Hello all I got stuck somewhere, I am working on mongodb with node.js where my collection data deleted automatically after 1 year on certain date and I want to stop that permanently how can I do that ? I have checked the available material on google but didn't got much success please help me friends ...
I have checked the index in one of my collection and it is showing data like this . Can you please tell me its is having TTL index or not
[
{
"v" : 1,
"key" : {
"_id" : 1
},
"name" : "_id_",
"ns" : "firstfive.teachers"
},
{
"v" : 1,
"key" : {
"_fts" : "text",
"_ftsx" : 1
},
"name" : "firstname_lastname_text",
"weights" : {
"firstName" : 1,
"lastName" : 1
},
"default_language" : "english",
"language_override" : "language",
"ns" : "firstfive.teachers",
"textIndexVersion" : 2
}
]
most likely you have TTL (time to limit) index defined on collection you're working with (https://docs.mongodb.com/v3.2/core/index-ttl/)
yu can check it by running db.your_collection.getIndexes() (it will be one with expireAfterSeconds) in mongo shell.
as any other index it can be removed - but do it carefully, apparently someone did it deliberately
Related
I have this collection in MongoDB:
{
"_id" : ObjectId("5df013b10a88910018267a89"),
"StockNo" : "33598",
"Description" : "some description",
"detections" : [
{
"lastDetectedOn" : ISODate("2020-01-29T04:36:41.191+0000"),
"lastDetectedBy" : "comp-t",
"_id" : ObjectId("5e3135f68c9e930017de8aec")
},
{
"lastDetectedOn" : ISODate("2019-12-21T18:12:06.571+0000"),
"lastDetectedBy" : "comp-n",
"_id" : ObjectId("5e3135f68c9e930017de8ae9")
},
{
"lastDetectedOn" : ISODate("2020-01-29T07:36:06.910+0000"),
"lastDetectedBy" : "comp-a",
"_id" : ObjectId("5e3135f68c9e930017de8ae7")
}
],
"createdAt" : ISODate("2019-12-10T21:52:49.788+0000"),
"updatedAt" : ISODate("2020-01-29T07:36:22.950+0000"),
"__v" : NumberInt(0)
}
I want to search by StockNo and get the name of the computer that last detected it (lastDetectedBy) only if lastDetectedOn was in the last 5 minutes with Mongoose in node.js with Express.
I also have this collection:
{
"_id" : ObjectId("5df113b10d35670018267a89"),
"InvoiceNo" : "1",
"InvoiceDate" : ISODate("2020-01-14T02:18:11.196+0000"),
"InvoiceContact : "",
"isActive" : true
},
{
"_id" : ObjectId("5df013c90a88910018267a8a"),
"InvoiceNo" : "2",
"InvoiceDate" : ISODate("2020-01-14T02:18:44.279+0000"),
"InvoiceContact : "Bob Smith",
"isActive" : true
},
{
"_id" : ObjectId("5e3096bb8c9e930017dc6e20"),
"InvoiceNo" : "3",
"InvoiceDate" : ISODate("2020-01-14T02:19:50.155+0000"),
"InvoiceContact : "",
"isActive" : true
}
And I want to update all the documents with empty InvoiceContact which has been issued in the last 30 seconds (or any date range between now and sometime in the past) with isActive equals true to isActive equals false. So for example, the first record has been issued in the last 30 seconds without InvoiceContact and isActive is true so this must be updated but the next two records will remain untouched for different reasons, the second record has InvoiceContact and the third record is out of range.
First Part
var mins5 = new Date(ISODate() - 1000* 60 * 5 )
db.getCollection('user').find({$and:[
{ "StockNo":"33598"},
{"detections.lastDetectedOn" : { $gte : mins5 }}
]})
.map(function(list){
var results = [];
list.detections.forEach(function (detections){
if(detections.lastDetectedOn > mins5){
results.push(detections.lastDetectedBy);
}
})
return results;
});
Second Part could be solved by a similar query using update instead of find.
I have to delete the second comment using index value.. Following is my document structure
{
"_id" : ObjectId("000000000fea5f24282e715b"),
"file_name" : "resume_of_ganga_.docx",
"created_date" : ISODate("2017-11-28T10:29:10.373Z"),
"updated_date" : ISODate("2017-11-28T12:39:32.148Z"),
"comments" : [
{
"created_date" : ISODate("2017-11-28T13:23:51.472Z"),
"status" : "N",
"comment_text" : "Yes...",
"username" : "name"
},
{
"created_date" : ISODate("2017-11-28T13:24:15.938Z"),
"status" : "N",
"comment_text" : "asdsd",
"username" : "name"
}
]
}
I have using this following mongoose query..But my comments are not get deleting
mongo.filemanager.findOneAndUpdate({ "_id": req.body.id},{$pull : {"'comments.' +req.body.c_index" : 1 }},function(err,response){
console.log("Deleted")
});
For example am getting index value as 2.. It should delete the second comment...
Thanks in Advance
I tried looking up to see if MongoDB has any such functionality but seems like they don't from what I found.
A workaround could be something like this. Not sure if this can be considered an atomic operation.
const removeCommentAtIndex = (index) => {
mongo.filemanager.findById(req.body.id, (err, file) => {
file.comments.splice(index, 1);
file.save();
})
}
I executed the accepted answer for In mongoDb, how do you remove an array element by its index in my test database and IT WORKS
mongo.filemanager.findOneAndUpdate({}, {"$unset" : {"comments.1" : 1 }})
mongo.filemanager.findOneAndUpdate({}, {"$pull" : {"comments" : null}})
Note that your req.body.c_index needs to be 1 to remove 2nd comment.
This question already has answers here:
MongoDB Query Help - query on values of any key in a sub-object
(3 answers)
Closed 6 years ago.
This is my data set, which is part of a bigger json code. I want to write a query, which will match all fields inside the value chain.
Dataset:
"value_chain" : {
"category" : "Source, Make & Deliver",
"hpe_level0" : "gift Chain Planning",
"hpe_level1" : "nodemand to Plan",
"hpe_level2" : "nodemand Planning",
"hpe_level3" : "nodemand Sensing"
},
Example:
If someone searches for "gift", the query should scan through all fields, and if there is a match, return the document.
This is something I tried, but didnt work
db.sw_api.find({
value_chain: { $elemMatch: { "Source, Make & Deliver" } }
})
Sounds like you need to create $text index on all the text fields first since it performs a text search on the content of the fields indexed with a text index:
db.sw_api.createIndex({
"value_chain.category" : "text",
"value_chain.hpe_level0" : "text",
"value_chain.hpe_level1" : "text",
"value_chain.hpe_level2" : "text",
"value_chain.hpe_level3" : "text"
}, { "name": "value_chain_text_idx"});
The index you create is a composite index consisting of 5 columns, and mongo will automatically create the text namespace for you by default if you don't override it. With the above, if you don't specify the index name as
db.sw_api.createIndex({
"value_chain.category" : "text",
"value_chain.hpe_level0" : "text",
"value_chain.hpe_level1" : "text",
"value_chain.hpe_level2" : "text",
"value_chain.hpe_level3" : "text"
});
there is a potential error "ns name is too long (127 byte max)" since the text index will look like this:
"you_db_name.sw_api.$value_chain.category_text_value_chain.hpe_level0_text_value_chain.hpe_level1_text_value_chain.hpe_level2_text_value_chain.hpe_level3_text"
Hence the need to give it a name which is not too long if autogenerated by mongo.
Once the index is created, a db.sw_api.getIndexes() query will show you the indexes present:
/* 1 */
[
{
"v" : 1,
"key" : {
"_id" : 1
},
"name" : "_id_",
"ns" : "dbname.sw_api"
},
{
"v" : 1,
"key" : {
"_fts" : "text",
"_ftsx" : 1
},
"name" : "value_chain_text_idx",
"ns" : "dbname.sw_api",
"weights" : {
"value_chain.category" : 1,
"value_chain.hpe_level0" : 1,
"value_chain.hpe_level1" : 1,
"value_chain.hpe_level2" : 1,
"value_chain.hpe_level3" : 1
},
"default_language" : "english",
"language_override" : "language",
"textIndexVersion" : 3
}
]
Once you create the index, you can then do a $text search:
db.sw_api.find({ "$text": { "$search": "gift" } })
I am trying to remove the lowest homework score.
I tried this,
var a = db.students.find({"scores.type":"homework"}, {"scores.$":1}).sort({"scores.score":1})
but how can I remove this set of data?
I have 200 pieces of similar data below.
{
"_id" : 148,
"name" : "Carli Belvins",
"scores" : [
{
"type" : "exam",
"score" : 84.4361816750119
},
{
"type" : "quiz",
"score" : 1.702113040528119
},
{
"type" : "homework",
"score" : 22.47397850465176
},
{
"type" : "homework",
"score" : 88.48032660881387
}
]
}
you are trying to remove an element but the statement you provided is just to find it.
Use db.students.remove(<query>) instead. Full documentation here
I have a structure like this:
{
"_id" : ObjectId("501abaa341021dc3a1d0c70c"),
"name" : "prova",
"idDj" : "1",
"list" : [
{
"id" : 1,
"votes" : 2
},
{
"id" : 2,
"votes" : 4
}
]
}
And I'm trying to increase votes with this query:
session_collection.update(
{'_id':session_collection.db.bson_serializer.ObjectID.createFromHexString(idSession),'list.id':idSong},
{$inc:{'list.$.votes':1}},
{safe: true} ,
callback);
But it doesn't work, there are no problems it just doesn't update anything.
I think it's because the ['] (simple quotation mark) on the 'list.id' and 'list.$.votes' because the same query inside the terminal works perfectly.
Thanks!
I suspect your matching is not working as you expect. The callback will return
function(err, numberofItemsUpdated, wholeUpdateObject)
numberofItemsUpdated should equal 1 if your matching worked. you'll need to check if idSession and idSong are what you think they are.