resources: https://localhost:9002/rest/v2/{baseSiteID}/users/{userID}/...
Cart resources: https://localhost:9002/rest/v2/{baseSiteID}/users/{userID}/carts/{cartID}...
Order resources: https://localhost:9002/rest/v2/{baseSiteID}/users/{userID}/orders/{orderID}
Related
I want to get all destinations on subaccount and instance level. In SAP API business Hub, I found the API information and "SAP Cloud SDK" tab to generate code by OpenAPI generator.
https://api.sap.com/api/SAP_CP_CF_Connectivity_Destination/overview
I downloaded the API specification and added dependencies into Cloud SDK for Java project. The code is generated successfully with some errors (unknown models）in generated api classes.
For example in DestinationsOnSubaccountLevelApi.class, model OneOfDestinationNameOnly is imported and used in method but it is not generated in model package.
I looked into API specification and found that there were two types of response entity. That is the reason why the code could not be generated properly. I can modify the API specification to make it work but it should not be the long term solution. Is there any other way to fix this issue?
Unfortunately the SAP Cloud SDK Generator for Open API services is not yet able to understand oneOf relationship that is modeled in the specification.
As an alternative, would you consider using the DestinationAccessor API for resolving single destinations?
You can also directly instantiate an ScpCfDestinationLoader, which allows for querying all destinations:
ScpCfDestinationLoader loader = new ScpCfDestinationLoader();
DestinationOptions options = DestinationOptions
.builder()
.augmentBuilder(ScpCfDestinationOptionsAugmenter.augmenter().retrievalStrategy(ScpCfDestinationRetrievalStrategy.ALWAYS_SUBSCRIBER))
.build();
Try<Iterable<ScpCfDestination>> destinations = loader.tryGetAllDestinations(options);
Similar to the default behavior of DestinationAccessor API, in the code above only the subscriber account will be considered. Other options are:
ScpCfDestinationRetrievalStrategy.ALWAYS_SUBSCRIBER
ScpCfDestinationRetrievalStrategy.ALWAYS_PROVIDER
ScpCfDestinationRetrievalStrategy.SUBSCRIBER_THEN_PROVIDER
I'm trying to get all the builds for a project using Odata for Azure Devops. However I found there was an endpoint for that https://analytics.dev.azure.com/{organization}/{project}/_odata/v3.0-preview/Builds but while trying the same for my Project I'm getting the below error
{"$id":"1","innerException":null,"message":"Resource not found for the segment 'Builds'.","typeName":"Microsoft.OData.UriParser.ODataUnrecognizedPathException, Microsoft.TeamFoundation.OData.Core","typeKey":"ODataUnrecognizedPathException","errorCode":0,"eventId":0}
Is this endpoint not available anymore. Or is there something wrong with my query?
Is this endpoint not available anymore. Or is there something wrong
with my query?
The entity set Build has been renamed. You can check this post from our User Voice forum.
All entity sets and entity properties with names starting with Build will be renamed to start with PipelineRun.
For e.g. Builds entity set will be called PipelineRuns, BuildId entity property will be called PipelineRunId.
So what you should use is : https://analytics.dev.azure.com/{organization}/{project}/_odata/v3.0-preview/PipelineRuns. It works on my side :)
Iam using Sharepoint.Client library(using context - ClientContext, load & then execute) to pull metadata from SP.Web. I was able to fetch some details except the one that i required the most: "APPS". How to pull apps that installed in SP ?
There's a solution from REST API part:
https:///_api/web/webinfos?$filter=(WebTemplate eq "APP")
But I need to pull down these from my Client Library.
Here is a reference link: https://sharepoint.stackexchange.com/questions/70628/get-list-of-installed-apps-using-client-object-model
You can go through this link and it will help you to get SharePoint apps using Client Library (CSOM).
Hope this will help you.
Is there a way to expose a Java rest web service in Liferay but not in a portlet, that can receive JSON request and store the data in Journal Article?
Therefore when a user logs into Liferay they will be see web content
Yes there is : JSONWebServiceActionsManagerUtil.registerJSONWebServiceAction
For instance :
Class<?> serviceImplClass;
Method serviceMethod;
Object serviceImpl;
String path = jsonWebServiceMappingResolver.resolvePath(serviceImplClass, serviceMethod);
String method = jsonWebServiceMappingResolver.resolveHttpMethod(serviceMethod);
JSONWebServiceActionsManagerUtil.registerJSONWebServiceAction("/yourwspath", serviceImpl, serviceImplClass, serviceMethod, path, method);
You should then be able to see the new web service in http://SERVER/api/jsonws
Well yes, Liferay has a full API (even JSON-based, SOAP optional, no classic REST though) that you can use. A simple Stackoverflow answer is not the right place to give a full introduction on how to work with Liferay's API, but you might want to look up Servicebuilder (which is used to create Liferay's API) and then look at JournalArticleService and related services: The Web Content Management API is called "Journal" in Liferay (for historical reasons)
`webClient.UploadFile("http://www.myurl.com/~/media/DCF92BB74CDA4D558EEF2D3C30216E30.ashx", #"E:\filesImage\Item.png");
I'm trying to upload images to sitecore using webclient.uploadfile() method by sending my sitecore address and the path of my local images.But I'm not able to upload it.I have to do this without any API's and Sitecore Instances.
The upload process would be the same as with any ASP.net application. However, once the file has been uploaded you need to create a media item programtically. You can do this from an actual file in the file system, or from a memory stream.
The process involves using a MediaCreator object and using its CreateFromFile method.
This blog post outlines the whole process:
Adding a file to the Sitecore Media Library programatically
If you're thinking simply about optimizing your developer workflow you could use the Sitecore PowerShell Extensions using the Remoting API as described in this this blog post
If you want to use web service way than you can use number of ways which are as follows:
a) Sitecore Rocks WebService (If you are allowed to install that or it is already available).
b) Sitecore Razl Service(It is third party which need license).
c) Sitecore Powershell Remoting (This needs Sitecore PowerShell extensions to be installed on Sitecore Server).
d) You can also use Sitecore Service which you can find under sitecore\shell\WebService\Service.asmx (But this is legacy of new SitecoreItemWebAPI)
e) Last is my enhanced SitecoreItemWebAPI (This also need SitecoreItemWebApi 1.2 as a pre-requisite).
But in end except option d you need to install some or other thing in order to upload the image using HTTP, you should also know the valid credentials to use any of above stated methods.
If your customers upload the image on the website, you need to create the item in your master database. (needs access and write right on the master database) depend on your security you might consider not build it with custom code.
But using the Sitecore webforms for marketers module With out of the box file upload. Create a form with upload field and using the WFFM webservices.
If you dont want to use Sitecore API, then you can do the following:
Write a code that uploads images into this folder : [root]/upload/
You might need to create folder structure that represent how the images are stored in Sitecore, eg: your images uploaded into [root]/upload/Import/ will be stored in /sitecore/media library/Import
Sitecore will automatically upload these images into Media library
Hope this helps
Option: You can use Item Web API for it. No reference to any Sitecore dll is needed. You will only need access to the host and be able to enable the Item Web API.
References:
Upload the files using it: http://www.sitecoreinsight.com/how-create-media-items-using-sitecore-item-web-api/
Enable Item Web Api: http://sdn.sitecore.net/upload/sdn5/modules/sitecore%20item%20web%20api/sitecore_item_web_api_developer_guide_sc66-71-a4.pdf#search=%22item%22
I guess that is pretty much what you need, but as Jay S mentioned, if you put more details on your question helps on finding the best option to your particular case.
private void CreateImageIteminSitecore()
{
filePath = #"C:\Sitecore\Website\ImageTemp\Pic.jpg;
using (new SecurityDisabler())
{
Database masterDb = Sitecore.Configuration.Factory.GetDatabase("master");
Sitecore.Resources.Media.MediaCreatorOptions options = new Sitecore.Resources.Media.MediaCreatorOptions();
options.FileBased = true;
options.AlternateText = Path.GetFileNameWithoutExtension(filePath);
options.Destination = "/sitecore/media library/Downloads/";
options.Database = masterDb;
options.Versioned = false; // Do not make a versioned template
options.KeepExisting = false;
Sitecore.Data.Items.MediaItem mediaitemImage = new Sitecore.Resources.Media.MediaCreator().CreateFromFile(filePath, options);
Item ImageItem = masterDb.GetItem(mediaitemImage.ID.ToString());
ImageItem.Editing.BeginEdit();
ImageItem.Name = Path.GetFileNameWithoutExtension(filePath);
ImageItem.Editing.EndEdit();
}
}