I'm using Excel 2013 and I have had to create a If statement which basically chooses a student's grade depending on a certain mark number (obviously, nesting is needed) Here is the If statement I created:
=IF(E2<=20,"N",
IF(OR(E2>=21,E2<=25),4,
IF(OR(E2>=26,E2<=32),"5C",
IF(OR(E2>=33,E2<=38),"5B",
IF(OR(E2>=39, E2<=44), "5A",
IF(OR(E2>=45, E2<=53), "6C",
IF(OR(E2>=54, E2<=61), "6B",
IF(OR(E2>=62, E2<=71), "6A",
IF(OR(E2>=72, E2<=87), "7C",
IF(OR(E2>=88, E2<=103), "7B",
IF(OR(E2>=104, E2<=120), "7A")))))))))))
The error I receive is:
the specified formula cannot be entered because it uses more levels of nesting than allowed in the current file format
My question is, how do I shorten this statement to allow Excel to use it?
Place the logic in the spreadsheet cells. One column for the minimum score, and one column for the grade-:
A B
1 0 N
2 21 4
3 26 5C
4 33 5B
5 39 5A
6 45 6C
7 54 6B
8 72 7C
9 88 7B
10 104 7A
Then do a vlookup to get the grade from the actual score. vlookup will find the highest value in the A column that is less that the lookup value of 38.
In the example vlookup below 38 is the score, A1:B10 is the lookup table 2 is the 2nd column (in this case the B column) that contains the result (the grade).
=VLOOKUP(38, A1:B3, 2, TRUE)
You can also use the following formula.
=LOOKUP(E2;{0;21;26;33;39;45;54;62;72;88;104;121};{"N";4;"5C";"5B";"5A";"6C";"6B";"6A";"7C";"7B";"7C";"No match"})
There are a few different solutions. AND agreements using OR instead of the first that comes to mind.
=IF(E2<=20,"N",
IF(AND(E2>=21,E2<=25),4,
IF(AND(E2>=26,E2<=32),"5C", ...
The best way, in my opinion, is to write a UDF. Then you can use VBA and a CASE statement.
Experiment with this code in VBA to create a UDF named GRADE() - just type it into a MODULE in the VBE:
Function Grade(Marks)
Dim Score As Integer
Score = Marks * 1
Select Case Score
Case 1 To 20
Grade = "N"
Case 21 To 50
Grade = "C"
Case 51 To 90
Grade = "B"
Case 91 To 120
Grade = "A"
End Select
End Function
Then use the Function GRADE() as you would any other function but type the address of the argument - like this GRADE(B7) to use it
=+IF(O3="Negative","Negative",IF(P3="Negative","Negative",IF(Q3="Negative","Negative",IF(R3="Negative","Negative",IF(O3="Refer","Refer",IF(P3="Refer","Refer",IF(Q3="Refer","Refer",IF(R3="Refer","Refer","Positive"))))))))
I find the final status in 4 cells have positive,negative,refer,pending or blank
Related
Here is my problem. I want to use =SLOPE formula with a cell range that refers to another sheet with criteria: Date period between Oct-21 until Apr-22, the known_ys = Emiten Name and known_xs = IHSG.
I use this formula:
=SLOPE(IF(AND(Emiten!B:B>=Risk!$A$2;Emiten!B:B<=Risk!$B$2;Emiten!A:A=Risk!D17);Emiten!D:D);IF(AND(Indeks!B:B>=Risk!$A$2;Indeks!B:B<=Risk!$B$2;Indeks!A:A=Risk!$D$2);Indeks!D:D))
But it shows the result #VALUE!, can anyone please tell me where's the problem?
Thanks
AND only ever returns a single value. To simulate 'and' conditions within array constructions, use nested IF statements.
Also, you should not be using entire column references for such a construction, since it will be forced to process several million rows unnecessarily.
Try:
=SLOPE(IF(Emiten!B1:B10>=Risk!A2,IF(Emiten!B1:B10<=Risk!B2,IF(Emiten!A1:A10=Risk!D17,Emiten!D1:D10))),IF(Indeks!B1:B10>=Risk!A2,IF(Indeks!B1:B10<=Risk!B2,IF(Indeks!A1:A10=Risk!D2,Indeks!D1:D10))))
adjusting the last row referenced (10 here) to a suitably low, though sufficient, upper bound.
Also, I take it you are aware that the SLOPE function will only consider rows for which both the known_ys and the known_xs are numeric? For example, assuming that the above resolved to:
known_ys
known_xs
14
FALSE
53
FALSE
FALSE
27
FALSE
FALSE
16
63
58
90
FALSE
FALSE
3
FALSE
80
85
25
40
then SLOPE would ignore everything apart from the the 5th, 6th, 9th and 10th pairs, effectively calculating over the following reduced array:
known_ys
known_xs
16
63
58
90
80
85
25
40
I Have two separate tables:
Start End Number
12/10/2017 31/10/2019 4
1/11/2019 28/02/2020 5
1/03/2020 1/12/2025 6
Also
Value Date Multiplication
45 1/11/2017
124 1/04/2018
43 1/09/2018
123 1/02/2019
46 1/07/2019
76 1/12/2019
789 1/05/2020
I want the Multiplication column to be populated by Value * Number based on if the date is between Stand and End
e.g.
Since 1/11/2017 is between 12/10/2017 & 31/10/2019 the values should be , 45*4.
According with the following sample data image, try this in H2:
=F2*VLOOKUP(G2, A$2:C$4, 3, TRUE)
Fill down as necessary.
I am using excel and I have a table of numbers with 6 columns from A to F and more than 1000 rows. For example, from my table,
4 17 37 38 47 53
8 43 54 55 56 60
4 18 21 25 38 57
15 25 37 38 58 59
4 16 19 20 27 43
18 32 47 50 54 56
i want to find if there is at least a row (it must be a row!) that contains the numbers 16 19 20 27. From this example, there is a match, but i don't know how to make a search or formula using four diferent numbers.
I feel like I need to use the match function but can't quite figure it out and I'm not sure about it. Does anyone know how to do this?
Thanks!
This should work:
=IF(AND(OR(A1=16,B1=16,C1=16,D1=16,E1=16,F1=16),OR(A1=19,B1=19,C1=19,D1=19,E1=19,F1=19),OR(A1=20,B1=20,C1=20,D1=20,E1=20,F1=20),OR(A1=27,B1=27,C1=27,D1=27,E1=27,F1=27)),"Yes","No")
Put it in a new column in the table. It will return a Yes if the row contains all 4 values, and a No otherwise. You can then filter the new column of Yes/No to search for a row with Yes
I put the four values you are seeking in I1:L1 and the array of data to be searched in A1:F#. Then in column G create a helper column that concatenates A:F into a delimited string. The formula in G1 is:
=":"&A1&":"&B1&":"&C1&":"&D1&":"&E1&":"&F1&":"
where I've used ":" for the delimiter (you can use any char that's not in your data).
The result in G1 is:
:4:17:37:38:47:53:
Now in H1 use this formula to search:
=NOT(ISERR(FIND(":"&$I$1&":",G1)*FIND(":"&$J$1&":",G1)*FIND(":"&$K$1&":",G1)*FIND(":"&$L$1&":",G1)))
Each FIND will return an INT if the value (with leading and trailing delimiters) is found and #VALUE! otherwise. So the product will be an INT if all values are found and #VALUE! otherwise. Wrapping the FINDs inside an ISERR makes the result prettier (TRUE/FALSE instead of #VALUE!), and inverting with NOT returns TRUE when all 4 values are found and FALSE otherwise.
Hope that helps.
Here's another way --- more elegant (no helper column). As before, I put the four values you are seeking in I1:L1 and the array of data to be searched in A1:F#. Then in column G use this ARRAY formula (CTRL-SHIFT-ENTER):
=NOT(OR(PRODUCT(A1:F1-$I$1)<>0,PRODUCT(A1:F1-$J$1)<>0,PRODUCT(A1:F1-$K$1)<>0,PRODUCT(A1:F1-$L$1)<>0))
Each PRODUCT term checks for the existence of one value and returns 0 when the value is found and a non-zero value otherwise. The results of each of the four PRODUCT terms is tested with <>0 which will return TRUE if a value is not found. Then OR with return TRUE if one or more values are not found and FALSE if all are found. That result is wrapped in a NOT so that the function result is TRUE when all four values are found.
I'm trying to pair a vlookup with a max function. For some reason it only returns #ref every time I try to use it though.
My sheet looks like this:
A - B - C - D - E - F - G
1...
5 - Prod5 id1 $100 $125 $155 $110 $150
6...
A:G is named buyAverages
C:G is named buyAveragesPrices
What I want to do is have a vlookup go and find a value in Col A and then return the highest value in that Col. So example:
A - B
1 - Prod5 *return highest price for Prod5
What I wrote in B1, which failed:
VLOOKUP(A1,buyAverages,MAX(buyAveragesPrices))
So how do I achieve this lookup? Everything I have found is how to use MAX for the lookup value, but nothing to use max on the returned index.
Try this
=MAX(IF(A:A="Prod1",C:G))
This is an Array Formula. i.e you have to press Ctrl+Shift+Enter
If there's only one instance of each Product then you can use INDEX/MATCH like this
=MAX(INDEX(C2:G100,MATCH("Prod 1",A2:A100,0),0))
Longer than Sid's suggestion but doesn't need CSE and might be more efficient if you only have a single match
If you have that formula in Z2, for example, you can use this version to get the location from row 1
=INDEX(C1:G1,MATCH(Z2,INDEX(C2:G100,MATCH("Prod 1",A2:A100,0),0),0))
You can have all in one cell using Vlookup and Max with a nested formula. For example at the top of the page:
A1 = Select the name of the product you want to find the max
A2= MAX(BUSCARV($A$1;$A$3:$F$11;3;FALSO);BUSCARV($A$1;$A$3:$F$11;4;FALSO)
;BUSCARV($A$1;$A$3:$F$11;5;FALSO);BUSCARV($A$1;$A$3:$F$11;6;FALSO))
It's long but you only have to type it once. With this formula we get all the different amounts in each column and then we ask for the maximum. It works if all the products are different. Change the name of the product and you'll find the MAX in the table.
Example Prod8
Prod8 41 ; If we change and you select in A1 Prod4 you'll
get 70 and so on..
Prod1 id1 100 125 155 110
Prod2 50 25 20 75
Prod3 60 65 15 90
Prod4 70 12 50 43
Prod5 100 200 80 25
Prod6 20 28 40 40
Prod7 14 43 60 80
Prod8 22 33 15 41
Prod9 65 48 50 70
Select your range accordingly.
You also could include in A1 a match code to select the name of your products..
Ive written a function to calculate what MARK a student gets, based on a scoring table.
Why does my function work only for A mark?
This what the excel sheet looks like
COLUMN: A B C
Student SCORE MARK
1 adsf 90 A
2 asgfd 89 FALSE
3 A 90 100
4 B 81 89
5 C 71 80
6 D 61 70
7 E 56 60
8 Fx 0 55
This is the function:
{=IF(B1>=$B$3:$B$8,IF(B1<=$C$3:$C$8,$A$3:$A$8))}
I'm using {} brackets for array functions. (CTRL SHIFT ENTER)
Thank you
You're on the right track but your formula is returning an array not a single value. Wrapping the result in LOOKUP should give the desired result:
=LOOKUP("Z",IF(B1>=$B$3:$B$8,IF(B1<=$C$3:$C$8,$A$3:$A$8))
This returns the last matching grade since "Z" is larger than any other text value in the range.
A simpler method is:
=LOOKUP(-B1,-C$3:C$8,A$3:A$8)
The negative signs are needed so that the lookup values are in ascending order.