This is what I'm trying to do. There are two columns. The first one contains the drawing number of a P&ID and The other one contains the IO type. Columns B and N respectively. I want the number of DOs for the drawing number ZCPL-P2179-B1-101. I know a simple COUNTIF function works but it is inefficient since rows keep expanding and it is quite tedious to constantly reselect the ranges.
Why dont you use Simple Countif with whole column as a Range
=COUNTIFS(B:B;"B1";C:C;"C1")
Just drag this formula in the whole column, even if your data is increasing you just have to click once to drag the formula.
Later take out Unique of P&ID number and Dos to find the distinct count.
I hope this helps
Related
I have 2 columns one is a period and another is a cycle. I need to create a 3rd column where I create a cycle identifier. Where the Letter changes on the cycle but resets every period.
I seem to have it with the following formula
IF(A1<>A2,1,IF(B1<>B2,C1+1,C1)). Which will give results of 1, 2 or 3. Then to get the numbers into letter form by using a switch SWITCH(C1,1,"A",2,"B",3,"C") in an adjacent cell. However I was curious if there is a more efficient or better way to accomplish this perhaps in all in one formula.
Any suggestions would be greatly appreciated.
Period & Cycle
Copy this formula to cell C2 and copy it down.
=IF(B2<>B1,IF(A2<>A1,CHAR(65),CHAR(CODE(C1)+1)),C1)
In Excel 365, you could use a spill formula like this:
=CHAR(B2:B15-XLOOKUP(A2:A15,A2:A15,B2:B15)+65)
You could argue that this is less efficient because it uses a lookup so there could be a speed hit with large amounts of data. On the other hand, it could be considered more efficient because it is a single formula and doesn't need to be pulled down.
If you were worried about the speed, you could set the binary search option in xlookup:
=CHAR(B2:B15-XLOOKUP(A2:A15,A2:A15,B2:B15,,2)+65)
(Column A has to be sorted ascending for this to work - I'm fairly sure that where there are duplicates this will still give the first match. However Microsoft are quoted as saying that there is only a slight benefit of using binary search according to this and other articles)
You could make the formula more dynamic:
=CHAR(B2:INDEX(B:B,COUNTA(B:B))-XLOOKUP(A2:INDEX(A:A,COUNTA(A:A)),A2:INDEX(A:A,COUNTA(A:A)),B2:INDEX(B:B,COUNTA(B:B)))+65)
Or using Let
=LET(Period,A2:INDEX(A:A,COUNTA(A:A)),
Cycle,B2:INDEX(B:B,COUNTA(B:B)),
CHAR(Cycle-XLOOKUP(Period,Period,Cycle)+65))
I am new to Excel/Google Sheets. I have a difficulty of writing a formula to compare columns as a pair-wise since the formula would be
so big as the day goes.
For example, there're 2 main columns Foo and Bar. I want to find the total number of days that Foo
and Bar are equal so the current formula is =IF(A3 = G3, 1, 0)+IF(B3 = H3, 1, 0)+IF(C3 = I3, 1, 0)+...
But this is kind of tedious because there're ~40 days to compare with. Are there any other alternatives
to write a formula in efficient way? Either Google-App-Scripts or Excel Formula is appreciated.
Cheers!
Give a try on below google-sheet formula. Adjust ranges as you need.
=ArrayFormula(SUM(IF(A3:E3=G3:K3,1,0)))
Assuming that you're needing to get such a total for each row and not merely a single row, try this:
=ArrayFormula(IF(A3:A="",,MMULT(IF(A3:F=G3:L,1,0),SEQUENCE(COLUMNS(A:F),1,1,0))))
Of course you will need to adjust the three ranges to match your own FOO and BAR ranges.
This one formula will produce all results for all rows.
The MMULT function is tricky to explain to those as yet unfamiliar with it. But it's a powerful tool. I'll add a picture I created that may best explain what it does:
By making the second matrix a simple SEQUENCE of 1s as long as the other matrix is wide, we wind up multiplying everything by 1 before adding together. And since anything multiplied by 1 is itself, this combination serves only to do a row-by-row add.
Things to keep in mind with MMULT:
1.) Every cell in every matrix must be a number or it will produce an error.
2.) As in the above formula, there are ways to use either/or conditions to turn every cell in a matrix into a number.
I'm trying to create a formula that takes C2-B2 and uses the result to determine which cells to add together. So if the result is 2 it takes AA2 and AB2, adds them together, and displays the result. In other words, it counts cells stemming from a point and adds them, with the amount counted determined by the result of two other cells.
This doesnt sound recursive the way you describe it.
Put this formula somewhere on the sheet and see if this is what you want:
=SUM($AA$2:INDEX($AA$2:$XFD$2, 1, SUM($B$2:$C$2)))
I'm working on data from a population of people with allergies. Each person has a unique ExceptionID, and each allergen has a unique AllergenID (451 in total).
I have a data table with 2 columns (ExceptionID and AllergenID), where each person's allergies are listed row by row. This means that the ExceptionID column has repeated values for people with multiple allergies, and the AllergenID column has repeated values for the different people who have that allergy.
I am trying to count how many times each pair of allergies is present in this population (e.g. Allergen#107 & Allergen#108, Allergen#107 & Allergen#109,etc). To keep it simple I've created a matrix of 451 rows X 451 columns, representing every pair (twice actually because A/B and B/A are equivalent).
I somehow need to use the row name (allergenID) to lookup the ExceptionID in my data table, and count the cases where that matches the ExceptionIDs from the column name (also AllergenID). I have no problem using Vlookup or Index/Match, but I'm struggling with the correct combination of a lookup and Sumproduct or Countif formula.
Any help is greatly appreciated!
Mike
PS I'm using Excel 2016 if that changes anything.
-=UPDATE=-
So the methods suggested by Dirk and MacroMarc both worked, though I couldn't apply the latter to my full data set (17,000+ rows) because it was taking a long time.
I've since decided to turn this into a VBA macro because we now want to see the counts of triplets instead of pairs.
With the 2 columns you start with, it is as good as impossible... You would need to check every ExceptionID to have 2 different specific AllergenID. Better use a helper-table with ExceptionID as rows and AllergenID as columns (or the opposite... whatever you like). The helper table needs a formula like:
=COUNTIFS($A:$A,$D2,$B:$B,E$1)
Which then can be auto-filled. (The ranges are from my example, you need to change them to your needs).
With this helper-matrix you can easily go for your bigger matrix like this:
=COUNTIFS(E:E,1,INDEX($E:$G,,MATCH($I2,$E$1:$G$1,0)),1)
Again, you can auto-fill with this formula, but you need to change it, so it fits your needs.
Because the columns have the same ID2 (would be your AllergenID), there is no need to lookup them because E:E changes automatically with the auto-fill.
Most important part of the formulas are the $ which should not be messed up, or you can not auto-fill it.
Picture of my self-made example (formulas are from the upper left cell in each table):
If you still have any questions, just ask :)
It can be done straight from your original set-up with array formulas:
Please note that array formulas MUST be entered with Ctrl-Shift-Enter, before copying across and down:
In the example pic, I have NAMED the data ranges $A$2:$A$21 as 'People' and $B$2:$B$21 as 'Allergens' to make it a nicer set-up. You can see in the formula bar how that looks as a formula. However you could use the standard references like this in your first matrix cell:
EDIT: silly me, N function is not needed to turn the booleans into 1's and 0's, since multiplying booleans will do the trick. Below formula works...
SUM(IF(MATCH($A$2:$A$21,$A$2:$A$21,0)=ROW($A$2:$A$21)-1, NOT(ISERROR(MATCH($A$2:$A$21&$E2,$A$2:$A$21&$B$2:$B$21,0)))*NOT(ISERROR(MATCH($A$2:$A$21&F$1, $A$2:$A$21&$B$2:$B$21,0))), 0))
Then copy from F2 across and down. It can be perhaps improved in technique with sumproduct or whatever, but it's just a rough example of the technique....
I am an excel beginner and I would like to do the following.
Let row1= (a_1 a_2 a_3) and row2= (b_1 b_2 b_3).
I want excel to calculate the largest number among the products (a_1b_1, a_2b_2, a_3b_3).
It is very difficult to look up these things for I am not sure what kind of calculation I am doing and it is hard to explain.
Take a third column, C and enter formula in C1 as $A1*$B1. Pull it down vertically to all other rows so that row number gets incremented for each.
Then in the fourth column, use the formula MAX(C:C)
The following formula, array-entered, gives you the result of the largest number among the products:
{=MATCH(A1:C1*A2:C2)}
(provided your data is in A1:C2 in the form you presented it).
For explanations on how to insert array formula in excel see e.g. this microsoft link; in short, you type the formula without the curly brackets and confirm with CTRL+SHIFT+ENTER instead of only ENTER.
If you want to find where this couple of numbers is (in your case: which column), I would try this:
{=MATCH(MAX(A1:C1*A2:C2);A1:C1*A2:C2;0)}
(also array-entered).
you can do that, or make a pivot with the raw data and get the MAX/MIN/AVG, based on the pivot options. I tend to use that instead and then vlookup the ID to the pivot to get whatever aggregate you need.