What I am trying to basically do with this shell script is to have the user input a directory via console and have the output be all of the .c files that are inside that directory and the sub-directories within it (the files are copied to the current location of the script).
rsync -va --include "*/" --include '*.c' --exclude '*' "$1/" .
However when I run the script (sh test.sh DirA) it copies all of the sub-directories within the $1 directory, with nothing inside them (not even the .c files). I want the output to not be the directories, but instead ONLY the .c files.
So if I were to ls in the current directory it should come out with a bunch of files like: file.c file1.c file2.c NOT dir1 dir2 dir3.
You should simply leave out --exclude '*'. As it occurs later on the command line, it is applied after a candidate file succeded the --include '*.c' test and causes any file to be rejected.
So, for simply copying any .c file within the given subtree to a hierarchy at current directory use a plain:
rsync -va --include '*.c' "$1" .
EDIT:
As rsync is all about copying and synchronizing hierarchies, it is the wrong tool for flattening hierarchies into a single directory. For such an operation you will need a command that is explicitly ignoring the source path for the target side (like plain cp).
E.g. in your case you could use:
find "$1" -name '*.c' -print0 | xargs -0 -I'{}' cp {} .
Related
I'm new to linux and as an exercice I need to copy the "etc" files that end with a digit from home directory to the test1 directory
(with one command).
I tried this but it dosn't work
find /etc -type f -iname "*[3-9]" -exec cp {} ../test1/ \;
this should work for your home directory files ending with digit
mv `ls . |grep -Eo "^.*[0-9]$"` your-directory
lets says in the current directory you have some files like ofjweifhwef9 or kfhiofeh8 ( files ending with digit)
so ls will list them.
this grep expression "^.*[0-9]$"` will find only files ending with digit. ( because in your home directory system wont allow to have a file like this "/etc/somefile123")
and then mv will move those files to your-directory
note :- if grep cannot find the files ending with number you will see an error ofcourse because mv needs 2 operands but since it wasn't there so error.
mv: missing destination file operand after './your-directory'
It is probably because /etc is a link in the system that you're using, and find doesn't seem to consider it a path until you add an extra / at the end. Try this instead:
find /etc/ -type f -iname "*[3-9]" -exec cp {} ../test1/ \;
Notice the /etc/ instead of /etc. I get the same behavior on my Mac where /etc is a link to another directory.
Of course, also make sure that you have files which names end on a digit under the /etc/ directory tree. I have none in my mac. You should get some files when you run:
find /etc/ -type f -iname "*[3-9]"
If you don't, you don't have any files to copy. You may also try: find /etc/ to see all files under the directory tree.
Finally, you may want to add the option: -depth 1 if you only want to copy the files in the /etc/ directory, as opposed to all the files that match in the directory tree under /etc/.
I have the following structure:
FolderA
Sub1
Sub2
filexx.csv
filexx.doc
FolderB
Sub1
Sub2
fileyy.csv
fileyy.doc
I want to write a script that will move the .csv files into the folder sub1 for each parent directory (Folder A, Folder B and so on) giving me the following structure:
FolderA
Sub1
filexx.csv
Sub2
filexx.doc
FolderB
Sub1
fileyy.csv
Sub2
fileyy.doc
This is what I have till now but I get the error mv: cannot stat *.csv: No such file or directory
for f in */*/*.csv; do
mv -v "$f" */*/Sub1;
done
for f in */*/*.doc; do
mv -v "$f" */*/Sub2;
done
I am new to bash scripting so please forgive me if I have made a very obvious mistake. I know I can do this in Python as well but it will be lengthier which is why I would like a solution using linux commands.
find . -name "*.csv" -type f -execdir mv '{}' Sub1/ \;
Using find, search for all files with the extension .csv and then when we find them, execute a move command from within the directory containing the files, moving the files to directory Sub1
find . -name "*.doc" -type f -execdir mv '{}' Sub2/ \;
Follow the same principle for files with the extension .doc but this time, move the files to Sub2.
I believe you are getting this error because no file matched your wildcard. When it happens, the for loop will give $f the value of the wildcard itself. You are basically trying to move the file *.csv which does not exist.
To prevent this behavior, you can add shopt -s nullglob at the top of your script. When using this, if no file is found, your script won't enter the loop.
My advise is, make sure you run your script from the correct location when using wildcards like this. But maybe what you meant to do by writing */*/*.csv is to recursively match all the csv files. If that's what you intended to do, this is not the right way to do it.
To recursively match all csv/doc/etc files using native bash you can add shopt -s globstar to the top of your script and use **/*.csv as wildcard
#!/bin/bash
shopt -s globstar nullglob
for f in **/*.csv; do
mv "$f" Destination/ # Note that $f is surrounded by "" to handle whitespaces in filenames
done
You could also use the find (1) utility to achieve that. But if you're planning to do more processing on the files than just moving them, a for loop might be cleaner as you won't have to inline everything in the same command.
Side note : "Linux commands" as you say are actually not Linux commands, they are part of the GNU utilities (https://www.gnu.org/gnu/linux-and-gnu.en.html)
If csv files you want to move are in the top directories (from the point of view of the current directory), but not in the subdirectories of them, then simply:
#!/bin/bash
for dir in */; do
mv -v "$dir"*.csv "${dir}Sub1/"
mv -v "$dir"*.doc "${dir}Sub2/"
done
If the files in all subdirectories are wanted to be moved similarly, then:
shopt -s globstar
for file in **/*.csv; do
mv -v "$file" "${file%/*}/Sub1/"
done
for file in **/*.doc; do
mv -v "$file" "${file%/*}/Sub2/"
done
Note that, the directories Sub1 and Sub2 are relative to the directory where csv and doc files reside.
I want to copy recursively files to its parent folder for a specific file extension. For example:
./folderA/folder1/*.txt to ./folderA/*.txt
./folderB/folder2/*.txt to ./folderB/*.txt
etc.
I checked cp and find commands but couldn't get it working.
I suspect that while you say copy, you actually mean to move the files up to their respective parent directories. It can be done easily using find:
$ find . -name '*.txt' -type f -execdir mv -n '{}' ../ \;
The above command recurses into the current directory . and then applies the following cascade of conditionals to each item found:
-name '*.txt' will filter out only files that have the .txt extension
-type f will filter out only regular files (eg, not directories that – for whatever reason – happen to have a name ending in .txt)
-execdir mv -n '{}' ../ \; executes the command mv -n '{}' ../ in the containing directory where the {} is a placeholder for the matched file's name and the single quotes are needed to stop the shell from interpreting the curly braces. The ; terminates the command and again has to be escaped from the shell interpreting it.
I have passed the -n flag to the mv program to avoid accidentally overwriting an existing file.
The above command will transform the following file system tree
dir1/
dir11/
file3.txt
file4.txt
dir12/
file2.txt
dir2/
dir21/
file6.dat
dir22/
dir221/
dir221/file8.txt
file7.txt
file5.txt
dir3/
file9.dat
file1.txt
into this one:
dir1/
dir11/
dir12/
file3.txt
file4.txt
dir2/
dir21/
file6.dat
dir22/
dir221/
file8.txt
file7.txt
dir3/
file9.dat
file2.txt
file5.txt
To get rid of the empty directories, run
$ find . -type d -empty -delete
Again, this command will traverse the current directory . and then apply the following:
-type d this time filters out only directories
-empty filters out only those that are empty
-delete deletes them.
Fine print: -execdir is not specified by POSIX, though major implementations (at least the GNU and BSD one) support it. If you need strict POSIX compliance, you'll have to make do with the less safe -exec which would need additional thought to be applied correctly in this case.
Finally, please try your commands in a test directory with dummy files, not your actual data. Especially with the -delete option of find, you can loose all your data quicker than you might imaging. Read the man page and, if that is not enough, the reference manual of find. Never blindly copy shell commands from random strangers posted on the internet if you don't understand them.
$cp ./folderA/folder1/*.txt ./folderA
Try this commnad
Run something like this from the root(ish) directory:
#! /bin/bash
BASE_DIR=./
new_dir() {
LOC_DIR=`pwd`
for i in "${LOC_DIR}"/*; do
[[ -f "${i}" ]] && cp "${i}" ../
[[ -d "${i}" ]] && cd "${i}" && new_dir
cd ..
done
return 0
}
new_dir
This will search each directory. When a file is encountered, it copies the file up a directory. When a directory is found, it will move down into the directory and start the process over again. I think it'll work for you.
Good luck.
Let's say I have the following subdirectories
./a/, ./b/, ./c/, ...
That is, in my current working directory are these subdirectories a/, b/ and c/, and in each of these subdirectories are files. In directory a/ is the file a.in, in directory b/ is the file b.in and so forth.
I now want to copy each .in file to a .out file, that is, a.in to a.out and b.in to b.out, and I want them to reside in the directories they were copied from. So a.out will be found in directory a/.
I've tried various different approaches, such as
find ./ -name '*.in'|cp * *.out
which doesn't work because it thinks *.out is a directory. Also tried
ls -d */ | cd; cp *.in *.out
but it that would list the subdirectories, go into each one of them, but won't let cp do it's work (which still doesn't work)
The
find ./ -name '*.in'
command works fine. Is there a way to pipe arguments to an assignment operator? E.g.
find ./ -name '*.in'| assign filename=|cp filename filename.out
where assign filename= gives filename the value of each .in file. In fact, it would be even better if the assignment could get rid of the .in file extension, then instead of getting a.in.out we would get the preferred a.out
Thank you for your time.
Let the shell help you out:
find . -name '*.in' | while read old; do
new=${old%.in}.out # strips the .in and adds .out
cp "$old" "$new"
done
I just took the find command you said works and let bash read its output one filename at a time. So the bash while loop gets the filenames one at a time, does a little substitution, and a straight copy. Nice and easy (but not tested!).
Try a for loop:
for f in */*.in; do
cp $f ${f%.in}.out;
done
The glob should catch all the files one directory down that have a .in extension. In the cp command, it strips off the .in suffix and then appends a .out (see Variable Mangling in Bash with String Operators)
Alternatively, if you want to recurse into every subdirectory (not just 1 level deep) replace the glob with a find:
for f in $(find . -name '*.in'); do
cp $f ${f%.in}.out;
done
This should do the trick!
for f in `find . -type f -name "*.in"`; do cp $f `echo $f | sed 's/in$/out/g'`; done
Can anyone give me a bash script or one line command i can run on linux to recursively go through each folder from the current folder and delete all files or directories starting with '._'?
Change directory to the root directory you want (or change . to the directory) and execute:
find . -name "._*" -print0 | xargs -0 rm -rf
xargs allows you to pass several parameters to a single command, so it will be faster than using the find -exec syntax. Also, you can run this once without the | to view the files it will delete, make sure it is safe.
find . -name '._*' -exec rm -Rf {} \;
I've had a similar problem a while ago (I assume you are trying to clean up a drive that was connected to a Mac which saves a lot of these files), so I wrote a simple python script which deletes these and other useless files; maybe it will be useful to you:
http://github.com/houbysoft/short/blob/master/tidy
find /path -name "._*" -exec rm -fr "{}" +;
Instead of deleting the AppleDouble files, you could merge them with the corresponding files. You can use dot_clean.
dot_clean -- Merge ._* files with corresponding native files.
For each dir, dot_clean recursively merges all ._* files with their corresponding native files according to the rules specified with the given arguments. By default, if there is an attribute on the native file that is also present in the ._ file, the most recent attribute will be used.
If no operands are given, a usage message is output. If more than one directory is given, directories are merged in the order in which they are specified.
Because dot_clean works recursively by default, use:
dot_clean <directory>
If you want to turn off the recursively merge, use -f for flat merge.
dot_clean -f <directory>
find . -name '.*' -delete
A bit shorter and perform better in case of extremely long list of files.