Eggplant/Sensetalk parsing and separating a string with capitalized words - string

I'm in need of the ability to parse and separate a text string using Sensetalk (the scripting language the Eggplant GUI tester uses). What I'd like to be able to do is provide the code a text string:
Put "MyTextIsHere" into exampleString
And then have spaces inserted before every capital letter save for the first, so the following is then stored in exampleString:
"My Text Is Here"
I basically want to separate the string into the words it contains. After searching the documentation and the web, I'm no closer to finding a solution to this (I agree, it would be far easier in a different language - alas, not my choice).
Thank you in advance to anyone who can provide some insight!

See question at http://www.testplant.com/phpBB2/viewtopic.php?t=2192.
With credit to Pamela at TestPlant forums:
set startingString to "HereAreMyWords"
set myRange to 2 to the number of characters in startingString // The range to iterate over– every character except the first
Put the first character in startingString into endString // The first character isn't included in the repeat loop, so you have to put it in separately
repeat with each character myletter of characters myRange of startingString
if charToNum(myLetter) is between 65 and 90 // if the character's unicode number is between 65-90...
Put space after endString
end if
Put myLetter after endString
end repeat
put endString
or you could do it this way:
Put "MyTextIsHere" into exampleString
repeat with each char of chars 2 to last of exampleString by reference
if it is an uppercase then put space before it
end repeat
put exampleString

Related

Replacing "invisible" special characters with something legible

About twelve years ago, I wrote a small VB.NET application that loads strings from files. These strings may contain one or more of the following characters: à, è, é, ì, ò, ù, ä, ö. The application uses a special custom font (JazzText Extended) that does not have those special characters. Yet, I somehow managed to make the application display words correctly in that font, and twelve years later, I have no idea how - thanks for not leaving a line of comment, past me!
The program has the following routine:
Private Sub SetWord(ByVal word() As String)
Dim nword(3) As String
nword(0) = word(0)
nword(1) = word(1)
nword(2) = word(2)
For i As Integer = 0 To 2
nword(i) = nword(i).Replace("à", "")
nword(i) = nword(i).Replace("é", "")
nword(i) = nword(i).Replace("è", "")
nword(i) = nword(i).Replace("ì", "ê")
nword(i) = nword(i).Replace("ò", "")
nword(i) = nword(i).Replace("ù", "")
nword(i) = nword(i).Replace("ä", "")
nword(i) = nword(i).Replace("ö", "")
Next
lblItaWord.Text = nword(0).ToUpper
lblEngWord.Text = nword(1).ToUpper
lblFinWord.Text = nword(2).ToUpper
End Sub
What it does is, it takes an array that contains three words, and for each of those three words, it looks if it contains any of the special characters. If it does, it replaces them with... something, makes the words all caps, and then assigns each of them to one of three labels.
In Visual Studio, the replacement characters look like empty strings. I had to put the cursor in between the quotation marks to realise that it was in fact not an empty string and there was an invisible character there. Here on SO... I'm not sure what you'll see. You might see just a square, or some other weird character. (The ê character is an exception, it seems to display in the same way everywhere.)
If you copypaste any of the invisible/square characters to Google and search for it, you'll get a different representation that uses two characters—for example, the first one translates to ‡. Using this pair in place of the invisible/square character in the Replace method does not produce the correct result. FYI, the encoding I use to read the files (the default one used by IO.StreamReader if you don't specify any encoding) works fine: if I use a more standard font, all special characters display correctly without using the SetWord sub at all.
Now, I have absolutely no idea how those characters, whatever they may be, manage to make the app display correctly the words when the font I use does not have those characters. I have no idea how I found out about this trick, either. Right now, my problem is that I would like to replace those squares/invisible characters with something intelligible, and I have no idea how. Any ideas?

Replace the string in all lines of itab?

I am trying to create an algorithm in SAP ABAP to eliminate the word IBAN from certain fields. For example, in the below photo we have that for KNBK-Bankschlüssel=7415000, the KNBK-Bankkontonummer= <IBAN 000000000008. I am trying to eliminate IBAN from the field so that only 000000000008 will be shown in the table.
Is there any string operation that would let me check whether a field has the keyword IBAN and to eliminate it?
Thank you all in advance!
You can do it with the REPLACE statement:
IF word CS 'IBAN'. "to check if the string contains IBAN (as substring)
REPLACE 'IBAN' WITH '' INTO word. "This will remove the substring IBAB, but it will be replaced with a space
CONDENSE word NO-GAPS. "This will remove the space (and other spaces as well, if there is any in the string)
ENDIF.
Looking at the screenshot, the field contains '< IBAN>' (instead of just 'IBAN'), so you have to modify the code accordingly.
Another possibility is REPLACE IN TABLE:
REPLACE ALL OCCURRENCES OF REGEX '^.*IBAN>'
IN TABLE itab WITH ''
RESPECTING CASE.
This snippet will delete all the <IBAN>s with all the preceding characters from all lines.

Tell if specific char in string is a long char or a short char

Be prepared, this is one of those hard questions.
In Farsi or Persian language ی which sounds like y or i and is written in 4 different shapes according to it's place in word. I'll call ی as YA from now for simplification.
take a look at this image
All YA characters are painted in red, in the first word YA is attached to it's previous (right , in Farsi we right from RIGHT to LEFT) character and is free at the end whereas the last YA (3rd word, left-most red char) is free both from left or right.
Having said this long story, I want to find out if a part of a string ends with long YA (YA without points) or short YA (YA with two points beneath it).
i.e تحصیلداری (the 3rd word) ends with long YA but تحصیـ which is a part of 3rd word does not ends with short YA.
Question: How can I say تحصیلداری ends whit which unicode? I just have a simple string, "تحصیلداری", how can I convert its characters to unicode?
I tried the unicodes
string unicodes = "";
foreach (char c in "تحصیلداری")
{
unicodes += c+" "+((int)c).ToString() + Environment.NewLine;
}
MessageBox.Show(unicodes);
result :
but at the end of the day unfortunately all YAs have the same unicode.
Bad news : YA was an example, a real one though. There are also a dozen of other characters like YA with different appearances too.
Additional info :
using this useful link about unicodes I found unicode of different YAs
We solved similar problem the way bellow:
We had a core banking application, the customer sub-system needed a full text search on customers name, family, father name etc.
Different encoding, legacy migrated data, keyboard layouts and Farsi fonts ... made search process inaccurate.
We overcame the problem by replacing problematic characters with some standard one and saving the standard string for search purpose.
After several iterations, the replacement is as bellow that may come in handy:
Formula="UPPER(REPLACE(REPLACE(REPLACE
(REPLACE(REPLACE(REPLACE(REPLACE(REPLACE
(REPLACE(REPLACE(REPLACE(REPLACE(REPLACE
(REPLACE(REPLACE(REPLACE(REPLACE(REPLACE
(REPLACE(REPLACE(REPLACE(REPLACE
(REPLACE(FirsName || LastName || FatherName,
chr(32),''),
chr(13),''),
chr(9),''),
chr(10),''),
'-',''),
'-',''),
'آ','ا'),
'أ', 'ا'),
'ئ', 'ي'),
'ي', 'ي'),
'ك', 'ک'),
'آإئؤةي','اايوهي'),
'ء',''),
'شأل','شاال'),
'ا.','اله'),
'.',''),
'الله','اله'),
'ؤ','و'),
'إ','ا'),
'ة','ه'),
' ا لله','اله'),
'ا لله','اله'),
' ا لله','اله'))"
Despite there are different YEHs in Unicode, it must noticed that all presentation forms of YEHs are same Unicode character with code 0x06cc. You can not determine presentation forms by their Unicode code.
But you can reach your goal be checking to see what characters is before or after YEH.
You can also use Fardis to see Unicode codes of strings.

Lua: Search a specific string

Hi all tried all the string pattrens and library arguments but still stuck.
i want to get the name of the director from the following string i have tried the string.matcH but it matches the from the first character it finD from the string
the string is...
fixstrdirector = {id:39254,cast:[{id:15250,name:Hope Davis,character:Aunt Debra,order:5,cast_id:10,profile_path:/aIHF11Ss8P0A8JUfiWf8OHPVhOs.jpg},{id:53650,name:Anthony Mackie,character:Finn,order:3,cast_id:11,profile_path:/5VGGJ0Co8SC94iiedWb2o3C36T.jpg},{id:19034,name:Evangeline Lilly,character:Bailey Tallet,order:2,cast_id:12,profile_path:/oAOpJKgKEdW49jXrjvUcPcEQJb3.jpg},{id:6968,name:Hugh Jackman,character:Charlie Kenton,order:0,cast_id:13,profile_path:/wnl7esRbP3paALKn4bCr0k8qaFu.jpg},{id:79072,name:Kevin Durand,character:Ricky,order:4,cast_id:14,profile_path:/c95tTUjx5T0D0ROqTcINojpH6nB.jpg},{id:234479,name:Dakota Goyo,character:Max Kenton,order:1,cast_id:15,profile_path:/7PU6n4fhDuFwuwcYVyRNVEZE7ct.jpg},{id:8986,name:James Rebhorn,character:Marvin,order:6,cast_id:16,profile_path:/ezETMv0YM0Rg6YhKpu4vHuIY37D.jpg},{id:930729,name:Marco Ruggeri,character:Cliff,order:7,cast_id:17,profile_path:/1Ox63ukTd2yfOf1LVJOMXwmeQjO.jpg},{id:19860,name:Karl Yune,character:Tak Mashido,order:8,cast_id:18,profile_path:/qK315vPObCNdywdRN66971FtFez.jpg},{id:111206,name:Olga Fonda,character:Farra Lemkova,order:9,cast_id:19,profile_path:/j1qabOHf3Pf82f1lFpUmdF5XvSp.jpg},{id:53176,name:John Gatins,character:Kingpin,order:10,cast_id:41,profile_path:/A2MqnSKVzOuBf8MVfNyve2h2LxJ.jpg},{id:1126350,name:Sophie Levy,character:Big Sister,order:11,cast_id:42,profile_path:null},{id:1126351,name:Tess Levy,character:Little Sister,order:12,cast_id:43,profile_path:null},{id:1126352,name:Charlie Levy,character:Littlest Sister,order:13,cast_id:44,profile_path:null},{id:187983,name:Gregory Sims,character:Bill Panner,order:14,cast_id:45,profile_path:null}],crew:[{id:58726,name:Leslie Bohem,department:Writing,job:Screenplay,profile_path:null},{id:53176,name:John Gatins,department:Writing,job:Screenplay,profile_path:/A2MqnSKVzOuBf8MVfNyve2h2LxJ.jpg},{id:17825,name:Shawn Levy,department:Directing,job:Director,profile_path:/7f2f8EXdlWsPYN0HPGcIlG21xU.jpg},{id:12415,name:Richard Matheson,department:Writing,job:Story,profile_path:null},{id:57113,name:Dan Gilroy,department:Writing,job:Story,profile_path:null},{id:25210,name:Jeremy Leven,department:Writing,job:Story,profile_path:null},{id:17825,name:Shawn Levy,department:Production,job:Producer,profile_path:/7f2f8EXdlWsPYN0HPGcIlG21xU.jpg},{id:34970,name:Susan Montford,department:Production,job:Producer,profile_path:/1XJt51Y9ciPhkHrAYE0j6Jsmgji.jpg},{id:3183,name:Don Murphy,department:Production,job:Producer,profile_path:null},{id:34967,name:Rick Benattar,department:Production,job:Producer,profile_path:null},{id:1126348,name:Eric Hedayat,department:Production,job:Producer,profile_path:null},{id:186721,name:Ron Ames,department:Production,job:Producer,profile_path:null},{id:10956,name:Josh McLaglen,department:Production,job:Executive Producer,profile_path:null},{id:57634,name:Mary McLaglen,department:Production,job:Executive Producer,profile_path:null},{id:23779,name:Jack Rapke,department:Production,job:Executive Producer,profile_path:null},{id:488,name:Steven Spielberg,department:Production,job:Executive Producer,profile_path:/cuIYdFbEe89PHpoiOS9tmo84ED2.jpg},{id:30,name:Steve Starkey,department:Production,job:Executive Producer,profile_path:null},{id:24,name:Robert Zemeckis,department:Production,job:Executive Producer,profile_path:/isCuZ9PWIOyXzdf3ihodXzjIumL.jpg},{id:531,name:Danny Elfman,department:Sound,job:Original Music Composer,profile_path:/pWacZpYPos8io22nEiim7d3wp2j.jpg},{id:18265,name:Mauro Fiore,department:Crew,job:Cinematography,profile_path:null},{id:54271,name:Dean Zimmerman,department:Editing,job:Editor,profile_path:null},{id:25365,name:Richard Hicks,department:Production,job:Casting,profile_path:null},{id:5490,name:David Rubin,department:Production,job:Casting,profile_path:null},{id:52088,name:Tom Meyer,department:Art,job:Production Design,profile_path:null}]}
i have tried string.match(fixstrdirector,"name:(.+),department:Directing")
but it gives me the from the first occurace it find the name to the end of thr string
output:
Hope Davis,character:Aunt Debra,order:5,cast_id:10,profile_path:/aIHF11Ss8P0A8JUfiWf8OHPVhOs.jpg},{id:53650,name:Anthony Mackie,character:Finn,order:3,cast_id:11,profile_path:/5VGGJ0Co8SC94iiedWb2o3C36T.jpg},{id:19034,name:Evangeline Lilly,character:Bailey Tallet,order:2,cast_id:12,profile_path:/oAOpJKgKEdW49jXrjvUcPcEQJb3.jpg},{id:6968,name:Hugh Jackman,character:Charlie Kenton,order:0,cast_id:13,profile_path:/wnl7esRbP3paALKn4bCr0k8qaFu.jpg},{id:79072,name:Kevin Durand,character:Ricky,order:4,cast_id:14,profile_path:/c95tTUjx5T0D0ROqTcINojpH6nB.jpg},{id:234479,name:Dakota Goyo,character:Max Kenton,order:1,cast_id:15,profile_path:/7PU6n4fhDuFwuwcYVyRNVEZE7ct.jpg},{id:8986,name:James Rebhorn,character:Marvin,order:6,cast_id:16,profile_path:/ezETMv0YM0Rg6YhKpu4vHuIY37D.jpg},{id:930729,name:Marco Ruggeri,character:Cliff,order:7,cast_id:17,profile_path:/1Ox63ukTd2yfOf1LVJOMXwmeQjO.jpg},{id:19860,name:Karl Yune,character:Tak Mashido,order:8,cast_id:18,profile_path:/qK315vPObCNdywdRN66971FtFez.jpg},{id:111206,name:Olga Fonda,character:Farra Lemkova,order:9,cast_id:19,profile_path:/j1qabOHf3Pf82f1lFpUmdF5XvSp.jpg},{id:53176,name:John Gatins,character:Kingpin,order:10,cast_id:41,profile_path:/A2MqnSKVzOuBf8MVfNyve2h2LxJ.jpg},{id:1126350,name:Sophie Levy,character:Big Sister,order:11,cast_id:42,profile_path:null},{id:1126351,name:Tess Levy,character:Little Sister,order:12,cast_id:43,profile_path:null},{id:1126352,name:Charlie Levy,character:Littlest Sister,order:13,cast_id:44,profile_path:null},{id:187983,name:Gregory Sims,character:Bill Panner,order:14,cast_id:45,profile_path:null}],crew:[{id:58726,name:Leslie Bohem,department:Writing,job:Screenplay,profile_path:null},{id:53176,name:John Gatins,department:Writing,job:Screenplay,profile_path:/A2MqnSKVzOuBf8MVfNyve2h2LxJ.jpg},{id:17825,name:Shawn Levy
You're searching from the first occurrence of "name:" until the "department:Directing" with everything in between.
Instead, you need to restrict what can be between the two strings. Here for example I'm saying that the characters that make up the name can only be alphanumeric or a space:
string.match(fixstrdirector,"name:([%w ]+),department:Directing")
Alternatively, given that there's a comma separating the parameters, a better approach would be to search for "name:" followed by any characters other than a comma, followed by "department:Directing":
string.match(fixstrdirector,"name:([^,]+),department:Directing")
Of course that wouldn't work if the name had a comma it in!
Lua patterns provides - modifier for tasks as you have above. As stated on PiL - Section 20.2:
The + modifier matches one or more characters of the original class.
It will always get the longest sequence that matches the pattern.
Like *, the modifier - also matches zero or more occurrences of
characters of the original class. However, instead of matching the
longest sequence, it matches the shortest one.
Next, when you are using . to match, it'll find any and all characters satisfying the pattern. Therefore, you'll get the result from first occurence of name until the ,department:Directing is found. Since you know that it is a JSON data, you can try to match for [^,]; that is, non-comma characters.
So, for your case try:
local tAllNames = {}
for sName in fixstrdirector:gmatch( "name:([^,]-),department:Directing" ) do
tAllNames[ #tAllNames + 1 ] = sName
end
and all your required names will be stored in the table tAllNames. An example of the above can be seen at codepad.

Split string by first delimiter

I have a column with a long list of folder and file names. The folders and file names vary. I want to extract the file name from the column into another column but I struggling to do this in Excel.
Example of column data:(files and folder altered to hide details that should not be public)
c:\data\1\nc2\media\ss\system media\ne\d - wnd enging works v5.swf
c:\data\1\nc2\media\ss\special campaigns\samns dec 2012\trainerv5.swf
C:\Local\Messages\17362~000000001~20131231235910~4.MUF
c:\data\1\nc2\media\ss\system media\tl\nd - tfl statusv4.swf
c:\data\1\nc2\media\ss\system media\core\ss_bagage v2.swf
I know I should be able to search from the right to the first occurence of "\" but I can't figure out the syntax.
Many thanks
UPDATE:
Formula =RIGHT(B2,LEN(B2)-SEARCH("\",B2,1)) should work, but it shows incorrect results. But If I change it to search for "." it pulls out the file extension. So there is a key item I'm missing
=RIGHT(A1,LEN(A1)-FIND("~",SUBSTITUTE(A1,"\","~",LEN(A1)-LEN(SUBSTITUTE(A1,"\","")))))
copy it in any column say b drag down,you are done
VBA is a more efficient option if you have many files to parse. Create a module and add the below:
Function GetFileName(file As String) As String
Set fso = CreateObject("Scripting.FileSystemObject")
GetFileName = fso.GetFileName(file)
End Function
There are several different ways to get the text following the last slash in a string, including the following formula. In this example, H15 is the cell containing the string to search. If it can't find a slash, it returns the "-" (dash) character.
=iferror(RIGHT(H15,LEN(H15)-SEARCH("|",SUBSTITUTE(H15,"/","|",LEN(H15)-LEN(SUBSTITUTE(H15,"/",""))))),"-")
The formula first finds the number of slashes in the string. LEN gives the total length of the string, and LEN of the string without slashes after using SUBSTITUTE to eliminate the slashes in the original string - the difference is the number of slashes.
Then, you substitute in a marker character(I used "|") for the last slash. By searching for the marker, you find where the bit after the slash starts. The total length of the string minus where the marker starts tells you how many characters to take from the right, which you then do.
If you need more generic string parsing and are willing to use a little bit of VBA, you can use the split function as suggested by Jamie Bull in his answer to this question on SuperUser.
His function will use any character you choose to split the string into segments and return whichever segment you choose.
I've copied Jamie's function here for convenient reference:
Function STR_SPLIT(str, sep, n) As String
Dim V() As String
V = Split(str, sep)
STR_SPLIT = V(n - 1)
End Function

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