error in if else in bash - linux

Question

i=0
EDA="xx7p2"
while read line
do
echo "i is --- $i"
echo " PACKAGE IS - --$EDA--"
#echo $line "\n"
if (( $i > 0 ))
then
package=$(echo $line | awk '{print $1}')
echo "EDA PACKAGE IN LOOP IS ---$Eda_package---"
if [ "$package" == "$EDA" ] ; then
#then
well_bias=$(echo $line | awk '{print $2}')
biasmap=$(echo $line | awk '{print $3}')
unified=$(echo $line | awk '{print $4}')
echo "eda pack --$package bias is --$wel biasmap is --$biasmap unified- --$unified"
fi
fi
i=$((i+1))
done < config.list
Here the statements inside the second if statement is not executed even if the two variables are same. Am I missing something here?

Answer 1

Make a simplified version of your problem to get it nailed down.
I can't reproduce your problem with this sample script:
#!/bin/bash
i=$1
a=$2
while read line
do
if (( $i > 0 ))
then
echo "1st if "+$i
if [ "$a" == "foo" ] ; then
echo "2nd if"
fi
fi
i=$((i+1))
done < nfoo.sh
called nfoo.sh and calling it ./nfoo.sh 4 bar, ./nfoo.sh -4 bar, ./nfoo.sh 4 foo and ./nfoo.sh -4 foo.
Might your error be in the package-assignement? You don't need awk for such a simple task. For a single word, to just extract the first word, you would use echo ${line/ */} while I see nothing wrong in your awk-statement.
Since you extract more arguments, I would suggest an array:
#!/bin/bash
i=$1
a=$2
while read line
do
if (( $i > 0 ))
then
arr=($line)
echo "1st if "+$i
if [ "if" == "${arr[0]}" ] ; then
echo "2nd if: " $line
fi
fi
i=$((i+1))
done < nfoo.sh
Btw.: Where is the else, the headline is talking about?

Answer 2

UPDATE: based on more testing with the small script below:
Having the $ as part of the string in package variable was a problem for me. If I escape it with a \$ I get it to work with the correct comparison operator mentioned below.
Use this for comparison (note the space before/after the =)
if [ "$package" = "$EDA" ] ; then
Without the space the expression seems to evaluate always to true. (Also, as an aside, using == without spaces before/after will result in an [: 11: $EDAx: unexpected operator)
I used this small script for testing, you can use to verify your own constructs, hope it's helpful. This works correctly as shown
#!/bin/bash
package="\$EDA"
echo $package
if [ "$package" = "\$EDA" ] ; then
echo "The same"
else
echo "Not the same"
fi
Note1: I added the else to be certain of the outcome of the comparison, as your script doesn't contain any else
Note2: It's always better to explicitly specify what shell to run rather than to depend on some external implicit environment settings, so I would recommend you add the #!/bin/bash to your script, it certainly won't hurt.
Other Comparison Operator from the Advanced Bash-Scripting Guide shows:
string comparison
=
is equal to
if [ "$a" = "$b" ]
Note the whitespace framing the =.
if [ "$a"="$b" ] is not equivalent to the above.
== is equal to
if [ "$a" == "$b" ]
This is a synonym for =.