Hoping someone can help me with my trouble with an index/match formula.
Column B has a list of names, column C has the frequency of an action taken (sales made) whilst column D has the average sales value.
I've created in column G a track of the 6 highest sales which has worked great:
=LARGE($D$8:$D$13, 2)
Then I've used column F to determine the name that matches each sales average:
=INDEX($B$8:$B$13, MATCH(G4, $D$8:$D$13, 0))
So far so good! However, I'd like to only include the sales average if that individual has had more than 3 sales. IE; the value in column C is >3.
Can any one provide help or suggestions please?
I think you could use a helper column to filter out the values you don't need before applying =LARGE() in the very beginning, like this:
=IF($C8>3, $D8, "")
Then do =LARGE() to this column instead:
=LARGE($X$8:$X$13, 2)
You could use an array formula:
=LARGE(IF(range=criteria,values),n)
so for your case:
=LARGE(IF($C$8:$C$13>3,$D$8:$D$13), 2)
press CTRL+SHIFT+ENTER to enter an array formula.
Related
I have simple problem, but I've not be able to get an answer from searching. I require a column to calculate the number of the nth occurrence of a value. It's best explained in this picture
I require a method to calculate column B.
I'd be very grateful for any help.
Are you looking to merely provide a count of the distinct entries of column A in column B? Or merely add a formula to come up with the table in your link?
If the latter, then the formula to write in cell B2 is:
=COUNTIF(A$2:A2,A2)
then copy/paste it down column B. Note - if your data is both a Date and Time, but the cell is formatted to only display a date, you may not get the results you want. You'd need to interject a new column with a "floor" calculation to round the date/time value to a date (Excel date times are decimal, with integer part dictating the date, and remaining 0.0 -> 1.0 dictating the time of day)
If you just want to derive a table of the counts of distinct entries in column A, then a pivot table will do this for you - simple add a pivot table to cover the data in column A, then select column A into the rows category, and then also drag it into the values category, ensuring the field is set to "Count of". You should then have a table with the distinct entries in your data set in one column, and the count of their occurrences in the other column.
You can use the COUNTIF worksheet function, with a relative address.
Eg. In cell B2, enter this formula:
=COUNTIF(A$2:A2,A2)
And then fill-down.
Use the following formula to generate the required series:
=COUNTIF($A$1:A1,A1) and strech(copy) it in all the cells
This will generate result like this:
A 1 COUNTIF($A$1:A1,A1)
A 2 COUNTIF($A$1:A2,A2)
C 1 COUNTIF($A$1:A3,A3)
C 2 COUNTIF($A$1:A4,A4)
B 1 COUNTIF($A$1:A5,A5)
B 2 COUNTIF($A$1:A6,A6)
A 3 COUNTIF($A$1:A7,A7)
C 3 COUNTIF($A$1:A8,A8)
D 1 COUNTIF($A$1:A9,A9)
D 2 COUNTIF($A$1:A10,A10)
D 3 COUNTIF($A$1:A11,A11)
D 4 COUNTIF($A$1:A12,A12)
I am trying to create a formula that will count the number of "Overdue" people instead of "Overdue" cells. Each person has the multiple rows with their name in it. The criteria to determine if it's "overdue" is:
-Column F and G are not within 3 years
-Column G are blank
-Column F = 0 and Column G are not within 3 years
The following code counts the criteria accurately. And doesn't account for duplicate names.
=SUM(COUNTIFS(TT[Fiscal Law 301 CBT],"<"&TODAY()-1065,TT[Fiscal Law 301 CBT],">"&TODAY()-1095,TT[Fiscal Law In-Residence],"<"&TODAY()-1065,TT[Fiscal Law In-Residence],">"&TODAY()-1095),COUNTIFS(TT[Fiscal Law In-Residence],"",TT[Fiscal Law 301 CBT],"<"&TODAY()-1065,TT[Fiscal Law 301 CBT],">"&TODAY()-1095))
The formula I want should count based on the criteria above and check column Z TT[Name] for duplicates and count them only once. And also count unique values once.
I just thought of another approach to this problem. What if I use the formula I have to create an Array, have another formula count the number of duplicates in Column Z from that Array, and subtract the two numbers.
This way should get me the correct number, i will still need assistance creating the second formula.
What you are after is a distinct count. Excel has a function for that in the new Dynamic Array function set, which is in Office 365 Insider builds but not available to everyone. Right now, a distinct count requires a few tricks.
For example, you can create a pivot table with the names in the rows, filter the table to include only values where column X = Overdue and use a CountA() on the result rows.
You are close, but not quite there.
Use a countifs formula like above. Then, create a column next to it with the logic if(countcell>0, 1, 0). This will return 1 if the person has at least 1 book overdue, and 0 otherwise. Then, take the sum of that column.
Formulas
I have provided a screenshots of the code that we would use (the E and F columns are dates). As you can see, the G column counts how many books are overdue. The H column provides a 1 if at least 1 book is overdue for each user. Then, we can simply sum the H column to find the total number of users with overdue books.
If this helps you, please consider choosing this as the answer.
I've googled for a solution to my problem for days and I just can't seem to get my head around how to do this.
I have 28 chickens and I track the eggs each one lays each month. My Excel sheet looks like this:
Current Egg-cel sheet
Column C is populated by the formula:
=LARGE($A$2:$A$29,$B1)
I'm using column B to increment the LARGE function
I want column D to populate with which chicken number laid the quantity in column C.
Obviously INDEX MATCH or VLOOKUP returns the first match for all equal values. How do I find the the next match? i.e.
Egg-cell sheet 2
I've seen similar questions and solutions but I for the life of me can not get it to work.
Use this formula in D2:
=INDEX(B:B,AGGREGATE(15,6,ROW($A$2:$A$29)/($A$2:$A$29=C2),COUNTIF($C$2:C2,C2)))
And drag down
If you're happy to add a few helper columns, this is a simple way to go:
The formula in column C creates a unique number by bringing together the eggs laid and the chicken number
=--(A2&"."&B2)
Column D is just your LARGE formula,
=LARGE($C$2:$C$4,B2)
Column E just gets the integer part of column D
=INT(D2)
And finally Column F gets the decimal part (chicken number) from column D
=--REPLACE(MOD(D2,1),1,2,"")
I have simple problem, but I've not be able to get an answer from searching. I require a column to calculate the number of the nth occurrence of a value. It's best explained in this picture
I require a method to calculate column B.
I'd be very grateful for any help.
Are you looking to merely provide a count of the distinct entries of column A in column B? Or merely add a formula to come up with the table in your link?
If the latter, then the formula to write in cell B2 is:
=COUNTIF(A$2:A2,A2)
then copy/paste it down column B. Note - if your data is both a Date and Time, but the cell is formatted to only display a date, you may not get the results you want. You'd need to interject a new column with a "floor" calculation to round the date/time value to a date (Excel date times are decimal, with integer part dictating the date, and remaining 0.0 -> 1.0 dictating the time of day)
If you just want to derive a table of the counts of distinct entries in column A, then a pivot table will do this for you - simple add a pivot table to cover the data in column A, then select column A into the rows category, and then also drag it into the values category, ensuring the field is set to "Count of". You should then have a table with the distinct entries in your data set in one column, and the count of their occurrences in the other column.
You can use the COUNTIF worksheet function, with a relative address.
Eg. In cell B2, enter this formula:
=COUNTIF(A$2:A2,A2)
And then fill-down.
Use the following formula to generate the required series:
=COUNTIF($A$1:A1,A1) and strech(copy) it in all the cells
This will generate result like this:
A 1 COUNTIF($A$1:A1,A1)
A 2 COUNTIF($A$1:A2,A2)
C 1 COUNTIF($A$1:A3,A3)
C 2 COUNTIF($A$1:A4,A4)
B 1 COUNTIF($A$1:A5,A5)
B 2 COUNTIF($A$1:A6,A6)
A 3 COUNTIF($A$1:A7,A7)
C 3 COUNTIF($A$1:A8,A8)
D 1 COUNTIF($A$1:A9,A9)
D 2 COUNTIF($A$1:A10,A10)
D 3 COUNTIF($A$1:A11,A11)
D 4 COUNTIF($A$1:A12,A12)
I have an excel sheet containing two columns of data that I'd like to rank.
Suppose we have the following:
A B
Franz 58
Daniel 92
Markus 37
Jörg 58
I would like a formula to rank the above data based on column B, and where there are duplicate values (Franz and Jörg) to put the alphabetical name first. What I have at the moment is simply duplicating Franz twice:
=INDEX(Name,MATCH(A2,Points,0))
Can someone advise me of formula / code that will rank the data and arrange duplicate values alphabetically?
Thanks
I would add a helper column in next to your data to help out with ties.
so in column C use
=B1+1/COUNTIF($A$1:$A$4,"<="&A1)/10
This will add on a decimal ranking system based on the name. This assumes that your numbers in column B do not have decimal places, if they do then you will need to increase the 10 on the end of the formula to account for it ie: for 2 decimal places use 1000, 3 : 10000 etc
Use this formula to get the first name
=INDEX(name,MATCH(LARGE(points,1),points,0))
adjust the 1 to 2 for the second name etc
EDIT had the sign around the wrong way
This will rank your data and will not repeat duplicates too:
In C2:
=SUM(1*(b2>$b$2:$b$5))+1+IF(ROW(b2)-ROW($b$2)=0,0,SUM(1*(b2=OFFSET($b$2,0,0,INDEX(ROW(b2)-ROW($b$2)+1,1)-1,1))))
CTRL+SHIFT+ENTER to turn it into an array
Drag these down to C5 and it will not duplicate rank where the name is the same, it will rank them alphabetically if they are the same.
Then if you wanted to order them automatically in order of top performer/score you then do this:
Putting this in E2:
=INDEX(A2:A5,MATCH(LARGE(C2:C5,ROW()-1),C2:C5,0))
...and drag down
Then use a vlookup on your data to return the score putting this in F2:
=vlookup(E2,A2:C5,2,false)
...and drag down
This should give you a table of highest scoring people in score order.
Assuming A2 is the first of the ranked points scores try this version
=INDEX(Name,SMALL(IF(A2=Points,ROW(Points)-MIN(ROW(Points))+1),COUNTIF(A$2:A2,A2)))
confirmed with CTRL+SHIFT+ENTER and copied down
Requires the Name list to be sorted because names with duplicate scores will be listed in the order shown