I am currently doing a "if then" loop in excel with following logic.
Value to Check
1. S9(7) C3
2. S9(11)V9(2) C3
3. X(3)
Logic I have used
=IF(ISNUMBER(SEARCH("S9",D1,1)),CONCATENATE("s370fpd",5,".","0"),CONCATENATE("$ebcdic",5,"."))
Now problem here is that S9 maybe of two types. In the first one i.e. S9(7) C3
it works fine but for second one i.e. S9(11)V9(2) C3 I have to CONCATENATE "s370fpd" with value inside bracket of V9 i.e. 2 in this case. So it will become "s370fpd5.2".
Since the value inside bracket is dynamic hence the logic has to search inside it. I am not sure how it will check and then append it.
I'm not sure what you're trying to do exactly, but keeping as much as what you have right now as possible, I would use this:
=IF(ISNUMBER(SEARCH("S9",D1,1)),CONCATENATE("s370fpd",5,".",IFERROR(MID(D1,SEARCH("V9",D1)+3,SEARCH(")",D1,SEARCH("V9",D1))-SEARCH("V9",D1)-3),"0")),CONCATENATE("$ebcdic",5,"."))
I substituted "0" with
IFERROR(MID(D1,SEARCH("V9",D1)+3,SEARCH(")",D1,SEARCH("V9",D1))-SEARCH("V9",D1)-3),"0")
which is what gets what's between brackets after V9.
It also appears to me that you can turn CONCATENATE("$ebcdic",5,".") into "$ebcdic5." directly and CONCATENATE("s370fpd",5,"." into CONCATENATE("s370fpd5.", and/or use & to make things a little shorter, but that's only subject to what you've put in your question:
=IF(ISNUMBER(SEARCH("S9",D1,1)),"s370fpd5."&IFERROR(MID(D1,SEARCH("V9",D1)+3,SEARCH(")",D1,SEARCH("V9",D1))-SEARCH("V9",D1)-3),"0"),"$ebcdic5.")
Related
Okay so my question is how do i use IF with 3 arguments while one of the arguments is "Ignore blanks".
If A1 is "Escalation_complaint or "Escalation_request" B1 must show "Escalated".
If A1 is any other text, B1 must show "Solved"
If A1 is blank, B1 must remain empty.
Can someone please help me figure this out?
Your first test must be whether the A1 is empty or not. This must be the first because if you test whether an empty string is contained in another string the answer is always yes. =SEARCH("","Something") returns 1. So, How do you test for an empty cell? I recommend Excel's COUNTA() function but you may prefer testing for "". So, let's say, your first test is this.
=IF(COUNTA(A1), True, False)
Some would say IF(COUNTA(A1)>0, True, False) and that is equivalent. The simple IF(COUNTA(A1) tests for non-zero. Any number other than zero returns True.
So, now you got your basic function. What's supposed to happen if the result is True? What do you want to happen if the result is False? The latter is easy. If the result is False you want a null string returns. So, now your formula looks like this:-
=IF(COUNTA(A1), True, "")
Observe that we simply replaced the False with the desired output. So, what do you want to happen if A1 has something in it, if the first test resulted in True? There are two possibilities. That makes the problem solvable with a single IF. IF A1 has something starting with "Escalation" in it the result should be "escalate", else it should be "solved". So, how do you test for cell content?
=Find("escalation", A1) will not find "Escalation" (with a capital E). Therefore I recommend SEARCH(), which does.
=SEARCH("escalation", A1) should return 1. If it returns 1 your problem is solved because if it returns any other number its not "escalated" but "solved". Unfortunately, there is a third option. It might return an error. In fact it will return an error every time the word isn't found. That gives you a 3-way possibility (1, bigger than 1, or Error) which can't be solved with a single IF. So, I suggest to avoid the error.
=Find("escalation", A1 & "escalation") will find the word "escalation" every time. But it will find it in first position only if the conditions for "Escalate" is met. Therefore the formula for the True condition in the basic formula must be this:-
IF(SEARCH("escalation", A1 & "escalation") = 1, "Escalated", "Solved")
That's it. Assemble the second IF into the first and you're done.
So, using two if(), and minimising the testing you need :
=IF(left(A1,3)="Esc","Escalated",IF(A1="","","Solved"))
Edit: Based on a comment to another answer, if testing for "esc" only could lead to problems then how about:
=IF(left(A1,5)="Escal","Escalated",IF(A1="","","Solved"))
Which will avoid words like "escaped" or "escargot"...
If you know that the text will always be Escalation_complaint or Escalation_request, you can do this with a nested IF query. =IF in Excel takes three parameters: what to verify, result if true, and result if false. You can have another IF statement in the what to do if it returns false section. We can also do an OR() statement to verify both Escalation_complaint and Escalation_request. The result looks like this:
=IF(OR(A1="Escalation_complaint",A1="Escalation_request"),"Escalated",IF(A1="","","Solved"))
The order here is important because you want the "for all other cases" to be in the final IF statement.
If you have a situation where you could also have "Request_escalation" or "complaint_escalation", you should make a more general solution that uses SEARCH or FIND which would allow you to do a more general lookup that allows for more values without having to hardcode them. Here is an example that makes it possible to find the word Escalation anywhere in the cell:
=IF(IFERROR(SEARCH("escalation",A1,1),0)>0, "Escalated", IF(A1="","","Solved"))
Excel have maximum 30 arguments in a formula.
= if (A1=1, "True",if(B1>2,"True", "false"))
Understand this pattern. easy way.
If you no longer understand this, or if your problem has not been resolved, attach a file or screenshot that relates to your problem.
I have column I as a calulation column and this is what I currently wrote.
and this gives me nothing.
=IF(B2<>""&D2<>"",B2*D2,IF(B2<>""&D2=""&C2<>"",B2*C2,IF(A2<>""&C2<>""&AND(B2&D2=""),A2*C2,IF(A2<>""&C2=""&D2<>""&B2="",A2*D2,A2*C2))))
The logic is if B2 and D2 are not null multiply b2*d2
if B2 is not null and D2 null then b2*c2
If B2 is null and D2 is not null then a2*d2
else a2*c2
Is any ways to make this code work?
Thank you
Alternative ways or rewriting your formula:
=IF(AND(B2<>"",D2<>""),B2*D2,IF(D2="",IF(B2<>"",B2*C2,A2*C2),IF(D2<>"",A2*D2,A2*C2)))
=IF(AND(B2<>"",D2<>""),B2*D2,IF(AND(B2="",D2=""),A2*C2,IF(D2="",B2*C2,A2*D2)))
They will make negligible difference in performance and what not. BruceWayne's answer is probably more readable in terms of following your logic and therefore easier to maintain or understand in the future. The above answers should provide the same results but are a few characters shorter in length.
And as a wacky alternative for thinking potentially outside the box:
=CHOOSE(SUM((B2<>"")*2+(D2<>""))+1,A2*C2,A2*D2,B2*C2,B2*D2)
Expanding (not just my waist size)
I had time on my hands so I was fooling around with the concept of TRUE and FALSE being equal to 1 and 0 when sent through a math operation. When I started looking at the options this reminded me of how a binary number works. Not that I have bgiven it too much thought, but I think it works because the options for each cell are binary or TRUE/FALSE. Since every possible combination was covered with a unique out come, I just had to come up with a formula that would produce unique results. In this case I just took the converting a a binary number approach. The key is TRUE = 1 after a math operation and FALSE = 0. Now going the other direction is not quite the same but as Jeeped once put it, 0 is FALSE and everything else is TRUE. so 3, -3, and 3.14 are all treated as TRUE if using the numerical values as the outcome of a logic check.
=IF(3.14,"THIS NUMBER IS TRUE","ONLY 0 IS FALSE")
So less side tracking and back on point (not sure how much I need to expand to!).
Looking at the table above, you will note in the yellow area, all possible combination for BLANK and NOT BLANK are listed. If you then assign a value to the column the same way binary numbers are (note row A) you can then start generating all the possible numbers
I started by generating the list I needed in E2:E5 for numbers that CHOOSE could work with. I assumed 0 would beat up CHOOSE and cause it to fail. I knew that FALSE+FALSE=0 and I also knew that TRUE+TRUE=2 and that both TRUE+FALSE=1 and FALSE+TRUE=1. I needed a way to distinguish the later two and I knew I needed a total of 4 results. That is when binary counting/conversion whatever you want to call it kicked in. I placed the following formula in D2 and copied down
=SUM((A2<>"")*2+(B2<>""))
Note the brackets around the logic check and
that the logic checks are sent through a math
operation before being summed.
technically speacking it is really:
=SUM((A2<>"")*2+(B2<>"")*1)
however the *1 is not needed
once I had that list generate, it was a simple +1 added to it to get into the 1 to 4 range seen in E2:E5.
Now that I had a way of generating the index number the only thing left to do was to match up the required results/formula with the right combination.
=CHOOSE(SUM((A2<>"")*2+(B2<>""))+1,"A","B","C","D")
Well I felt like I was beating a dead horse there for a bit, so if I over explained, my apologies. If there is something still missing ask for more explination.
UPDATE TID BIT
IF there were more columns to check it may be possible to adjust the choose formula by simply adding the next binary value to the column and making sure there is an appropriate number of results in the choose list. There should be 2^(# of columns to check) options
=CHOOSE(SUM((A2<>"")*4+(A2<>"")*2+(B2<>""))+1,"A","B","C","D","E","F","G","H")
Which kind of beats multiple nested IFs for brevity, but I think I finds the nested IFs easier to understand.
You should be using AND():
=IF(AND(B2<>"",D2<>""),B2*D2,IF(AND(B2<>"",D2=""),B2*C2,IF(AND(B2="",D2<>""),A2*D2,A2*C2)))
You seem to be mixing operators from other programming languages:
In Excel:
AND : binary operator : AND(TRUE, FALSE) => FALSE
& : concatenation : "Hello " & "World" => "Hello World"
I have something like this:
A1: ABC-DE442
B1: 0069-1234-12
I'm trying to make a formula that will look at A1, get the number 442, and then check if B1 is in the format of 4 numbers, a dash, 4 numbers, a dash, and then finally 2 numbers. I want to make sure that this could work with any number besides 442 though. So if I had like 123 instead of 442, it would need to be 1 number, dash, 2 numbers, dash, and three numbers.
It would also need to give me an error if I had something like this:
A1: ABC-DE442
B1: 004-2345-34
because it only has three numbers in the first section before the dash.
Hopefully I have been clear enough in what I'm trying to do. Any help would be greatly appreciated.
So in the end, this is the giant formula I had to create:
=IF(LEN(LEFT(J4,FIND("-",J4)-1))=VALUE(MID(I4,9,1)),IF(LEN(LEFT(MID(J4,FIND("-",J4)+1,999),FIND("-",MID(J4,FIND("-",J4)+1,999))-1))=VALUE(MID(I4,10,1)),IF(LEN(MID(MID(J4,FIND("-",J4)+1,999),FIND("-",MID(J4,FIND("-",J4)+1,999))+1,999))=VALUE(MID(I4,11,1)),"True","Doesn't match code part 3"),"Doesn't match code part 2"),"Doesn't match code part 1")
J15: 0069=LEFT(J5,FIND("-",J5)-1)
J16: 4=VALUE(MID(I5,7,1))
J17: 4=LEN(J15)
J18: 0469-56=MID(J5,FIND("-",J5)+1,999)
J19: 0469=LEFT(J18,FIND("-",J18)-1)
J20: 4=VALUE(MID(I5,8,1))
J21: 4=LEN(J19)
J22: 56=MID(J18,FIND("-",J18)+1,999)
J23: 2=VALUE(MID(I5,9,1))
J24: 2=LEN(J22)
Hopefully all of these formulas will make it easier to understand how I combined everything together.
I essentially put every formula into one giant one using the information used in the answer I said was right. For the first part, I took the LEN(D1) but had it all written out, and then set it equal to the =VALUE(MID(A1,7,1)).
Then, for the true part of that if statement, I had to first get A1 without D1, then get it to just be the middle section using the LEFT formula, and then finally taking the LEN of that. Checked to see if it was equal to the =VALUE(MID(I4,10,1)), which was the next number in B1.
If that was true, I went to the final IF statement which again had to go through the same process of getting the last section of A1 on it's own, taking the length of that, and seeing if it was equal to =VALUE(MID(I4,11,1)).
Finally, I just created different print statements for the last true, and every false section of the IF statements.
Moral of the story, I was able to make a formula that works with every single number combination because it turns out B1 could only be in the form of AB - CDE###, so I could always find that number in B1 and compare it.
This should be possible with Excel formulae but it will get a bit complicated. The functions you're probably going to want to make use of are FIND, LEFT, LEN, MID, and VALUE.
For example,
C1: =FIND("-",B1)
will return the position of the first dash in the string to be tested, which for your example is 5. Then
D1: =LEFT(B1,C1-1)
would return the characters before that dash, i.e. '0069'. Meanwhile you need to get the lengths of the three runs of digits out of your first string (the one in A1). Will that string always be the same length? If so you can use e.g.
=VALUE(MID(A1,7,1))
which returns the 7th character of the string in A1 and converts it to a number (4). Now you can test whether that value is equal to the length of the first run of characters, i.e. LEN(D1).
But are those characters all numeric? Well, you can try converting them to a number with VALUE(D1) which will return #VALUE if the argument can't be made into a number.
OK, that checked the first run of characters, what about the rest of them? Well,
=MID(B1,FIND("-",B1)+1,999)
will give you the remainder of the original string after the first dash, which you can analyse in the same way, and so on.
It's easiest to develop these formulae by using lots of cells to hold the intermediate values as you work them out, but once you're confident these are working OK you can consolidate them into fewer cells. Whatever you come up with, make sure you test it with lots of different inputs to check that your formulae respond to them in the way that you expect. (In particular, check what happens if you have one or more spaces after a dash, as VALUE will ignore leading spaces - you might want to use a SUBSTITUTE function on your initial text to remove any spaces.)
It seems like a bit of an omission that there's no easy way to create a user-defined declarative function in Excel without defining a macro. I can't use XSLM with the uphill battle that will entail in the Enterprise, but I want to be able to define a function with intent thus.
I want to do this;
=BreakEven(C1:C20)
But I can't use a macro, although I can use a "named formula". The trouble is how to pass parameters to that? I've seen a couple of tricks (kludgy workarounds) but not for xslx.
I'd like to be able to define a Breakeven() function in another tab and reference it here passing in MORE THAN one parameter, two ranges in fact. I'm sure there's some way using string parsing but I can't see it.
I don't mind if the function doesn't look exactly like that, as long as it evaluates within the cell and I can parse it for 'intent'. For instance, this example (http://www.jkp-ads.com/articles/ExcelNames09.asp) which I was unable to get to work in xlsx uses this syntax;
=IF(ROW(D3),CellColor)
Where "cellcolor" is the name of the function and D3 is the range parameter. The other solution I'm toying with is to define a function in column format with a variable argument list (this is two rows of an excel spreadsheet);
[Value][function][parameter1][parameter2][parameter3]
24050 BreakEven C1:C20 A1:A20
It's not pretty, but the benefit of the latter is that it describes the function to an external reader. We know it's a breakeven function, whereas if we put the actual formula "OFFSET,INDIRECT,SUM()()()()etc" it would not be readable/parseable. Of course, in that case, I'd have to construct the value field by parsing the cells to the right in Excel, which would make the Value formula messy but at least it would be a self-describing row.
Can anyone suggest a better method?
Poor-man's UDF
So I think what we're going to have to do is this;
A B C D E
1 [Value][function][parameter1][parameter2][parameter3]
2 24050 BreakEven C1:C20 A1:A20
3 111 mySum 1 10 100
Where "BreakEven" is a "named function". Here's the formula for "mySum";
=sum(C1:E1)
To evaluate functions listed in B, we just put this in column A (transposing the same value for all rows in column A;
=value(B)
This works because A2 and A3 both evaluate column B as a value, which causes BreakEven and Sum to run (as poor-man's UDFs) in the context of A2 and A3. The range (C1:E1) is relative of course.
So in effect, we can write any function name in column B (as long as there's a corresponding named function defined in the workbook which can be as complex as you like). Columns C, D and E act as the parameters for the function on the same row.
I would have loved to just be able to write the following in column A instead;
=mySum(1,10,100)
But in the absence of that support, the mechanism above serves to provide a readable parameterised function that would be understandable by a user, that's also machine readable (works in CSV too) and allows us to offload our re-usable functions to a library sheet somewhere in the workbook for maintenance.
Not perfect, but an acceptable compromise, unless anyone has a clever way of doing this in a single cell?
Not really an answer, but easier to illustrate here than in a comment. Although you can't rename formulas in a simplistic way - I like your suggestion actually I've never thought about that before; but then I've never worked in a non-macro environment so this has never occurred- you can add notes into the actual formula explaining what it does. For example:
=N("This is a really complex BreakEven Formula")+SUM(3,4,5)
Is a perfectly valid formula. As I said, not really an answer, but could potentially add clarity to a complex formula
You can do this with a small trick
For example to create effectively a cuberoot UDF that emulates =cuberoot(x) then name a variable as cuberoot with a 'value' like this.
=(RC[-1])^(1/3)
Now you can either do this using a temporary switch to RC mode, or put the cursor in say cell E5 and type the name value as =(D5)^(1/3)
Now whenever you need a cuberoot you can put the argument in any cell and put =cuberoot in the cell to its right. It really works and follows true Excel rules.
I use it for multiparameter models that have the single 'argument' Time as a dependent variable. I then define the term Model as the model equation eg =a+bTime+cTime^2
where a,b,c are already named locations holding unique parameter values -
and then define Time as =RC[-1]
My sheets are filled with cells simply saying =Model and have the required time value to the left (ie their argument). It is simple to extend to multi arg functions using multiple cells. It usually fits in well with spreadsheet layouts. Change the definition of your model once in the define name box and all places change simultaneously.
I have a function called ToDMS which takes the decimal degree value in the preceding cell and converts it to a deg Min and Sec string - very tidy.
You need the degrees to be in a single cell but want it in the alt. form in another cell
elegant, simple and it works
Bob Jordan
Seems like it would be a simple thing really (and it may be), but I'm trying to take the string data of a column and then through a calculated column, replace all the spaces with %20's so that the HTML link in the workflow produced email will actually not break off at the first space.
For example, we have this in our source column:
file:///Z:/data/This is our report.rpt
And would like to end up with this in the calculated column:
file:///Z:/data/This%20is%20our%20report.rpt
Already used the REPLACE, and made up a ghastly super nested REPLACE/SEARCH version, but the problem there is that you have to nest for EACH potential space, and if you don't know how many up front, it doesn't work, or will miss some.
Have any of you come across this scenario and how did you handle it?
Thanks in advance!
As far as I know there is no generic solution using the calculated-column syntax. The standard solution for this situation is using an ItemAdded (/ItemUpdated) event and initializing the field value from code.
I was able to solve this issue for my circumstances by using a series of calculated columns.
In the first calculated column (C1) I entered a formula to remove the first space, something like this:
=IF(ISNUMBER(FIND(" ",[Title])),REPLACE([Title],FIND(" ",[Title]),1,"%20"),[Title])
In the second Calculated column (C2) I used:
=IF(ISNUMBER(FIND(" ",[C1])),REPLACE([C1],FIND(" ",[C1]),1,"%20"),[C1]).
In my case, I wanted to encode upto four spaces, so I used 3 calculated columns (C1, C2, C3) in the same fashion and got the desired result.
This is not as efficient as using a single calculated column, but if SUBSTITUTE will not work in your SharePoint environment, and you cannot use an event handler or workflow, it may offer a workable alternative.
I actually used a slightly different formula, but it was on a work machine to which I don't have access at the moment, so I just grabbed this formula from a similar S.O. question. Any formula that will replace the first occurrence of a space with "%20" will work, the trick is to a) make sure the formula returns the original string unchanged if it does not have more spaces in it, and b) test, test, test. Create a view of your list that has the field you are trying to encode, plus the calculated fields, and see if you are getting the results you want.
so that the HTML link in the workflow produced email will actually not break off at the first space.
The browser only does this if you have not enclosed your link in quotes
If you wrap the link in quotes, it does not cut off at the first space
In a SharePoint Formula it would be:
="""file:///Z:/data/This is our report.rpt"""
becuase two quotes are the SP escape notation to output a quote
You can use this formula (Start trim for 1, in my case was 4):
=IF(ISBLANK([EUR Amount]),"",(TRIM(MID([EUR Amount],4,2))&TRIM(MID([EUR Amount],6,2))&TRIM(MID([EUR Amount],8,2))&TRIM(MID([EUR Amount],10,2))&TRIM(MID([EUR Amount],12,2))&TRIM(MID([EUR Amount],14,2)))*1)