In excel I have a dataset. This represents how much stock of 2 products is sold in the first, second, third, etc... month of the product being on the shelves (starts in A1):
Month 1 2 3 4 5 6 7 8 9 10 11 12
Product 1 3 5 2 1 6 1 2 4 7 2 1 5
Product 2 2 1 5 6 2 8 2 1 2 3 4 9
However, the first product sales do not always occur in month 1. They occur in month X. Is there a way (not VBA or copy and paste) of shifting the entries right by 'x' so they align with the month.
Example for data above
Product 1 starts in month 2
Product 2 starts in month 5
Month 1 2 3 4 5 6 7 8 9 10 11 12
Product 1 0 3 5 2 1 6 1 2 4 7 2 1 5
Product 2 0 0 0 0 2 1 5 6 2 8 2 1 2 3 4 9
*0 not required (great if possible), but more for illustration
Thanks
I have created a simple example that does the same job. The shown formula is copied over the shown cells in the row of new data. (The number '2' in the formula refers to the column number of the starting data cell which is column B, hence 2.)
Related
I have excel sheet with repeating ids
id jun19
1 3
2 2
3 7
1 3
2 2
3 7
1 3
2 2
3 7
i want to append another column 'jul19' from another sheet.
that jul19 sheet has all and even more ids:
id jul19
1 4
2 6
3 45
4 7
5 9
it should take only those that have the id and pull values from column 'jul19'.
the end result is this:
id jun19 jul19
1 3 4
2 2 6
3 7 45
1 3 4
2 2 6
3 7 45
1 3 4
2 2 6
3 7 45
how to do this? how to pull corresponding values from column "jul19" based on the id?
I tried to do this in pandas, but failed.
Assuming table1 is in A1:B10, table2 is in D1:E6, & table3 is in G1:I10. put :
=INDEX(E:E,MATCH(G2,D:D,0)) in I2
and drag downwards. ref : https://exceljet.net/index-and-match
Hope it helps. ( :
I have an dataframe which contain the observed data as:
import pandas as pd
d = {'humanID': [1, 1, 2,2,2,2 ,2,2,2,2], 'dogID':
[1,2,1,5,4,6,7,20,9,7],'month': [1,1,2,3,1,2,3,1,2,2]}
df = pd.DataFrame(data=d)
The df is follow
humanID dogID month
0 1 1 1
1 1 2 1
2 2 1 2
3 2 5 3
4 2 4 1
5 2 6 2
6 2 7 3
7 2 20 1
8 2 9 2
9 2 7 2
We total have two human and twenty dog, and above df contains the observed data. For example:
The first row means: human1 adopt dog1 at January
The second row means: human1 adopt dog2 at January
The third row means: human2 adopt dog1 at Febuary
========================================================================
My goal is randomly generating two unobserved data for each (human, month) that are not appear in the original observed data.
like for human1 at January, he does't adopt the dog [3,4,5,6,7,..20] And I want to randomly create two unobserved sample (human, month) in triple form
humanID dogID month
1 20 1
1 10 1
However, the follow sample is not allowed since it appear in original df
humanID dogID month
1 2 1
For human1, he doesn't have any activity at Feb, so we don't need to sample the unobserved data.
For human2, he have activity for Jan, Feb and March. Therefore, for each month, we want to randomly create the unobserved data. For example, In Jan, human2 adopt dog1, dog4 and god 20. The two random unobserved samples can be
humanID dogID month
2 2 1
2 6 1
same process can be used for Feb and March.
I want to put all of the unobserved in one dataframe such as follow unobserved
humanID dogID month
0 1 20 1
1 1 10 1
2 2 2 1
3 2 6 1
4 2 13 2
5 2 16 2
6 2 1 3
7 2 20 3
Any fast way to do this?
PS: this is a code interview for a start-up company.
Using groupby and random.choices:
import random
dogs = list(range(1,21))
dfs = []
n_sample = 2
for i,d in df.groupby(['humanID', 'month']):
h_id, month = i
sample = pd.DataFrame([(h_id, dogID, month) for dogID in random.choices(list(set(dogs)-set(d['dogID'])), k=n_sample)])
dfs.append(sample)
new_df = pd.concat(dfs).reset_index(drop=True)
new_df.columns = ['humanID', 'dogID', 'month']
print(new_df)
humanID dogID month
0 1 11 1
1 1 5 1
2 2 19 1
3 2 18 1
4 2 15 2
5 2 14 2
6 2 16 3
7 2 18 3
If I understand you correctly, you can use np.random.permutation() for the dogID column to generate random permutations of the column,
df_new=df.copy()
df_new['dogID']=np.random.permutation(df.dogID)
print(df_new.sort_values('month'))
humanID dogID month
0 1 1 1
1 1 20 1
4 2 9 1
7 2 1 1
2 2 4 2
5 2 5 2
8 2 2 2
9 2 7 2
3 2 7 3
6 2 6 3
Or to create random sampling of missing values within the range of dogID:
df_new=df.copy()
a=np.random.permutation(range(df_new.dogID.min(),df_new.dogID.max()))
df_new['dogID']=np.random.choice(a,df_new.shape[0])
print(df_new.sort_values('month'))
humanID dogID month
0 1 18 1
1 1 16 1
4 2 1 1
7 2 8 1
2 2 4 2
5 2 2 2
8 2 16 2
9 2 14 2
3 2 4 3
6 2 12 3
In Excel, I have an hours log that looks like this:
PersonID Hours JobCode
1 7 1
1 6 2
1 8 3
1 10 1
2 5 3
2 3 5
2 12 2
2 4 1
What I would like to do is create a column with a running total, but only within each PersonID so I want to create this:
PersonID Hours JobCode Total
1 7 1 7
1 6 2 13
1 8 3 21
1 10 1 31
2 5 3 5
2 3 5 8
2 12 2 20
2 4 1 24
Any ideas on how to do that?
In D2 and fill down:
=SUMIF(A$2:A2,A2,B$2:B2)
Assuming that your data starts in cell A1, this formula will accumulate the hours until it finds a change in person ID.
=IF(A2=A1,D1+B2,B2)
Put the formula in cell D2, and copy down for each row of your data.
A B ANSWER
1 1 1
3 3 3
1 2 1
2 4 2
4 4 4
5 5 5
6 6 6
i have used this function to get above answer "=IF(ISERROR(MATCH(A2:A8,$B$1:$B$8,0)),"",A2)"
but I need answer like this i have given below (suppose if you take value in A column "1"
Which is repeated only once in column B)
A B ANR
1 1 1
3 3 3
1 2 0
2 4 2
4 4 4
5 5 5
6 6 6
I've just wrapped your formula in a condition that returns 0 where the count of the A value from start to the current row is more than one:
=IF(COUNTIF(A$1:A2,A2)>1,0,IF(ISERROR(MATCH(A2:A8,$B$1:$B$8,0)),"",A2))
.
An alternative formula that gives the same results as above for the sample data provided but may (or may not) suit the additional requirements mentioned in a comment:
=IF(COUNTIF(A$2:A$10,A2)<=COUNTIF(B$2:B$10,A2),A2,IF(COUNTIF(A$2:A2,A2)>COUNTIF(B$2:B$10,A2),0,IF(COUNTIF(A$2:A$10,A2)>COUNTIF(B$2:B2,A2),A2,0)))
I am trying to fill data in MS Excel. I am given following pattern:
1 2
1
1
2 5
2 5
2
3
3 6
3
4
4
5 4
And I want my output in following format:
1 2
1 2
1 2
2 5
2 5
2 5
3 6
3 6
3 6
4
4
5 4
I tried using if(b2,b2,c1) in column 3. but that doesn't solve the problem for a=3 and a=4.
Any idea how to do this in Excel?
With sorting thus:
(the effect of which in this case is merely to move 6 up once cell) and a blank row above:
=IF(AND(A2<>A1,B2=""),"",IF(B2<>"",B2,C1))
In C2 and copied down should get the result you ask for from the data sample provided.