I have the following data sheet:
As you can see I have a date and a no which is a string.
Now I want to filter out all dates which have the same number in a +-20 day intervall around the date. So for example:
If the 12.2.2014 has the value a then it gets a 1 and if the 3.2.2014 has the value a it gets also a 1. In contrast if the value 15.1.2014 has the value a it gets a 0 because it is not in the +-20 day range. If there exists two rows like in the example below with 10.07.2002 and value d then it gets a 0 because there is no other day in a 20 day intervall around it.
My implementation idea is: Calculate for each value and date the difference of the dates and if it is less or equal than 20 and greater and equal to 1 then give out a 1 else a 0.
Can this be done in excel?
I really appreciate any suggestions
PS.: I hope that I showed the problem clearly!
UPDATE
Using this formula I get:
=COUNTIFS($B$2:$B$32;B2;$A$2:$A$32;">"&(A2-20);$A$2:$A$32;"<"&(A2+20))-1
see col E.
Something like this (adjust the $B$2:$B$32 etc to your actual data range):
=COUNTIFS($B$2:$B$32,B2,
$A$2:$A$32,">" & (A2-20),
$A$2:$A$32,"<" & (A2+20))-1
-1 is to avoid counting the row the formula is on.
To give only 0 or 1:
=MIN(COUNTIFS($B$2:$B$32,B2,
$A$2:$A$32,">" & (A2-20),
$A$2:$A$32,"<" & (A2+20))-1,1)
Related
Breaking my head over this, time to look for help :(
I have a sheet with raw data, as illustrated below.
I'd like to calculate the average duration per TestName (column A) between the 2 timestamps (B and C) in another sheet.
How can I do this in 1 formula?
Note 1: The correct answer is (done manually)
test1 = 26:41:23
test2 = 08:23:10
Note 2: 1 formula please, without adding extra columns to calculate the duration per each first
Note 3: I cannot change the format of the raw data
Note 4: ignore empty fields
Thank you!
Use a new Column D to calculate the difference between start and end date on each row:
=DATEVALUE(C2)+TIMEVALUE(C2) - (DATEVALUE(B2)+TIMEVALUE(B2))
Next calculate the average on test1 and test2
=AVERAGEIFS($D:$D, $A:$A, "test1")
=AVERAGEIFS($D:$D, $A:$A, "test2")
Note that I'm using a comma as separator, in some languages, other separators, like semicolon are needed to write the formulas properly.
Now format the view to display at least the days in addition to the time: "DD - hh:mm:ss". Going beyond 31 days is a bit difficult as the month will count up.
If you don't like the formatting, go with the raw number format and extract the information through a bit of math. If it shows for example 1,5 it means one and a half days. I hope you can handle converting decimals to hours, minutes and seconds. MOD(ulo) and Rounddown are going to be your friends. :-)
I have this table in excel:
Date value
1/2/1970 100.00
1/5/1970 99.99
1/6/1970 100.37
1/7/1970 100.74
1/8/1970 101.26
1/9/1970 100.74
1/12/1970 100.79
1/13/1970 101.27
1/14/1970 101.95
1/15/1970 101.97
1/16/1970 101.76
1/19/1970 102.21
1/20/1970 102.70
1/21/1970 102.00
1/22/1970 101.46
1/23/1970 101.49
1/26/1970 100.97
1/27/1970 101.45
1/28/1970 101.70
1/29/1970 102.08
1/30/1970 102.19
2/2/1970 102.02
2/3/1970 101.85
These are values that I have daily, and I need to construct a sheet that takes a monthly index of the daily values, example below:
date index
1/31/1970 some_index
2/28/1970 some_index
3/31/1970 some_index
4/30/1970 some_index
I could only get this far when it came to getting the index of 30 days:
=AVERAGE(INDEX(B:B,1+30*(ROW()-ROW($C$1))):INDEX(B:B,30*(ROW()-ROW($C$1)+1)))
I'm just not sure how to structure this in the most efficient, yet correct way possible. Not all months are the same amount of days, so I was hoping to check to get all the next n rows where the date starts with a "1" for example, sometimes certain days are also missing. I can't think of a catch all approach.
With 1/31/1970 in C1 try this,
=averageifs(daily!b:b, daily!a:a, "<="&c1, daily!a:a, ">="&eomonth(c1, -1)+1)
A PivotTable might be more convenient:
Excel's assumptions about cells are confusing the heck out of me. I'm on Office 365 - Excel for Mac, Version 15.28.
I'm TimeRecording on a lot of things, I would like to calculate relations and tendencies on the different things. I've exported my log-files, and have opened it in excel. A simple version looks like this:
In the real sheet, then I have 40+ tasks and 50+ dates. I would like to be able to do some calculations on these data. But Excel doesn't 'know what it is' (time durations) and therefore can't add them up or do anything.
So one question would be, to how to let Excel know, that this is time durations? I tried doing what this question suggests. But when I format the cells as [h]:mm then it gives me this error:
FYI: In the big sheet, then there's so many times, so the total amounts up to something along the lines of 633:33.
I would just like to be able to do simple calculations, such as:
=SUM(B1, C4, D5)
or
=SUM(B1, C4, D5)/COUNT(B1, C4, D5)
And maybe also make some charts and graphs.
Another attempt I've done is to try to get all the cells to have the format hh.mm instead of hh:mm, but this gave me problems. My approach was this:
Convert all the cells to 'Text' to tell Excel: 'Hey... Don't do any auto-converting/guessing here, and don't turn any of the cells into dates or decimal numbers or fricking origami swans!'
After that then I make a simple 'Replace all' of : to .
But after the 'Replace all', then 633:33 turns into 633.36.00 (even though the cell was a 'Text' cell).
And if I then simply double-click on the cell to edit it, then the numbers 'magically' turns from 633.36.00 to 27/01/1900 15.36.00 ... What the hell!? I need a procedure that doesn't require me to go through all my thousands of numbers and edit any of them (or ensure that Excel have turned the numbers into flying unicorns.
EDIT1
Here's an example of the total sheet I'm working on in Google Sheets.
EDIT2
If I format the cells as [h]:mm, then I get an error (see above). But if I format it as [t]:mm, then I don't get an error (thanks to Axel Richter for pointing that out). It may have something to do with the initial language of my Excel-installation (danish).
However... If I then try to sum up a bunch of cell, after doing this formatting to everything, then it sums up to 0:00.
If I format all the cells to Time (well-knowing that it's the wrong format, but hoping that Excel can see it and fix it) - and thereafter trying to sum up a couple of cells, then it sums up to 00.00.00 (even though it wasn't empty cells).
Is it also important, that when I sum up some numbers, that I do it from a General-cell - or does Excel know, that if I start with the =-sign, that it's going to be a calculation (and therefore the cell-format doesn't matter)?
Excel will store date-time values as floating point double values in following form:
1 day = 1
1 hour = 1/24 = 0.0416666666666667
1 minute = 1/24/60 = 0.000694444444444444
So formatted as time all values greater than or equal 0 but lower than 1 will be from 00:00 to 23:59. Values greater than 1 will be dates with 1 = 01/01/1900 00:00:00. But if you are formatting such values as time only using hh:mm for example, then only the time is shown. The date is simply hidden.
For example 1.25 formatted using hh:mm will show 06:00 although it is 1 1/4 day which is 01/01/1900 06:00:00. To see hours from multiple days the format [h]:mm can be used. For example 1.25 formatted using [h]:mm will show 30:00 which is 1 day (24:00) + 1/4 day (06:00).
Although Excel will do this independent of locale settings, the user defined format codes used and the kind of input values which Excel will take as time values are dependent of locale settings.
For example with your locale Danish (Greenland) the format codes are different. See Formatere tal som datoer eller klokkeslæt .
So your format code will be [t]:mm instead of [h]:mm.
And also with your locale Danish (Greenland) the time separator is . instead of :. So values which Excel will take as time values are 123.45 (123 hours, 45 minutes) instead of 123:45.
In your last comment you say: "whereafter it weirdly looked the same, such as: 123:45 and not 123.45". Yes that is because your user defined format [t]:mm contains the time separator : also. But that is different from your locale settings where . is the time separator. While inputting values Excel respects the locale settings and so expects 123.45 as time value for 123 hours and 45 minutes. But after the input Excel applies the cell formatting [t]:mm and so shows 123:45.
In your last comment you say that it confuses you that 17:24 * 24 equals 417:36. But that is exactly what it should.
17:24 is 17 hours and 24 minutes. That multiplied by 24 is 17 hours * 24 = 408 hours and 24 minutes * 24 = 576 minutes. 576 minutes are 9 hours and 36 minutes. So we get (408 hours + 9 hours) and 36 minutes = 417 hours and 36 minutes = 417:36.
I cannot edit the sheet so I copied it. As you can see in column AS and row 43, Google provides 'duration' format. You don't have to manipulate something. Just change the cell format.
In Excel, duration format is [h]:mm. Hit ctrl + 1 at the cell and choose Custom and type [h]:mm at Type and hit enter.
If SO answer is too difficult to follow, try this.
I apologize in advance for how rough this is, but I mostly slapped this code together to fit the task and didn't want to waste time on it. The principles are there though, so at the least it should point you in the direction you need to be heading.
Sub Time_Summarization()
Dim i As Long
Dim j As Long
Dim cell As Range
Dim sHolder As String
Dim vHolder As Variant
Dim arrHolder() As Double
Dim bAdd As Boolean
Dim dHolder_Whole As Double
Dim dHolder_Remainder As Double
Dim sOutput As String
ReDim arrHolder(0 To 2)
' Use a set range. Selection here is just for testing
' Ideally there should be data validation in this loop to ensure that the input
' values are numeric time values.
For Each cell In Selection
' Convert the cell value to a date to permit splitting.
' The value is then split into a 1-d array with 3 positions (H, M, S)
vHolder = Split(CDate(cell.value), ":")
' Loop through the split values from first to last, and trim off the AM/PM.
' If it is a PM date, set the flag to add 12 (13:00:00 gets displayed as 1:00:00 PM)
For j = LBound(vHolder) To UBound(vHolder)
' If PM, set the flag.
If InStr(vHolder(j), "PM") Then bAdd = True
' Remove "AM" and "PM"
vHolder(j) = Replace(vHolder(j), " AM", vbNullString)
vHolder(j) = Replace(vHolder(j), " PM", vbNullString)
' Add the values into the array in the same order.
arrHolder(j) = arrHolder(j) + vHolder(j)
Next
' Add 12 hours if needed
If bAdd Then arrHolder(0) = arrHolder(0) + 12
' Reset the flag for the next loop
bAdd = False
Next
' Step backwards through the array to round up increments of 60.
For i = UBound(arrHolder) To LBound(arrHolder) + 1 Step -1
' This will return the number of times the value goes into 60.
dHolder_Whole = arrHolder(i) \ 60
' This will return the remainder of the value divided by 60.
dHolder_Remainder = arrHolder(i) Mod 60
' Round up seconds to minutes, and minutes to hours.
arrHolder(i - 1) = arrHolder(i - 1) + dHolder_Whole
' Overwrite the remainder
arrHolder(i) = dHolder_Remainder
Next
' Combine the separate values into a string.
sHolder = arrHolder(0) & ":" & arrHolder(1) & ":" & arrHolder(2)
' Just for testing, do with the values whatever you wish.
Debug.Print sHolder
End Sub
Again, this is mostly a model that will work, but will need to be adapted to suit your needs.
Zeth, I downloaded your file and I can make some calculation with your time data. I juss selected all cell with time duration and change the format of cell to "time". Seemingly you should change all cells format, incluiding the empty cells.
If it does not work, find the "More format of numbers" ate the "Numbers" menu. Then, select the option "Hour" and chose the format closest to the format of your data. Also pay attenction to the option "locality" at the bottom of this menu. The option of hour format deppends on the region selected. (Each region in the world have some convenctions about it and Excel reconize much of then.
Formatting the numbers does not change the way Excel does calculations.
So a cell (c3) formatted as time and showing 01:28:00 actually contains 0.061111 because Excel treats time as fractions of a 24 hour day.
When you add up a lot of times and they add up to more than 24 hours the underlying number is more than 1 day so you get number of days before the decimal point and after the decimal point is the fraction of 24 hours remaining. So to convert a duration or time to hours you just multiply it by 24 and format it as a number or general (and the numbers after the decimal point are fractions of an hour). If you just want to format the result as hours and minutes use a format of [h]:mm and do not multiply by 24 - on your system look at Format Cells - Custom to see what the equivalent of [h:mm] is.
I am trying to compare the date of my Last B Service + Service interval months to todays date in Sharepoint. But it is giving me an error.
=IF(DATE(YEAR([Last B Service]),
MONTH([Last B Service])+[B Service Monthly Interval],
DAY([Last B Service])),"D")) >= NOW(), 0, 1)
I add B Service Monthly Interval to the Months section in the Date variable, then try and compare it to NOW() (todays date) to make this example easier, i have changed the result to 0 and 1 (i ahve also tested this and it returns an error)
Can you see whats wrong with that code?
I don't know what the "D" is doing in your formula as all the parentheses around that area make the formula invalid (you actually tried to close the IF after "D".
I don't know if it makes sense, but the following formula would work:
=IF(DATE(YEAR([Last B Service]);MONTH([Last B Service])+[B Service Monthly Interval];DAY([Last B Service])) >= NOW();0;1)
Here comes the trick: SharePoint calculated columns formula are largely compatible to Excel! What I actually did to try this out:
Open a new sheet
Write "4/14/13" into A1 (the last service)
Write "3" into B2 (the service interval)
Create the formula in C3: =IF(DATE(YEAR(A1);MONTH(A1)+B1;DAY(A1)) >= NOW();0;1)
Profit
i need to know how can i exclude 0 from rows and get the MIN Value.
But also i need to exlude the F1 Cell.
Ex:
A B C D E F
1 0 18 20 0 150 = 18
but if i do this In excel with =MIN(A1,B1,C1,D1,E1) return 0.
Any help is appreciated.
Try this formula
=SMALL((A1,C1,E1),INDEX(FREQUENCY((A1,C1,E1),0),1)+1)
Both SMALL and FREQUENCY functions accept "unions" as arguments, i.e. single cell references separated by commas and enclosed in brackets like (A1,C1,E1).
So the formula uses FREQUENCY and INDEX to find the number of zeroes in a range and if you add 1 to that you get the k value such that the kth smallest is always the minimum value excluding zero.
I'm assuming you don't have negative numbers.....
Enter the following into the result cell and then press Ctrl & Shift while pushing ENTER:
=MIN(If(A1:E1>0,A1:E1))
Not entirely sure what you want here, but if you want to discount blank cells in the range and pass over zeros then this would do it; if a little contrived:
=MIN(IF(A1:E1=0,MAX(A1:E1),A1:E1))
With Ctrl+Shift+Enter as an array.
What I'm doing here is replacing zeros with the maximum value in the list.
if all your value are positive, you can do -max(-n)
Solutions listed did not exactly work for me. The closest was Chief Wiggum - I wanted to add a comment on his answer but lack the reputation to do so. So I post as separate answer:
=MIN(IF(A1:E1>0;A1:E1))
Then instead of pressing ENTER, press CTRL+SHIFT+ENTER and watch Excel add { and } to respectively the beginning and the end of the formula (to activate the formula on array).
The comma "," and "If" statement as proposed by Chief Wiggum did not work on Excel Home and Student 2013. Need a semicolon ";" as well as full cap "IF" did the trick. Small syntax difference but took me 1.5 hour to figure out why I was getting an error and #VALUE.
Throwing my hat in the ring:
1) First we execute the NOT function on a set of integers,
evaluating non-zeros to 0 and zeros to 1
2) Then we search for the MAX in our original set of integers
3) Then we multiply each number in the set generated in step 1 by the MAX found in step 2, setting ones as 0 and zeros as MAX
4) Then we add the set generated in step 3 to our original set
5) Lastly we look for the MIN in the set generated in step 4
{=MIN((NOT(A1:A5000)* MAX(A1:A5000))+ A1:A5000)}
If you know the rough range of numbers, you can replace the MAX(RANGE) with a constant. This speeds things up slightly, still not enough to compete with the faster functions.
Also did a quick test run on data set of 5000 integers with formula being executed 5000 times.
{=SMALL(A1:A5000,COUNTIF(A1:A5000,0)+1)}
1.700859 Seconds Elapsed |
5,301,902 Ticks Elapsed
{=SMALL(A1:A5000,INDEX(FREQUENCY(A1:A5000,0),1)+1)}
1.935807 Seconds Elapsed |
6,034,279 Ticks Elapsed
{=MIN((NOT(A1:A5000)* MAX(A1:A5000))+ A1:A5000)}
3.127774 Seconds Elapsed |
9,749,865 Ticks Elapsed
{=MIN(If(A1:A5000>0,A1:A5000))}
3.287850 Seconds Elapsed |
10,248,852 Ticks Elapsed
{"=MIN(((A1:A5000=0)* MAX(A1:A5000))+ A1:A5000)"}
3.328824 Seconds Elapsed |
10,376,576 Ticks Elapsed
{=MIN(IF(A1:A5000=0,MAX(A1:A5000),A1:A5000))}
3.394730 Seconds Elapsed |
10,582,017 Ticks Elapsed
min() fuction exlude BOOLEAN and STRING values.
if you replace your zeroes with "" (empty string) - min() function will do its job as you like!
In Microsoft 365 you can use the new function MINIFS
=MINIFS(A1:E1;A1:E1;">0")
gives 1
=MINIFS(A1:E1;A1:E1;">1")
gives 18
*replace ; with , if using english version
All you have to do is to delete the "0" in the cells that contain just that and try again. That should work.