I have the following time stamps in Excel, and i want to calculate the time (in seconds) between these two intervalls.
Start: 2016-07-15 13:39:41.602553
End: 2016-07-15 13:42:52.597283
(yyyy-mm-dd hh:mm:ss.ffffff)
The start value is in cell A1 and the end value is in cell B1.
The cells are currently formated as "General" which might be wrong, so they are not as per definition timestamps.
I have tried:
=Int(B1)-Int(A1)
=B1-A1
But it won't do the job (half expected)
Thank you in advance.
EDIT: Some clarifications
Best regards,
VD
This turned out to be the solution for this question:
=(DATEVALUE(LEFT(B1;10))+TIMEVALUE(MID(SUBSTITUTE(B1;”.”;”,”);12;8))-(DATEVALUE(LEFT(A1;10))+TIMEVALUE(MID(SUBSTITUTE(A1;”.”;”,”);12;8))
Thanks for the help!
Try and make your question a bit clearer and include what you've tried to achieve this and I'd imagine people won't downvote you so quickly (not me btw).
If you have your start and end in two cells (A1 and A2) then the difference in seconds is =VALUE(TEXT(A2-A1,"[s]"))
Excel stores dates and times as days (since 1 Jan 1900) and fractions of a day. So you were pretty close.
=B1-A1 and format result as [s]
or (there are 86400 seconds in a day)
=ROUND((B1-A1)*86400,0)
Here is a screenshot.
The timestamps are formatted as General, but they are text strings; the first formula as [s], and the second as General
Related
I've been looking on the internet and here on the site, but I don't find an example: I would like to calculate the difference between two hours, but if one is in the morning (smaller than 12:00) and the other in the afternoon (larger than 13:00), an hour should be subtracted.
As the values "08:00", "16:00" and "17:00" are accepted by Excel, I thought this would be easy, something like:
=IF(AND(B3<=12:00,C3>=13:00),C3-B3-1,C3-B3)
But the values "12:00" and "13:00" are not recognised by Excel. How can I write my formula (as readable as possible, please, calculating 13/24 and using this constant in my formula is not very readable :-) ).
I've opted for this solution:
=IF(AND(B3<=TIME(12,0,0),C3>=TIME(13,0,0)),C3-B3-TIME(1,0,0),C3-B3)
This says precisely what I want: in case I started in the morning (B3<=TIME(12,0,0)) and ended in the afternoon (C3>=TIME(13,0,0)), then I subtract one hour TIME(1,0,0) from the difference (taking lunchtime into account).
Currently trying to setup a formula that will calculate the hours/minutes between two different hours of time.
I currently use the following formula in Cell D3 and receive 12:35am as the answer:
=C3-B3
What I would want it to display is 35 minutes, which is the correct amount of time in between (6:42AM and 7:17AM).
Something like this would work:
=TEXT(C3-B3,"[m]")
or if you want "minutes" written after
=TEXT(C3-B3,"[m] ""minutes""")
Examples:
C3-B3 and formatted as [m] will work - either =TEXT(C3-B3,"[m]") or just giving the cell a custom number format of [m].
If Begin is 11:45PM and End is 12:15AM you'll only see ############# as both times are considered to be in the same day, while 12:15AM is the start of the next day.
Try =IF(C4<B4,(1+C4)-B4,C4-B4)
If C4 is less than B4 it adds 1 day to the value of End.
You have to multiply your formula by the amount of hours in a day (24) and the amount of minutes in an hour (60) in order to convert.
So your formula should be the following.
=(C3-B3)*24*60
As requested, I have included a simplified screenshot that illustrates the issue.
As you can see, I subtracted the two dates and formatted it as "h:mm:ss". Why doesn't this give you the total amount of hours that have passed between the two dates? Is there a better way to do this? There is a great answer below, but I am trying to figure out why doing the way illustrated in this screenshot doesn't work.
END OF EDIT
I am aware that similar questions have been answered here, but for whatever reason this is not working for me at all.
I have two columns: one is a date, one is the time.
As you can see from the currently highlighted cell, the "time" column is actually stored as date with the time included. In column H, I have the date stored as a serial code so that the decimal number refers to a month, day, year, hour, minute, and second. When I subtract the serial code that refers to 2/16/2016 3:20:01 PM from the serial code that refers to refers to 2/14/2016 1:20:01 PM and format that cell as "h:mm", I am getting 2:00. Why?????
I have been hacking away at this for a while and this is supposed to be stupid easy and it's not working. Any help is greatly appreciated so I can move on to more important things.
It does work. Just take the difference between the two dates, format the cell containing the difference as Number, and then use one of the following formulas to get the units you want. I will assume that:
A1 has the value 2/16/2016 3:20:01 PM
B1 has the value 2/14/2016 1:20:01 PM
Into C1 enter A1 - B1, and format it as Number
If you want the difference as days, leave C1 as is.
If you want hours, use =24*(A1 - B1)
If you want minutes, use =24*60*(A1 - B1)
If you want seconds, use =24*60*60*(A1 - B1)
THE ANSWER TO THIS IS REALLY SILLY.
Below, you will find that Tim Biegeleisen provided an excellent answer to this question. I just wanted to further elaborate.
Sometimes having too many option for formatting can be a problem, which is what happened here.
When you subtract 2/14/2016 1:20:01 PM from 2/16/2016 3:20:01 PM and format it as h:mm:ss it only subtracts the hours portion and ignores days. You just have to somehow know that if you are trying to do what I'm trying to do, you have to format it as [h]:mm:ss and then it will calculate the total number of hours passed. The bracket around the "h" is the important part here. I hope this helps the next person who comes across this.
I have two time:
9:29:00 AM (B2)
6:16:00 PM (C2)
I want to get the hh:mm (hours and minutes) between those two times. I tried the following function:
=TEXT(B2-C2,"h:mm")
But I get a #VALUE! error.
I formatted the two time cells as TIME format (*h:mm:ss am:pm) and result cell also as TIME format (hh:mm)
Is that the right way round? Try
=C2-B2
You don't need TEXT function
I believe your #VALUE error is due to your order of subtraction, but I can't be sure without knowing which of those times is B2 and which is C2, and I can't quite comment on your question yet, so an answer it is!
Times in excel are stored as doubles which increment by 1 each day; 0.5 is 12 hours etc.
Best thing to do is use =TEXT(B2-C2,"HH:MM")
This will format B2-C2 (a decimal number) as a time interval.
Of course the contents of B2 and C2 must be numeric; see my VALUE function in the comments.
As barry houdini mentioned back in 2013, I also ran into the error of subtracting giving a negative number, and excel just throws an error. No other response on the internet gave me good results. Although my method is longer, it always works with times in hh:mm:ss AM/PM. Just change the text format part of the formula for whatever you have. My data was:
11:15:45 PM 1:41:20 AM
I converted it to military time for ease with
=TEXT(A2, "hh:mm:ss")
Data was now:
23:15:45 01:41:20
I made another column, let's call it C, that just subtracts the second time from the first time,
=B2-A2
I next used an IF statement on this column, so that if the absolute value of the difference was the same as the number (a positive), I'd use
TEXT(B2-A2,"hh:mm:ss")
which just subtracts the later time from the earlier time. But...
If the absolute value of the difference was not the same, e.g. error-ville with a lot of hashes ##########, I use:
TEXT(24-(A10-B10),"hh:mm:ss")
Altogether, we have one more column, which finally spits out the correct hour difference. This column is predicated on columns A, B, and our error-prone difference column C:
=IF(C2=ABS(C2),TEXT(B2-A2,"hh:mm:ss"),TEXT(24-(A2-B2),"hh:mm:ss"))
this is the most ridiculous thing I have ever done. It's been years and such a simple case, never solved by Excel.
Where I work I don't get paid overtime, but I accrue holiday days for the overtime I work. I have the following spreadsheet which calculates how much overtime I've done and totals it in D15.
Now I want to calculate how many days this is, based on 8 hours per day. In D16, I've done =D15/8 and formatted it as h.mm \d\a\y\s, but this shows as 2.26 days instead of 2.4375 days.
What is the correct formula to use in D16?
Note to reader: this question led to multiple solutions some of which were discussed in the comments. Here is a summary of the solution found.
First solution
=(HOUR(D15)+MINUTE(D15)/60)/8
Explanation
Dates and time in Excel are stored as serial numbers, so 19:30 is actually 0.8125.
So, if you divide it by 8, you will get 0.1015625.
This latter value is worth 2.26 days
OP's version (thanks to Danny Becket (OP)) - see the comments below.
This solution now handles hours > 24.
=((DAY(D20)*24)+HOUR(D20)+(MINUTE(D20)/60))/8
or better (credits to Barry Houdini):
=((INT(D20)*24)+HOUR(D20)+(MINUTE(D20)/60))/8
The former formula has a limitation for large values, perhaps not relevant here but if D20 is 800:00 then you get the wrong answer (7 days rather than 100 days). This is probably because DAY function is giving you calendar day which will "reset" at 31, best to use INT in place of DAY.
Another easily understandable version
Divide by the length of the day as a time value:
=D15/"8:00"
More easily changed if length of workday changes
Enter:
in B3 8:3
in C3 16:3
in D3 =IF(B3<C3,C3-B3-1/3,2/3-B3+C3)
Select B3:D3, format as hh:mm and copy down as far as required.
Sum ColumnD and append *3 to the formula, but format as Number.
Add data by overwriting cells in ColumnB and/or ColumnC as required (defaults do not add to total).
Copes with overtime up to next regular start time (ie including past midnight, new serial number). 1/3 because standard working day is 8 hours (24 hours is unity for date serial counter). B3 and C3 could be hard coded but (i) there is no need and (ii) allows more flexibility. If to readily identify non standard start/finish could use conditional formatting.
Does not address weekend overtime but could easily be adapted to do so (eg add column, flag weekend day with 8 in that extra column then add that 8 [1/3] to the finish time).
Make sure that D15 has a number format of [h]:mm
then have D16 as =sum(D15/"8:00") should work fine
thats what i have tracking my annual leave, I work 37h pw with a leave day being classed as 7h24m or a half day of leave as "3:42"
I have leave taken as a cumulative figure assigned as [h]:mm in cell K2 of my spreadsheet
then I have K3=SUM(K2/"7:24") for days taken formatted as a general number
you may also need to change the date datum in excel to the 1904 date system http://support.microsoft.com/kb/182247/en-gb
to get this to work (only a problem if you have negative time as I do when calculating flex hours)