I'm fairly new to shell and I'm trying to use wget to download a .zip file from one directory to another. The only file in the directory I am copying the file from is the .zip file. However when I use wget IP address/directory it downloads an index.html file instead of the .zip. Is there something I am missing to get it to download the .zip without having to explicitly state it?
wget is the utility to download file from web.
you have mentioned you want to copy from one directory to other. you meant it is on same server/node?
In that case you can simply use cp command
And if you want if from any other server/node [file transfer] you can use scp or ftp
Related
in Python I have the following command executed unzip '{dir}ATTOM_RECORDER/*.zip' -d {dir}ATTOM_RECORDER/ as a bash command. The python call works perfectly. my question is about the unzip command itself.
for some reason when unzip is called to expand any relevent zip files in the folder specified, not all the files WITHIN the zip is extracted. There's usually a rpt and a txt file. However, sometimes the txt file is not coming out and I do not have an error command.
How can I ensure the txt file is guaranteed to be extracted before moving on?
Thanks
While you want to unzip your specific zip file. There are many option to decompress any file from zip files. Easiest way is the ‘-l’ option with unzip command is used to list the contents of a zip file after extracting it.
Syntax: unzip -l [file_name.zip]
I used command zip in linux (RedHat), this is my command:
zip -r /home/username/folder/compress/zip.zip /home/username/folder/compressed/*
Then, i open file zip.zip, i see architecture as path folder compress.
I want to in folder zip only consist list file *.txt
Because i used this command in script crontab hence i can't use command cd to path folder before run command zip
Please help me
I skimmed the zip man page and this is what I have found. There is not an option archive files relative to a different directory. The closest I have found is zip -j which removes the entire path and stores the files directly in the zip rather than sub directories. I do not know what happens in the case of file name conflicts such as if /home/username/folder/compressed/a.txt and /home/username/folder/compressed/subdir/a.txt both exist. If this is not a problem for you, you can use this option, but I am concerned because you did specify the -r option indicating that you expect zip to traverse sub folders.
I also thought of the possibility that your script could somehow call zip with a different working directory, but I took a look at this unix stack exchange page and it looks like their options use cd.
I have to admit I do not understand why you cannot use cd and I am very curious about it. You said something about using crontab, but I have never heard of anything wrong with changing directories in a crontab script.
I used option -j in command zip
zip -jr /home/username/folder/compress/zip.zip /home/username/folder/compressed/*
and i was yet settled this problem, thanks
I'm currently using wget to download specific files from a remote server. The files are updated every week, but always have the same file names. e.g new upload file1.jpg will replace local file1.jpg
This is how I am grabbing them, nothing fancy :
wget -N -P /path/to/local/folder/ http://xx.xxx.xxx.xxx/remote/files/file1.jpg
This downloads file1.jpg from the remote server if it is newer than the local version then overwrites the local one with the new one.
Trouble is, I'm doing this for over 100 files every week and have set up cron jobs to fire the 100 different download scripts at specific times.
Is there a way I can use a wildcard for the file name and have just one script that fires every 5 minutes for example?
Something like....
wget -N -P /path/to/local/folder/ http://xx.xxx.xxx.xxx/remote/files/*.jpg
Will that work? Will it check the local folder for all current file names, see what is new and then download and overwrite only the new ones? Also, is there any danger of it downloading partially uploaded files on the remote server?
I know that some kind of file sync script between servers would be a better option but they all look pretty complicated to set up.
Many thanks!
You can specify the files to be downloaded one by one in a text file, and then pass that file name using option -i or --input-file.
e.g. contents of list.txt:
http://xx.xxx.xxx.xxx/remote/files/file1.jpg
http://xx.xxx.xxx.xxx/remote/files/file2.jpg
http://xx.xxx.xxx.xxx/remote/files/file3.jpg
....
then
wget .... --input-file list.txt
Alternatively, If all your *.jpg files are linked from a particular HTML page, you can use recursive downloading, i.e. let wget follow links on your page to all linked resources. You might need to limit the "recursion level" and file types in order to prevent downloading too much. See wget --help for more info.
wget .... --recursive --level=1 --accept=jpg --no-parent http://.../your-index-page.html
I have downloaded 1200 jpeg files using wget. But the name of the files are based on links from which they are downloaded.
For ex.
http://www.*.*.*/index.php?id=0MwfTcqbP9dl1_icR3_gVezE8tlpUJt-wumA5hHjpjk will download the file with name index.php?id=0MwfTcqbP9dl1_icR3_gVezE8tlpUJt-wumA5hHjpjk.jpg but its name on server is different. Now I want all the files to be named as the name on the server.
One way is to delete all the files and re-download it with wget option --content-dispostion but total size of the download is 8GB and downloading it again is not a good option.
How can I rename all the downloaded files as names on server?
Edit: Name of the jpeg files downloaded from the links using wget --content-disposition or browser would be like 2014:08:09_18:07:51_IMG_5543.jpg (not created by wget, it's oringinal name on server, uploader's file name). I want all the files to be named as their oringinal names without again downloading them.
If the webserver supports HEAD request, you can use commands like wget --server-response --spider $URL, otherwise you can use range 0-1 to get one byte only. After you have the response heahers, you can write a script to rename. – Wu Yongzheng
I have written a shellscript which tries to pull a tar file from an ftp server and untar it locally. I need to extract specific files from the tar archive. The filename of the tarfile contains a date; I need to be able to select a tar file based on this date.
abc_myfile_$date.tar is the format of the file I am pulling from the ftp server.
My current code looks like this:
for host in ftpserver
do
ftp -inv host <<END_SCRIPT
user username password
prompt
cd remotepath
lcd localpath
mget *myfile_$date*.tar
quit
END_SCRIPT
done
for next in `ls localpath/*.tar`
do
tar xvf $next *required_file_in_tar_file*.dat
done
when i run the script am not able to untar the files
I am able to get a single tar file from the ftp server only if I mention the exact name of that file. I would like to get a file which has myfile_$date in its name. After this I would like to extract it to a local path to get the specified files in that tar file whose names consist of my required_files.
You get the .tar file, but decompress it with z option. Compressed files (those that require z) normally have .tar.gz prefix. Try
tar xvf $next *required_file_in_tar_file*.dat
Firstly, if you want to use wildcards for the file name that you're getting from the server you need to use mget instead of get. Wildcard file expansion (the *) does not work for the get command.
Once you have pulled the file the tar operation will work as expected, most modern versions of linux/bsd have a 'smart' tar, which doesn't need the 'z' command to specify that the tar file is compressed - they'll figure out that the tarball is compressed on their own and uncompress it automatically, providing the appropriate compression/decompression tool is on the system (bzip2 for .jz files, gzip for .gz files).
I'm not quite sure, but does the FTP protocol not have a command mget if you want to download multiple files? (instead of get)