We have run into a high CPU usage situation when one of our EventHandlers broke.
Let's say we have several consumers (EventHanlders), that are configured to run sequentially over the buffer. If the first EventHandler throws an exception, is there a way to halt (and awake them later) all the other EventHandlers.
What we are doing is putting the failing thread to sleep and after we try to consume the same event again. But we have notice that the other threads continue running and trying to read from the RingBuffer even where there are not events to read, raising the CPU behind acceptable levels.
For the moment I'm discarding that this is happening because WaitStrategy of the disruptor, because under normal conditions is working as expected. We are using a BlockingWaitStrategy there.
Some more explanations for the sake of the example
INPUT -> [A*] -> [B] -> [C] -> [D]
Where INPUT is the event polled from the RingBuffer and A, B, C and D are the different EventHandlers that are executing sequentially. A* is the consumer throwing an exception.
What we want to achieve is that when consumer A cannot consume an event (eg. after an exception happens), the OnEvent(...) method of that consumer does not exit but will stay in a loop with regular sleeps trying to consume again the same event when it wakes up. In the meanwhile all the other consumers should be parked or sleeping until A succeeds.
We are using disruptor version 3.3.0.
I have been googling but haven't found a working solution.
Thanks in advance.
Salva.
A college has founded out that this issue could be related with a while loop in the waitFor method in BlockingWaitStrategy.
long availableSequence;
while((availableSequence = dependentSequence.get()) < sequence) {
barrier.checkAlert();
}
After several test we have came across this possible solution:
var availableSequence: Long = dependentSequence.get()
while(availableSequence < sequence) {
this.lock.lock()
this.lock.unlock()
availableSequence = dependentSequence.get()
}
availableSequence
Basically it makes that one thread locks the resource and with that we park momentary all the other consumers avoiding the high usage of CPU.
The second point here is the while condition. This is happening just when the available sequence (that is the sequence of the dependent threads) is below the current sequence number. And that only happens when one thread is holding the lock, for example when A throws the exception.
We still investigating if this is a valid solution, or if it can have some undesired side effects.
Any though about it is welcome.
Related
I have a MailBoxProcessor, which does the following things:
Main loop (type AsyncRunner: https://github.com/kkkmail/ClmFSharp/blob/master/Clm/ContGen/AsyncRun.fs#L257 – the line number may change as I keep updating the code). It generates some "models", compiles each of them into a model specific folder, spawns them as external processes, and then each model uses WCF to "inform" AsyncRunner about its progress by calling updateProgress. A model may take several days to run. Once any of the models is completed, the runner generates / spawns more. It is designed to run at 100% processor load (but with priority: ProcessPriorityClass.BelowNormal), though I can specify a smaller number of logical cores to use (some number between 1 and Environment.ProcessorCount). Currently I "async"-ed almost everything that goes inside MailBoxProcessor by using … |> Async.Start to ensure that I "never ever" block the main loop.
I can "ask" the runner (using WCF) about its state by calling member this.getState () = messageLoop.PostAndReply GetState.
OR I can send some commands to it (again using WCF), e.g. member this.start(), member this.stop(), …
Here is where it gets interesting. Everything works! However, if I run a "monitor", which would ask for a state by effectively calling PostAndReply (exposed as this.getState ()) in an infinite loop, the after a while it sort of hangs up. I mean that it does eventually return, but with some unpredictably large delays (like a few minutes). At that same time, I can issue commands and they do return fast while getState still has not returned.
Is it possible to make it responsive at nearly 100% load? Thanks a lot!
I would suggest not asyncing anything(other than your spawning of processes) in your main program, since your code creates additional processes. Your main loop is waiting on the loop return to continue before processing the GetState() method.
Vert.x have many thread pool, eventLoopGroup,acceptorEventLoopGroup,internalBlockingPool,workerPool.
Why need so many?
FileSystem read file will use internalBlockingPool, but like this code executeBlocking will use workerPool.
And in this code why resultHandler execute in eventLoop thread not
workpool?
vertx.executeBlocking(future -> {
System.out.println(Thread.currentThread().getName());
future.complete();
}, r -> {
System.out.println(Thread.currentThread().getName());
});
In my understanding eventloop just a single thread is endless loop for channel.If nothing to do with network, no need to use eventLoopGroup.
how to understand event in Vert.x, can give some Vert.x code not netty code？
Event loops: there can be more than one event loop thread. There typically will be more than one event loop thread (it depends on your number of cores). For example,if you start N instances of a verticle, you will want it to spread across multiple cores using multiple event loops. In the docs, look up the multi-reactor pattern.
Vert.x works differently here. Instead of a single event loop, each
Vertx instance maintains several event loops. By default we choose the
number based on the number of available cores on the machine, but this
can be overridden.
http://vertx.io/docs/vertx-core/java/#_reactor_and_multi_reactor
Regarding your question about the result handler: The execute blocking function will run on a worker thread, but once it is all done, it will be pushed over to the event loop thread to finish the result handler. This behavior helps with keeping certain logic on the event loop thread.
Regarding the other thread groups, they just handle specific functionality in vert.x. If you are stressed about the number of threads in vert.x, I would not worry about it. Vert.x does a good job keeping the OS threads to a minimum while maintaining high functionality and throughput.
I'm reading C++ Concurrency in Action by Anthony Williams, and don't understand its push implementation of the lock_free_stack class. Listing 7.12 to be precise
void push(T const& data)
{
counted_node_ptr new_node;
new_node.ptr=new node(data);
new_node.external_count=1;
new_node.ptr->next=head.load(std::memory_order_relaxed)
while(!head.compare_exchange_weak(new_node.ptr->next,new_node, std::memory_order_release, std::memory_order_relaxed));
}
So imagine 2 threads (A, B) calling push function. Both of them reach while loop but not start it. So they both read the same value from head.load(std::memory_order_relaxed).
Then we have the following things going on:
B thread gets swiped out for any reason
A thread starts the loop and obviously successfully adds a new node to the stack.
B thread gets back on track and also starts the loop.
And this is where it gets interesting as it seems to me.
Because there was a load operation with std::memory_order_relaxed and compare_exchange_weak(..., std::memory_order_release, ...) in case of success it looks like there is no synchronization between threads whatsoever.
I mean it's like std::memory_order_relaxed - std::memory_order_release and not std::memory_order_acquire - std::memory_order_release.
So B thread will simply add a new node to the stack but to its initial state when we had no nodes in the stack and reset head to this new node.
I was doing my research all around this subject and the best i could find was in this post Does exchange or compare_and_exchange reads last value in modification order?
So the question is, is it true? and all RMW functions see the last value in modification order? No matter what std::memory_order we used, if we use RMW operation it will synchronize with all threads (CPU and etc) and find the last value to be written to the atomic operation upon it is called?
So after some research and asking a bunch of people I believe I found the proper answer to this question, I hope it'll be a help to someone.
So the question is, is it true? and all RMW functions see the last
value in modification order?
Yes, it is true.
No matter what std::memory_order we used, if we use RMW operation it
will synchronize with all threads (CPU and etc) and find the last
value to be written to the atomic operation upon it is called?
Yes, it is also true, however there is something that needs to be highlighted.
RMW operation will synchronize only the atomic variable it works with. In our case, it is head.load
Perhaps you would like to ask why we need release - acquire semantics at all if RMW does the synchronization even with the relaxed memory order.
The answer is because RMW works only with the variable it synchronizes, but other operations which occurred before RMW might not be seen in the other thread.
lets look at the push function again:
void push(T const& data)
{
counted_node_ptr new_node;
new_node.ptr=new node(data);
new_node.external_count=1;
new_node.ptr->next=head.load(std::memory_order_relaxed)
while(!head.compare_exchange_weak(new_node.ptr->next,new_node, std::memory_order_release, std::memory_order_relaxed));
}
In this example, in case of using two push threads they won't be synchronized with each other to some extent, but it could be allowed here.
Both threads will always see the newest head because compare_exchange_weak
provides this. And a new node will be always added to the top of the stack.
However if we tried to get the value like this *(new_node.ptr->next) after this line new_node.ptr->next=head.load(std::memory_order_relaxed) things could easily turn ugly: empty pointer might be dereferenced.
This might happen because a processor can change the order of instructions and because there is no synchronization between threads the second thread could see the pointer to a top node even before that was initialized!
And this is exactly where release-acquire semantic comes to help. It ensures that all operations which happened before release operation will be seen in acquire part!
Check out and compare listings 5.5 and 5.8 in the book.
I also recommend you to read this article about how processors work, it might provide some essential information for better understanding.
memory barriers
I'm new to multithread programming. I wrote this simple multi thread program with Qt. But when I run this program it freezes my GUI and when I click inside my widow, it responds that your program is not responding .
Here is my widget class. My thread starts to count an integer number and emits it when this number is dividable by 1000. In my widget simply I catch this number with signal-slot mechanism and show it in a label and a progress bar.
Widget::Widget(QWidget *parent) :
QWidget(parent),
ui(new Ui::Widget)
{
ui->setupUi(this);
MyThread *th = new MyThread;
connect( th, SIGNAL(num(int)), this, SLOT(setNum(int)));
th->start();
}
void Widget::setNum(int n)
{
ui->label->setNum( n);
ui->progressBar->setValue(n%101);
}
and here is my thread run() function :
void MyThread::run()
{
for( int i = 0; i < 10000000; i++){
if( i % 1000 == 0)
emit num(i);
}
}
thanks!
The problem is with your thread code producing an event storm. The loop counts very fast -- so fast, that the fact that you emit a signal every 1000 iterations is pretty much immaterial. On modern CPUs, doing a 1000 integer divisions takes on the order of 10 microseconds IIRC. If the loop was the only limiting factor, you'd be emitting signals at a peak rate of about 100,000 per second. This is not the case because the performance is limited by other factors, which we shall discuss below.
Let's understand what happens when you emit signals in a different thread from where the receiver QObject lives. The signals are packaged in a QMetaCallEvent and posted to the event queue of the receiving thread. An event loop running in the receiving thread -- here, the GUI thread -- acts on those events using an instance of QAbstractEventDispatcher. Each QMetaCallEvent results in a call to the connected slot.
The access to the event queue of the receiving GUI thread is serialized by a QMutex. On Qt 4.8 and newer, the QMutex implementation got a nice speedup, so the fact that each signal emission results in locking of the queue mutex is not likely to be a problem. Alas, the events need to be allocated on the heap in the worker thread, and then deallocated in the GUI thread. Many heap allocators perform quite poorly when this happens in quick succession if the threads happen to execute on different cores.
The biggest problem comes in the GUI thread. There seems to be a bunch of hidden O(n^2) complexity algorithms! The event loop has to process 10,000 events. Those events will be most likely delivered very quickly and end up in a contiguous block in the event queue. The event loop will have to deal with all of them before it can process further events. A lot of expensive operations happen when you invoke your slot. Not only is the QMetaCallEvent deallocated from the heap, but the label schedules an update() (repaint), and this internally posts a compressible event to the event queue. Compressible event posting has to, in worst case, iterate over entire event queue. That's one potential O(n^2) complexity action. Another such action, probably more important in practice, is the progressbar's setValue internally calling QApplication::processEvents(). This can, recursively call your slot to deliver the subsequent signal from the event queue. You're doing way more work than you think you are, and this locks up the GUI thread.
Instrument your slot and see if it's called recursively. A quick-and-dirty way of doing it is
void Widget::setNum(int n)
{
static int level = 0, maxLevel = 0;
level ++;
maxLevel = qMax(level, maxLevel);
ui->label->setNum( n);
ui->progressBar->setValue(n%101);
if (level > 1 && level == maxLevel-1) {
qDebug("setNum recursed up to level %d", maxLevel);
}
level --;
}
What is freezing your GUI thread is not QThread's execution, but the huge amount of work you make the GUI thread do. Even if your code looks innocuous.
Side Note on processEvents and Run-to-Completion Code
I think it was a very bad idea to have QProgressBar::setValue invoke processEvents(). It only encourages the broken way people code things (continuously running code instead of short run-to-completion code). Since the processEvents() call can recurse into the caller, setValue becomes a persona-non-grata, and possibly quite dangerous.
If one wants to code in continuous style yet keep the run-to-completion semantics, there are ways of dealing with that in C++. One is just by leveraging the preprocessor, for example code see my other answer.
Another way is to use expression templates to get the C++ compiler to generate the code you want. You may want to leverage a template library here -- Boost spirit has a decent starting point of an implementation that can be reused even though you're not writing a parser.
The Windows Workflow Foundation also tackles the problem of how to write sequential style code yet have it run as short run-to-completion fragments. They resort to specifying the flow of control in XML. There's apparently no direct way of reusing standard C# syntax. They only provide it as a data structure, a-la JSON. It'd be simple enough to implement both XML and code-based WF in Qt, if one wanted to. All that in spite of .NET and C# providing ample support for programmatic generation of code...
The way you implemented your thread, it does not have its own event loop (because it does not call exec()). I'm not sure if your code within run() is actually executed within your thread or within the GUI thread.
Usually you should not subclass QThread. You probably did so because you read the Qt Documentation which unfortunately still recommends subclassing QThread - even though the developers long ago wrote a blog entry stating that you should not subclass QThread. Unfortunately, they still haven't updated the documentation appropriately.
I recommend reading "You're doing it wrong" on Qt Blog and then use the answer by "Kari" as an example of how to set up a basic multi-threaded system.
But when I run this program it freezes my GUI and when I click inside my window,
it responds that your program is not responding.
Yes because IMO you're doing too much work in thread that it exhausts CPU. Generally program is not responding message pops up when process show no progress in handling application event queue requests. In your case this happens.
So in this case you should find a way to divide the work. Just for the sake of example say, thread runs in chunks of 100 and repeat the thread till it completes 10000000.
Also you should have look at QCoreApplication::processEvents() when you're performing a lengthy operation.
I have a single-threaded linux app which I would like to make parallel. It reads a data file, creates objects, and places them in a vector. Then it calls a compute-intensive method (.5 second+) on each object. I want to call the method in parallel with object creation. While I've looked at qt and tbb, I am open to other options.
I planned to start the thread(s) while the vector was empty. Each one would call makeSolids (below), which has a while loop that would run until interpDone==true and all objects in the vector have been processed. However, I'm a n00b when it comes to threading, and I've been looking for a ready-made solution.
QtConcurrent::map(Iter begin,Iter end,function()) looks very easy, but I can't use it on a vector that's changing in size, can I? And how would I tell it to wait for more data?
I also looked at intel's tbb, but it looked like my main thread would halt if I used parallel_for or parallel_while. That stinks, since their memory manager was recommended (open cascade's mmgt has poor performance when multithreaded).
/**intended to be called by a thread
\param start the first item to get from the vector
\param skip how many to skip over (4 for 4 threads)
*/
void g2m::makeSolids(uint start, uint incr) {
uint curr = start;
while ((!interpDone) || (lineVector.size() > curr)) {
if (lineVector.size() > curr) {
if (lineVector[curr]->isMotion()) {
((canonMotion*)lineVector[curr])->setSolidMode(SWEPT);
((canonMotion*)lineVector[curr])->computeSolid();
}
lineVector[curr]->setDispMode(BEST);
lineVector[curr]->display();
curr += incr;
} else {
uio::sleep(); //wait a little bit for interp
}
}
}
EDIT: To summarize, what's the simplest way to process a vector at the same time that the main thread is populating the vector?
Firstly, to benefit from threading you need to find similarly slow tasks for each thread to do. You said your per-object processing takes .5s+, how long does your file reading / object creation take? It could easily be a tenth or a thousandth of that time, in which case your multithreading approach is going to produce neglegible benefit. If that's the case, (yes, I'll answer your original question soon incase it's not) then think about simultaneously processing multiple objects. Given your processing takes quite a while, the thread creation overhead isn't terribly significant, so you could simply have your main file reading/object creation thread spawn a new thread and direct it at the newly created object. The main thread then continues reading/creating subsequent objects. Once all objects are read/created, and all the processing threads launched, the main thread "joins" (waits for) the worker threads. If this will create too many threads (thousands), then put a limit on how far ahead the main thread is allowed to get: it might read/create 10 objects then join 5, then read/create 10, join 10, read/create 10, join 10 etc. until finished.
Now, if you really want the read/create to be in parallel with the processing, but the processing to be serialised, then you can still use the above approach but join after each object. That's kind of weird if you're designing this with only this approach in mind, but good because you can easily experiment with the object processing parallelism above as well.
Alternatively, you can use a more complex approach that just involves the main thread (that the OS creates when your program starts), and a single worker thread that the main thread must start. They should be coordinated using a mutex (a variable ensuring mutually-exclusive, which means not-concurrent, access to data), and a condition variable which allows the worker thread to efficiently block until the main thread has provided more work. The terms - mutex and condition variable - are the standard terms in the POSIX threading that Linux uses, so should be used in the explanation of the particular libraries you're interested in. Summarily, the worker thread waits until the main read/create thread broadcasts it a wake-up signal indicating another object is ready for processing. You may want to have a counter with index of the last fully created, ready-for-processing object, so the worker thread can maintain it's count of processed objects and move along the ready ones before once again checking the condition variable.
It's hard to tell if you have been thinking about this problem deeply and there is more than you are letting on, or if you are just over thinking it, or if you are just wary of threading.
Reading the file and creating the objects is fast; the one method is slow. The dependency is each consecutive ctor depends on the outcome of the previous ctor - a little odd - but otherwise there are no data integrity issues so there doesn't seem to be anything that needs to be protected by mutexes and such.
Why is this more complicated than something like this (in crude pseudo-code):
while (! eof)
{
readfile;
object O(data);
push_back(O);
pthread_create(...., O, makeSolid);
}
while(x < vector.size())
{
pthread_join();
x++;
}
If you don't want to loop on the joins in your main then spawn off a thread to wait on them by passing a vector of TIDs.
If the number of created objects/threads is insane, use a thread pool. Or put a counter is the creation loop to limit the number of threads that can be created before running ones are joined.
#Caleb: quite -- perhaps I should have emphasized active threads. The GUI thread should always be considered one.