So if the user input is:
user = input('Enter numbers here in the following format "10 12 14": ')
then the user inputs numbers 10 11 12 in that exact way, not separated by commas, and all in one string separated by spaces, how can i add the numbers to a list and then convert them to int instead of string
One approach to achieve this would be by the following,
list(map(int,input('Enter Numbers: ').split()))
This will ask the user for numbers to enter which will return back a str object as the user has entered them via input. The split call at the end, returns a comma separated list containing those numbers. They are still considered str at this point.
The next map function accepts a fnc and list arguments, which will apply the fnc argument to each item within the list. In this case, it will cast each value in the list of str objects to an int type.
The last step would be to convert the map object we had created into a list via the list() call.
Related
I have a list of values as follows:
no column
1. 111-222-11
2. 112-333-12
3. 113-444-13
I want to format the value from 111-222-11 to 111-222-011 and format the other values similarly. Here is my code snippet in Python 3, which I am trying to use for that:
‘{:03}-{:06}-{:03}.format(column)
I hope that you can help.
Assuming that column is a variable that can be assigned string values 111-222-11, 112-333-12, 113-444-13 and so on, which you want to change to 111-222-011, 112-333-012, 113-444-013 and so on, it appears that you tried to use a combination of slice notation and format method to achieve this.
Slice notation
Slice notation, when applied to a string, treats it as a list-like object consisting of characters. The positional index of a character from the beginning of the string starts from zero. The positional index of a character from the end of the string starts with -1. The first colon : separates the beginning and the end of a slice. The end of the slice is not included into it, unlike its beginning. You indicate slices as you would indicate indexes of items in a list by using square brackets:
'111-222-11'[0:8]
would return
'111-222-'
Usually, the indexes of the first and the last characters of the string are skipped and implied by the colon.
Knowing the exact position where you need to add a leading zero before the last two digits of a string assigned to column, you could do it just with slice notation:
column[:8] + '0' + column[-2:]
format method
The format method is a string formatting method. So, you want to use single quotes or double quotes around your strings to indicate them when applying that method to them:
'your output string here'.format('your input string here')
The numbers in the curly brackets are not slices. They are placeholders, where the strings, which are passed to the format method, are inserted. So, combining slices and format method, you could add a leading zero before the last two digits of a column string like this:
'{0}0{1}'.format(column[:8], column[-2:])
Making more slices is not necessary because there is only one place where you want to insert a character.
split method
An alternative to slicing would be using split method to split the string by a delimiter. The split method returns a list of strings. You need to prefix it with * operator to unpack the arguments from the list before passing them to the format method. Otherwise, the whole list will be passed to the first placeholder.
'{0}-{1}-0{2}'.format(*column.split('-'))
It splits the string into a list treating - as the separator and puts each item into a new string, which adds 0 character before the last one.
Given a string in this format: "Here is some random text, like 5/4=3./12/3/4", so "Again some spaces\n/12/12/12" would count as well... I have to convert this into a four part tuple, such as (12,3,4,"Here is some random text, like 5/4=3") where the first three numbers are made into integers. how would I go about doing this using split and slicing?
I would like to use the command text to type numbers within 57 hexagons. I want to use a loop:
for mm=1:57
text(x(m),y(m),'m')
end
where x(m) and y(m) are the coordinates of the text .
The script above types the string "m" and not the value of m. What am I doing wrong?
Jubobs pretty much told you how to do it. Use the num2str function. BTW, small typo in your for loop. You mean to use mm:
for mm=1:57
text(x(mm),y(mm),num2str(mm));
end
The reason why I've even decided to post an answer is because you can do this vectorized without a loop, which I'd also like to write an answer for. What you can do place each number into a character array where each row denotes a unique number, and you can use text to print out all numbers simultaneously.
m = sprintfc('%2d', 1:57);
d = reshape([m{:}], 2, 57).';
text(x, y, d);
The (undocumented!) function sprintfc takes a formatting specifier and an array and creates a cell array of strings where each cell is the string version of each element in the array you supply. In order to ensure that the character array has the same number of columns per row, I ensure that each string takes up 2 characters, and so any number less than 10 will have a blank space at the beginning. I then convert the cell array of strings into a character array by converting the cell array into a comma-separated list of strings and I reshape the matrix into an acceptable form, and then I call text with all of the pairs of x and y, with the corresponding labels in m together on the screen.
I want to extract only last two numeric values from a string variable and assign it to a new variable. Firstly i have extracted all the numeric values from the string using the code below and assigned it to a new variable but i ultimately want to extract only the last two numeric values so is there any better way to do this.
UI_DUM = input(compress(Prod_Desc,,"kd"),best.);
And one more question is: how to assign a temp variable for doing some manupulation work in SAS?
Here is the code.
You are doing it right, to remove the characters and keeping only digits. The same is being done for variable "temp1"(in the below code).
In the second step, using the length function, to calculate the total length of the string which now contains only digits. In the third step using the substr function to extract the last two digits.
If you want to do it in one statement, "final" variable is the answer.
LENGTH Function - Returns the length of a non-blank character string, excluding
trailing blanks, and returns 1 for a blank character string
compress function with "kd" option - would keep only digits.
COMPRESS(<, chars><, modifiers>)
Modifier - specifies a character constant, variable, or expression in which each non-blank character modifies the action of the COMPRESS function. Blanks are ignored. The following characters can be used as modifiers.
d or D adds digits to the list of characters.
k or K keeps the characters in the list instead of removing them
substr function - Extracts a substring from an argument -
SUBSTR(string, position<,length>)
data _null_;
Test_string="ada13117a1w11da1286s";
temp1=compress(Test_string, , 'kd');
temp2=length(temp1);
temp3=substr(temp1,temp2-1,2);
final=substr(compress(Test_string, , 'kd'),length(compress(temp1))-1,2);
put _all_;
run;
Regarding the temp variable, there is no such one in SAS. Just use any variable name and use the drop statement in final dataset like below;
data test(drop = temp); /*Would work as the temp variable*/
temp= 2*balance;/*just for example*/
/*use the temp in further calculations*/
run;
A somewhat different take:
data want;
set have;
UI_DUM = input(compress(Prod_Desc,,"kd"),best.);
UI_DUM_last2 = mod(UI_DUM,100);
run;
You could do that all in one line of course as well. This uses the numeric modulo function to simply give you the last 2 digits (any number modulo 100 will return the final 2 digits).
I am having an issue printing a string in MATLAB (2012a) using the fprtinf command (and sprintf).
I have an array of 12 dates (numeric). I am converting them to strings using the following command:
months = datestr(data(:,1)-365,12); %Mar13 format
I obtain the following (and desired) output when I call the months variable:
Jan12
Feb12
Mar12
Apr12
etc..
The issue is when I call the fprintf or sprintf, say with the following code:
fprintf('%s', months(1))
I will only get the first letter of the month and not the full string. Any idea how to make it print the full string?
Thanks!
The resulting data type for your months variable is an NxM character array. You need to process it as a cell array of strings instead.
dates = num2cell(data(:,1)-365)
months = cellfun(#(x) datestr(x,12),dates,'UniformOutput',false)
fprintf('%s', months{1})
should get you what you want.
Simply change your call to
fprintf('%s', months(1, :))
datestr returns the string of each of the supplied dates on a separate row.
Alternatively you could use the cellstr function to convert the result to a cell array (this would also work with non fixed-length date formats like 'dddd')
months = cellstr(months);
fprintf('%s', months{1});