I have an excel table with 2 columns. First column contains a string such as A,B,C and second column contains numbers. I want to obtain sum of numbers in each row if text of first column for that row is equal to given text.
For example:
A 2
C 3
B 4
A 1
C 3
formula(A) = 3
formula(B) = 4
formula(C) = 6
and so on.
One way to achieve this is via SubTotal option. Follow the example in this link Creating subtotals
Another way to do the same is using sumif function follow this link Sumif function
SUMIFS() is capable of doing this. As is SUMPRODUCT()
In european excel this would look like this. I don't know where your reference is so I am putting it in a cell named Reference.
SUMIFS($B:$B;$A:$A;"="Reference)
If you want a "running" count, then replace the arrays - from $B:$B to B$2:B2 and similar with $A:$A, and copy it down the rows.
Related
I have simple problem, but I've not be able to get an answer from searching. I require a column to calculate the number of the nth occurrence of a value. It's best explained in this picture
I require a method to calculate column B.
I'd be very grateful for any help.
Are you looking to merely provide a count of the distinct entries of column A in column B? Or merely add a formula to come up with the table in your link?
If the latter, then the formula to write in cell B2 is:
=COUNTIF(A$2:A2,A2)
then copy/paste it down column B. Note - if your data is both a Date and Time, but the cell is formatted to only display a date, you may not get the results you want. You'd need to interject a new column with a "floor" calculation to round the date/time value to a date (Excel date times are decimal, with integer part dictating the date, and remaining 0.0 -> 1.0 dictating the time of day)
If you just want to derive a table of the counts of distinct entries in column A, then a pivot table will do this for you - simple add a pivot table to cover the data in column A, then select column A into the rows category, and then also drag it into the values category, ensuring the field is set to "Count of". You should then have a table with the distinct entries in your data set in one column, and the count of their occurrences in the other column.
You can use the COUNTIF worksheet function, with a relative address.
Eg. In cell B2, enter this formula:
=COUNTIF(A$2:A2,A2)
And then fill-down.
Use the following formula to generate the required series:
=COUNTIF($A$1:A1,A1) and strech(copy) it in all the cells
This will generate result like this:
A 1 COUNTIF($A$1:A1,A1)
A 2 COUNTIF($A$1:A2,A2)
C 1 COUNTIF($A$1:A3,A3)
C 2 COUNTIF($A$1:A4,A4)
B 1 COUNTIF($A$1:A5,A5)
B 2 COUNTIF($A$1:A6,A6)
A 3 COUNTIF($A$1:A7,A7)
C 3 COUNTIF($A$1:A8,A8)
D 1 COUNTIF($A$1:A9,A9)
D 2 COUNTIF($A$1:A10,A10)
D 3 COUNTIF($A$1:A11,A11)
D 4 COUNTIF($A$1:A12,A12)
As a result of this closed topic I started wondering myself the following:
Let's say we have data like this:
A
1
a
2
b
3
c
4
a
5
b
6
c
7
g
8
h
9
i
I want to divide the list into 3 (I used TEXTJOIN) and check which of the 3 of these is unique.
I used a combination of MATCH and COUNTIF (and SEQUENCE) for this.
Question:
I managed to get that correct, but wanted to get the 3 textjoin-results all at once as a spill range.
In the picture below you can see my results of attempts, but I couldn't get the TEXTJOIN to reference the correct column in it's spill-result. What is missing, or what am I doing wrong?
Not sure what you want for output.
If all you want is to determine which is/are unique entries, just use the UNIQUE function. Note the exactly_once argument.
For example:
C1: =OR(B1=UNIQUE($B$1:$B$3,,TRUE))
and fill down, but the formula will fill down automatically.
Edit:
I don't know how to get the TEXTJOIN function to spill down in groups of three like you want. However, to be able to enter the formula just once, and have the results appear in column B, and have that adjust as you add/remove entries from column A, you can use a Table structure.
In that case, row 1 would be the column headers, and the formula in B2 would be:
=IFERROR(TEXTJOIN(",",TRUE,INDEX([Column1],SEQUENCE(3)+(ROW()-ROW(Table2[#Headers]))*3-3)),"")`
No need to fill down.
Edit2:
To create a list of unique (listed only once) values from Column B in Column C, you can use the UNIQUE function. However, due to limitations on SPILL functions within a Table, this column cannot be part of the table.
In the example below, where Column C is NOT part of the table:
B2: =IFERROR(TEXTJOIN(",",TRUE,INDEX([Column1],SEQUENCE(3)+(ROW()-ROW(Table2[#Headers]))*3-3)),"")
C2: =UNIQUE(Table2[Column2],,TRUE)
Edit3:
If you were OK with omitting columnB, and reporting the unique triplets in separate cells instead of concatenated, you could do that with the UNIQUE function:
or, without a table,
=UNIQUE(INDEX($A:$A,SEQUENCE(COUNTA($A:$A)/3,3,2)),,TRUE)
Note that the start argument in the SEQUENCE function represents the first line of data in column A, (2 in this example)
I have simple problem, but I've not be able to get an answer from searching. I require a column to calculate the number of the nth occurrence of a value. It's best explained in this picture
I require a method to calculate column B.
I'd be very grateful for any help.
Are you looking to merely provide a count of the distinct entries of column A in column B? Or merely add a formula to come up with the table in your link?
If the latter, then the formula to write in cell B2 is:
=COUNTIF(A$2:A2,A2)
then copy/paste it down column B. Note - if your data is both a Date and Time, but the cell is formatted to only display a date, you may not get the results you want. You'd need to interject a new column with a "floor" calculation to round the date/time value to a date (Excel date times are decimal, with integer part dictating the date, and remaining 0.0 -> 1.0 dictating the time of day)
If you just want to derive a table of the counts of distinct entries in column A, then a pivot table will do this for you - simple add a pivot table to cover the data in column A, then select column A into the rows category, and then also drag it into the values category, ensuring the field is set to "Count of". You should then have a table with the distinct entries in your data set in one column, and the count of their occurrences in the other column.
You can use the COUNTIF worksheet function, with a relative address.
Eg. In cell B2, enter this formula:
=COUNTIF(A$2:A2,A2)
And then fill-down.
Use the following formula to generate the required series:
=COUNTIF($A$1:A1,A1) and strech(copy) it in all the cells
This will generate result like this:
A 1 COUNTIF($A$1:A1,A1)
A 2 COUNTIF($A$1:A2,A2)
C 1 COUNTIF($A$1:A3,A3)
C 2 COUNTIF($A$1:A4,A4)
B 1 COUNTIF($A$1:A5,A5)
B 2 COUNTIF($A$1:A6,A6)
A 3 COUNTIF($A$1:A7,A7)
C 3 COUNTIF($A$1:A8,A8)
D 1 COUNTIF($A$1:A9,A9)
D 2 COUNTIF($A$1:A10,A10)
D 3 COUNTIF($A$1:A11,A11)
D 4 COUNTIF($A$1:A12,A12)
I have a data looks like this:
a b c
1 3 4
2 3 3
4 1 2
2 4 2
In another worksheet, I want to do the following calculation:
whenever A1 returns a (header of data worksheet), count number of items that are smaller and equal to 2 in column "a". (result will be 2)
if A1 returns b, count number of items that are smaller and equal to 2 in column "b". (result will be 1).
A1 has already been preset with formula such that it will show a or b or c as conditions changed.
I need the formula to be lean... I actually have 6 headers, so if I keep on using if functions, I will probably have to set 6 if functions in one cell...that can be overwhelming. index match cannot provide a range to work on...Any suggestion? thanks
I don't know vba. If you could provide a workable vba code, i don't mind. but i don't know how to read it...>.< please provide user manual for that. lol, thank you~
If your data is found on Sheet1 and the a is found on column a, b is found on column b etc. enter this formula on then next sheet on b1 when a1 is the column value:
=COUNTIF(INDIRECT("Sheet1!"&a1&":"&a1),"<=2")
The Indirect is for adding text to your reference.
If your data sheet is Sheet1, you could try the array formula:-
=SUM((Sheet1!A1:C1=$A$1)*(Sheet1!A2:C5<=2))
Must be entered with CtrlShiftEnter
(actually there are 3 items less than or equal to 2 in column A)
Or you can use the SUMPRODUCT version if you prefer not to use an array formula:-
=SUMPRODUCT((Sheet1!A1:C1=$A$1)*(Sheet1!A2:C5<=2))
Or you can use this INDEX/MATCH method which is probably more efficient:-
=COUNTIF(INDEX(Sheet1!A2:C5,,MATCH(A1,Sheet1!A1:C1,0)),"<="&2)
I have a column with the values in A excel sheet 1 1 1 2 2 2 3 3 3 4 4 4.... and i have in B excel sheet another column with values 1 2 4 ...., what i want is read values from B and see if they are in A sheet, for example if value 2 is in B sheet, then write true in a new column in sheet A in front of 2, and similarly false or nothing in front of value 3.
thanks
You can use a simple VLOOKUP - For example, assuming that the content of cell A1 of sheet B is 2, and that the sheet you call A is called SheetA, you can put the following formula in cell B1:
=IF(ISERROR(VLOOKUP(A1,SheetA!A:A,1,FALSE)),"",VLOOKUP(A1,SheetA!A:A,1,FALSE))
Use the approach described here:
http://spreadsheetpage.com/index.php/tip/comparing_two_lists_with_conditional_formatting/
Key formula is this: =COUNTIF(OldList,D2)=0, which you can use within the conditional formatting context as described, or to generate your true/false indicators as you mention in your question, i.e.:
=IF(COUNTIF(OldList,D2)=0,FALSE,TRUE)
OldList is just a range, and you don't need to use a named range. But if you don't name the range, just be sure to use absolute references for the range you're searching against.
Do you want a cool formula you can use to count the number of each matching value. Try this for your original post:
=IF(SUMPRODUCT(--($A1 =Sheet1!$A:$A) > 0), "True", "False")
And this to count the values: =SUMPRODUCT(--($A1 =Sheet1!$A:$A))