I have an Excel Sheet from a work logging software that contains a column
with dates, a second one with Tasks and a third one with a name.
Basically I see that "John" worked 3 hours on task A, and 5 hours on task B on a given day.
If there were many short tasks on a certain day, there might be 8 line items for "John" that day.
There are also 100 different workers on this sheet.
-> 30 Days * 5 tasks * 100 Workers is about 15000 lines per month.
My desire is to see how many days a worker was working at all in a given month"
"Find unique dates for worker X and sum them up"
I can use
=SUMPRODUCT(1/COUNTIF(A2:A7000,A2:A7000&""))
to find unique days in column A (By the way this seems to be limited to 7000 lines!!! 7001 will give "0" as the result although cells A7000 and A7001 have an identical date.
But now I only want to count the date if worker A is in column B...
=SUMPRODUCT(1/(COUNTIF(A2:A7000,A2:A7000&"")) * (A25:A7000 = "John"))
This seems to be syntactically correct but always returns "0"
Hhhmmm?
Any tips?
Thanks
Change it to an array formula:
=SUM(IF(B2:B7000 = "John",1/COUNTIFS(B2:B7000,"John",A2:A7000,A2:A7000)))
Being an array formula it must be confirmed with Ctrl-Shift-Enter instead of Enter when exiting edit mode. If done correctly then Excel will put {} around the formula.
If you want to use SUMPRODUCT then you need to change it a little:
=SUMPRODUCT(--(B2:B7000= "John"),1/COUNTIFS(B2:B7000,"John",A2:A7000,A2:A7000))
Sumproduct will ignore the errors when split with a comma.
Also, Both formulas where tested with up to 8000 and had no problems returning the correct answer.
Related
In assessing how many agents can be added to certain times of day without exceeding the number of seats in the call center, I'm trying to discern how many agents are scheduled for each half hour interval on each day of the week.
Using the =SUMPRODUCT(((A$2:A$1000<=D2)+(B$2:B$1000>D2)+(A$2:A$1000>B$2:B$1000)=2)+0) formula I've been able to identify how many total agents work for each interval, however this doesn't take the day of week into account.
I currently have my spreadsheet setup this way:
K is the start time of the shift, L is the end time of the shift, M to S pulls data from another sheet that shows a 1 if the agent works on that day of the week and 0 if they do not, and then U has all the time intervals listed out. In the example, it's cut off but the columns continue down as needed. U goes to 49 and I've just been using a range from 2 to 500 for the others as we currently do not have that many shifts and I'm leaving space for the moment.
After some Googling, I tried =SUMPRODUCT(--(M2:M500="1"),(((K$2:K$1000<=U2)+(L$2:L$1000>U2)+(K$2:K$1000>L$2:L$1000)=2)+0)) but it only returns #VALUE! so I'm not sure what I'm doing wrong.
Any suggestions of how I can make this work? Please let me know if more information would be useful. Thanks.
=sumproduct(($K$2:$K$1000<=U2)*($L$2:$L$1000>=U2))
That will count the number of occurrences where the start time is less than or equal to the time in U2 AND the end time is greater than or equal to U2. It will check time from row 2 to row 1000. Any time one condition is checked and its true the comparison will result in value of TRUE and FALSE when its not true. The * act like an AND condition while at the same time converts TRUE and FALSE values to 1 and 0. So both conditions have to be true for a value of 1 to result. Sumproduct then totals up all the 1 and 0 to get you a count.
In order to consider the days of the week, you will need one thing to be true. Your headers in M1:S1 will need to be unique (which I believe they are). You will need to either repeat them in adjacent columns to M or in say V1 you have a cell that can change to the header of the day of the week you are interested in. I would assume the former so you can see each day at the same time.
In order to do this you want to add more conditions and pay attention to you reference locks $.
In V2 you could use the following formula and copy down and to the right as needed:
=sumproduct(($K$2:$K$1000<=$U2)*($L$2:$L$1000>=$U2)*(M$2:M$1000))
UPDATE #1
ISSUE 1 Time ranges ending the following day (after midnight)
It is based on the assumption that the ending time is later than the start time. When a shift starts at 22:00 and end at 6:30 as an example, our mind says that the 0630 is later than 22:00 because it is the following day. Excel however has no clue that 0630 is the following day and without extra information assumes it to be the same day. In excel date is stored as an integer and time is stored as a decimal. When you only supply the time during entry it uses 0 for the date.
In excel the date is the number of days since 1900/01/00. So one way to deal with your time out is to add a day to it. This way excel will know your out time is after your in time when the hour is actually earlier in the day.
See your sample data below.
Using your sample data, I did a straight copy of the value in L and placed it in M (=L3 and copy down). I then changed the cell display format from time to general. This allows you to see how excel sees the time. Note how all the time is less than 1.
In column N I added 1 to the value when the out time was less than the in time to indicate that it was the following day and we had not actually invented time travel. I also used the trick of a math operation will convert a TRUE/FALSE result to 1 or 0 to shorten the equation. I used =M3+(L3<K3) and copied down. You will notice in the green bands that the values are now greater than 1.
In the next column I just copied the values from N over using =N3 copied down, and then I applied just a time display format for the cell. Because it is only time format, the date is ignored and visually your time in column O looks the same as column L. The big difference is excel now knows that it is the following day.
you can quickly fix your out times by using the following formula in a blank column and then copying the results and pasting them back over the source column using paste special values.
=M2+(L2<K2)
The next part is for your time check. When looking at the 12:00 time you need to look at 1200 of the current day incase a shift started at 12:00 and you need to look at the 1200 period of the following day. In order to do that we need to modify the the original formula as follows:
=sumproduct(($K$2:$K$1000<=$U2)*($L$2:$L$1000>=$U2)*(M$2:M$1000)+($K$2:$K$1000<=$U2+1)*($L$2:$L$1000>=$U2+1)*(M$2:M$1000))
Note that the + in the middle of (M$2:M$1000) + ($K$2:$K$1000<=$U2+1)? This + acts like an OR function.
Issue 2 Time In/Out 15 minute increments, range 30 minute increments
You may be able to achieve this with the ROUNDDOWN Function or MROUND. I would combine this with the TIME function. Basically you want to have any quarter hour start time be treated as 15 minutes sooner.
=ROUNDDOWN(E3/TIME(0,30,0),0)*TIME(0,30,0)
Where E3 is your time to be converted
So your formula may wind up looking something like:
=sumproduct((ROUNDDOWN($K$2:$K$1000/TIME(0,30,0),0)*TIME(0,30,0)<=$U2)*($L$2:$L$1000>=$U2)*(M$2:M$1000)+((ROUNDDOWN($K$2:$K$1000/TIME(0,30,0),0)*TIME(0,30,0)<=$U2+1)*($L$2:$L$1000>=$U2+1)*(M$2:M$1000))
similar option could be used for the leaving time and rounding it up to the next 30 minute interval. In which case just use the ROUNDUP function. Though I am not sure it is required.
I need to count the number of employee who work in a particular hour:
For ex: My shift is 11:00pm to 8:00am, and I'm looking for the number of employees who's working within 11:00pm to 12:00am. My current shift is within the provided time (1 hour). If I'm looking for 8:00am to 9:00am and my shift is not within the provided time, then no count for me.
The problem is the formula doesn't counting time that passes midnight.
I tried several formulas and converted it into VBA code, but I failed. Here's the formula that I recently converted to code:
=COUNTIFS(B$2:B$7,"<"&F9,C$2:C$7,">"&E9)
and
=SUMPRODUCT(--(B2:B7<F2),--(C2:C7>F1))
Any ideas?
My solution utilizes two formulas.
Your current problem is to tell if a worker who works (for example) between 10:00pm - 3:00am. In order to reduce the risk of confusing the system, I opted to use a 24 hour clock. To minimize the need for input such as a date in addition to the time, I created a table as such:
Each cell contains the formula =IF($H$3>C3,IF(IF(C3>D3,D3+24,D3)>$H$3,"X",""),""). The cells under "Active?" displays an "X" as long as the worker is currently on the clock.
The cell to check how many employees are on the clock, it runs a simple count if formula =COUNTIF(E3:E6,"X") to count how many instances of "x" in the Active column are present.
To operate, you simply extend the range for any additional workers and fill out the cells accordingly. Once the table is populated, you can verify who is working by typing in the desired time in H3. Hope this helps!
I have a time diary spreadsheet that was given to me to record times taken for staff to complete different activities. Column A is the start time, column B is the finish time, where column C is the difference, using the formula B3-A3.
In row 3, this gives me answer of 0:01. Is there a way to convert this to "1" using a formula?
i.e. 0:0X becomes X
or, 0:YX becomes YX?
Thanks
MINUTE() will convert the time to time in minutes.
I'm trying to perform an AVERAGEIFS formula on some data, but there are 2 possible results and as far as I can tell AVERAGEIFS doesn't deal with that situation.
I basically want to have an ELSE inside it.
At the moment I have 2 ranges of data:
The first column only contains values 'M-T' and 'F' (Mon-Thurs and Fri).
The second column contains a time.
The times on the rows with an 'F' value in column 1 are an hour behind the rest.
I want to take an average of all the times, adjusting for the hour delay on Fridays.
So for example I want it to take an average of all the times, but subtract 1 hour from the values which are in a row with an 'F' value in it.
The way I've been doing it so far is by having 2 separate results for each day, then averaging them again for a final one:
=AVERAGEIFS(G3:G172, B3:B172, "M-T")
=AVERAGEIFS(G3:G172, B3:B172, "F")
I want to combine this into just one result.
The closest I can get is the following:
=AVERAGE(IF(B3:B172="M-T",G3:G172,((G3:G172)-1/24)))
But this doesn't produce the correct result.
Any advice?
Try this
=(SUMPRODUCT(G3:G172)-(COUNTIF(B3:B172,"=F")/24))/COUNTIF(B3:B172,"<>""""")
EDIT
Explaining various steps in the formula as per sample data in the snapshot.
SUMPRODUCT(G3:G17) sums up all the value from G3 to G17. It gives a
value of 4.635416667. This after formatting to [h]:mm gives a value
of 111.15
OP desires that Friday time be one hour less. So I have kept one hour less for Friday's in the sample data. Similar SUMPRODUCT on H3:H17 leads to a value of 4.510416667. This after formatting to [h]:mm gives a value
of 108.15. Which is exactly three hours less for three occurrences of Fridays in the sample data.
=COUNTIF(B3:B17,"=F") counts the occurrences of Friday's in the B3:B17 range which are 3 occurrences.Hence 3 hours have to less. These hours are to be represented in terms of 24 hours hence the Function COUNTIF() value is divided by 24. This gives 0.125. Same is the difference of 4.635416667 and 4.510416667 i.e. 0.125
Demonstration column H is for illustrative purposes only. Infact Friday accounted values that is 108.15 in sample data has to be divided by total data points to get the AVERAGE. The occurrences of data points are calculated by =COUNTIF(B3:B17,"<>""""") with a check for empty columns.
Thus 108:15 divided by 15 data points give 7:13 in the answer.
Revised EDIT Based upon suggestions by #Tom Sharpe
#TomSharpe has been kind enough to point the shortcomings in the method proposed by me. COUNTIF(B3:B172,"<>""""") gives too many values and is not advised. Instead of it COUNTA(B3:B172) or COUNT(G3:G172) are preferable. Better Formula to get AVERAGE as per his suggestion gives very accurate results and is revised to:
=AVERAGE(IF(B3:B172="M-T",G3:G172,((G3:G172)-1/24)))
This is an Array Formula. It has to be entered with CSE and further cell to be formatted as time.
If your column of M-T and F is named Day and your column of times is named TIME then:
=SUMPRODUCT(((Day="M-T")*TIME + (Day="F")*(TIME-1/24)))/COUNT(TIME)
One simple solution would be to create a separate column that maps the time column and performs the adjustment there. Then average this new column.
Is that an option?
Ended up just combining the two averageifs. No idea why I didn't just do that from the start:
=((AVERAGEIFS(G$3:G171, $B$3:$B171, "F")-1/24)+AVERAGEIFS(G$3:G171, $B$3:$B171, "M-T"))/2
I have to determine per specialty the total percentage of surgeries that started outside the regular working hours or in weekends.
This is what I have so far:
=COUNTIFS(Table1[Start surgery];">17:00")+COUNTIFS(Table1[Start surgery];"<09:00")+COUNTIFS(Table1[Surgery date];"MOD(WEEKDAY(cell), 7) <2")
The first 2 countifs work, but I'm not able to count the weekend days. And a second thing is that its possible for excel to count some surgeries twice, because a surgery can be after 17:00 and in the weekend, but that has to count as one.
Who can help me:)?
Since the first part of your formula is working for time I just modified the last part of your formula...
=COUNTIFS(Table1[Start surgery];">17:00")+COUNTIFS(Table1[Start surgery];"<09:00")+SUMPRODUCT((WEEKDAY(Table1[Surgery date])=1)+(WEEKDAY(Table1[Surgery date])=7)
Where 1 and 7 are equivalent to Saturday and Sunday.
The current problem with the formula above is that surgery time after 1700 and before 0900 on the weekend are counted twice!
To rectify this all conditions could be moved inside the sumproduct as one potential solution and you would wind up with:
=SUMPRODUCT((WEEKDAY(Table1[Surgery Date])=1)+(WEEKDAY(Table1[Surgery Date])=7)+(WEEKDAY(Table1[Surgery Date])=MEDIAN(WEEKDAY(Table1[Surgery Date]),2,6))*(Table1[Start surgery]<"09:00")+(WEEKDAY(Table1[Surgery Date])=MEDIAN(WEEKDAY(Table1[Surgery Date]),2,6))*(Table1[Start surgery]>"17:00"))
Now the bracket count may be off in there as I was not using excel at the time. The other potential issue we may have is with time. is your time n the time column text or a number formatted to display as time? This may involve modifying are time comparison to a different format, but the formula itself should remain the same.
Basic think here is we put each condition inside the sumproduct. The condition will evaluate to either TRUE or FALSE. If the condition undergoes a math operation it will be turned into 1 for TRUE and 0 for FALSE. + act like OR statements, and * act like AND statement.