Break a String array of size 5 into two parts 2 & 3 string arrays?
Orignal
String Array[] = {"asjjsjamsssssssssssssssssssssss",
"hcb j m dnfijvkfkjvkjdffkbdfblllfl",
"bjbvfumfkkf md",
"jdsjvjsdjvjjjjdjjdj",
"bsdjdddddddddddddddddddddddd"}
Resulting String contains 2 & 3 strings.
Try this below.
string[] arr = {"asjjsjamsssssssssssssssssssssss",
"hcb j m dnfijvkfkjvkjdffkbdfblllfl",
"bjbvfumfkkf md",
"jdsjvjsdjvjjjjdjjdj",
"bsdjdddddddddddddddddddddddd"};
var first = arr.Take(2).ToArray();
var second = arr.Skip(2).Take(3).ToArray();
You will never be able to break string array unless the number of elements in array are even.
Rethink about your operation.
Related
I got a string array of the format
sLine =
{
[1,1] = 13-Jul-16,10.46,100.63,15.7,54.4,55656465
[1,2] = 12-Jul-16,10.47,100.64,15.7,54.4,55656465
[1,3] = 11-Jul-16,10.48,100.65,15.7,54.4,55656465
[1,4] = 10-Jul-16,10.49,100.66,15.7,54.4,55656465
}
In which each element is a string ("13-Jul-16,10.46,100.63,15.7,54.4,55656465" is a string).
I need to convert this to 6 vectors, something like
[a b c d e f] = ...
such a way, for example, for the 1st column, it would be
a = [13-Jul-16;12-Jul-16;11-Jul-16;10-Jul-16]
I tried to use cell2mat function, but for some reason it does not separate the fields into matrix elements, but it concatenates the whole string into something like
cell2mat(sLine)
ans =
13-Jul-16,10.46,100.63,15.7,54.4,5565646512-Jul-16,10.47,100.64,15.7,54.4,5565646511-Jul-16,10.48,100.65,15.7,54.4,5565646510-Jul-16,10.49,100.66,15.7,54.4,55656465
So, how can I solve this?
Update
I got the sLine matrix following the steps
pFile = urlread('http://www.google.com/finance/historical?q=BVMF:PETR4&num=365&output=csv');
sLine = strsplit(pFile,'\n');
sLine(:,1)=[];
Update
Thanks to #Suever I could get now the column dates. So the updated last version of the code is
pFile = urlread('http://www.google.com/finance/historical?q=BVMF:PETR4&num=365&output=csv');
pFile=strtrim(pFile);
sLine = strsplit(pFile,'\n');
sLine(:,1)=[];
split_values = regexp(sLine, ',', 'split');
values = cat(1, split_values{:});
values(:,1)
Your data is all strings, therefore you will need to do some string manipulation rather than using cell2mat.
You will want to split each element at the ,characters and then concatenate the result together.
sLine = {'13-Jul-16,10.46,100.63,15.7,54.4,55656465',
'12-Jul-16,10.47,100.64,15.7,54.4,55656465',
'11-Jul-16,10.48,100.65,15.7,54.4,55656465',
'10-Jul-16,10.49,100.66,15.7,54.4,55656465'};
split_values = cellfun(#(x)strsplit(x, ','), sLine, 'uniformoutput', 0);
values = cat(1, split_values{:});
values(:,1)
% {
% [1,1] = 13-Jul-16
% [2,1] = 12-Jul-16
% [3,1] = 11-Jul-16
% [4,1] = 10-Jul-16
% }
If you want it to be more concise, we can just use regexp to split it up instead of strsplit since it can accept a cell array as input.
split_values = regexp(sLine, ',', 'split');
values = cat(1, split_values{:});
Update
The issue with the code that you've posted is that there is a trailing newline in the input and when you split on newlines the last element of your sLine cell array is empty causing your issues. You'll want to use strtrim on pFile before creating the cell array to remove trailing newlines.
sLine = strsplit(strtrim(pFile), '\n');
sLine(:,1) = [];
I have two string arrays and I want to find where each string from the first array is in the second array, so i tried this:
for i = 1:length(array1);
cmp(i) = strfind(array2,array1(i,:));
end
This doesn't seem to work and I get an error: "must be one row".
Just for the sake of completeness, an array of strings is nothing but a char matrix. This can be quite restrictive because all of your strings must have the same number of elements. And that's what #neerad29 solution is all about.
However, instead of an array of strings you might want to consider a cell array of strings, in which every string can be arbitrarily long. I will report the very same #neerad29 solution, but with cell arrays. The code will also look a little bit smarter:
a = {'abcd'; 'efgh'; 'ijkl'};
b = {'efgh'; 'abcd'; 'ijkl'};
pos=[];
for i=1:size(a,1)
AreStringFound=cellfun(#(x) strcmp(x,a(i,:)),b);
pos=[pos find(AreStringFound)];
end
But some additional words might be needed:
pos will contain the indices, 2 1 3 in our case, just like #neerad29 's solution
cellfun() is a function which applies a given function, the strcmp() in our case, to every cell of a given cell array. x will be the generic cell from array b which will be compared with a(i,:)
the cellfun() returns a boolean array (AreStringFound) with true in position j if a(i,:) is found in the j-th cell of b and the find() will indeed return the value of j, our proper index. This code is more robust and works also if a given string is found in more than one position in b.
strfind won't work, because it is used to find a string within another string, not within an array of strings. So, how about this:
a = ['abcd'; 'efgh'; 'ijkl'];
b = ['efgh'; 'abcd'; 'ijkl'];
cmp = zeros(1, size(a, 1));
for i = 1:size(a, 1)
for j = 1:size(b, 1)
if strcmp(a(i, :), b(j, :))
cmp(i) = j;
break;
end
end
end
cmp =
2 1 3
I have an cell array composed by several strings
names = {'2name_19surn', '3name_2surn', '1name_2surn', '10name_1surn'}
and I would like to sort them according to the prefixnumber.
I tried
[~,index] = sortrows(names.');
sorted_names = names(index);
but I get
sorted_names = {'10name_1surn', '1name_2surn', '2name_19surn', '3name_2surn'}
instead of the desired
sorted_names = {'1name_2surn', '2name_19surn', '3name_2surn','10name_1surn'}
any suggestion?
Simple approach using regular expressions:
r = regexp(names,'^\d+','match'); %// get prefixes
[~, ind] = sort(cellfun(#(c) str2num(c{1}), r)); %// convert to numbers and sort
sorted_names = names(ind); %// use index to build result
As long as speed is not a concern you can loop through all strings and save the first digets in an array. Subsequently sort the array as usual...
names = {'2name_2', '3name', '1name', '10name'}
number_in_string = zeros(1,length(names));
% Read numbers from the strings
for ii = 1:length(names)
number_in_string(ii) = sscanf(names{ii}, '%i');
end
% Sort names using number_in_string
[sorted, idx] = sort(number_in_string)
sorted_names = names(idx)
Take the file sort_nat from here
Then
names = {'2name', '3name', '1name', '10name'}
sort_nat(names)
returns
sorted_names = {'1name', '2name', '3name','10name'}
You can deal with arbitrary patterns using a regular expression:
names = {'2name', '3name', '1name', '10name'}
match = regexpi(names,'(?<number>\d+)\D+','names'); % created with regex editor on rubular.com
match = cell2mat(match); % cell array to struct array
clear numbersStr
[numbersStr{1:length(match)}] = match.number; % cell array with number strings
numbers = str2double(numbersStr); % vector of numbers
[B,I] = sort(numbers); % sorted vector of numbers (B) and the indices (I)
clear namesSorted
[namesSorted{1:length(names)}] = names{I} % cell array with sorted name strings
I have a Hex string that has a value like
26C726F026C426A1269A26AB26F026CC26E226C726E226CD
I was wondering how to split it into a string array, where each index of the array holds a group of 2 of those chars.
Example:
string(0)=26,string(1)=C7,string(2) = 26,string (3) = F0, and so on.
How can I do this?
Dim MyList as New List(Of String)
Dim s as String = "26C726F026C426A1269A26AB26F026CC26E226C726E226CD"
For x as Integer = 0 to s.Length - 1 step 2
MyList.Add(s.substring(x,2))
Next
You can get it with MyList(0), MyList(1) or etc
I have a string (eg. 'STA') and I want to make a cell array that will be a concatenation of my sting with a numbers from 1 to X.
I want the code to do something like the fore loop here below:
for i = 1:Num
a = [{a} {strcat('STA',num2str(i))}]
end
I want the end results to be in the form of {<1xNum cell>}
a = 'STA1' 'STA2' 'STA3' ...
(I want to set this to a uitable in the ColumnFormat array)
ColumnFormat = {{a},... % 1
'numeric',... % 2
'numeric'}; % 3
I'm not sure about starting with STA1, but this should get you a list that starts with STA (from which I guess you could remove the first entry).
N = 5;
[X{1:N+1}] = deal('STA');
a = genvarname(X);
a = a(2:end);
You can do it with combination of NUM2STR (converts numbers to strings), CELLSTR (converts strings to cell array), STRTRIM (removes extra spaces)and STRCAT (combines with another string) functions.
You need (:) to make sure the numeric vector is column.
x = 1:Num;
a = strcat( 'STA', strtrim( cellstr( num2str(x(:)) ) ) );
As an alternative for matrix with more dimensions I have this helper function:
function c = num2cellstr(xx, varargin)
%Converts matrix of numeric data to cell array of strings
c = cellfun(#(x) num2str(x,varargin{:}), num2cell(xx), 'UniformOutput', false);
Try this:
N = 10;
a = cell(1,N);
for i = 1:N
a(i) = {['STA',num2str(i)]};
end