can find string if a variable batch (existing code needs editing) - string

I have devised a way to remove a files name from its path and extension (replacing the files name with an asterisk).
However the out put file adds an extra space just before the closing quotation marks and i dont know why or how to fix this?
#echo off
SET EXTENT=%~x1
SET PATH=%~dp1
SET /P FILETYPE=
rem SET FILETYPE="%PATH%*%EXTENT%"
echo %FILETYPE%
pause
Type C:\HELLO.txt | findstr /I /V /C:%FILETYPE% >>C:\TEMP.txt
DEL /S/Q "C:\HELLO.txt"
ren "C:\TEMP.txt" "HELLO.txt"
DEL /s/q "C:\TEMP.txt"

UPDATED
I changed this answer after gaining a better understanding of the question.
I think this code is close to what you want. You may need to play around with regexes for the FINDSTR command.
#ECHO OFF
SET EXT=%~x1
FINDSTR /I /V /C:%EXT% HELLO.TXT >>TEMP.TXT
DEL /Q HELLO.TXT
REN TEMP.TXT HELLO.TXT

Related

Bat file to list files, using semicolon delimiter?

So far I have this:
#ECHO OFF
dir *.txt /c /b /on > content.txt
Which gives output:
file1.txt
file2.txt
file3.txt
But I need it like this, separated with semicolon on each line:
file1.txt;
file2.txt;
file3.txt;
I assume I probably need to write for loop and add string ";" somewhere, but I don't know where or how to do this. Or is there a way to just set a specific delimiter?
Edit:
My usecase changed, I thought it would be better if there are files in subfolders listed as well, but "/" should be replaced with space " ".
Example output:
file1.txt;
file2.txt;
subfolder1 file1.txt;
subfolder2 file1.txt;
Note that I do not want the full parent path, only subfolders.
Quick single line batch-file answer:
#(For /F Tokens^=*^ Delims^=^ EOL^= %%G In ('Dir "*.txt" /A:-D /B /O:N 2^>NUL') Do #Echo %%G;) 1>"content.log"
…and in cmd:
(For /F Tokens^=*^ Delims^=^ EOL^= %G In ('Dir "*.txt" /A:-D /B /O:N 2^>NUL') Do #Echo %G;) 1>"content.log"
I have decided to output to a .log file, so that the listing doesn't include itself.
Please use the built-in help to learn how each command works.
When you read the help information, please be aware that a 'simple' for loop will not pick up all files, it will ignore all hidden files for instance. Also despite any first impressions you may have from testing, the order of files returned, depends upon both the file system and type. The dir command is the most efficient way of ensuring that sort order.
[EDIT /]
Here is a batch-file solution, (as that's what you posted as an answer), for your New and completely different question.
#(For /F Tokens^=*^ Delims^=^ EOL^= %%G In ('Dir "*.txt" /A:-D /B /O:N /S 2^>NUL') Do #(Set "FileName=%%~dpG" & SetLocal EnableDelayedExpansion & Set "Filename=!FileName:~,-1!" & For %%H In ("!FileName:%__CD__%=!") Do #EndLocal & Echo %%~H %%~nxG;)) 1>"content.log"
In future, when you have existing answers to your asked question, do not change that question when not only the main command is different, but the intended result format too.
a Simple for loop will do:
#(for %%i in (*.txt) do #echo %%i;)>"content.txt"
That will however also echo the content of contents.txt to itself if it exists, so you can exclude it.
#(for %%i in (*.txt) do #if /i not "%%~i" == "content.txt" #echo %%i;)>"content.txt"
if the plan is to iterate through subdirs as well, run for /R
I found a partial solution to list subfolders, excluding parent path. It is not perfect (for loop is not accurate as mentioned in above comments, neither I am happy with pushd command), but works. I left "space" in place of \ because thats how I need it.
#echo off
setlocal enabledelayedexpansion
pushd "c:\users\documents\"
(
for /r %%a in (*.txt) do (
set x=%%a
set x=!x:%cd%=!;
echo !x:\= !
)
)>filelist.log
popd
Code explanation:
First I remove the parent path with set x=!x:%cd%=!; (exclamation marks replace the %, see enabledelayedexpansion help) and then remove the slashes when echoing.

Windows Batch: find a string in file with "[" in the string

I have a function already working to remove all lines which doesn't contain a string in several files, it's working great to use with common strings:
#echo off
set "string_to_find=level.waypoints["
for /f "tokens=*" %%a in ('dir /B *.gsc') do (
set "tempfile=%temp%\%%a"
if exist "%tempfile%" del "%tempfile%" >NUL
findstr /C:"%string_to_find%" "%~dp0\%%a" >> "%tempfile%"
if not errorlevel 1 (
del "%%a" >NUL
move /Y "%tempfile%" "%~dp0\%%a" >NUL
if exist "%tempfile%" del "%tempfile%" >NUL
echo File "%~dp0\%%a" processed successfully
) else (
echo Problem processing file "%~dp0\%%a"
)
)
If I search for just "level.waypoints" (without the "[") works fine but few lines that I don't want to keep are not deleted. I need to search for "level.waypoints[" to really delete all the lines that I need to, but because the char "[" make everything goes wrong, messing up with the temp files, giving in the end the error "file not found"...
I think should have some char that I need to put before "[" like "[" to make it work, but I can't find it... tryed already many without luck. :/
So how can I search for the string "level.waypoints[" and works?
thanks
On the link sent by #jmoon says:
Special Cases
A small number of commands follow slightly different rules, FINDSTR, REG and RUNAS all use \ as an escape character instead of ^
Tryed and works! so the end string is "level.waypoints\["
cheers!

Findstr /g with token or delim

Suppose we have 2 files
First.txt
123
456
And Second.txt
789;123
123;def
482;xaq
What i need is to find the lines in the second file only containing entries of the first file in first column (token 1, delim ; ).
This is what i need:
Output.txt
123;def
Of course,
findstr /g:first.txt second.txt
will output both lines:
789;123
123;def
Any idea how i can mix findstr and for /f to get the needed output?
Thank you!
If all of the elements in the first column are of the same length, then the simple answer would be
findstr /b /g:first.txt second.txt
Note however that if first.txt contains a line 12 then this would match 123;abc and 129;pqr in the second file.
You can take advantage of the super-limited regex capabilities of findstr and compare each line of first.txt to only the very beginning of each line of second.txt.
#echo off
for /F %%A in (first.txt) do findstr /R /C:"^%%A;" second.txt
The /R flag means that the search string should be treated as a regular expression. The ^ in the search string means that %%A comes at the very beginning of the line. The ; is a literal semicolon that will prevent the 123 line from picking up 1234;abcd in second.txt.
Without executing a separate findstr for each value and to avoid the problem with partial matches at the start of the line, you can try with
#echo off
setlocal enableextensions disabledelayedexpansion
( cmd /q /c"(for /f "delims=" %%a in (first.txt) do echo(%%a;)"
) | findstr /g:/ /l /b second.txt
What it does is read first.txt and echo each line with the delimiter. This output is retrieved by the findstr using /g:/ to use the standard input as the source for the elements to match, that will be considered as literals (/l) at the start of the line (/b) in the second.txt file
Is the general form for CSV. Note in batch %A becomes %%A.
for /f "delims=," %A in (csv.txt) do findstr /c:"%A" file2.txt
Here's the output
C:\Users\User>for /f "delims=," %A in (csv.txt) do findstr /c:"%A" csv1.txt
C:\Users\User>findstr /c:"55" csv1.txt
55,61,hi there, Good
C:\Users\User>findstr /c:"60" csv1.txt
54,60,hi there, Bad
C:\Users\User>findstr /c:"Bad" csv1.txt
54,63,hi there, Bad
54,60,hi there, Bad
C:\Users\User>findstr /c:"55" csv1.txt
55,61,hi there, Good
Contents of two files.
55,60
60,60
Bad,60
55,60
and
55,61,hi there, Good
54,62,hi there, Good
54,63,hi there, Bad
54,60,hi there, Bad

I need to delete a string in multiple lines from a file using batch script

Working file: Projects/fentbase/common/javasrc/validators/PasswordSetupVal.java
Working file: Projects/fentbase/channeladministration/spec/ui/dev/ppdl/AccessSchemeMaintenancePreview.dppdl
Working file: Projects/fentbase/common/javasrc/validators/EmailValidator.java
Working file: Projects/fentbase/common/javasrc/validators/MailIdVal.java
I have this in a file. I need to take out "Working file: " from every line. Please let me know how do I do that.
#echo off
setlocal enabledelayedexpansion
for /f "delims=" %%a in (%1) do (
set line=%%a
echo !line:Working file=!
)
Usage:
sciprt.cmd file.txt > new_file.txt
move /y new_file.txt file.txt
another way to skin the cat:
for /f "tokens=2,*" %%i in ('type "file.txt"') do #echo(%%j
Here is one way:
type "file.txt" | repl "Working file: " "" L >"newfile.txt"
This uses a helper batch file called repl.bat (by dbenham) - download from: https://www.dropbox.com/s/qidqwztmetbvklt/repl.bat
Place repl.bat in the same folder as the batch file or in a folder that is on the path.

search multiple strings in multiple files via command-line

I have a txt file that contains about 500 values, one per line. I need to check to see of any of those 500 values appear in any of 6 csv files each containing 100k lines. I can search for one value in those 6 csv files using
for /f "delims==" %%f in ('dir /s /b "P:\*.txt"') do FIND /N "[SEARCHSTRING]" "%~1%%f" >> "C:\found.txt"
but how do I do multiple searches automatically via command-line or batch file (CaSe SenSiTIve)?
#ECHO OFF
SETLOCAL
SET "sourcedir=c:\sourcedir"
SET "destdir=C:\destdir"
for /f "delims=" %%a in ('dir /s /b "%sourcedir%\*.csv"') do (
FINDSTR /N /g:"yourtextfilecontaining500linestomatch.txt" "%%~fa") > "%destdir%\%%~nafound.txt"
GOTO :EOF
What you are asking is rather unclear. I used c:\sourcedir as the location of the .csv files and c:\destdir as the location for the reports. Replacing
FINDSTR /N /g:"yourtextfilecontaining500linestomatch.txt" "%%~fa") > "%destdir%\%%~nafound.txt with your original (with the double > would accumulate the lines into a single file - if that's what you want. As it stands, a new file will be created with name the same as your .csv+found.txt
An easy way is to use a batch script. You can loop through each of the files one by one. If you want to do them all at once you need to thread your program.
for /L %%A in (1,1,6) do (
Your code goes here
)
That batch script will loop six times. I am not really sure how you specify the file but if you loop through each file it will work.
So put your current batch script where I said "Your code goes here"
for /f "delims==" %%f in ('dir /s /b "P:\*.txt"') do FIND /N "[SEARCHSTRING]" "%~1%%f" >> "C:\found.txt"
But you need to edit it to point to the file that you want to search. If your files are 1.txt, 2.txt 3.txt then all you need to do is set your file name to the current loop iteration number.
I've been using variants of this shell function for years:
ematch () {
for f in $(find . -type f | grep -v '~' | grep -v \.svn\/) ; do
egrep "$1" "$f" /dev/null 2> /dev/null
done
}
-> ematch "(string1|string2|string3)"
Feel free to adapt to your needs and post your mods here.

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