confuse wiht the Title
Well sorry my English doesn't look good
but I'll try to describe what I mean
Suppose I have this kind of values
0 A B C D F G H I J
1 20 =B1
2 10 =B3
3 30 =B5
4 8 =B7
5 9 =B9
6 4 etc.
7 79
8 67
9 63
10 45
as you seen above
I want to copy every value in cell B in two step down to cell D with Fill Handle
How can I do it ?
Any Formula I can use regarding this ?
Thanks before
In Cell D2 you can use the below formula, then drag down:
=INDEX(B:B,(ROWS($B$1:B1)*2)-1,1)
Please try:
=OFFSET(B1,ROW()-1,)
I have a form, thanks to user JamTay317, That lists data depending on folder number (bold number in form). I need to copy it for all 1500 folders (about 400 pages)
Form is divided on 4 labels on a page for easier printing
form overview
Form get it's folder number (nr teczki) from list with all folders from another sheet called "lista teczek":
list of folders
For first 4 folder numbers I use formula:
A2='lista teczek'!A1
J2='lista teczek'!A2
A21='lista teczek'!A3
J21='lista teczek'!A4
When I copy whole page underneath it increments by 36 (number of rows between)
A38='lista teczek'!A37
J38='lista teczek'!A38
A57='lista teczek'!A39
J38='lista teczek'!A40
Instead of A5, A6, etc.
Is there any way to override excel's incrementation to force it to use consecutive numbers? Or at least formula which will make it easier to follow folders list?
So I would use offset() to get the correct position
=A2=OFFSET('lista teczek'!$A$1;ROW(A1)-INT(ROW(A1)/36)*36+4*INT(ROW(A1)/36)-1;0)
So this will offset from A1 in the list sheet.
Below are row numbers a resultant lookup row numbers
Note the formula I used in the offset has an extra "-1" as this is an OFFSET so to get 1 from 1 we need to offset by 0
1 1
2 2
3 3
4 4
37 5
38 6
39 7
40 8
73 9
74 10
75 11
76 12
109 13
110 14
111 15
112 16
145 17
146 18
147 19
----LOGIC--- (edit)
So the idea is that you work out the occurrence you are on. Int(row()/36) gives us this. For example
int(1/36)=0
Int(363/36)=10
First part gives us the offset from the start of the occurrence
3-int(3/36)*36=3
378-Int(363/36)*36=3
Second part give the total of the previous occurrence
4*int(3/36)=0
4*Int(363/36)*36=40
So you need to change the 36 to the gap between the occurrences and the 4 to the length of occurrences Not sure if that helps to explain
I'm trying to pair a vlookup with a max function. For some reason it only returns #ref every time I try to use it though.
My sheet looks like this:
A - B - C - D - E - F - G
1...
5 - Prod5 id1 $100 $125 $155 $110 $150
6...
A:G is named buyAverages
C:G is named buyAveragesPrices
What I want to do is have a vlookup go and find a value in Col A and then return the highest value in that Col. So example:
A - B
1 - Prod5 *return highest price for Prod5
What I wrote in B1, which failed:
VLOOKUP(A1,buyAverages,MAX(buyAveragesPrices))
So how do I achieve this lookup? Everything I have found is how to use MAX for the lookup value, but nothing to use max on the returned index.
Try this
=MAX(IF(A:A="Prod1",C:G))
This is an Array Formula. i.e you have to press Ctrl+Shift+Enter
If there's only one instance of each Product then you can use INDEX/MATCH like this
=MAX(INDEX(C2:G100,MATCH("Prod 1",A2:A100,0),0))
Longer than Sid's suggestion but doesn't need CSE and might be more efficient if you only have a single match
If you have that formula in Z2, for example, you can use this version to get the location from row 1
=INDEX(C1:G1,MATCH(Z2,INDEX(C2:G100,MATCH("Prod 1",A2:A100,0),0),0))
You can have all in one cell using Vlookup and Max with a nested formula. For example at the top of the page:
A1 = Select the name of the product you want to find the max
A2= MAX(BUSCARV($A$1;$A$3:$F$11;3;FALSO);BUSCARV($A$1;$A$3:$F$11;4;FALSO)
;BUSCARV($A$1;$A$3:$F$11;5;FALSO);BUSCARV($A$1;$A$3:$F$11;6;FALSO))
It's long but you only have to type it once. With this formula we get all the different amounts in each column and then we ask for the maximum. It works if all the products are different. Change the name of the product and you'll find the MAX in the table.
Example Prod8
Prod8 41 ; If we change and you select in A1 Prod4 you'll
get 70 and so on..
Prod1 id1 100 125 155 110
Prod2 50 25 20 75
Prod3 60 65 15 90
Prod4 70 12 50 43
Prod5 100 200 80 25
Prod6 20 28 40 40
Prod7 14 43 60 80
Prod8 22 33 15 41
Prod9 65 48 50 70
Select your range accordingly.
You also could include in A1 a match code to select the name of your products..
I'm using Excel 2013 and I have had to create a If statement which basically chooses a student's grade depending on a certain mark number (obviously, nesting is needed) Here is the If statement I created:
=IF(E2<=20,"N",
IF(OR(E2>=21,E2<=25),4,
IF(OR(E2>=26,E2<=32),"5C",
IF(OR(E2>=33,E2<=38),"5B",
IF(OR(E2>=39, E2<=44), "5A",
IF(OR(E2>=45, E2<=53), "6C",
IF(OR(E2>=54, E2<=61), "6B",
IF(OR(E2>=62, E2<=71), "6A",
IF(OR(E2>=72, E2<=87), "7C",
IF(OR(E2>=88, E2<=103), "7B",
IF(OR(E2>=104, E2<=120), "7A")))))))))))
The error I receive is:
the specified formula cannot be entered because it uses more levels of nesting than allowed in the current file format
My question is, how do I shorten this statement to allow Excel to use it?
Place the logic in the spreadsheet cells. One column for the minimum score, and one column for the grade-:
A B
1 0 N
2 21 4
3 26 5C
4 33 5B
5 39 5A
6 45 6C
7 54 6B
8 72 7C
9 88 7B
10 104 7A
Then do a vlookup to get the grade from the actual score. vlookup will find the highest value in the A column that is less that the lookup value of 38.
In the example vlookup below 38 is the score, A1:B10 is the lookup table 2 is the 2nd column (in this case the B column) that contains the result (the grade).
=VLOOKUP(38, A1:B3, 2, TRUE)
You can also use the following formula.
=LOOKUP(E2;{0;21;26;33;39;45;54;62;72;88;104;121};{"N";4;"5C";"5B";"5A";"6C";"6B";"6A";"7C";"7B";"7C";"No match"})
There are a few different solutions. AND agreements using OR instead of the first that comes to mind.
=IF(E2<=20,"N",
IF(AND(E2>=21,E2<=25),4,
IF(AND(E2>=26,E2<=32),"5C", ...
The best way, in my opinion, is to write a UDF. Then you can use VBA and a CASE statement.
Experiment with this code in VBA to create a UDF named GRADE() - just type it into a MODULE in the VBE:
Function Grade(Marks)
Dim Score As Integer
Score = Marks * 1
Select Case Score
Case 1 To 20
Grade = "N"
Case 21 To 50
Grade = "C"
Case 51 To 90
Grade = "B"
Case 91 To 120
Grade = "A"
End Select
End Function
Then use the Function GRADE() as you would any other function but type the address of the argument - like this GRADE(B7) to use it
=+IF(O3="Negative","Negative",IF(P3="Negative","Negative",IF(Q3="Negative","Negative",IF(R3="Negative","Negative",IF(O3="Refer","Refer",IF(P3="Refer","Refer",IF(Q3="Refer","Refer",IF(R3="Refer","Refer","Positive"))))))))
I find the final status in 4 cells have positive,negative,refer,pending or blank
Ive written a function to calculate what MARK a student gets, based on a scoring table.
Why does my function work only for A mark?
This what the excel sheet looks like
COLUMN: A B C
Student SCORE MARK
1 adsf 90 A
2 asgfd 89 FALSE
3 A 90 100
4 B 81 89
5 C 71 80
6 D 61 70
7 E 56 60
8 Fx 0 55
This is the function:
{=IF(B1>=$B$3:$B$8,IF(B1<=$C$3:$C$8,$A$3:$A$8))}
I'm using {} brackets for array functions. (CTRL SHIFT ENTER)
Thank you
You're on the right track but your formula is returning an array not a single value. Wrapping the result in LOOKUP should give the desired result:
=LOOKUP("Z",IF(B1>=$B$3:$B$8,IF(B1<=$C$3:$C$8,$A$3:$A$8))
This returns the last matching grade since "Z" is larger than any other text value in the range.
A simpler method is:
=LOOKUP(-B1,-C$3:C$8,A$3:A$8)
The negative signs are needed so that the lookup values are in ascending order.