How can I employ repmat to produce the vector below;
sysHealthy={'sys';'sys';'sys';'sys';'sys'}
I tried:
A=repmat({'sys'},1,5);
unique_cell = {sprintf('%3s;',A{:})};
but it produces the put below:
{'sys;sys;sys;sys;sys;'}
This output has two problems: first, in doesn't have double quotation above each sys and second, it has an ; at the end of the array. I would like to get something like
sysHealthy={'sys';'sys';'sys';'sys';'sys'}.
Try the following lines --
charLength = 3; repCount = 5;
A=repmat('sys',repCount,1); % Creates a column vector
sysHealthy = mat2cell(A, repmat(1, [1,repCount]),charLength); % Convert them into cell.
Related
prompt = 'Enter ASCII codes';
dlg_title = 'Input';
num_lines = 5;
defaultans = {''};
answer = inputdlg(prompt,dlg_title,num_lines,defaultans);
answer = answer{1};
m2=matrixA.'; result=char(m2(:)).';
result
What Im trying to do is write a script that when i run it, it will convert the matrix of numbers you input into a sentence. What am I doing wrong?
Your input matrix is a string, not numeric. Change line 7 to:
answer = str2num(answer{1});
But since you never assign anything to matrixA, you might as well change it to this:
matrixA = str2num(answer{1});
I have a simple question that I need help on. My code,I believe, is almost complete but im having trouble with the a specific line of code.
I have an assignment question (2 parts) that asks me to find whether a protein (string), has the specified motif (substring) at that particular location (location). This is the first part, and the function and code looks like this:
function output = Motif_Match(motif,protein,location)
%This code wil print a '1' if the motif occurs in the protein starting
at the given location, else it wil print a '0'
for k = 1:location %Iterates through specified location
if protein(1, [k, k+1]) == motif; % if the location matches the protein and motif
output = 1;
else
output = 0;
end
end
This part I was able to get correctly, and example of this is as follows:
p = 'MGNAAAAKKGN'
m = 'GN'
Motif_Match(m,p,2)
ans =
1
The second part of the question, which I am stuck on, is to take the motif and protein and return a vector containing the locations at which the motif occurs in the protein. To do this, I am using calls to my previous code and I am not supposed to use any functions that make this easy such as strfind, find, hist, strcmp etc.
My code for this, so far, is:
function output = Motif_Find(motif,protein)
[r,c] = size(protein)
output = zeros(r,c)
for k = 1:c-1
if Motif_Match(motif,protein,k) == 1;
output(k) = protein(k)
else
output = [];
end
end
I belive something is wrong at line 6 of this code. My thinking on this is that I want the output to give me the locations to me and that this code on this line is incorrect, but I can't seem to think of anything else. An example of what should happen is as follows:
p = 'MGNAAAAKKGN';
m = 'GN';
Motif_Find(m,p)
ans =
2 10
So my question is, how can I get my code to give me the locations? I've been stuck on this for quite a while and can't seem to get anywhere with this. Any help will be greatly appreciated!
Thank you all!
you are very close.
output(k) = protein(k)
should be
output(k) = k
This is because we want just the location K of the match. Using protien(k) will gives us the character at position K in the protein string.
Also the very last thing I would do is only return the nonzero elements. The easiest way is to just use the find command with no arguments besides the vector/matrix
so after your loop just do this
output = find(output); %returns only non zero elements
edit
I just noticed another problem output = []; means set output to an empty array. this isn't what you want i think what you meant was output(k) = 0; this is why you weren't getting the result you expected. But REALLY since you already made the whole array zeros, you don't need that at all. all together, the code should look like this. I also replaced your size with length since your proteins are linear sequences, not 2d matricies
function output = Motif_Find(motif,protein)
protein_len = length(protein)
motif_len = length(motif)
output = zeros(1,protein_len)
%notice here I changed this to motif_length. think of it this way, if the
%length is 4, we don't need to search the last 3,2,or 1 protein groups
for k = 1:protein_len-motif_len + 1
if Motif_Match(motif,protein,k) == 1;
output(k) = k;
%we don't really need these lines, since the array already has zeros
%else
% output(k) = 0;
end
end
%returns only nonzero elements
output = find(output);
I have an cell array composed by several strings
names = {'2name_19surn', '3name_2surn', '1name_2surn', '10name_1surn'}
and I would like to sort them according to the prefixnumber.
I tried
[~,index] = sortrows(names.');
sorted_names = names(index);
but I get
sorted_names = {'10name_1surn', '1name_2surn', '2name_19surn', '3name_2surn'}
instead of the desired
sorted_names = {'1name_2surn', '2name_19surn', '3name_2surn','10name_1surn'}
any suggestion?
Simple approach using regular expressions:
r = regexp(names,'^\d+','match'); %// get prefixes
[~, ind] = sort(cellfun(#(c) str2num(c{1}), r)); %// convert to numbers and sort
sorted_names = names(ind); %// use index to build result
As long as speed is not a concern you can loop through all strings and save the first digets in an array. Subsequently sort the array as usual...
names = {'2name_2', '3name', '1name', '10name'}
number_in_string = zeros(1,length(names));
% Read numbers from the strings
for ii = 1:length(names)
number_in_string(ii) = sscanf(names{ii}, '%i');
end
% Sort names using number_in_string
[sorted, idx] = sort(number_in_string)
sorted_names = names(idx)
Take the file sort_nat from here
Then
names = {'2name', '3name', '1name', '10name'}
sort_nat(names)
returns
sorted_names = {'1name', '2name', '3name','10name'}
You can deal with arbitrary patterns using a regular expression:
names = {'2name', '3name', '1name', '10name'}
match = regexpi(names,'(?<number>\d+)\D+','names'); % created with regex editor on rubular.com
match = cell2mat(match); % cell array to struct array
clear numbersStr
[numbersStr{1:length(match)}] = match.number; % cell array with number strings
numbers = str2double(numbersStr); % vector of numbers
[B,I] = sort(numbers); % sorted vector of numbers (B) and the indices (I)
clear namesSorted
[namesSorted{1:length(names)}] = names{I} % cell array with sorted name strings
I have a string (eg. 'STA') and I want to make a cell array that will be a concatenation of my sting with a numbers from 1 to X.
I want the code to do something like the fore loop here below:
for i = 1:Num
a = [{a} {strcat('STA',num2str(i))}]
end
I want the end results to be in the form of {<1xNum cell>}
a = 'STA1' 'STA2' 'STA3' ...
(I want to set this to a uitable in the ColumnFormat array)
ColumnFormat = {{a},... % 1
'numeric',... % 2
'numeric'}; % 3
I'm not sure about starting with STA1, but this should get you a list that starts with STA (from which I guess you could remove the first entry).
N = 5;
[X{1:N+1}] = deal('STA');
a = genvarname(X);
a = a(2:end);
You can do it with combination of NUM2STR (converts numbers to strings), CELLSTR (converts strings to cell array), STRTRIM (removes extra spaces)and STRCAT (combines with another string) functions.
You need (:) to make sure the numeric vector is column.
x = 1:Num;
a = strcat( 'STA', strtrim( cellstr( num2str(x(:)) ) ) );
As an alternative for matrix with more dimensions I have this helper function:
function c = num2cellstr(xx, varargin)
%Converts matrix of numeric data to cell array of strings
c = cellfun(#(x) num2str(x,varargin{:}), num2cell(xx), 'UniformOutput', false);
Try this:
N = 10;
a = cell(1,N);
for i = 1:N
a(i) = {['STA',num2str(i)]};
end
What is the quickest way to create an empty cell array of strings ?
cell(n,m)
creates an empty cell array of double.
How about a similar command but creating empty strings ?
Depends on what you want to achieve really. I guess the simplest method would be:
repmat({''},n,m);
Assignment to all cell elements using the colon operator will do the job:
m = 3; n = 5;
C = cell(m,n);
C(:) = {''}
The cell array created by cell(n,m) contains empty matrices, not doubles.
If you really need to pre populate your cell array with empty strings
test = cell(n,m);
test(:) = {''};
test(1,:) = {'1st row'};
test(:,1) = {'1st col'};
This is a super old post but I'd like to add an approach that might be working. I am not sure if it's working in an earlier version of MATLAB. I tried in 2018+ versions and it works.
Instead of using remat, it seems even more convenient and intuitive to start a cell string array like this:
C(1:10) = {''} % Array of empty char
And the same approach can be used to generate cell array with other data types
C(1:10) = {""} % Array of empty string
C(1:10) = {[]} % Array of empty double, same as cell(1,10)
But be careful with scalers
C(1:10) = {1} % an 1x10 cell with all values = {[1]}
C(1:10) = 1 % !!!Error
C(1:10) = '1' % !!!Error
C(1:10) = [] % an 1x0 empty cell array