Excel Vlookup calculating marks with age range and pushup result - excel

I am testing my clients for pushups and other exercises.
I want to make excel table where I can put client name, age, number of reps
and to make some formula that can put the new column with given mark. According to
table of ranges.
Table of problem


Use INDEX/MATCH:
As stated, change your Age and number of pushups to just the minimums; 20,30,40,50. And change the order from lowest mark to highest.
And do not skip any lines.
=INDEX($A:$A,MATCH($D11,INDEX($A:$F,0,MATCH($C11,$1:$1))))


Reformat your values, just write your minimum values in the cells (e.g. 20 instead of 20-29) and turn the table around so that 1 is on top and 5 is at the bottom. Then you can use the following formula:
=Indirect(Address(Match(val, Indirect(Address(4, Match(age, A2:F2, 1)) & ":"
& Address(8, Match(age, A2:F2, 1))), 1) + 3, 1))
Quite some formula actually ;) What it does:
Match(age, A2:F2, 1)
returns the column in which the user is to be sorted.
The inner Indirect creates a matrix with that column (e.g. if age is 25, this returns B4:B8).
The outter Match searches the value within this matrix and returns the corresponding row.
With that row and the fixed first column you can get your desired mark.


I wrote this one
=INDEX($A:$A,MATCH($D$11:$D$17,INDEX($A:$F,0,MATCH($C​$11:$C$17,1:1))))
table2


Just one more thing,
if I want to be able to keep formula open for more people...formula remain the same,just to change D number and C number?
table3

Related

Function to search for specific number and then to further search for the prefix

I have a huge amount of data to process in which 4 points with a related prefix needs to be subtracted from each other.
Data consists of ID and x value
Example
ID = 290.12, 290.03, 290.06, 290.09, 300.12, 300.03, 300.06, 300.09, 301.12, 301.03, 301.06, 301.09
(let's call prefix a "ring number" and suffix time on the clock)
X value = any numerical value for each ID assigned
What I'm hoping to do is to search for the first number before the dot i.e. 300 and then subtract the value of 300.06-300.12 in one cell and in another cell 300.03-300.09.
(The subtraction is just an example, how I need to manipulate with the numbers is slightly more complicated, but I got this one under control)
This is my actual Data and what I need to produce is to the right of the raw data. At the moment, I'm doing it manually for each set of "rings"
Anyone knows how to approach this? I'm thinking vlookup, but I'm not very proficient in excel.
New Excel
I tried vlookup, but I don't know how to construct the formula and I run out of ideas.

Edit:
I found out that REDUCE is no requirement in this case, so it can be shortened to:
=SQRT(SUM(((INDEX(B:D,XMATCH(I3+0.09,A:A),SEQUENCE(1,3))-INDEX(B:D,XMATCH(I3+0.03,A:A),SEQUENCE(1,3)))^2)))
You could change +0.09 and +0.03 to your needs and may reference them using LET() for easy maintaining:
=LET(id,I3,
_id1,0.09,
_id2,0.03,
SQRT(SUM(((INDEX(B:D,XMATCH(id+_id1,A:A),SEQUENCE(1,3))-INDEX(B:D,XMATCH(id+_id2,A:A),SEQUENCE(1,3)))^2))))
Previous answer:
=LET(
id,I3,
_id1,0.09,
_id2,0.03,
SQRT(
REDUCE(0, SEQUENCE(1,3),
LAMBDA(x, y,
x+((INDEX(B:D,XMATCH(id+_id1,A:A),y)
-INDEX(B:D,XMATCH(id+_id2,A:A),y))
^2)))))
This formula looks for the matching value of the id value I3 + _id1 minus the matching value of id value + _id2 for columns B to D and adds the ^2 results per column. Then it calculates it's square root.
You can change _id1 and _id2 to your needs.
To calculate the Delta (as shown) at once you could use:
=LET(id,I3,
_id1,0.09,
_id2,0.03,
_id3,0.12,
_id4,0.06,
x,SQRT(SUM((INDEX(B:D,XMATCH(id+_id1,A:A),SEQUENCE(1,3))-INDEX(B:D,XMATCH(id+_id2,A:A),SEQUENCE(1,3)))^2)),
y,SQRT(SUM((INDEX(B:D,XMATCH(id+_id3,A:A),SEQUENCE(1,3))-INDEX(B:D,XMATCH(id+_id4,A:A),SEQUENCE(1,3)))^2)),
(x-y)*1000)
You can have a column of unique values of the integers and a new column where you reference these values as id and drag down the formula to get your row by row result
In another column you can refer to these columns and sort per the second column using SORTBY()

Reference cells with no gaps to fill table with gaps

I have included 2 tables below to illustrate my problem.
Table 1
Table 2
I am trying to find a formula that fills rows 140, 143 & 146 (Table 2) from rows 15,16 & 17 (Table 1). There is over 100 so it is quite time consuming to input =B15 etc over and over again.
The offset method e.g. =OFFSET($B$15,(ROW()-1)*3,0) only works when I'm referencing gaps, not trying to fill them.
Essentially, where B140's formula is =B15, B143's will be =B140 + 1 row i.e. B16
Thanks for your help!

If you are trying find value for appropriate month you can use INDEX/MATCH entered as array formula:
=IFERROR(INDEX($B$1:$B$4,MATCH(TRUE,MONTH(A10)=MONTH($A$1:$A$4),0)),"")
Array formula after editing is confirmed by pressing ctrl + shift + enter
Edit
To find by month & year use:
=IFERROR(INDEX($B$1:$B$4,MATCH(1,(MONTH(A10)=MONTH($A$1:$A$4))*(YEAR(A10)=YEAR($A$1:$A$4)),0)),"")
it's also array formula

You can use modulo for this. With the Modulo function, you check if the remainder of the row you're on is divisible by a number (e.g. 3 if you want to copy a value every third row). IF(MOD(ROW(E1);3 = 0)
If that's the case, you can divide by 3 and use for example the Index function to copy the nth value of another location (or another worksheet). If that's not the case, you print "" to get an empty row.
=IF(MOD(ROW(E1);3)=0;INDEX($B$1:$B$4;ROW(E1)/3);"")
If you're working with offsets because the row numbers are not on numbers divisible by three, you could manually offset the rows (and do the same for the division that yields the index row). For example, if you want to have rows 2, 5, 8 etc:
=IF(MOD(ROW(E1)+1;3)=0;INDEX($B$1:$B$4;ROW(E2)+1/3);"")

Three Dimensional Lookup Using INDEX/MATCH

This was taken and improved slightly from Question that has since been deleted
For those who can see deleted posts, it was taken from here: https://stackoverflow.com/questions/39793322/three-dimensional-lookup-no-concatenate-or-named-ranges-excel
I'm trying to do a three dimensional lookup without named ranges or concatenates. Simplified, my data is on the form:
Column1 Column2 Column3
Scott
P 1 2 3
M 4 5 6
N 7 8 9
George
P 10 11 12
M 13 14 15
N 16 17 18
I now want to search for a specific Name and then for a specific letter within that names table, I then want to match this row number with a specific column.
I tried a simple INDEX/MATCH:
=INDEX(A:D,MATCH("M",A:A,0),MATCH("Column1",1:1,0))
And that works for the fist name but not any others as it finds the first instance of M.
How do I modify it to look for a different name?
I have answered below, but want to see if someone has a better solution.

I used an IF() statement array formula to find what the P row number was after the George row... I also needed to use the MIN() function to get the first P row number after the name.
Beyond that, it's a simple INDEX() function.... that racked my brain for over an hour :).
=INDEX($A$1:$D$9,MIN(IF((ROW(A1:A9)>MATCH($F$4,A1:A9,0))*(A1:A9=$F$5),ROW(A1:A9),"")),MATCH($F$6,$A$1:$D$1,0))
Don't Forget!
Use Ctrl+Shift+Enter when finishing the formula, so it gets evaluated as an array formula.

You can use two other INDEX/MATCH's inside the first MATCH to set the lookup range. Then you simply need to add the MATCH() to find the absolute position of the name.
=INDEX(A:D,MATCH($H$4,INDEX(A:A,MATCH($H$3,A:A,0)):INDEX(A:A,MATCH($H$3,A:A,0)+4),0)+MATCH($H$3,A:A,0)-1,MATCH($H$5,$1:$1,0))
This one works better and does not have a size constraint:
=INDEX(A:D,MATCH(F4,INDEX(A:A,MATCH(F3,A:A,0)):A1040000,0)+MATCH(F3,A:A,0)-1,MATCH(F5,A1:D1,0))

You can do this just by adding the results of two matches together. One match for the names plus one match for the letter equals the total row.
=INDEX(A:D,MATCH(G5,A3:A5,0)+MATCH(G3,A:A,0),MATCH(G4,1:1,0))
In other words: Index(All of the Data, Match(Name, In name column, exact) + Match(Letter, In letter column, exact), Match(Column name, in Column row, exact)
Screen capture of working sheet

My answer attempts the general case with only one caveat:
That a letter is single character text, and a name is more than 1 character. Otherwise i feel there is no difference logically between letters and names, and it is then impossible to really do...
RE-EDIT for better function construction:
{=INDEX($A$1:$D$17, MATCH($H$3,$A1:$A17, 0)+MATCH($H$4, INDEX($A1:$A17, MATCH($H$3,$A1:$A17, 0)):INDEX($A:$A, SMALL(IFERROR(MATCH($H$3,$A1:$A17, 0)+POWER(SQRT(IF(LEN($A$1:$A$17)>1, ROW($A$1:$A$17), 0)-MATCH($H$3,$A$1:$A$17, 0)), 2)-1, ROWS($A$1:$A$17)), 2)), 0)-1, MATCH($H$5, $A$1:$D$1, 0))}
This uses an array formula along column A, and checks if the length is > 1 and throws the row nums into an array, with letters given a 0.
Then match row of unique name(e.g. George) is subtracted from each.
We then use a min(of all other name rows, with the last data row as the final default - SMALL function with 2 parameter) to find the next name row(or last data row if there is no following name).
Rest is standard index/match etc.
It will correctly return #N/A if there is no such letter under the chosen name...
My dataset is A1:A17, and the formula could use A:A instead each time, but the array calc inside the IF needs the A1:A17 for speed.
EDIT for better function construction:
If we wanted to avoid editing the formula when the data length changes, then we could let full column references of A:A go through the entire construction(and lose speed/efficiency) with the last data row in colA calculated via ROWS(A:A):
Re-edit:
{=INDEX($A:$D, MATCH($H$3,$A:$A, 0)+MATCH($H$4, INDEX($A:$A, MATCH($H$3,$A:$A, 0)):INDEX($A:$A, SMALL(IFERROR(MATCH($H$3,$A:$A, 0)+POWER(SQRT(IF(LEN($A:$A)>1, ROW($A:$A), 0)-MATCH($H$3,$A:$A, 0)), 2)-1, ROWS($A:$A)), 2)), 0)-1, MATCH($H$5,1:1, 0))}
It really depends on the setup...
Edit again for version which takes blanks as separators for names
If you want to use blanks as the separator for names, where no blanks are in the data results, but blanks appear in columns B to D where there is a name, then a tiny change in the above formulae will result in this:
=INDEX($A$1:$D$17, MATCH($H$3,$A$1:$A$17, 0)+MATCH($H$4, INDEX($A:$A, MATCH($H$3,$A:$A, 0)):INDEX($A:$A, SMALL(IFERROR(MATCH($H$3,$A:$A, 0)+POWER(SQRT(IF($B$1:$B$17="", ROW($A$1:$A$17), 0)-MATCH($H$3,$A$1:$A$17, 0)), 2)-1, ROWS($A$1:$A$17)), 2)), 0)-1, MATCH($H$5, $A$1:$D$1, 0))
This means that the names and letters do not have to be any specified length, but just one proviso is that blanks appear in the row with the name.
A small amendment to the condition to find the end range to search for the letter by replacing this: SQRT(IF(LEN($A$1:$A$17)>1, with this:
SQRT(IF($B$1:$B$17="",

I would use the area (4th parameter) of Index(). Below is a screenshot of test data. This example assumes the same columns and keys are sorted and consistent.
This works by using (Range1,Range2) as the first parameter of index. For the 4th parameter of index, use N for which area in the () you want Index to return.

I think this may be slightly tidier, and a little easier to modify maybe.
=INDEX(OFFSET(INDIRECT("A"&MATCH($H$3,$A:$A,0),TRUE),0,0,4,4),MATCH($H$4,$A:$A,0),MATCH(H5,$1:$1,0))
Using offset to create the range first, we're able to use the name from H3 to set that up, and then beyond that we are just indexing within that new range.
Now this is still dependendent on staying in Column A for the names.

Assuming the format of the data is always Name then P, M and N this formula does the work:
=INDEX($A:$D,
MATCH($H$3,$A:$A,0)
+LOOKUP($H$4,{"P",1;"M",2;"N",3}),
MATCH($H$5,$1:$1,0))

This solution works on almost all conditions. One restriction I found is when one of the subjects (Names) does no have data for any of the details (letters), but as of now the same occurs with all the other answers.
The formula assumes the data is located at B6:F30 (in order to ensure it can be applied regardless of the source range location).
The formula uses the Index\Match functions:
First, a MATCH to retrieve the position of the Name:
MATCH($H8,$B$6:$B$30,0)
With that info it uses INDEX to build a range that is used to obtain the position of the Detail (letter) using a second MATCH Function:
+ MATCH($I8,INDEX($B$6:$B$30, 1 + MATCH($H8,$B$6:$B$30,0))
:INDEX($B$6:$B$30,ROWS($B$6:$B$30)),0),
Adding the results of the first and second MATCH functions obtains the position of the Name`Detail` combination and uses it in an Index to the entire data. The position of the Data Column required is obtained with a Match:
INDEX($B$6:$F$30, 1st.MATCH + 2nd.MATCH,
MATCH(J$6,$B$6:$F$6,0))
With the results located at G6:L30 enter this formula in J8 then copy to J8:L30:
= INDEX( $B$6:$F$30,
MATCH( $H8, $B$6:$B$30, 0)
+MATCH( $I8, INDEX( $B$6:$B$30 , 1 + MATCH( $H8, $B$6:$B$30 ,0))
: INDEX( $B$6:$B$30, ROWS($B$6:$B$30) ),0),
MATCH( J$6, $B$6:$F$6, 0)),"")

This solution works in all conditions discussed so far (let me know of any condition that it does not work and I’ll try to cover it).
I’m posting this as a separated answer as the formulas applied in prior answer rightly apply to the conditions stated in them, as such they will be useful to users with those specific scenarios, so they don’t need to apply these long formulas.
This formula assumes the data is located at B6:E30 (in order to ensure it can be applied regardless of the source range location).
This formula uses the Index\Match functions and it’s a Formula Array.
FormulaArrays are entered pressing [Ctrl] + [Shift] + [Enter] simultaneously, you shall see { and } around the formula if entered correctly
Syntax:
=IFERROR(INDEX(DataRng,
MATCH(Value1,NamesRng,0)
+IFERROR(MATCH(Value2,INDEX(NamesRng,
1+MATCH(Value1,NamesRng,0))
:INDEX(NamesRng, IFERROR(MATCH(Value1,NamesRng,0)
+MATCH("#",IF((INDEX(Col1Rng,1+MATCH(Value1,NamesRng,0))
:INDEX(Col1Rng,ROWS(NamesRng)))="","#","!"),0),
ROWS(NamesRng))),0),NA()),MATCH(ValCol,DataHdr,0)),"")
Arguments:
Assuming the data is located at B6:E30.
Value1= Name to be found in Data, i.e. George, Scott, etc.
Value2= Detail to be found in Data, i.e. Detail1, Detalle2, etc.
ValCol = Column to be found in Data i.e. Column1, Column2, etc.
DataRng= $B$6:$E$30
DataHdr= $B$6:$E$6
NamesRng= $B$6:$B$30
Col1Rng= $C$6:$C$30
1st MATCH: Retrieves the position of the Name:
MATCH(Value1,NamesRng,0)
2nd MATCH: Retrieves the end position of the Name’s corresponding Details, which is determined by a blank value in column C or the end of the data range:
MATCH("#",IF((INDEX(Col1Rng, 1 + 1stMATCH)
:INDEX(Col1Rng,ROWS(NamesRng)))="","#","!"),0),
Builds a Range (vRange): With the Names's Details using the 1st and 2nd match functions. If 2nd Match returns an error then it uses the last row of the Data range:
INDEX(NamesRng, 1 + 1stMATCH )
:INDEX(NamesRng, IFERROR( 1stMATCH + 2ndMATCH, ROWS(NamesRng)))
3rd MATCH: Retrieves the position of the Detail within the vRange. It returns #NA if the combination is not present.
IFERROR(MATCH(Value2, vRange,0), NA())
Adding the results of the 1st and 3rd match functions obtains the Row index of the Name`Detailcombination or#NAif no found.
The Column index is obtained with a Match from the Header of the Data.
It then applying the INDEX function to the Data Range returns the value of theName\Detail\Columncombination.
If theName\Detail` combination is not found it returns blank.
=IFERROR( INDEX( DataRng, 1stMATCH + 3rdMATCH, MATCH(Column,DataHdr,0)),"")
With the results located at H6:L37 enter this Formula Array in J8 then copy to K8:L37 and to J9:L37:
=IFERROR( INDEX($B$6:$E$30,
MATCH($H8,$B$6:$B$30,0)
+IFERROR( MATCH($I8, INDEX($B$6:$B$30,
1+MATCH($H8,$B$6:$B$30,0))
:INDEX($B$6:$B$30, IFERROR(MATCH($H8,$B$6:$B$30,0)
+MATCH("#", IF((INDEX($C$6:$C$30,1+MATCH($H8,$B$6:$B$30,0))
:INDEX($C$6:$C$30,ROWS($B$6:$B$30)))="","#","!"),0),
ROWS($B$6:$B$30))),0),NA()),
MATCH(J$6,$B$6:$E$6,0)), "")

Wow... So many solutions already.
I think a simpler solution could be using offset to get a more generic answer.
=INDEX($A$1:$D$9, MATCH($G$3,OFFSET($A$1,MATCH($G$2,$A$1:$A$9,0),0,3,1),0)+MATCH($G$2,$A$1:$A$9,0), MATCH($G$4,$B$1:$D$1,0)+1)
The only variable to look for is 3 which is the number of M/N/P options present because that will affect the number of rows. Otherwise, the solution works fine in all possible scenarios and different orders.

When I have more than two inpunts for a data search I prefer to have the data organized as shown in the figure, so that I can use a pivot table and get it to organize the data in rows and columns as I like.
Then I use GETPIVOTDATA to search for a value.
Cell G9 contains this formula:
=GETPIVOTDATA("Value";$F$3;"Name";G15;"Letter";G16;"Column";G17)

Sort Order formula to alphabetise in Excel

I am currently drawing up a spreadsheet that will automatically remove duplicates and alphabetize a list:
I am using the COUNTIF() function in column G to create a sort order and then VLOOKUP() to find the sort in column J.
The problem I am having is that I can't seem to get my SortOrder column to function properly. At the moment it creates an index for two number 1's meaning the cell highlighted in yellow is missed out and the last entry in the sorted list is null:
If anyone can find and rectify this mistake for me I'll be very grateful as it has been driving me insane all day! Many thanks.

I'll provide my usual method for doing an automatic pulling-in of raw data into a sorted, duplicate-removed list:
Assume raw data is in column A. In column B, use this formula to increase the counter each time the row shows a non-duplicate item in column A. Hardcord B2 to be "1", and use this formula in B3 and drag down.
=if(iserror(match(A3,$A$2:A2,0)),B2+1,B2)
This takes advantage of the fact that when we refer to this row counter in our revised list, we will use the match function, which only checks for the first matching number. Then say you want your new list of data on column D (usually I do this for display purposes, so either 'group-out' [hide] columns that form the formulas, or do this on another tab). You can avoid this step, but if you are already using helper columns I usually do each step in a different column - easier to document. In column C, starting in C3 [C2 hardcoded to 1] and drag down, just have a simple counter, which error-checks to the stop at the end of your list:
=if(C2<max(B:B),C2+1," ")
Then in column D, starting at D2 and dragged down:
=iferror(index(A:A,match(C2,B:B,0)),"")
The index function is like half of the vlookup function - it pulls the result out of a given array, when you provide it with a row number. The match function is like the other half of the vlookup function - it provides you with the row number where an item appears in a given array.
Hope this helps you in the future as well.

The actual reason that this is going wrong as implied by Jeeped's comment is that you can't meaningfully compare a string to a number unless you do a conversion because they are stored differently. So COUNTIF counts numbers and text separately.
20212 will give a count of 1 because it is the only (or lowest) number.
CS10Z002 will give a count of 1 because it is the first text string in alphabetical order.
Another approach is to add the count of numbers to the count if the current cell contains text:-
=COUNTIF(INDIRECT("$D$2:$D$"&$F$3),"<="&D2)+ISTEXT(D2)*COUNT(INDIRECT("$D$2:$D$"&$F$3))
It's easier to show the result of three different conversions with some test data:-
(0) No conversion - just use COUNTIF
=COUNTIF(D$2:D$7,"<="&D2)
"999"<"abc"<"def", 999<1000
(1) Count everything as text
=SUMPRODUCT(--(D$2:D$7&""<=D2&""))
"1000"<"999"
(2) Count numbers before text
=COUNTIF(D$2:D$7,"<="&D2)+ISTEXT(D2)*COUNT(D$2:D$7)
999<1000<"999"
(3) Count everything as text but convert numbers with leading zeroes
=SUMPRODUCT(--(TEXT(D$2:D$7,"000000")<=TEXT(D2,"000000")))
"000999" = "000999", "000999"<"001000"

EXCEL Formulas Sum Everything above specific row

I want to SUM everything above a cell that contains the word "SUMTOTAL". So if I have 50 columns I want it to go to first row that has the text "SUMTOTAL" in it and then Sum everything aboce that word. Is it possible?

Use a MATCH formula to find the row and minus one from it then use an INDIRECT formula to put together a string of the address then plop it into a sum formula like this:
=SUM(INDIRECT("A1:A" & MATCH("SUMTOTAL",B:B,0)-1))
Assumption:
SUMTOTAL is in column B somewhere
The numbers you want to sum are in column A
Your data starts at row 1.
You are summing ONE column. To expand simply change "A1:A" to "A1:X" if you wanted to sum columns A to X

I assume that all your data is located in A1:N20, and SUMTOTAL appears somewhere inside this area (you can easily change the desired data location). The following formula does the summation of all numbers directly above SUMTOTAL, i.e., in the same column.
=SUM(OFFSET($A$1,0,SUMPRODUCT(COLUMN($A$1:$N$20)*($A$1:$N$20="SUMTOTAL"))-1,SUMPRODUCT(ROW($A$1:$N$20)*($A$1:$N$20="SUMTOTAL"))-1))
If you want to sum all numbers above SUMTOTAL, no matter if in the same column or not, use
=SUM(OFFSET($A$1,0,0,SUMPRODUCT(ROW($A$1:$N$20)*($A$1:$N$20="SUMTOTAL"))-1,COLUMNS($A$1:$N$20)))

=SUM(INDIRECT(ADDRESS(1,COLUMN())&":"&ADDRESS(ROW()-1,COLUMN())))

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