I am trying to find a formula that will represent the best prize from my prizes list.
I have two different variables for each prize:
1. How many people want that prize
2. The amount of money that each of the people who wanted the prize was want to invest in the prize.
For example:
1. 6 people invests 4 coins each for the prize.
2. 4 people invests 6 coins each for the prize.
In my opinion the amount of peoples have more wight than the money invested.
Is there any formula for this calculation.
Thank
how about
=A2^2*B2
it will emphasize "crowded" options
so 10 persons, 4 coins will be equal to 2 persons, 100 coins or 4 persons 25 coins or 5 persons 16 coins etc.
Related
I am tracking the progress of students reading books in class. For the number of books they read they get a reward. It is not 1 book = prize, 2 books = prize. Instead there are dead spaces along the way, for example there is no reward for books 3 and 4 but there is for 5 books. I want to be able to input the number of books each student read and have it update as to what the next reward will be. For example:
List one
Name Books Next Tier Prize
Sally 4 5 Candy Store
Luke 1 2 Extra coloring time
Jane 8 10 10 Extra minutes on the playground
And so on
The table for rewards would be
Books Prize
1 Ribbon
2 Extra coloring time
5 Candy Store
7 Prize bucket
10 10 Extra minutes on the playground
And so on
This is just an abbreviated list and I have used if then statements previously. However the previous list that had 18 values was cumbersome as it was, the new list has 35 values.
I have used if/then statements in the past in combination with vlookup, but with the increased number of values, it just seemed daunting. I could still use an if statement but was hoping there would be an easier way.
Put this in C2 and copy over and down:
=INDEX(F$2:F$6,IFERROR(MATCH($B2,$F$2:$F$6),0)+1)
How can I use time as a factor in calculating consistency/reliability.
Given a simplified scenario :
If a person ate at 1 apple on a day, a score will be given 1 to that person.
Out of 10 days, john has 5 days where he ate at 1 apple.
Out of 30days, ben has 15 days where he ate at 1 apple.
Currently the way I calculated their consistency is by giving them a score using X/Y where X is the number of days a person ate 1 apple and Y is the total number of days.
For john, his score will be 5/10 == 0.5.
For ben, his score will be 15/30 == 0.5.
But clearly, ben is more much consistent as due to the number of days(30). Is there a way to use the time to enhance the score so that I can clearly state that ben is more consistent with numbers.
thank you.
9 chairs numbered 1 to 9. 3 women and 4 men wish to occupy one chair each. First the women will choose the chairs from amongst the chair marked 1 to 5, then the men select chairs from amongst the remaining. what is the possible number of arrangements?
The answer should be 150, but i got 1440 instead can someone tell me how to get the correct answer?
First, the 3 women must choose amongst the 5 first chairs. The number of possible ways is given by the binomial coefficient Binomial(n, k) (or "n choose k") with n=5 and k=3, which is equal to 10. This give you the number of ways to seat the 3 women when 5 chairs are available.
After that, there are 6 seats remaining since 3 have are now occupied, and the 4 men must choose among these remaining seats. The number of ways to seat the 4 men when 6 chairs are available is Binomial(6, 4) = 15.
Now these two processes happen one after the other, so that the number of possibilities for your scenario is simply the multiplication of both, i.e., 10*150=150. Indeed, your first find seats for women (10 configurations), and for each possible configuration, there are 15 ways to seat the men, so that 150 configurations in total to accommodate both women and men.
e.g. There are 300 apples. There are 100 people. Each person has a preset value (represented as a number 1 to 5). 1=1 apple, if their value is 5 they get 5 apples etc. But there are 300 apples available so each person is going to get more then the value says they "deserve". Or one day there are only 200 apples and every one gets less then what the value states says they "deserve". Is this possible in excel?
NAME VALUE
john 5
james 5
sam 4
matt 5
mike 3
steve 2
etc...
This absolutely sounds like a perfect problem for Solver to handle. As you know, this in included within Excel's addins. It can deal with all the variables you mentioned.
You need 100 lbs of bird feed. John's bag can carry 15 lbs and Mark's bag can carry 25 lbs. Both guys have to contribute exactly the same total amount each. What's the lowest number of trips each will have to take?
I have calculated this using systems of equations.
15x + 25y = 100
15x - 25y = 0
This equals out to:
John would have 3.33 trips and Mark would have 2 trips. Only one problem: you can't have 1/3 of a trip.
The correct answers is:
John would take 5 trips (75 lbs) and Mark would take 3 trips (75 lbs).
How do you calculate this? Is there an excel formula which can do both layers of this?
Assuming you put the total bird feed required in A1 and John's and Mark's bag limits in B1 and B2 respectively, then this formula in C1:
=MATCH(TRUE,INDEX(2*ROW(INDIRECT("1:100"))*LCM($B$1:$B$2)>=$A$1,,),0)*LCM($B$1:$B$2)/B1
will give the lowest number of trips required of John. Copying this formula down to C2 will give the equivalent result for Mark.
Note that the 100 in the part:
ROW(INDIRECT("1:100"))
was arbitrarily chosen and will give correct results providing neither John nor Mark is required to make more than twice that number of trips, i.e. 200. Obviously you can amend this value if you feel it necessary (up to a theoretical limit of 2^20).
Regards
Since John and Mark need to carry the same total amount of bird feed, what they will carry has to be a multiple of the least common multiple.
Since they both carry that amount the total amount will always be an even multiple of the LCM.
So find the least even multiple of the LCM that is larger than 100. And calculate the number of trips John and Mark will have to take from that.
For John:
CEILING(100/(2*LCM(15; 25));1)*LCM(15;25)/15
For Mark:
CEILING(100/(2*LCM(15; 25));1)*LCM(15;25)/25