Product if date = specific year - excel

I am trying to compute the column M to do a product of column D if the date(column A) falls within the year as specific on column L.
So far I have tried the above formula =PRODUCT(IF(YEAR(A4:A345)=L5,D4:D345,1)) but it failed to work. Any suggestion?

I am afraid there is no such formula.
One workaround I can suggest:
Create a dummy column which stores IF(YEAR($A4) = $L4, $A4, 1) and now apply PRODUCT on this column. If this report is one of your presentable reports, you can hide this column.

Related

Number occurrences in another cell (Excell) [duplicate]

I have simple problem, but I've not be able to get an answer from searching. I require a column to calculate the number of the nth occurrence of a value. It's best explained in this picture
I require a method to calculate column B.
I'd be very grateful for any help.
Are you looking to merely provide a count of the distinct entries of column A in column B? Or merely add a formula to come up with the table in your link?
If the latter, then the formula to write in cell B2 is:
=COUNTIF(A$2:A2,A2)
then copy/paste it down column B. Note - if your data is both a Date and Time, but the cell is formatted to only display a date, you may not get the results you want. You'd need to interject a new column with a "floor" calculation to round the date/time value to a date (Excel date times are decimal, with integer part dictating the date, and remaining 0.0 -> 1.0 dictating the time of day)
If you just want to derive a table of the counts of distinct entries in column A, then a pivot table will do this for you - simple add a pivot table to cover the data in column A, then select column A into the rows category, and then also drag it into the values category, ensuring the field is set to "Count of". You should then have a table with the distinct entries in your data set in one column, and the count of their occurrences in the other column.
You can use the COUNTIF worksheet function, with a relative address.
Eg. In cell B2, enter this formula:
=COUNTIF(A$2:A2,A2)
And then fill-down.
Use the following formula to generate the required series:
=COUNTIF($A$1:A1,A1) and strech(copy) it in all the cells
This will generate result like this:
A 1 COUNTIF($A$1:A1,A1)
A 2 COUNTIF($A$1:A2,A2)
C 1 COUNTIF($A$1:A3,A3)
C 2 COUNTIF($A$1:A4,A4)
B 1 COUNTIF($A$1:A5,A5)
B 2 COUNTIF($A$1:A6,A6)
A 3 COUNTIF($A$1:A7,A7)
C 3 COUNTIF($A$1:A8,A8)
D 1 COUNTIF($A$1:A9,A9)
D 2 COUNTIF($A$1:A10,A10)
D 3 COUNTIF($A$1:A11,A11)
D 4 COUNTIF($A$1:A12,A12)

Excel: Count Only Once If Another Column Has Duplicates

I am trying to create a formula that will count the number of "Overdue" people instead of "Overdue" cells. Each person has the multiple rows with their name in it. The criteria to determine if it's "overdue" is:
-Column F and G are not within 3 years
-Column G are blank
-Column F = 0 and Column G are not within 3 years
The following code counts the criteria accurately. And doesn't account for duplicate names.
=SUM(COUNTIFS(TT[Fiscal Law 301 CBT],"<"&TODAY()-1065,TT[Fiscal Law 301 CBT],">"&TODAY()-1095,TT[Fiscal Law In-Residence],"<"&TODAY()-1065,TT[Fiscal Law In-Residence],">"&TODAY()-1095),COUNTIFS(TT[Fiscal Law In-Residence],"",TT[Fiscal Law 301 CBT],"<"&TODAY()-1065,TT[Fiscal Law 301 CBT],">"&TODAY()-1095))
The formula I want should count based on the criteria above and check column Z TT[Name] for duplicates and count them only once. And also count unique values once.
I just thought of another approach to this problem. What if I use the formula I have to create an Array, have another formula count the number of duplicates in Column Z from that Array, and subtract the two numbers.
This way should get me the correct number, i will still need assistance creating the second formula.
What you are after is a distinct count. Excel has a function for that in the new Dynamic Array function set, which is in Office 365 Insider builds but not available to everyone. Right now, a distinct count requires a few tricks.
For example, you can create a pivot table with the names in the rows, filter the table to include only values where column X = Overdue and use a CountA() on the result rows.
You are close, but not quite there.
Use a countifs formula like above. Then, create a column next to it with the logic if(countcell>0, 1, 0). This will return 1 if the person has at least 1 book overdue, and 0 otherwise. Then, take the sum of that column.
Formulas
I have provided a screenshots of the code that we would use (the E and F columns are dates). As you can see, the G column counts how many books are overdue. The H column provides a 1 if at least 1 book is overdue for each user. Then, we can simply sum the H column to find the total number of users with overdue books.
If this helps you, please consider choosing this as the answer.

Calculate Occurrence Number - Excel

I have simple problem, but I've not be able to get an answer from searching. I require a column to calculate the number of the nth occurrence of a value. It's best explained in this picture
I require a method to calculate column B.
I'd be very grateful for any help.
Are you looking to merely provide a count of the distinct entries of column A in column B? Or merely add a formula to come up with the table in your link?
If the latter, then the formula to write in cell B2 is:
=COUNTIF(A$2:A2,A2)
then copy/paste it down column B. Note - if your data is both a Date and Time, but the cell is formatted to only display a date, you may not get the results you want. You'd need to interject a new column with a "floor" calculation to round the date/time value to a date (Excel date times are decimal, with integer part dictating the date, and remaining 0.0 -> 1.0 dictating the time of day)
If you just want to derive a table of the counts of distinct entries in column A, then a pivot table will do this for you - simple add a pivot table to cover the data in column A, then select column A into the rows category, and then also drag it into the values category, ensuring the field is set to "Count of". You should then have a table with the distinct entries in your data set in one column, and the count of their occurrences in the other column.
You can use the COUNTIF worksheet function, with a relative address.
Eg. In cell B2, enter this formula:
=COUNTIF(A$2:A2,A2)
And then fill-down.
Use the following formula to generate the required series:
=COUNTIF($A$1:A1,A1) and strech(copy) it in all the cells
This will generate result like this:
A 1 COUNTIF($A$1:A1,A1)
A 2 COUNTIF($A$1:A2,A2)
C 1 COUNTIF($A$1:A3,A3)
C 2 COUNTIF($A$1:A4,A4)
B 1 COUNTIF($A$1:A5,A5)
B 2 COUNTIF($A$1:A6,A6)
A 3 COUNTIF($A$1:A7,A7)
C 3 COUNTIF($A$1:A8,A8)
D 1 COUNTIF($A$1:A9,A9)
D 2 COUNTIF($A$1:A10,A10)
D 3 COUNTIF($A$1:A11,A11)
D 4 COUNTIF($A$1:A12,A12)

Index/match if greater than

Hoping someone can help me with my trouble with an index/match formula.
Column B has a list of names, column C has the frequency of an action taken (sales made) whilst column D has the average sales value.
I've created in column G a track of the 6 highest sales which has worked great:
=LARGE($D$8:$D$13, 2)
Then I've used column F to determine the name that matches each sales average:
=INDEX($B$8:$B$13, MATCH(G4, $D$8:$D$13, 0))
So far so good! However, I'd like to only include the sales average if that individual has had more than 3 sales. IE; the value in column C is >3.
Can any one provide help or suggestions please?
I think you could use a helper column to filter out the values you don't need before applying =LARGE() in the very beginning, like this:
=IF($C8>3, $D8, "")
Then do =LARGE() to this column instead:
=LARGE($X$8:$X$13, 2)
You could use an array formula:
=LARGE(IF(range=criteria,values),n)
so for your case:
=LARGE(IF($C$8:$C$13>3,$D$8:$D$13), 2)
press CTRL+SHIFT+ENTER to enter an array formula.

Excel Complex Conditional

Ok so I did this in LibreOffice but now I have to duplicate it to excel for my Pay Roll department since they use excel. So I am having to figure out how to convert the formulas to Excel. This is only 1 of two totaling formulas that did not convert when I saved it as Excel format.
I have the following sheet called DailyReport
I am currently calculating Column M with =SUMPRODUCT(A2:A200=A2, G2:G200)
Then on a secondary sheet I have the following second sheet WeeklyReport
Now what I want to do is if WeeklyReport Column A2 == DailyReport Column A then take the date in DailyReport Column B and test it to fall in the date range in WeeklyReport Column B and Column C with =IF(AND(DailyReport.B2>=B2,DailyReport.B2<=C2),1, 0) and if that is true add the Total Daily Hours to the total in WeeklyReports Column D from DailyReports Column M
I hope this is clear enough if not please let me know what else I can do to make my question more clear.
Thanks in advance!
So, to me it sounds like:
You want a sum of all hours, for a specific employee (defined by the A column value weekly report), in between the dates specified (also defined by weekly report, b & c column) - and you want the end result to be in WeeklyReport column D and all of it to relate to the same row as the result?
sumproduct will do the trick. I am renaming your sheets to DR and WR for my sanity's sake.
=sumproduct((DR!G$2:G$200)*(DR!A$2:A$200=A2)*(DR!B$2:B$200>=B2)*(DR!B$2:B$200<C2))
Now, if you want a new daily report sheet every day it gets a bit trickier to do with formulas alone, you should then have a macro to store the "current" value and add the "new" value, or for simplicity's sake create more columns (one for each working day) and duplicate the formula to all daily columns, or have as many named dailyreports as there are working days in a week and increase the formula to check multiple sheets. I would add columns - least amount of work and the dumbest solution often proves the most resilient.
Did that help in any way?

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