I have a couple of columns as shown below:
A B C D E
1 12 4 1
2 3 2 2
3 7
4 3 0 6
How would I be able to return a count of each column above so for example receive the result:
A B C D E
1 12 4 1
2 3 2 2
3 7
4 3 0 6
5 count:3 4 2 1
for each of the column. Im looking for a formula that would be able to do that in one cell(B5) returning a count for each of the columns, and avoid using fill handling as the data set is quite large
It's pretty easy, using Google Spreadsheet's functions:
=ArrayFormula(MMULT(TRANSPOSE(row(A1:A4)^0),--(len(A1:E4)>0)))
Or, if you want join them all:
=JOIN(", ",ArrayFormula(MMULT(TRANSPOSE(row(A1:A4)^0),--(len(A1:E4)>0))))
Related
I am having issues trying to modify a value if columnA contains lets say 0,2,12,44,75,81 (looking at 33 different numerical values in columnA. If columnA contains 1 of the 33 vaules defined, i need to then change the same row of colulmnB to "approved".
I have tried this:
df[(df.columnA == '0|2|12|44|75|81')][df.columnB] = 'approved'
I get an error that there are none of index are in the columns but, i know that isn't correct looking at my csv file data. I must be searching wrong or using the wrong syntax.
As others have said, if you need the value in column A to match exactly with a value in the list, then you can use .isin. If you need a partial match, then you can convert to string dtypes and use .contains.
setup:
nums_to_match = [0,2,9]
df
A B
0 6 e
1 1 f
2 3 b
3 6 g
4 6 i
5 0 f
6 9 a
7 6 i
8 6 a
9 2 h
Exact match:
df.loc[df.A.isin(nums_to_match),'B']='approved'
df:
A B
0 6 e
1 1 f
2 3 b
3 6 g
4 6 i
5 0 approved
6 9 approved
7 6 i
8 6 a
9 2 approved
partial match:
nums_to_match_str = list(map(str,nums_to_match))
df['A']=df['A'].astype(str)
df.loc[df.A.str.contains('|'.join(nums_to_match_str),case=False,na=False),'B']='approved'
df
A B
0 1 h
1 4 c
2 6 i
3 7 d
4 3 d
5 9 approved
6 5 i
7 1 c
8 0 approved
9 5 d
HOW TO JOIN MULTIPLE COLUMN IN ONE COLUMN
TABLE 1 TABLE 2 TABLE 3
1 2 5
2 4 3
3 5 3
4 5 1
I WANT TO
1
2
3
4
2
4
5
5
5
3
3
1
If your data is like below, enter the formula in the first row of any column and drag down until there is no value left over,
=IF(ROW()<=COUNTA(A:A),INDEX(A:A,ROW()),IF(ROW()<=COUNTA(A:B),INDEX(B:B,ROW()-COUNTA(A:A)),IF(ROW()>COUNTA(A:C),"",INDEX(C:C,ROW()-COUNTA(A:B)))))
1 2 2
4 5 4
3 3 3
0 1 0
1 2 2
4 4 3
4 5 4
4 5 4
3 4 4
3 4 4
4 4 4
3 4 3
I have above three columns in excel,how to find the number that appears more times, for example, first row is 2 (because it has two 2 and one 1)
Assuming your layout is such that the first column is A, second column is B, etc., then you could put the following in cell D1:
=IF(ISNUMBER(MODE(A1:C1)),MODE(A1:C1),0)
This also outputs 0 in case there is a tie. You can replace the 0 with whatever excel expression you want if you don't want ties to result in a 0.
A B ANSWER
1 1 1
3 3 3
1 2 1
2 4 2
4 4 4
5 5 5
6 6 6
i have used this function to get above answer "=IF(ISERROR(MATCH(A2:A8,$B$1:$B$8,0)),"",A2)"
but I need answer like this i have given below (suppose if you take value in A column "1"
Which is repeated only once in column B)
A B ANR
1 1 1
3 3 3
1 2 0
2 4 2
4 4 4
5 5 5
6 6 6
I've just wrapped your formula in a condition that returns 0 where the count of the A value from start to the current row is more than one:
=IF(COUNTIF(A$1:A2,A2)>1,0,IF(ISERROR(MATCH(A2:A8,$B$1:$B$8,0)),"",A2))
.
An alternative formula that gives the same results as above for the sample data provided but may (or may not) suit the additional requirements mentioned in a comment:
=IF(COUNTIF(A$2:A$10,A2)<=COUNTIF(B$2:B$10,A2),A2,IF(COUNTIF(A$2:A2,A2)>COUNTIF(B$2:B$10,A2),0,IF(COUNTIF(A$2:A$10,A2)>COUNTIF(B$2:B2,A2),A2,0)))
I am trying to fill data in MS Excel. I am given following pattern:
1 2
1
1
2 5
2 5
2
3
3 6
3
4
4
5 4
And I want my output in following format:
1 2
1 2
1 2
2 5
2 5
2 5
3 6
3 6
3 6
4
4
5 4
I tried using if(b2,b2,c1) in column 3. but that doesn't solve the problem for a=3 and a=4.
Any idea how to do this in Excel?
With sorting thus:
(the effect of which in this case is merely to move 6 up once cell) and a blank row above:
=IF(AND(A2<>A1,B2=""),"",IF(B2<>"",B2,C1))
In C2 and copied down should get the result you ask for from the data sample provided.