hi all i have made a app using appsgeyser.com the app is for railway access point that i have made on google maps now i have saved the url as a bookmark on my phone and when i open it all works well .but that is because it askes me when i open it do i want to use internet or maps so i choose maps ..so i have now added this url to appsgeyser and downloaded app to phone but when i open the app its not using google maps so when i click on a access it does not show direction or any info //
so basicle how do i make the url of my google maps open up by default on my phone
railway access points
Leah from AppsGeyser here. Did you make sure to enable Geolocation on your app?
To do it, you need to go to your AppsGeyser Dashboard, go to the Edit tab, choose the Advanced tab, and then choose the checkbox that says 'App can get location data.' You'll need to hit Create again, and download the app again to see the change. If that doesn't help, feel free to drop me an email Leah (at) AppsGeyser.com
Leah
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I am trying to create a powerapps web part that will open a specific screen from a canvas app using parameters. I have added the web part and added the power apps web link to it. When I enter ¶metername=parameter nothing shows up. I can enter the web link and parameters directly into a browser window (tried in Chrome and Edge) and the app will display properly. I can also created a button in a web part and added the link to it and it will also display the app when the button is clicked. The app is working properly with no errors, it will just not show up in the web part when the parameters are added to the link (If no parameters are added to the link, everything will display fine).
I am trying to create a powerapps web part that will open a specific screen from a canvas app using parameters. I have added the web part and added the power apps web link to it. When I enter ¶metername=parameter nothing shows up. I can enter the web link and parameters directly into a browser window (tried in Chrome and Edge) and the app will display properly. I can also created a button in a web part and added the link to it and it will also display the app when the button is clicked. The app is working properly with no errors, it will just not show up in the web part when the parameters are added to the link (If no parameters are added to the link, everything will display fine).
I was struggling with this myself; just figured it out.
You need to put the full URL with parameters in to the "App web link or ID" property for the PowerApp web part. Be careful because the first parameter needs to be prepended with ? not &. The ampersand is used for additional, following parameters after the first parameter.
Note that I have omitted my TLD from this screenshot, however you will want to substitute your own here.
The example URL syntax given by Microsoft is https://apps.powerapps.com/play/{App ID}?{Query}. For me that URL looks something like this:
https://apps.powerapps.com/play/f813580f-3182-90b0-b3a9-781cfb288808?linkId=checkIn
I have one URL for checkIn and another for checkOut that I can use to display different forms.
My primary mistake was that I was only pasting my appID into the "App web link or ID" field rather than the entire URL. Remember, you can edit your Canvas Form, click on "Share" and get the Web Link from this page. This contains the full URL, minus your custom parameters. Play around with the full URL plus parameters until you get something that the web part will accept.
[context part] I am currently on vacation in austria, and decided to buy some tickets for the zoo in insbruck. After typing in my data... a link to their app in the google play store. And after downloading it, google play didnt show the usual open button, to open the app, rather it showed a button saying "continue" and after clicking it, the app opened with my data already in place
so here is my question: how may they have done it, and how can i implement it in my own app / website
thanks a lot in advance, would be nice if there was a easy way of doing this
EDIT: idk, may they have shared the session-token somehow, used the ip of my mobile?
You can achieve this using Firebase Dynamic Links
this is done by Add an intent filter for deep links
As with plain deep links, you must add a new intent filter to the activity that handles deep links for your app. The intent filter should catch deep links of your domain, since the Dynamic Link will redirect to your domain if your app is installed. This is required for your app to receive the Dynamic Link data after it is installed/updated from the Play Store and one taps on Continue button. In AndroidManifest.xml:
Is it possible to load a app store link in uiwebview. I have tried to open it in uiwebview but it doesnt load in there. I dont want users to leave my app when they click on the url from my app. Is it possible?
Regards
Pankaj
iTunes content does not have an "iTunes Preview" page on mobile - iOS automatically recognizes itunes.apple.com links and opens the store.
If you want to keep the user within your app, use SKStoreProductViewController to open the store to a specific piece of content. After the user dismisses the sheet, they are still within your app.
http://developer.apple.com/library/ios/#documentation/StoreKit/Reference/SKITunesProductViewController_Ref/Introduction/Introduction.html
I've install my CF on http://paas.azure4j.us
Now I want to use an eclipse plugin for CF , but when I add my CF server an error occured it said
The currently selected server type does not support remote hosts
But it works when I test it to api.vcap.me / my local CF.
Any solution ?
This looks like a similar issue addressed in a git change;
https://github.com/SpringSource/eclipse-integration-cloudfoundry/pull/2
I am not really an Eclipse user, so this is a bit of a stab in the dark!
I think Dan is correct here. At the moment you create your Cloud Foundry connection against 'localhost' (which doesn't make much sense from an Eclipse point-of-view) and in the new panel you specify your actual API target, username, password etc. Is that what you are doing?
I was able to connect to your Cloud Foundry instant without any problem using STS. First I used vmc to register for a account. Once I registered an account, I went to STS and on the server tab I right clicked, and choose Cloud Foundry from my vmware folder.
When you choose the Cloud Foundry option on the server tab, keep the Server's host name the same (which is localhost). Give a name to your Server Name and keep the Server runtime environment the same as well. Click Next to move to the next screen. On the next screen you should see Email, Password and URL. Email and password are pretty straight forward and those should be your information which you registered with your Cloud Foundry instance. For the URL section, click on the Manage Cloud... button and then the Add... button. You should get a window popup which have Name and URL. For name put whatever name you want and for URL put in "http://paas.azure4j.us", then click on Finish. Now you have your custom Cloud URL added to the list so go ahead and click on the OK button again. Now you should be on the New Server window where you have the Email, Password and URL options. For the URL option go ahead and choose the newly added url you just created and then click on "Validate Account" to see if everything is validated. You should get a "Account information is valid" message. then click on Next and continue with the wizard until you are done and you have your Cloud Foundry instance added to your servers list.
Again I have performed the same exact steps I mentioned above and I was able to have your Cloud Foundry instance added to my servers tab.
I've done this issue , so I edit my cloud_controller.yml and uaa.yml on
~/cloudfoundry/.deployment/devbox/config
Then change uaa uri at http://uaa.cloudfoundry.com to http://paas.azure4j.us:8080/ to redirect it to own uaa.
Thanks for all solutions :))
Is it possible to create a checkin by allowing a user to click on button in a html page that takes them to a share location (checkin page)?
I am thinking- something like the twitter share url?
for example-
http://foursquare.com/share/?venue_id=12345
I want this functionality in order to allow users to swipe their nfc phone on a smart tag and it loads a html page with different options
On an Android-based or iOS-based mobile device, you can use special formed URLs in order to start the Foursquare application viewing the desired venue: https://developer.foursquare.com/resources/client
The URL https://m.foursquare.com/venue/#venue_id# (e.g. https://m.foursquare.com/venue/4b477346f964a520723226e3) can either be opened by the installed Android Foursquare App or opened by a normal browser (or other Intent receivers registered for that URL).
You can further use the URL https://foursquare.com/mobile/checkin?vid=#venue_id# to get to the mobile page, where you can just press "check in" or enter a shout. By checking-in via the mobile page (and not the app), you do not get points and are not able to earn Mayorships (see Foursquare support).
But you can, for example, create your own web app that accesses the Foursquare API and performs the check-in for the OAuth'ed users. By using the HTML5 Geolocation feature, you can also send the mobile device's Lat/Lon coordinates to your web app and perform valid check-ins that also count for Mayorships, etc. A good start is Foursquare's developer page: https://developer.foursquare.com/overview/