Finding the minimum of the functional - search

I have to find the minimum of the following functional
task photo
Functional to be minimized is first integral, the rest are constraints
Here is what i've done so far
my work photo
I wrote Lagrange equation, calculated it with WOLFRAM. By substitution x(0)=0 and x(1)=3 I calculate C1. I have to calculate Lambda and C2 which is dependent from lambda. I'm pretty shure that in order to do that I have to use this integral constraint, but I have no idea how.
Maybe someone has any idea? :)

Related

How do I use Excel Solver for exponents?

My equation is Q^Q^.25=6,512,786
I have the following input
And here is my solver
I keep getting errors.
The problem is with the non-standard way that Excel handles iterated exponents. Excel parses Q^Q^0.25 as (Q^Q)^0.25, which grows very rapidly. You probably intended Q^(Q^0.25), which, while still growing rapidly, doesn't explode in the same way. If you change your equation in D2 to
=C2^(C2^0.25)
and rerun the solver with the same settings (but a nonzero starting value at C2 since 0^0 is undefined) you will get convergence, to approximately 117.44.
On Edit: It turns out that in the programming world there is a greater diversity of how associativity of exponentiation is handled than I realized. This answer to a related question contains an interesting table surveying how different programming languages handle it.

How would I construct an integer optimization model corresponding to a graph

Suppose we're given some sort of graph where the feasible region of our optimization problem is given. For example: here is an image
How would I go on about constructing these constraints in an integer optimization problem? Anyone got any tips? Thanks!
Mate, I agree with the others that you should be a little more specific than that paint-ish picture ;). In particular you are neither specifying any objective/objective direction nor are you giving any context, what about this graph should be integer-variable related, except for the existence of disjunctive feasible sets, which may be modeled by MIP-techniques. It seems like your problem is formalization of what you conceptualized. However, in case you are just being lazy and are just interested in modelling disjunctive regions, you should be looking into disjunctive programming techniques, such as "big-M" (Note: big-M reformulations can be problematic). You should be aiming at some convex-hull reformulation if you can attain one (fairly easily).
Back to your picture, it is quite clear that you have a problem in two real dimensions (let's say in R^2), where the constraints bounding the feasible set are linear (the lines making up the feasible polygons).
So you know that you have two dimensions and need two real continuous variables, say x[1] and x[2], to formulate each of your linear constraints (a[i,1]*x[1]+a[i,2]<=rhs[i] for some index i corresponding to the number of lines in your graph). Additionally your variables seem to be constrained to the first orthant so x[1]>=0 and x[2]>=0 should hold. Now, to add disjunctions you want some constraints that only hold when a certain condition is true. Therefore, you can add two binary decision variables, say y[1],y[2] and an additional constraint y[1]+y[2]=1, to tell that only one set of constraints can be active at the same time. You should be able to implement this with the help of big-M by reformulating the constraints as follows:
If you bound things from above with your line:
a[i,1]*x[1]+a[i,2]-rhs[i]<=M*(1-y[1]) if i corresponds to the one polygon,
a[i,1]*x[1]+a[i,2]-rhs[i]<=M*(1-y[2]) if i corresponds to the other polygon,
and if your line bounds things from below:
-M*(1-y[1])<=-a[i,1]*x[1]-a[i,2]+rhs[i] if i corresponds to the one polygon,
-M*(1-y[1])<=-a[i,1]*x[1]-a[i,2]+rhs[i] if i corresponds to the other polygon.
It is important that M is sufficiently large, but not too large to cause numerical issues.
That being said, I am by no means an expert on these disjunctive programming techniques, so feel free to chime in, add corrections or make things clearer.
Also, a more elaborate question typically yields more elaborate and satisfying answers ;) If you had gone to the effort of making up a true small example problem you likely would have gotten a full formulation of your problem or even an executable piece of code in no time.

Does Julia have a way to solve for unknown variables

Is there a function in Julia that is similar to the solver function in Excel where I can provide and equation, and it will solve for the unknown variable? If not, does anybody know the math behind Excel's solver function?
I am not expecting anybody to solve the equation, but if it helps:
Price = (Earnings_1/(1+r)^1)+(Earnings_2/(1+r)^2)++(Earnings_3/(1+r)^3)+(Earnings_4/(1+r)^4)+(Earnings_5/(1+r)^5)+(((Earnings_5)(RiskFreeRate))/((1+r)^5)(1-RiskFreeRate))
The known variables are: Price, All Earnings, and RiskFreeRate. I am just trying to figure out how to solve for r.
Write this instead as an expression f(r) = 0 by subtracting Price over to the other side. Now it's a rootfinding problem. If you only have one variable you're solving for (looks to be the case), then Roots.jl is a good choice.
fzero(f, a::Real, b::Real)
will search for a solution between a and b for example, and the docs have more choices for algorithms when you don't know a range to start with and only give an initial condition for example.
In addition, KINSOL in Sundials.jl is good when you know you're starting close to a multidimensional root. For multidimensional and needing some robustness to the initial condition, I'd recommend using NLsolve.jl.
There's nothing out of the box no. Root finding is a science in itself.
Luckily for you, your function has an analytic first derivative with respect to r. That means that you can use Newton Raphson, which will be extremely stable for your function.
I'm sure you're aware your function behaves badly around r = -1.

Adjusting initial bullet angle to match user set distance(scope zero) (for math gods)

So my question is pretty specific, which means it was pretty hard to find anything that could help me on google or stackoverflow.
I want to give users the ability to set the distance/range on their guns. I have almost everything I need to make this happen, I just don't have the angle that I need to add on to the direction angle at which the bullet comes from. I don't know what equation/formula I would need to get this. I am not looking for anything code-specific, just an idea of what/how to do this.
Since I do not know what formula to use, I just started messing around with some numbers with this formula I found:
(This formula applies to actual sniper)
Range = 1000 * ActualTargetHeight/TargetHeightInMils(on the scope)
BulletDrop = BulletDropSpeed*Range^2/2*VelocityOfTheBullet
MilsToRaiseScope = 1000 * BulletDrop * RangeToTarget
I just replaced Range with the whatever zero the user is on.
I have a feeling I would just toss the MilsToRaiseScope into a trigonometry function. But I'm not sure.
If anyone is confused as to what I'm talking about, you can find an example of what I want in Battlefield 4 or any of the Arma games. With snipers, you can zero in the scope on to whatever distance you need so you won't have to adjust for bullet drop on the scope.
Sorry for the long question, just want to make sure everyone understands! :)
Mils corresponds to (military) angular measurement unit of 1/1000 of radian, so it is ready-to-use angle
Second formula looks strange. Height loss depends on time of flight:
dH = g*t^2/2 = g * (Range / VelocityOfTheBullet)^2 / 2
where g is 9.81 m/sec^2
I am using a 2D table look up for this.
I generate the table by doing a whole bunch of test firings at different angles, and record the path of the bullet for each angle.
To analytically determine this, it can get quite complex if aerodynamic drag is involved.
It is also discussed on this game-specific question.
For inspiration, this animated gif is great.

Excel Solver Curve Fitting Failing - MatLab recast

I am having some strange problems with excel's solver. Basically what I am trying to do is curve fit my data. I have two different lines, one is my calibration line and the other is the derived line that I am attempting to match up to the calibration line. My line depends on 19 different variable parameters (Perhaps this is too many? I have tried fewer without result) and I am using solver to adjust these parameters to make the two lines as close as possible.
For Example:
The QP column contains the variables I would like changed, changing these will draw me closer or further from the calibration curve. Each subsequent value of QP must be greater than the first.
Col=B Col=C
Power .QP_'
1 ..... 57000
2 ..... 65000
3 ..... 70000
4 ..... 80000
5 ..... 80000
Therefore my excel solver parameters look like this: C1:C19>=0,C1:C19<=100000 and C2>=C1, C3>=C2,C4>=C3... I have also tried making another column of the differences between each value and then saying that these must be diff>=0.
To compare this with my calibration curve I have taken the calibration curve data and subtracted my data derived from QP and then squared that to create my sum of the squares error. For example:
(Calibration-DerivedQP)^2=SS(x) <- where x represents the row number
Sum(SS(x))=SSE
SSE is what I have set solver to minimize. And upon changing QP everything automatically updates. There are no if statements being used and no pivot tables are used.
If I remove the parameters similar to C2>=C1 everything works perfectly, except the derived values are not feasible. But when the solver is run with these parameters, nothing gets changed and no matter which guesses I used as starting values ( so that I can ensure I haven't guessed a local minimum), the solver cannot improve upon my solution. This has led me to believe that something in my parameters is being broken, since I can very easily improve on my solution by guess and check. The rest of solvers settings are at the defaults, and the evolutionary method is used since my curve isn't smooth (I don't think) I had this working in the past and now something seems to be broken. Any ideas are appreciated! Thank you so much! Sorry if I am missing any critical information. I am also familiar with matlab and R if there are better methods in those languages.
I found the solution to my problem. I don't know if this will be helpful to anyone else since my problem vague and pretty specific to me. That being said, my problem was in the constraints. I changed some data on my excel sheet to allow for fewer constraints. An example might look like this:
Guess..........Squared......Added..................Q
-12..............(-12)^2....... 0
-16..............(-16)^2.......=(-16)^2+0.............256
+7.................(7)^2..........=(7)^2+(-16)^2+0....305
Now I allow solver to guess any number subject to minimal constraints.
Essentially, what is happening now, is the excel sheet allows for any guess that solver makes to work. By squaring the numbers it give me positive values, and the added column ensures that each successive value is equal to or greater than the first. This means there are very few constraints. I also changed the solver option from evolutionary to GRG Nonlinear.
Tips for getting solver to work:
Try and use the spreadsheet to set constraints (other than bounds, bounds seem to be good) wherever possible, the more constraints that I set in solver, the less likely my solution was to work.
Hope that helps, sorry if I have provided any incorrect information.

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