A B ANSWER
1 1 1
3 3 3
1 2 1
2 4 2
4 4 4
5 5 5
6 6 6
i have used this function to get above answer "=IF(ISERROR(MATCH(A2:A8,$B$1:$B$8,0)),"",A2)"
but I need answer like this i have given below (suppose if you take value in A column "1"
Which is repeated only once in column B)
A B ANR
1 1 1
3 3 3
1 2 0
2 4 2
4 4 4
5 5 5
6 6 6
I've just wrapped your formula in a condition that returns 0 where the count of the A value from start to the current row is more than one:
=IF(COUNTIF(A$1:A2,A2)>1,0,IF(ISERROR(MATCH(A2:A8,$B$1:$B$8,0)),"",A2))
.
An alternative formula that gives the same results as above for the sample data provided but may (or may not) suit the additional requirements mentioned in a comment:
=IF(COUNTIF(A$2:A$10,A2)<=COUNTIF(B$2:B$10,A2),A2,IF(COUNTIF(A$2:A2,A2)>COUNTIF(B$2:B$10,A2),0,IF(COUNTIF(A$2:A$10,A2)>COUNTIF(B$2:B2,A2),A2,0)))
Related
I am having issues trying to modify a value if columnA contains lets say 0,2,12,44,75,81 (looking at 33 different numerical values in columnA. If columnA contains 1 of the 33 vaules defined, i need to then change the same row of colulmnB to "approved".
I have tried this:
df[(df.columnA == '0|2|12|44|75|81')][df.columnB] = 'approved'
I get an error that there are none of index are in the columns but, i know that isn't correct looking at my csv file data. I must be searching wrong or using the wrong syntax.
As others have said, if you need the value in column A to match exactly with a value in the list, then you can use .isin. If you need a partial match, then you can convert to string dtypes and use .contains.
setup:
nums_to_match = [0,2,9]
df
A B
0 6 e
1 1 f
2 3 b
3 6 g
4 6 i
5 0 f
6 9 a
7 6 i
8 6 a
9 2 h
Exact match:
df.loc[df.A.isin(nums_to_match),'B']='approved'
df:
A B
0 6 e
1 1 f
2 3 b
3 6 g
4 6 i
5 0 approved
6 9 approved
7 6 i
8 6 a
9 2 approved
partial match:
nums_to_match_str = list(map(str,nums_to_match))
df['A']=df['A'].astype(str)
df.loc[df.A.str.contains('|'.join(nums_to_match_str),case=False,na=False),'B']='approved'
df
A B
0 1 h
1 4 c
2 6 i
3 7 d
4 3 d
5 9 approved
6 5 i
7 1 c
8 0 approved
9 5 d
In excel I have a dataset. This represents how much stock of 2 products is sold in the first, second, third, etc... month of the product being on the shelves (starts in A1):
Month 1 2 3 4 5 6 7 8 9 10 11 12
Product 1 3 5 2 1 6 1 2 4 7 2 1 5
Product 2 2 1 5 6 2 8 2 1 2 3 4 9
However, the first product sales do not always occur in month 1. They occur in month X. Is there a way (not VBA or copy and paste) of shifting the entries right by 'x' so they align with the month.
Example for data above
Product 1 starts in month 2
Product 2 starts in month 5
Month 1 2 3 4 5 6 7 8 9 10 11 12
Product 1 0 3 5 2 1 6 1 2 4 7 2 1 5
Product 2 0 0 0 0 2 1 5 6 2 8 2 1 2 3 4 9
*0 not required (great if possible), but more for illustration
Thanks
I have created a simple example that does the same job. The shown formula is copied over the shown cells in the row of new data. (The number '2' in the formula refers to the column number of the starting data cell which is column B, hence 2.)
I have a couple of columns as shown below:
A B C D E
1 12 4 1
2 3 2 2
3 7
4 3 0 6
How would I be able to return a count of each column above so for example receive the result:
A B C D E
1 12 4 1
2 3 2 2
3 7
4 3 0 6
5 count:3 4 2 1
for each of the column. Im looking for a formula that would be able to do that in one cell(B5) returning a count for each of the columns, and avoid using fill handling as the data set is quite large
It's pretty easy, using Google Spreadsheet's functions:
=ArrayFormula(MMULT(TRANSPOSE(row(A1:A4)^0),--(len(A1:E4)>0)))
Or, if you want join them all:
=JOIN(", ",ArrayFormula(MMULT(TRANSPOSE(row(A1:A4)^0),--(len(A1:E4)>0))))
1 2 2
4 5 4
3 3 3
0 1 0
1 2 2
4 4 3
4 5 4
4 5 4
3 4 4
3 4 4
4 4 4
3 4 3
I have above three columns in excel,how to find the number that appears more times, for example, first row is 2 (because it has two 2 and one 1)
Assuming your layout is such that the first column is A, second column is B, etc., then you could put the following in cell D1:
=IF(ISNUMBER(MODE(A1:C1)),MODE(A1:C1),0)
This also outputs 0 in case there is a tie. You can replace the 0 with whatever excel expression you want if you don't want ties to result in a 0.
I am trying to fill data in MS Excel. I am given following pattern:
1 2
1
1
2 5
2 5
2
3
3 6
3
4
4
5 4
And I want my output in following format:
1 2
1 2
1 2
2 5
2 5
2 5
3 6
3 6
3 6
4
4
5 4
I tried using if(b2,b2,c1) in column 3. but that doesn't solve the problem for a=3 and a=4.
Any idea how to do this in Excel?
With sorting thus:
(the effect of which in this case is merely to move 6 up once cell) and a blank row above:
=IF(AND(A2<>A1,B2=""),"",IF(B2<>"",B2,C1))
In C2 and copied down should get the result you ask for from the data sample provided.